C primer plus 編程練習答案

1、c primer plus 編程練習答案chapter 2pe 2-1/* programming exercise 2-1 */#include int main(void) printf(anton brucknern); printf(antonnbrucknern); printf(anton ); printf(brucknern); return 0;pe 2-3/* programming exercise 2-3 */#include int main(void) int ageyears; /* age in years */ int agedays; /* age in d

2、ays */ /* large ages may require the long type */ ageyears = 44; agedays = 365 * ageyears; printf(an age of %d years is %d days.n, ageyears, agedays); return 0;pe 2-4/* programming exercise 2-4 */#include void jolly(void);void deny(void);int main(void) jolly(); jolly(); jolly(); deny(); return 0;voi

3、d jolly(void) printf(for hes a jolly good fellow!n);void deny(void) printf(which nobody can deny!n);pe 2-5/* programming exercise 2-5 */#include int main(void) int toes; toes = 10; printf(toes = %dn, toes); printf(twice toes = %dn, 2 * toes); printf(toes squared = %dn, toes * toes); return 0;/* or c

4、reate two more variables, set them to 2 * toes and toes * toes */pe 2-6/* programming exercise 2-6 */#include void once();void main(void)once();once();once();printf(n);once();once();printf(n);once();printf(n);void once()printf(smile!);pe 2-7/* programming exercise 2-7 */#include void one_three(void)

5、;void two(void);int main(void) printf(starting now:n); one_three(); printf(done!n); return 0;void one_three(void) printf(onen); two(); printf(threen);void two(void) printf(twon);chapter 3pe 3-2/* programming exercise 3-2(1) */#include int main(void) int ascii; printf(enter an ascii code: ); scanf(%d

6、, &ascii); printf(%d is the ascii code for %c.n, ascii, ascii); return 0;/* programming exercise 3-2(2) */#include int main(void)int num;printf(please enter a num:);scanf(%d,&num);printf(the code for the num is %cn,num);return 0;pe 3-3/* programming exercise 3-3 */#include int main(void)printf(a);pr

7、intf(alarm and print a line of wordn);return 0;pe 3-4/* programming exercise 3-4(1) */#include int main(void) float num; printf(enter a floating-point value: ); scanf(%f, &num); printf(fixed-point notation: %fn, num); printf(exponential notation: %en, num); return 0;/* programming exercise 3-4(2) */

8、#include int main(void)long float a;a=21.290000;printf(the input is %lf or %le.n,a,a);return 0;pe 3-5/* programming exercise 3-5 */#include int main(void)long int age;printf(please enter your age:n);scanf(%d,&age);printf(your age equals to %lf seconds.n,age*3.156e7);return 0;pe 3-6/* programming exe

9、rcise 3-6 */#include int main(void) float mass_mol = 3.0e-23; /* mass of water molecule in grams */ float mass_qt = 950; /* mass of quart of water in grams */ float quarts; float molecules; printf(enter the number of quarts of water: ); scanf(%f, &quarts); molecules = quarts * mass_qt / mass_mol; pr

10、intf(%f quarts of water contain %e molecules.n, quarts, molecules); return 0;pe 3-6/* programming exercise 3-7 */#include int main(void)float height;printf(please enter your height:n);scanf(%fg,&height);printf(your height equals to %f cm.n,height*2.54);return 0;chapter 4pe 4-1/* programming exercise

11、 4-1 */#include int main(void) char fname40; char lname40; printf(enter your first name: ); scanf(%s, fname); printf(enter your last name: ); scanf(%s, lname); printf(%s, %sn, lname, fname); return 0;pe 4-4/* programming exercise 4-4 */#include int main(void) float height; char name40; printf(enter

12、your height in inches: ); scanf(%f, &height); printf(enter your name: ); scanf(%s, name); printf(%s, you are %.3f feet talln, name, height / 12.0); return 0;pe 4-6/* programming exercise 4-6 */#include #include int main(void) float ot_f = 1.0 / 3.0; double ot_d = 1.0 / 3.0; printf( float values: );

13、printf(%.4f %.12f %.16fn, ot_f, ot_f, ot_f); printf(double values: ); printf(%.4f %.12f %.16fn, ot_d, ot_d, ot_d); printf(flt_dig: %dn, flt_dig); printf(dbl_dig: %dn, dbl_dig); return 0;chapter 5pe 5-1/* programming exercise 5-1 */#include int main(void) const int minperhour = 60; int minutes, hours

14、, mins; printf(enter the number of minutes to convert: ); scanf(%d, &minutes); while (minutes 0 ) hours = minutes / minperhour; mins = minutes % minperhour; printf(%d minutes = %d hours, %d minutesn, minutes, hours, mins); printf(enter next minutes value (0 to quit): ); scanf(%d, &minutes); printf(b

15、yen); return 0;pe 5-3/* programming exercise 5-3 */#include int main(void) const int daysperweek = 7; int days, weeks, day_rem; printf(enter the number of days: ); scanf(%d, &days); weeks = days / daysperweek; day_rem = days % daysperweek; printf(%d days are %d weeks and %d days.n, days, weeks, day_

16、rem); return 0;pe 5-5/* programming exercise 5-5 */#include int main(void) /* finds sum of first n integers */ int count, sum; int n; printf(enter the upper limit: ); scanf(%d, &n); count = 0; sum = 0; while (count+ n) sum = sum + count; printf(sum = %dn, sum); return 0;pe 5-7/* programming exercise

17、 5-7 */#include void showcube(double x);int main(void) /* finds cube of entered number */ double val; printf(enter a floating-point value: ); scanf(%lf, &val); showcube(val); return 0;void showcube(double x) printf(the cube of %e is %e.n, x, x*x*x );chapter 6pe 6-1/* pe6-1.c */* this implementation

18、assumes the character codes */* are sequential, as they are in ascii. */#include #define size 26int main( void ) char lcasesize; int i; for (i = 0; i size; i+) lcasei = a + i; for (i = 0; i size; i+) printf(%c, lcasei); printf(n); return 0;pe 6-3/* pe6-3.c */* this implementation assumes the charact

19、er codes */* are sequential, as they are in ascii. */#include int main( void ) char let = f; char start; char end; for (end = let; end = a; end-) for (start = let; start = end; start-) printf(%c, start); printf(n); return 0;pe 6-5/* pe6-5.c */#include int main( void ) int lower, upper, index; int sq

20、uare, cube; printf(enter starting integer: ); scanf(%d, &lower); printf(enter ending integer: ); scanf(%d, &upper); printf(%5s %10s %15sn, num, square, cube); for (index = lower; index = upper; index+) square = index * index; cube = index * square; printf(%5d %10d %15dn, index, square, cube); return

21、 0;pe 6-7/* pe6-7.c */#include int main( void ) double n, m; double res; printf(enter a pair of numbers: ); while (scanf(%lf %lf, &n, &m) = 2) res = (n - m) / (n * m); printf(%.3g - %.3g)/(%.3g*%.3g) = %.5gn, n, m, n, m, res); printf(enter next pair (non-numeric to quit): ); return 0;pe 6-10/* pe6-1

22、0.c */#include #define size 8int main( void ) int valssize; int i; printf(please enter %d integers.n, size); for (i = 0; i 0; i-) printf(%d , valsi); printf(n); return 0;pe 6-12/* pe6-12.c */* this version starts with the 0 power */#include #define size 8int main( void ) int twopowssize; int i; int

23、value = 1; /* 2 to the 0 */ for (i = 0; i size; i+) twopowsi = value; value *= 2; i = 0; do printf(%d , twopowsi); i+; while (i size); printf(n); return 0;pe 6-13/* pe-13.c */* programming exercise 6-13 */#include #define size 8int main(void) double arrsize; double arr_cumulsize; int i; printf(enter

24、 %d numbers:n, size); for (i = 0; i size; i+) printf(value #%d: , i + 1); scanf(%lf, &arri); /* or scanf(%lf, arr + i); */ arr_cumul0 = arr0; /* set first element */ for (i = 1; i size; i+) arr_cumuli = arr_cumuli-1 + arri; for (i = 0; i size; i+) printf(%8g , arri); printf(n); for (i = 0; i size; i

25、+) printf(%8g , arr_cumuli); printf(n); return 0;pe 6-15/* pe6-15.c */#include #define rate_simp 0.10#define rate_comp 0.05#define init_amt 100.0int main( void ) double daphne = init_amt; double deidre = init_amt; int years = 0; while (deidre = daphne) daphne += rate_simp * init_amt; deidre += rate_

26、comp * deidre; +years; printf(investment values after %d years:n, years); printf(daphne: $%.2fn, daphne); printf(deidre: $%.2fn, deidre); return 0;chapter 7pe 7-1/* programming exercise 7-1 */#include int main(void) char ch; int sp_ct = 0; int nl_ct = 0; int other = 0; while (ch = getchar() != #) if

27、 (ch = ) sp_ct+; else if (ch = n) nl_ct+; else other+; printf(spaces: %d, newlines: %d, others: %dn, sp_ct, nl_ct, other); return 0;pe 7-3/* programming exercise 7-3 */#include int main(void) int n; double sumeven = 0.0; int ct_even = 0; double sumodd = 0.0; int ct_odd = 0; while (scanf(%d, &n) = 1

28、& n != 0) if (n % 2 = 1) sumodd += n; +ct_odd; else sumeven += n; +ct_even; printf(number of evens: %d, ct_even); if (ct_even 0) printf( average: %g, sumeven / ct_even); putchar(n); printf(number of odds: %d, ct_odd); if (ct_odd 0) printf( average: %g, sumodd / ct_odd); putchar(n); printf(ndonen); r

29、eturn 0;pe 7-5 /* programming exercise 7-5 */#include int main(void) char ch; int ct1 = 0; int ct2 = 0; while (ch = getchar() != #) switch(ch) case . : putchar(!); +ct1; break; case ! : putchar(!); putchar(!); +ct2; break; default : putchar(ch); printf(%d replacements of . with !n, ct1); printf(%d r

30、eplacements of ! with !n, ct2); return 0;pe 7-7 /* programming exercise 7-7 */#include #define basepay 10 /* $10 per hour */#define basehrs 40 /* hours at basepay */#define overtime 1.5 /* 1.5 time */#define amt1 300 /* 1st rate tier */#define amt2 150 /* 2st rate tier */#define rate1 0.15 /* rate f

31、or 1st tier */#define rate2 0.20 /* rate for 2nd tier */#define rate3 0.25 /* rate for 3rd tier */int main(void) double hours; double gross; double net; double taxes; printf(enter the number of hours worked this week: ); scanf(%lf, &hours); if (hours = basehrs) gross = hours * basepay; else gross =

32、basehrs * basepay + (hours - basehrs) * basepay * overtime; if (gross = amt1) taxes = gross * rate1; else if (gross = amt1 + amt2) taxes = amt1 * rate1 + (gross - amt1) * rate2; else taxes = amt1 * rate1 + amt2 * rate2 + (gross - amt1 - amt2) * rate3; net = gross - taxes; printf(gross: $%.2f; taxes:

33、 $%.2f; net: $%.2fn, gross, taxes, net); return 0;pe 7-9 /* programmming exercise 7-9 */#include #define no 0#define yes 1int main(void) long num; /* value to be checked */ long div; /* potential divisors */ long lim; /* limit to values */ int prime; printf(please enter limit to values to be checked

34、; ); printf(enter q to quit.n); while (scanf(%ld, &lim) = 1 & lim 0) for (num = 2; num = lim; num+) for (div = 2, prime = yes; (div * div) = num; div+) if (num % div = 0) prime = no; /* number is not prime */ if (prime = yes) printf(%ld is prime.n, num); printf(please enter another limit; ); printf(

35、enter q to quit.n); return 0;pe 7-11 /* pe7-11.c */* programming exercise 7-11 */#include #include int main(void) const double price_artichokes = 1.25; const double price_beets = 0.65; const double price_carrots = 0.89; const double discount_rate = 0.05; char ch; double lb_artichokes; double lb_beet

36、s; double lb_carrots; double lb_total; double cost_artichokes; double cost_beets; double cost_carrots; double cost_total; double final_total; double discount; double shipping; printf(enter a to buy artichokes, b for beets, ); printf(c for carrots, q to quit: ); while (ch = getchar() != q & ch != q)

37、if (ch = n) continue; while (getchar() != n) continue; ch = tolower(ch); switch (ch) case a : printf(enter pounds of artichokes: ); scanf(%lf, &lb_artichokes); break; case b : printf(enter pounds of beets: ); scanf(%lf, &lb_beets); break; case c : printf(enter pounds of carrots: ); scanf(%lf, &lb_ca

38、rrots); break; default : printf(%c is not a valid choice.n); printf(enter a to buy artichokes, b for beets, ); printf(c for carrots, q to quit: ); cost_artichokes = price_artichokes * lb_artichokes; cost_beets = price_beets * lb_beets; cost_carrots = price_carrots * lb_carrots; cost_total = cost_art

39、ichokes + cost_beets + cost_carrots; lb_total = lb_artichokes + lb_beets + lb_carrots; if (lb_total = 0) shipping = 0.0; else if (lb_total 5.0) shipping = 3.50; else if (lb_total 100.0) discount = discount_rate * cost_total; else discount = 0.0; final_total = cost_total + shipping - discount; printf

40、(your order:n); printf(%.2f lbs of artichokes at $%.2f per pound:$ %.2fn, lb_artichokes, price_artichokes, cost_artichokes); printf(%.2f lbs of beets at $%.2f per pound: $%.2fn, lb_beets, price_beets, cost_beets); printf(%.2f lbs of carrots at $%.2f per pound: $%.2fn, lb_carrots, price_carrots, cost

41、_carrots); printf(total cost of vegetables: $%.2fn, cost_total); if (cost_total 100) printf(volume discount: $%.2fn, discount); printf(shipping: $%.2fn, shipping); printf(total charges: $%.2fn, final_total); return 0;chapter 8pe 8-1 /* programming exercise 8-1 */#include int main(void) int ch; int ct = 0; while (ch = getchar() != eof) ct+; printf(%d characters readn, ct); return 0;pe 8-3 /* programming exercise 8-3 */* using ctype.h eliminates need to assume ascii coding */#include #include int main(void) in