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1、2014年上海市金山區(qū)中考數(shù)學(xué)一模試卷一、選擇題:(本大題共6題,每題4分,滿分24分)1兩個相似三角形的面積比為1:4,那么這兩個三角形的周長比為()a1:2b1:4c1:8d1:16顯示解析2如果向量a與單位向量e方向相反,且長度為12,那么向量a用單位向量e表示為()aa12eba2eca12eda2e顯示解析3將拋物線y=x2向右平移1個單位,所得新拋物線的函數(shù)解析式是()ay=(x+1)2by=(x-1)2cy=x2+1dy=x2-1顯示解析4在rtabc中,a=90,如果把這個直角三角形的各邊長都擴(kuò)大2倍,那么所得到的直角三角形中,b的正切值()a擴(kuò)大2倍b縮小2倍c擴(kuò)大4倍d大小
2、不變顯示解析5已知在rtabc中,c=90,a=,bc=m,那么ab的長為()amsinbmcoscmsindmcos顯示解析6在平面直角坐標(biāo)系中,拋物線y=-(x-2)2+1的頂點(diǎn)是點(diǎn)p,對稱軸與x軸相交于點(diǎn)q,以點(diǎn)p為圓心,pq長為半徑畫p,那么下列判斷正確的是()ax軸與p相離bx軸與p相切cy軸與p相切dy軸與p相交顯示解析二、填空題:(本大題共12題,每題4分,滿分48分)7如果2x=3y,那么2x+y2xy=顯示解析8已知在abc中,點(diǎn)d、e分別在邊ab、ac上,debc,adab=35,那么aece的值等于顯示解析9計算:2(a+2b)3b=顯示解析10拋物線y=x2+2x的對稱
3、軸是顯示解析11二次函數(shù)y=2x2+t的圖象向下平移2個單位后經(jīng)過點(diǎn)(1,3),那么t=顯示解析12已知在abc中,c=90,ab=12,點(diǎn)g為abc的重心,那么cg=顯示解析13已知在rtabc中,c=90,bc=3ac,那么a=度顯示解析14已知在rtabc中,c=90,cotb=13,bc=3,那么ac=顯示解析15已知內(nèi)切兩圓的圓心距為6,其中一個圓的半徑為4,那么另一個圓的半徑為顯示解析16如果正n邊形的每一個內(nèi)角都等于144,那么n=顯示解析17正六邊形的邊長為a,面積為s,那么s關(guān)于a的函數(shù)關(guān)系式是顯示解析18在rtabc中,c=90,cosb35,把這個直角三角形繞頂點(diǎn)c旋轉(zhuǎn)后
4、得到rtabc,其中點(diǎn)b正好落在ab上,ab與ac相交于點(diǎn)d,那么bdcd=顯示解析三、解答題:(本大題共7題,滿分78分)19計算:2sin260cos245cos30tan30tan60cot45顯示解析20已知一個二次函數(shù)y=x2+bx+c的圖象經(jīng)過點(diǎn)(4,1)和(-1,6)(1)求這個二次函數(shù)的解析式;(2)求這個二次函數(shù)圖象的頂點(diǎn)坐標(biāo)和對稱軸顯示解析21如圖,已知ab是o的弦,點(diǎn)c在線段ab上,oc=ac=4,cb=8求o的半徑顯示解析22如圖1,某超市從底樓到二樓有一自動扶梯,圖2是側(cè)面示意圖已知自動扶梯ab的坡度為1:2.4,ab的長度是13米,mn是二樓樓頂,mnpq,c是mn
5、上處在自動扶梯頂端b點(diǎn)正上方的一點(diǎn),bcmn,在自動扶梯底端a處測得c點(diǎn)的仰角為42,求二樓的層高bc(精確到0.1米)(參考數(shù)據(jù):sin420.67,cos420.74,tan420.90)顯示解析23如圖,在abcd中,e是ab的中點(diǎn),ed和ac相交于點(diǎn)f,過點(diǎn)f作fgab,交ad于點(diǎn)g(1)求證:ab=3fg;(2)若ab:ac=2:3,求證:df2=dgda顯示解析24已知,二次函數(shù)y=ax2+bx的圖象經(jīng)過點(diǎn)a(-5,0)和點(diǎn)b,其中點(diǎn)b在第一象限,且oa=ob,cotbao=2(1)求點(diǎn)b的坐標(biāo);(2)求二次函數(shù)的解析式;(3)過點(diǎn)b作直線bc平行于x軸,直線bc與二次函數(shù)圖象的另
6、一個交點(diǎn)為c,聯(lián)結(jié)ac,如果點(diǎn)p在x軸上,且abc和pab相似,求點(diǎn)p的坐標(biāo)顯示解析25如圖1,rtabc中,acb=90,ac=4,bc=3,p是斜邊ab上的一個動點(diǎn)(點(diǎn)p與點(diǎn)a、b不重合),以點(diǎn)p為圓心,pa為半徑的p與射線ac的另一個交點(diǎn)為d,射線pd交射線bc于點(diǎn)e(1)如圖2,若點(diǎn)e在線段bc的延長線上,設(shè)ap=x,ce=y,求y關(guān)于x的函數(shù)關(guān)系式,并寫出x的取值范圍;當(dāng)以be為直徑的圓和p外切時,求ap的長;(2)設(shè)線段be的中點(diǎn)為q,射線pq與p相交于點(diǎn)i,若ci=ap,求ap的長qcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92
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