c語言練習題-循環(huán)和數(shù)組

-10-C語言練習題——循環(huán)及數(shù)組1.求1000之內(nèi)的所有完數(shù)2.輸入兩個正整數(shù)m和n，求其最大公約數(shù)和最小公倍數(shù)。3.求1！+2！+3！+4！+……20！4．用for循環(huán)求分數(shù)序列：2/1，3/2，5/3，8/5，13/8，21/13，…，前20項之和。5.打印楊輝三角形。6.輸入5個學生的數(shù)學、語文、英語3門課程的成績，計算并輸出每一門課程的平均成績和每一位學生的平均成績7．求一個3*3的整型矩陣對角線元素之和。8.編程計算m×s階矩陣A和s×n階矩陣B之積9.任意輸入n個從小到大的整數(shù)的數(shù)列，然后輸入一個整數(shù)插入到數(shù)列中，使數(shù)列保持從小到大的順序10.編寫程序鍵盤輸入整型變量n，從低位開始取出整型變量n偶數(shù)位上的數(shù)依次放在整型變量s中，然后輸出s。例如：當n中的數(shù)為：87654321時，s中的數(shù)為：8642。輸入樣例：87654321輸出樣例：86421．程序代碼：#include

<stdio.h>int

main(){

int

n,

sum,

i;

for(n

=

1;

n

<=

1000;

n++)

{

sum

=

0;

for

(i

=

1;

i

<

n;

i++)

{

if

(n

%

i

==

0)

{

sum

=sum+i;

}

}

if(sum

==

n)

{

printf("%d

",

n);

}

}

return

0;}運行結果：628496Processexitedafter0.1057secondswithreturnvalue0請按任意鍵繼續(xù)...2．程序代碼：#include<stdio.h>int

main(void){

/*********Begin*********/

int

m,n,a,b,t;

scanf("%d%d",&m,&n);

t=m%n;

if(m<n)

{

t=m;

m=n;

n=t;

}

a=m;

b=n;

while(b!=0)

{

t=a%b;

a=b;

b=t;

}

printf("最大公約數(shù)是:%d\n最小公倍數(shù)是:%d",a,m*n/a);

return

0;}運行結果：1436最大公約數(shù)是:2最小公倍數(shù)是:252Processexitedafter6.193secondswithreturnvalue0請按任意鍵繼續(xù)...3．程序代碼：#include

<stdio.h>int

main(){

int

i;

double

f=1,sum=0;

for(i=1;i<=20;i++)

{

f=f*i;

sum+=f;

}

printf("%f",sum);

return

0;

}

運行結果：2561327494111820300.000000Processexitedafter0.03475secondswithreturnvalue0請按任意鍵繼續(xù)...4．程序代碼#include

<stdio.h>int

main(){int

i;

double

a,b,s,t;

a=2;

b=1;

s=a/b;

for(i=1;i<20;i++)

{

t=b;

b=a;

a=a+t;

s=s+a/b;}printf("sum=%.2lf\n",s);

return

0;}運行結果sum=32.66Processexitedafter0.03287secondswithreturnvalue0請按任意鍵繼續(xù)...5．程序代碼#include<stdio.h>#define

N

50int

main(){

int

a[N][N],i,j,n;

scanf("%d",&n);

//輸入打印行數(shù)

for(i=0;i<=n;i++)

{

a[i][0]=1;

a[i][i]=1;

}for(i=1;i<n;i++)for(j=1;j<n;j++){a[i][j]=a[i-1][j]+a[i-1][j-1];}for(i=0;i<n;i++){for(j=0;j<i+1;j++){printf("%d\t",a[i][j]);}printf("\n");}

return

0;}運行結果611112113311464115101051Processexitedafter12.06secondswithreturnvalue0請按任意鍵繼續(xù)...6．程序代碼#include<stdio.h>#define

M

5#define

N

3int

main(){

/*********Begin*********/

double

average,sum;

int

a[M][N],i,j;

for(i=0;i<M;i++)

{

for(j=0;j<N;j++)

scanf("%d",&a[i][j]);

}

printf("每個學生的平均分:\n");

for(i=0;i<M;i++)

{

for(j=0,sum=0;j<N;j++)

{

sum+=a[i][j];

average=sum/N;

printf("%d

",a[i][j]);

}

printf("%.1f",average);

printf("\n");

}

printf("每門課的平均分:\n");

for(j=0;j<N;j++)

{

for(i=0,sum=0;i<M;i++)

{

sum+=a[i][j];

average=sum/M;

}

printf("%.1f

",average);

}

return

0;

}運行結果857888609080917992508483458680每個學生的平均分:85788883.760908076.791799287.350848372.345868070.3每門課的平均分:66.283.484.6Processexitedafter19.6secondswithreturnvalue0請按任意鍵繼續(xù)...7．程序代碼#include<stdio.h>int

main()

{

int

a[3][3];

int

i,

j;

int

sum;

for

(i

=

0;

i

<

3;

i++)

for

(j

=

0;

j

<

3;

j++)

scanf("%d",

&a[i][j]);

for

(i

=

0;

i

<

3;

i++)

for

(j

=

0;

j

<

3;

j++)

if

((i

==

j)

||

(i

+

j

==

2))

sum

=

sum

+

a[i][j];

printf("%d",sum);

return

0;}運行結果12345678925Processexitedafter25.93secondswithreturnvalue0請按任意鍵繼續(xù)...8．程序代碼#include

<stdio.h>#include

<stdlib.h>#define

M

10#define

S

10#define

N

10int

main(){

/**********

Begin

**********/

int

a[M][S],

b[S][M],

c[M][N],

i,j,k;

int

m,s,n;

scanf("%d",

&m);

scanf("%d",

&s);

scanf("%d",

&n);

for

(i=0;

i<m

;i++)

{

for

(j=0;

j<s;

j++)

{

scanf("%d",

&a[i][j]);

}

}

for

(i=0;

i<s;

i++)

{

for

(j=0;

j<n;

j++)

{

scanf("%d",

&b[i][j]);

}

}

for

(i=0;

i<m;

i++)

{

for

(j=0;

j<n;

j++)

{

c[i][j]

=

0

;

for

(k=0;

k<s;

k++)

{

c[i][j]

=

c[i][j]+a[i][k]*b[k][j]

;

}

}

}

for

(i=0;

i<m;

i++)

{

for

(j=0;

j<n;

j++)

{

printf("%d\t",

c[i][j]);

}

printf("\n")

;

}

/**********

End

**********/

return

0;}運行結果323231-2311-2-32-108-7-6-30-35-7-9Processexitedafter21.96secondswithreturnvalue0請按任意鍵繼續(xù)...9．程序代碼#include

<stdio.h>#define

N

100int

main(){

/**********

Begin

**********/int

a[N],i,n,x,j;

scanf("%d\n",&n);

for(i=0;i<n;i++)

{

scanf("%d

\n",&a[i]);

}

scanf("%d",&x);while(

a[j]<=x

&&

j<n

){

j++;

//找不到比x大的元素時也要退出循環(huán)

}for(i=n-1;i>=j;i--

){

a[i+1]=a[i];

}a[j]=x;for(i=0;i<=n;i++)printf("%d

",a[i]);

/**********

End

**********/

return

0;

}運行結果1010154252596467738288601015425259606467738288Processexitedafter1.863secondswithreturnvalue0請按任意鍵繼續(xù)...10．程序代碼#include<stdio.h>int

main(){