新高考數(shù)學(xué)二輪復(fù)習(xí)函數(shù)培優(yōu)專題04 函數(shù)的解析式（含解析）

專題04函數(shù)的解析式專項(xiàng)突破一待定系數(shù)法1．設(shè)SKIPIF1<0為一次函數(shù)，且SKIPIF1<0．若SKIPIF1<0，則SKIPIF1<0的解析式為（

）A．SKIPIF1<0或SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．冪函數(shù)SKIPIF1<0的圖象經(jīng)過函數(shù)SKIPIF1<0SKIPIF1<0且SKIPIF1<0所過的定點(diǎn)，則SKIPIF1<0的值等于（

）A．8 B．4 C．2 D．13．已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的增函數(shù)，且SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．2 D．34．已知二次函數(shù)f（x）的圖象經(jīng)過點(diǎn)（-3，2），頂點(diǎn)是（-2，3），則函數(shù)f（x）的解析式為___________.5．已知函數(shù)SKIPIF1<0恒過定點(diǎn)P，點(diǎn)P恰好在冪函數(shù)SKIPIF1<0的圖象上，則SKIPIF1<0___________.6．（1）已知SKIPIF1<0是一次函數(shù)，且SKIPIF1<0，求SKIPIF1<0；（2）已知SKIPIF1<0是二次函數(shù)，且滿足SKIPIF1<0，求SKIPIF1<0.7．已知SKIPIF1<0是二次函數(shù)，且滿足SKIPIF1<0，SKIPIF1<0，SKIPIF1<0.(1)求函數(shù)SKIPIF1<0的解析式；(2)當(dāng)SKIPIF1<0時(shí)，表示出函數(shù)SKIPIF1<0的最小值SKIPIF1<0，并求出SKIPIF1<0的最小值.8．已知函數(shù)SKIPIF1<0為二次函數(shù)，不等式SKIPIF1<0的解集是SKIPIF1<0，且SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為SKIPIF1<0.(1)求SKIPIF1<0的解析式；(2)設(shè)函數(shù)SKIPIF1<0在SKIPIF1<0上的最大值為SKIPIF1<0，求SKIPIF1<0的表達(dá)式.9．已知一次函數(shù)SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0.(1)求實(shí)數(shù)a?b的值；(2)令SKIPIF1<0，求函數(shù)SKIPIF1<0的解析式.專項(xiàng)突破二換元法1．設(shè)函數(shù)SKIPIF1<0，則SKIPIF1<0的表達(dá)式為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．若SKIPIF1<0，則SKIPIF1<0的解析式為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．若SKIPIF1<0，則SKIPIF1<0等于（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知SKIPIF1<0是定義域?yàn)镾KIPIF1<0上的單調(diào)增函數(shù)，且對(duì)任意SKIPIF1<0，都有SKIPIF1<0，則SKIPIF1<0的值為（

）A．12 B．14 C．SKIPIF1<0 D．186．已知函數(shù)SKIPIF1<0，那么SKIPIF1<0的表達(dá)式是___________.7．已知SKIPIF1<0，則SKIPIF1<0______.8．若SKIPIF1<0，則SKIPIF1<0______．9．若函數(shù)SKIPIF1<0，則SKIPIF1<0______．10．已知定義在SKIPIF1<0上的單調(diào)函數(shù)SKIPIF1<0，若對(duì)任意SKIPIF1<0都有SKIPIF1<0，則SKIPIF1<0_____專項(xiàng)突破三配湊法1．已知函數(shù)SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．已知函數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知SKIPIF1<0求SKIPIF1<0=（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．若函數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0的解析式是__________5．已知SKIPIF1<0，則SKIPIF1<0______．6．已知函數(shù)SKIPIF1<0，則函數(shù)SKIPIF1<0的解析式為SKIPIF1<0______.7．若SKIPIF1<0，則SKIPIF1<0______.8．已知函數(shù)y＝f(x)滿足SKIPIF1<0，求函數(shù)y＝f(x)的解析式．專項(xiàng)突破四構(gòu)造方程組法1．已知SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．若函數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．已知函數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0___________.4．若SKIPIF1<0，則SKIPIF1<0______．5．設(shè)函數(shù)SKIPIF1<0是SKIPIF1<0→SKIPIF1<0的函數(shù)，滿足對(duì)一切SKIPIF1<0，都有SKIPIF1<0，則SKIPIF1<0的解析式為SKIPIF1<0______．6．已知函數(shù)SKIPIF1<0對(duì)SKIPIF1<0的一切實(shí)數(shù)都有SKIPIF1<0，則SKIPIF1<0______．專項(xiàng)突破五利用奇偶性1．已知SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù)，且當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．設(shè)SKIPIF1<0為奇函數(shù)，且當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù)，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．若SKIPIF1<0是定義在SKIPIF1<0的奇函數(shù)，且SKIPIF1<0是偶函數(shù)，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則SKIPIF1<0時(shí)SKIPIF1<0的解析式為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．若定義在R上的偶函數(shù)SKIPIF1<0和奇函數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0的解析式為SKIPIF1<0___________.6．已知函數(shù)SKIPIF1<0是SKIPIF1<0上的奇函數(shù)，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0