新高考數(shù)學(xué)三輪沖刺 押題卷練習(xí)第8題 函數(shù)的綜合應(yīng)用（原卷版）

函數(shù)的綜合應(yīng)用考點(diǎn)4年考題考情分析函數(shù)的綜合應(yīng)用2023年新高考Ⅰ卷第11題2023年新高考Ⅱ卷第11題2022年新高考Ⅰ卷第7、10、12題函數(shù)的綜合會(huì)以單選題、多選題、填空題、解答題4類(lèi)題型進(jìn)行考查，通常伴隨著導(dǎo)數(shù)的考查，在單選題中難度較難，縱觀近幾年的新高考試題，分別以導(dǎo)數(shù)為背景命題考查極值點(diǎn)、零點(diǎn)、函數(shù)值大小比較、函數(shù)的基本性質(zhì)、最值及切線方程等知識(shí)點(diǎn)，本內(nèi)容也是新高考沖刺復(fù)習(xí)的重點(diǎn)復(fù)習(xí)內(nèi)容?？梢灶A(yù)測(cè)2024年新高考命題方向?qū)⒗^續(xù)以導(dǎo)數(shù)綜合應(yīng)用問(wèn)題展開(kāi)命題．1．（2023·新高考Ⅰ卷高考真題第11題）已知函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，SKIPIF1<0，則（

）．A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0是偶函數(shù) D．SKIPIF1<0為SKIPIF1<0的極小值點(diǎn)2．（2023·新高考Ⅱ卷高考真題第11題）若函數(shù)SKIPIF1<0既有極大值也有極小值，則（

）．A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·新高考Ⅰ卷高考真題第7題）設(shè)SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·新高考Ⅰ卷高考真題第10題）已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0有兩個(gè)極值點(diǎn) B．SKIPIF1<0有三個(gè)零點(diǎn)C．點(diǎn)SKIPIF1<0是曲線SKIPIF1<0的對(duì)稱(chēng)中心 D．直線SKIPIF1<0是曲線SKIPIF1<0的切線5．（2022·新高考Ⅰ卷高考真題第12題）已知函數(shù)SKIPIF1<0及其導(dǎo)函數(shù)SKIPIF1<0的定義域均為SKIPIF1<0，記SKIPIF1<0，若SKIPIF1<0，SKIPIF1<0均為偶函數(shù)，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0在定義域內(nèi)，若SKIPIF1<0，其中SKIPIF1<0為奇函數(shù)，SKIPIF1<0為常數(shù)，則最大值SKIPIF1<0，最小值SKIPIF1<0有SKIPIF1<0即SKIPIF1<0倍常數(shù)在定義域內(nèi)，若SKIPIF1<0，其中SKIPIF1<0為奇函數(shù)，SKIPIF1<0為常數(shù)，有SKIPIF1<0即SKIPIF1<0倍常數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0常見(jiàn)函數(shù)的泰勒展開(kāi)式：結(jié)論1SKIPIF1<0．結(jié)論2SKIPIF1<0．結(jié)論3SKIPIF1<0（SKIPIF1<0）．結(jié)論4SKIPIF1<0．結(jié)論5SKIPIF1<0；SKIPIF1<0；SKIPIF1<0．結(jié)論6SKIPIF1<0；結(jié)論7SKIPIF1<0結(jié)論8SKIPIF1<0．結(jié)論9SKIPIF1<0．放縮程度綜合SKIPIF1<0SKIPIF1<0SKIPIF1<0端點(diǎn)效應(yīng)的類(lèi)型1.如果函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上,SKIPIF1<0恒成立,則SKIPIF1<0或SKIPIF1<0.2.如果函數(shù)SKIPIF1<0在區(qū)問(wèn)SKIPIF1<0上,SKIPIF1<0恒成立,且SKIPIF1<0(或SKIPIF1<0),則SKIPIF1<0SKIPIF1<0或SKIPIF1<0.3.如果函數(shù)SKIPIF1<0在區(qū)問(wèn)SKIPIF1<0上,SKIPIF1<0恒成立,且SKIPIF1<0(或SKIPIF1<0,SKIPIF1<0則SKIPIF1<0或SKIPIF1<0.函數(shù)的凹凸性凹函數(shù)：對(duì)于某區(qū)間內(nèi)SKIPIF1<0,都有SKIPIF1<0.凸函數(shù)：對(duì)于某區(qū)間內(nèi)SKIPIF1<0,都有SKIPIF1<0.1．（2024·陜西·模擬預(yù)測(cè)）設(shè)SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2024·浙江溫州·二模）已知SKIPIF1<0，則SKIPIF1<0的大小關(guān)系是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2024·廣東佛山·二模）若函數(shù)SKIPIF1<0（SKIPIF1<0）既有極大值也有極小值，則下列結(jié)論一定正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2024·全國(guó)·模擬預(yù)測(cè)）若SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的大小順序?yàn)椋?/p>

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2024·全國(guó)·模擬預(yù)測(cè)）若SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2024·遼寧大連·一模）設(shè)函數(shù)SKIPIF1<0則滿足SKIPIF1<0的x的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（2024·江蘇·一模）用SKIPIF1<0表示x，y中的最小數(shù)．已知函數(shù)SKIPIF1<0，則SKIPIF1<0的最大值為(

)A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．ln28．（2024·云南·模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0，若SKIPIF1<0在SKIPIF1<0有實(shí)數(shù)解，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<09．（2024·全國(guó)·模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0恰有一個(gè)零點(diǎn)SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．（2024·湖南邵陽(yáng)·二模）已知函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0為SKIPIF1<0的導(dǎo)函數(shù).若SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0上恒成立，則不等式SKIPIF1<0的解集為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<011．（2024·全國(guó)·模擬預(yù)測(cè)）設(shè)函數(shù)SKIPIF1<0，記SKIPIF1<0的極小值點(diǎn)為SKIPIF1<0，極大值點(diǎn)為SKIPIF1<0，則SKIPIF1<0（

）A．2 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<012．（2024·遼寧·模擬預(yù)測(cè)）已知SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù)，SKIPIF1<0也是定義在SKIPIF1<0上的奇函數(shù)，則關(guān)于SKIPIF1<0的不等式SKIPIF1<0的解集為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<013．（2024·全國(guó)·模擬預(yù)測(cè)）若函數(shù)SKIPIF1<0有兩個(gè)零點(diǎn)，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<014．（2024·河南鄭州·模擬預(yù)測(cè)）已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<015．（2024·浙江·二模）已知函數(shù)SKIPIF1<0若SKIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<016．（2024·山東濟(jì)南·一模）若不等式SKIPIF1<0對(duì)任意的SKIPIF1<0恒成立，則SKIPIF1<0的最小值為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<017．（2024·福建漳州·一模）已知可導(dǎo)函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，SKIPIF1<0為奇函數(shù)，設(shè)SKIPIF1<0是SKIPIF1<0的導(dǎo)函數(shù)，若SKIPIF1<0為奇函數(shù)，且SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<018．（2024·湖南邵陽(yáng)·一模）設(shè)SKIPIF1<0，則SKIPIF1<0的大小關(guān)系為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<019．（2024·湖南長(zhǎng)沙·一模）已知實(shí)數(shù)SKIPIF1<0分別滿足SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<020．（2024·貴州貴陽(yáng)·一模）已知SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù)，且SKIPIF1<0也是偶函數(shù)，若SKIPIF1<0，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<021．（2024·黑龍江哈爾濱·一模）設(shè)SKIPIF1<0且SKIPIF1<0，若函數(shù)SKIPIF1<0有三個(gè)極值點(diǎn)，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<022．（2024·遼寧·一模）已知函數(shù)SKIPIF1<0，若SKIPIF1<0成立，則實(shí)數(shù)a的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<023．（2024·遼寧·一模）已知函數(shù)SKIPIF1<0，若關(guān)于SKIPIF1<0的方程SKIPIF1<0有五個(gè)不等的實(shí)數(shù)解，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<024．（2024·全國(guó)·模擬預(yù)測(cè)）若關(guān)于SKIPIF1<0的不等式SKIPIF1<0在SKIPIF1<0內(nèi)有解，則正實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<025．（2024·全國(guó)·模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0，SKIPIF1<0，其中SKIPIF1<0是函數(shù)SKIPIF1<0的導(dǎo)函數(shù)，若不等式SKIPIF1<0對(duì)任意的SKIPIF1<0恒成立，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<026．（2024·遼寧·二模）若SKIPIF1<0，則（

）A．SKIPIF1<0