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專題03函數(shù)的最值(值域)求法專項(xiàng)突破一單調(diào)性法1.函數(shù)SKIPIF1<0在SKIPIF1<0的最大值是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0,若SKIPIF1<0對任意SKIPIF1<0恒成立,則實(shí)數(shù)m的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.若函數(shù)SKIPIF1<0的值域是SKIPIF1<0,則函數(shù)SKIPIF1<0的值域是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.已知函數(shù)SKIPIF1<0,SKIPIF1<0,若SKIPIF1<0,SKIPIF1<0,使得SKIPIF1<0,則實(shí)數(shù)a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.函數(shù)SKIPIF1<0,若SKIPIF1<0的最大值和最小值是____.6.函數(shù)SKIPIF1<0的值域?yàn)開__________.7.已知函數(shù)SKIPIF1<0.(1)試判斷函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的單調(diào)性,并證明;(2)求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的值域.8.檢驗(yàn)下列函數(shù)的增減性,并說明是否有最大(?。┲担绻校赋鲎畲螅ㄐ。┲岛蛯?yīng)的最大(?。┲迭c(diǎn).(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0;(4)SKIPIF1<0.9.已知SKIPIF1<0.(1)求SKIPIF1<0的定義域;(2)討論SKIPIF1<0的單調(diào)性;(3)求SKIPIF1<0在區(qū)間SKIPIF1<0上的值域.10.已知函數(shù)SKIPIF1<0為冪函數(shù),且為奇函數(shù).(1)求SKIPIF1<0的值,并確定SKIPIF1<0的解析式;(2)令SKIPIF1<0,求SKIPIF1<0在SKIPIF1<0的值域.11.已知函數(shù)SKIPIF1<0.(1)用定義法證明函數(shù)SKIPIF1<0在SKIPIF1<0上為增函數(shù);(2)若SKIPIF1<0,且當(dāng)SKIPIF1<0時(shí)SKIPIF1<0恒成立,求實(shí)數(shù)a的取值范圍.專項(xiàng)突破二判別式法1.函數(shù)SKIPIF1<0的最大值與最小值的和是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.求函數(shù)SKIPIF1<0的值域______________.3.求函數(shù)SKIPIF1<0的最小值.4.求下列函數(shù)的值域:(1)SKIPIF1<0;(2)SKIPIF1<05.已知函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0,求SKIPIF1<0的值.6.求下列函數(shù)的值域:(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0;(4)SKIPIF1<0;(5)SKIPIF1<0;(6)SKIPIF1<0.專項(xiàng)突破三分離常數(shù)法1.函數(shù)SKIPIF1<0的值域是(
)A.SKIPIF1<0SKIPIF1<0SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0SKIPIF1<0SKIPIF1<0 D.SKIPIF1<02.函數(shù)SKIPIF1<0,x∈[3,+∞)的值域是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.函數(shù)ySKIPIF1<0的值域是()A.(﹣∞,+∞) B.(﹣∞,SKIPIF1<0)∪(SKIPIF1<0,+∞)C.(﹣∞,SKIPIF1<0)∪(SKIPIF1<0,+∞) D.(﹣∞,SKIPIF1<0)∪(SKIPIF1<0,+∞)4.函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0的最大值是______.5.函數(shù)SKIPIF1<0在SKIPIF1<0上的值域?yàn)開__________.6.函數(shù)SKIPIF1<0的值域?yàn)開______.7.函數(shù)SKIPIF1<0的值域是______.8.函數(shù)SKIPIF1<0的值域是________________.9.已知函數(shù)SKIPIF1<0為奇函數(shù)(1)求實(shí)數(shù)SKIPIF1<0的值及函數(shù)SKIPIF1<0的值域;(2)若不等式SKIPIF1<0對任意SKIPIF1<0都成立,求實(shí)數(shù)SKIPIF1<0的取值范圍.專項(xiàng)突破四二次函數(shù)分類討論1.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0,求函數(shù)SKIPIF1<0的最小值和最大值;(2)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的最小值.2.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的最大值和最小值.(2)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值.3.已知SKIPIF1<0是定義在R上的偶函數(shù)SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),SKIPIF1<0.(1)求SKIPIF1<0的解析式;(2)求SKIPIF1<0在區(qū)間SKIPIF1<0上的值域.4.二次函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上有最大值4,最小值0.(1)求函數(shù)SKIPIF1<0的解析式;(2)設(shè)SKIPIF1<0,且SKIPIF1<0在SKIPIF1<0的最小值為SKIPIF1<0,求SKIPIF1<0的值.5.已知一次函數(shù)SKIPIF1<0滿足SKIPIF1<0.(1)求函數(shù)f(x)的解析式;(2)設(shè)函數(shù)SKIPIF1<0SKIPIF1<0,求SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值.6.已知函數(shù)SKIPIF1<0(1)若函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞減,求a的取值范圍:(2)是否存在實(shí)數(shù)a,使得函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為SKIPIF1<0?若存在,求出a的值;若不存在,請說明理由.7.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)當(dāng)SKIPIF1<0,且SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的值域;(2)若函數(shù)SKIPIF1<0在SKIPIF1<0的最小值為SKIPIF1<0,求實(shí)數(shù)SKIPIF1<0的值;8.已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),判斷并證明函數(shù)SKIPIF1<0的奇偶性;(2)求函數(shù)SKIPIF1<0在SKIPIF1<0上的最小值.專項(xiàng)突破五基本不等式法1.下列函數(shù)中最小值為8的是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知圓SKIPIF1<0關(guān)于直線SKIPIF1<0為大于0的常數(shù)SKIPIF1<0對稱,則SKIPIF1<0的最大值為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.1 D.23.已知SKIPIF1<0,則SKIPIF1<0的最小值是(
)A.14 B.SKIPIF1<0 C.8 D.SKIPIF1<04.若SKIPIF1<0在SKIPIF1<0上恒成立,則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.下列函數(shù)中,最小值為9的是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.已知正實(shí)數(shù)a,b滿足SKIPIF1<0,則SKIPIF1<0的最大值為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.27.已知函數(shù)SKIPIF1<0則函數(shù)SKIPIF1<0的值域?yàn)椋?/p>
)A.R B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.函數(shù)SKIPIF1<0的值域是______.9.已知x>1,那么SKIPIF1<0的最小值為________.10.函數(shù)SKIPIF1<0在SKIPIF1<0上的值域?yàn)開_______.11.函數(shù)SKIPIF1<0的值域是____________.12.已知SKIPIF1<0,則SKIPIF1<0的最小值為___________.13.已知SKIPIF1<0、SKIPIF1<0均為正實(shí)數(shù),且SKIPIF1<0,則SKIPIF1<0的最小值為___________.14.若正實(shí)數(shù)SKIPIF1<0滿足SKIPIF1<0,則SKIPIF1<0的最大值為________.15.已知關(guān)于SKIPIF1<0的一元二次不等式SKIPIF1<0在實(shí)數(shù)集上恒成立,且SKIPIF1<0,則SKIPIF1<0的最小值為________16.若SKIPIF1<0,則函數(shù)SKIPIF1<0的值域?yàn)開_________.17.若函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍是____.專項(xiàng)突破六指、對數(shù)復(fù)合型1.函數(shù)SKIPIF1<0的值域?yàn)椋?/p>
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.函數(shù)SKIPIF1<0的最小值是(
).A.10 B.1 C.11 D.SKIPIF1<03.函數(shù)SKIPIF1<0,SKIPIF1<0的值域是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.已知函數(shù)SKIPIF1<0的圖象過定點(diǎn)SKIPIF1<0,則SKIPIF1<0在SKIPIF1<0上的值域是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.函數(shù)SKIPIF1<0的值域?yàn)開_____.6.若函數(shù)f(x)=SKIPIF1<0有最大值3,則a=________.7.函數(shù)SKIPIF1<0的值域是________.8.求下列函數(shù)的值域:(1)SKI
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