2018秋招阿里巴巴java筆試試題

2018java1、以下函數(shù)的時(shí)間復(fù)雜度 （1voidfunc(intx,inty,int3printf("%d,%d\n",y,6func(x-7func(x-264C(x[2]+4)[3]等價(jià)的類型是int**） 3iosAndroidObjectiveCARCJavaGC，iosAndroidIosAndroidiosAndriodios和Andriod應(yīng)用都可以注冊(cè)自定義 4abcdef，每次出棧可以選擇一個(gè)或者兩個(gè)元素棧，當(dāng)有兩個(gè)式有（）種？5linuxkernelspaceuserspace（）A.userspacespaceuserspaceuserspacekernelspaceKernelspaceuserspacekernel6publicclassC{staticclass}staticclassBextends}publicstaticvoidmain(String[]ArrayList<A>list=newArrayList<A>();list.add(newB());method1(list);}privatestaticvoidmethod1(List<?1]supperA>list){for(inti=0;i<list.size();i++){Aa=list.get(0);}以上程序的運(yùn)行結(jié)果可能出現(xiàn)的是：（list.add(newB())編譯報(bào)錯(cuò)B.method1C.Aa=list.get(0)編譯報(bào)錯(cuò)list.add(newB())method1(list)list.add(newB())Aa=list.get(0);7publicclassprivatestaticAtomicIntegeratomicInteger=newpublicstaticvoidmain(String[]Aa=new}catch(InterruptedExceptionstaticclassAextendsThread{<aclass="js-nc-card"data-card-uid="992988"href="/profile/992988"13publicvoidB.3int32_t4unit64_t5char*a=new7return3int32_t4unit64_t5char*a=new7return3int32_t4unit64_t5char*a=new6*(a+size-7returnF.正常9、下列程序的輸出是usingnamespaceclassA(intintintresult=0,i=0,j=for(intk=m_n;k>0;k--10j=12j=13while(j>=10)14intt=j%15j=j/16result=((i++%2==0)?result+t:result-20result=((i++%2==0)?result+j:result-21return24int26int27Aa=29returnA.-個(gè)四位數(shù)（）111？（）200-6n=11(20-12、以下描述正確的是NP-HardK-T1648(10)，A[2][2](10)存放在什么位置？腳注(10)10（）3n+2=1848-1601，解得n=15每一行15個(gè)元素，每個(gè)元素占據(jù)一個(gè)空間，因此1484%，點(diǎn)之前就降水的概率是多大？（15publicclassListParamTestpublicstaticvoidresetList(List<Integer>dataList)dataList=newpublicstaticvoidsetOne(List<Integer>dataList)10publicstaticvoidmain(String[]11List<Integer>dataList=newintsum=0;for(Integerv:dataList){sum+=v;UnsupportedOperationExceptionNullPointerException16x,y,zy,z,xx+yz+y（）A.-B.-WeightdecayEarlyData {Bread,Milk}{Bread,Milk,Beer}是{Bread,Milk}{Bread,Milk}{Bread,Milk}{Bread,Diaper}評(píng)分卡算法（ScoreCard）是在金融領(lǐng)域廣泛應(yīng)用的一種評(píng)分算法，通過(guò)多E.ROCF.2000（否則不能清關(guān)）2000，必須使用多（箱子長(zhǎng)，箱子寬，箱子高（商品價(jià)格，商品長(zhǎng)，商品寬，商品高intclassMain/**process/**當(dāng)然，你也可以不按照這個(gè)模板來(lái)作答，完全按照自己的想法來(lái)^- privatestaticint}publicstaticvoidmain(StringScannerscanner=newScanner(System.in);boxTemplate.priceCUSTOMS_LIMIT_MONEY_PER_BOX;whileboxTemplate.length=scanner.nextInt();boxTemplate.widthscanner.nextInt();boxTemplate.height=scanner.nextInt();itemNum=scanner.nextInt();items=newModel[itemNum];for(inti<itemNum;i++){Modelitem=newitem.price=item.length=scanner.nextInt();item.width=scanner.nextInt();item.height=scanner.nextInt();items[i]=}longstartTime=System.currentTimeMillis();boxMinNumSystem.out.println(process());將單邊車優(yōu)化的規(guī)則進(jìn)行可抽象為以下三種（A,B,C規(guī)則-1:A-B，B-AA-BB-A規(guī)則-2:A-B，B-C，C-AA-B、B-C、C-規(guī)則-3:A-B，C-A，B、CB、C參照以上，并且優(yōu)先級(jí)依次降低，合并的時(shí)候需要考慮車型（17.5m9.6m）：1、相同車型才能進(jìn)行合并；29.6m17.5m2016120001+2016120002ID201612000120161200021publicclassMainpublicstaticvoidmain(String[]args)Scannerscanner=newList<UnilateralLine>lineList=newwhile(scanner.hasNextLine())String[]options=if(options.length<5)10lineList.add(newUnilateralLine(options[0],options[1],options[2],options[3],options[4],options[5]));//wirteyourcodehereList<String>result=calculateUnilateral(lineList);for(Stringstr:result){19publicstaticList<String>lineList){List<String>result=newArrayList<String>();returnpublicstaticclassUnilateralLine{privateStringid;privateStringsCen;//出發(fā)分撥privateStringsPro;//出發(fā)省privateStringeCen;//到達(dá)分撥privateStringePro;//到達(dá)省privateStringtType;//車型32publicUnilateralLine(Stringid,StringsCen,StringsPro,StringeCen,StringePro,StringtType){this.id=id;this.sCen=sCen;this.sPro=sPro;this.eCen=eCen;this.ePro=ePro;this.tType=35publicStringgetId(){return36publicvoidsetId(Stringid){this.id=37publicStringgetSCen(){return38publicvoidsetSCen(StringePro){this.ePro=39publicStringgetSPro(){return40publicvoidsetSPro(StringsPro){this.sPro=41publicStringgetECen(){return42publ