新高考數(shù)學(xué)一輪復(fù)習(xí) 專項(xiàng)分層精練第14 課 導(dǎo)數(shù)與函數(shù)的極值、最值（原卷版）

第14課導(dǎo)數(shù)與函數(shù)的極值、最值（分層專項(xiàng)精練）【一層練基礎(chǔ)】一、單選題1．（2023春·四川遂寧·高三射洪中學(xué)?？茧A段練習(xí)）已知SKIPIF1<0，且函數(shù)SKIPIF1<0恰有兩個(gè)極大值點(diǎn)在SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2023·四川宜賓·四川省宜賓市第四中學(xué)校校考三模）已知函數(shù)SKIPIF1<0和SKIPIF1<0有相同的極大值，則SKIPIF1<0（

）A．0 B．2 C．SKIPIF1<0 D．SKIPIF1<03．（2023·廣西南寧·南寧三中?？寄M預(yù)測(cè)）當(dāng)SKIPIF1<0時(shí)，函數(shù)SKIPIF1<0取得最小值SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2023·廣西·統(tǒng)考模擬預(yù)測(cè)）已知函數(shù)SKIPIF1<0存在最大值0，則SKIPIF1<0的值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．SKIPIF1<0二、多選題5．（2023·江蘇鎮(zhèn)江·揚(yáng)中市第二高級(jí)中學(xué)?？寄M預(yù)測(cè)）關(guān)于函數(shù)SKIPIF1<0，下列判斷正確的是（

）A．函數(shù)SKIPIF1<0的圖像在點(diǎn)SKIPIF1<0處的切線方程為SKIPIF1<0B．SKIPIF1<0是函數(shù)SKIPIF1<0的一個(gè)極值點(diǎn)C．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0D．當(dāng)SKIPIF1<0時(shí)，不等式SKIPIF1<0的解集為SKIPIF1<06．（2023·全國·高三專題練習(xí)）對(duì)于函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0有極大值，沒有極小值B．SKIPIF1<0有極小值，沒有極大值C．函數(shù)SKIPIF1<0與SKIPIF1<0的圖象有兩個(gè)交點(diǎn)D．函數(shù)SKIPIF1<0有兩個(gè)零點(diǎn)三、填空題7．（2023·湖南岳陽·湖南省岳陽縣第一中學(xué)?？级＃┮阎瘮?shù)SKIPIF1<0有2個(gè)極值點(diǎn)SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0．8．（2023·遼寧沈陽·沈陽二中?？寄M預(yù)測(cè)）函數(shù)SKIPIF1<0的極小值點(diǎn)為．9．（2023·全國·高三專題練習(xí)）若SKIPIF1<0是函數(shù)SKIPIF1<0的極小值點(diǎn)，則函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為．10．（2023·安徽滁州·安徽省定遠(yuǎn)中學(xué)?？寄M預(yù)測(cè)）若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為SKIPIF1<0，則SKIPIF1<0的取值范圍是.【二層練綜合】一、單選題1．（2023春·陜西商洛·高二?？茧A段練習(xí)）已知函數(shù)SKIPIF1<0的圖象上存在點(diǎn)SKIPIF1<0，函數(shù)SKIPIF1<0的圖象上存在點(diǎn)SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0關(guān)于SKIPIF1<0軸對(duì)稱，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2023秋·福建莆田·高三莆田第四中學(xué)?？茧A段練習(xí)）若函數(shù)SKIPIF1<0有兩個(gè)極值點(diǎn)SKIPIF1<0，且SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多選題3．（2023春·湖南郴州·高二?？茧A段練習(xí)）設(shè)函數(shù)SKIPIF1<0，則下列說法正確的是（

）A．SKIPIF1<0沒有零點(diǎn) B．當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0的圖象位于SKIPIF1<0軸下方C．SKIPIF1<0存在單調(diào)遞增區(qū)間 D．SKIPIF1<0有且僅有兩個(gè)極值點(diǎn)三、填空題4．（2023·廣東佛山·華南師大附中南海實(shí)驗(yàn)高中?？寄M預(yù)測(cè)）函數(shù)SKIPIF1<0，若關(guān)于x的不等式SKIPIF1<0的解集為SKIPIF1<0，則實(shí)數(shù)a的取值范圍為．【三層練能力】1．（2023·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0，使得SKIPIF1<0在SKIPIF1<0上遞減B．SKIPIF1<0，使得直線SKIPIF1<0為曲線SKIPIF1<0的切線C．SKIPIF1<0，使得SKIPIF1<0既為SKIPIF1<0的極大值也為SKIPIF1<0的極小值D．SKIPIF1<0，使得SKIPIF1<0在SKIPIF1<0上有兩個(gè)零點(diǎn)SKIPIF1<0，且SKIPIF1<02．（2023·高二單元測(cè)試）函數(shù)SKIPIF1<0（e為自然對(duì)數(shù)的底數(shù)），則下列選項(xiàng)正確的有（

）A．函數(shù)SKIPIF1<0的極大值為1B．函數(shù)SKIPIF1<0