新高考數(shù)學(xué)一輪復(fù)習(xí) 函數(shù)專項(xiàng)重難點(diǎn)突破專題03 函數(shù)的最值(值域)求法(原卷版)

專題03函數(shù)的最值(值域)求法考點(diǎn)一單調(diào)性法一、單選題1．已知函數(shù)SKIPIF1<0，則SKIPIF1<0在SKIPIF1<0上的最大值為（

）A．9 B．8 C．3 D．SKIPIF1<02．當(dāng)SKIPIF1<0時(shí)，函數(shù)SKIPIF1<0的值域是（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．若存在負(fù)實(shí)數(shù)使得方程SKIPIF1<0成立，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0,若SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．若關(guān)于SKIPIF1<0的不等式SKIPIF1<0在SKIPIF1<0上恒成立，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、填空題6．已知函數(shù)SKIPIF1<0的值域是SKIPIF1<0，則SKIPIF1<0_________．7．已知函數(shù)SKIPIF1<0，對(duì)SKIPIF1<0都有SKIPIF1<0成立，則實(shí)數(shù)SKIPIF1<0的取值范圍是________.8．函數(shù)SKIPIF1<0的值域?yàn)開_______.9．已知SKIPIF1<0，設(shè)SKIPIF1<0，則函數(shù)SKIPIF1<0的值域?yàn)開__________．三、解答題10．已知函數(shù)SKIPIF1<0.(1)求函數(shù)SKIPIF1<0的單調(diào)區(qū)間；(2)求SKIPIF1<0在SKIPIF1<0上的值域.考點(diǎn)二判別式法一、單選題1．已知正實(shí)數(shù)SKIPIF1<0滿足SKIPIF1<0則SKIPIF1<0的最大值是（

）A．SKIPIF1<0B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．函數(shù)SKIPIF1<0的值域?yàn)椋?/p>

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．以上答案都不對(duì)3．若函數(shù)SKIPIF1<0的最大值為SKIPIF1<0，最小值為SKIPIF1<0，則SKIPIF1<0（

）A．4B．6C．7 D．8二、多選題4．下列求函數(shù)值域正確的是（

）A．函數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的值域是SKIPIF1<0B．函數(shù)SKIPIF1<0的值域是SKIPIF1<0或SKIPIF1<0C．函數(shù)SKIPIF1<0的值域是SKIPIF1<0或SKIPIF1<0D．函數(shù)SKIPIF1<0的值域是SKIPIF1<0三、填空題5．已知實(shí)數(shù)a，b滿足SKIPIF1<0，則SKIPIF1<0的最小值是__________.6．若函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0，則SKIPIF1<0的值為__________.7．已知SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的取值范圍是___________.8．設(shè)非零實(shí)數(shù)a，b滿足SKIPIF1<0，若函數(shù)SKIPIF1<0存在最大值M和最小值m，則SKIPIF1<0_________.考點(diǎn)三分離常數(shù)法一、單選題1．函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0SKIPIF1<0SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0SKIPIF1<0SKIPIF1<0 D．SKIPIF1<02．函數(shù)SKIPIF1<0（SKIPIF1<0）的值域?yàn)椋?/p>

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<03．已知冪函數(shù)SKIPIF1<0的圖象過點(diǎn)(9,3)，則函數(shù)SKIPIF1<0在區(qū)間［1,9]上的值域?yàn)椋?/p>

）A．［－1,0] B．SKIPIF1<0 C．［0,2] D．SKIPIF1<04．點(diǎn)SKIPIF1<0在函數(shù)SKIPIF1<0的圖象上，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0二、多選題6．已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0為奇函數(shù) B．SKIPIF1<0為減函數(shù)C．SKIPIF1<0有且只有一個(gè)零點(diǎn) D．SKIPIF1<0的值域?yàn)镾KIPIF1<0三、填空題7．函數(shù)SKIPIF1<0的值域是___________.四、解答題8．求下列函數(shù)的最值.(1)SKIPIF1<0的最大值.(2)SKIPIF1<0的最大值.考點(diǎn)四二次函數(shù)分類討論一、單選題1．已知函數(shù)SKIPIF1<0的最大值為4，則SKIPIF1<0的值為（

）A．SKIPIF1<0B．2 C．SKIPIF1<0 D．42．若函數(shù)的定義域?yàn)?，值域?yàn)?，則的取值范圍是A． B． C． D．3．已知函數(shù)SKIPIF1<0R)．當(dāng)SKIPIF1<0時(shí)，設(shè)SKIPIF1<0的最大值為SKIPIF1<0，則SKIPIF1<0的最小值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知SKIPIF1<0在區(qū)間[0，1]上的最大值為g(a)，則g(a)的最小值為（

）A．0 B．SKIPIF1<0 C．1 D．2二、多選題5．已知函數(shù)SKIPIF1<0，關(guān)于SKIPIF1<0的最值有如下結(jié)論，其中正確的是（

）A．SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為1B．SKIPIF1<0在區(qū)間SKIPIF1<0上既有最小值，又有最大值C．SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為2，最大值為5D．SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為SKIPIF1<06．已知SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為SKIPIF1<0，則SKIPIF1<0可能的取值為（

）A．SKIPIF1<0 B．3 C．SKIPIF1<0 D．17．已知二次函數(shù)SKIPIF1<0（SKIPIF1<0為常數(shù)），當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0的最大值是SKIPIF1<0，則SKIPIF1<0的值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0三、填空題8．設(shè)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，對(duì)于任意實(shí)數(shù)t，則SKIPIF1<0的最小值SKIPIF1<0__________．9．若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為4，則SKIPIF1<0的取值集合為______.四、解答題10．（1）已知SKIPIF1<0是偶函數(shù)，SKIPIF1<0時(shí)，SKIPIF1<0，求SKIPIF1<0時(shí)SKIPIF1<0的解析式．（2）已知函數(shù)SKIPIF1<0若SKIPIF1<0的最小值為SKIPIF1<0，寫出SKIPIF1<0的表達(dá)式．11．已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0，求SKIPIF1<0在SKIPIF1<0上的最大值；(2)若函數(shù)在區(qū)間SKIPIF1<0上的最大值為9，最小值為1，求實(shí)數(shù)a，b的值.12．已知二次函數(shù)SKIPIF1<0的圖像過點(diǎn)SKIPIF1<0和原點(diǎn)，對(duì)于任意SKIPIF1<0，都有SKIPIF1<0．(1)求函數(shù)SKIPIF1<0的表達(dá)式；(2)設(shè)SKIPIF1<0，求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值．考點(diǎn)五基本不等式法一、單選題1．函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為（

）A．SKIPIF1<0B．4 C．3 D．SKIPIF1<02．已知SKIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的最小值為（

）A．4 B．6 C．8 D．104．若函數(shù)SKIPIF1<0的最大值為SKIPIF1<0，最小值為SKIPIF1<0，則SKIPIF1<0（

）A．3 B．2 C．1 D．0.5二、多選題5．已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0最小值為SKIPIF1<0 B．SKIPIF1<0在SKIPIF1<0上是增函數(shù)C．SKIPIF1<0的最大值為1 D．SKIPIF1<0無最大值6．下列函數(shù)求值域正確的是（

）A．SKIPIF1<0的值域?yàn)镾KIPIF1<0B．SKIPIF1<0的值域?yàn)镾KIPIF1<0C．SKIPIF1<0的值域?yàn)镾KIPIF1<0D．SKIPIF1<0的值域?yàn)镾KIPIF1<0三、填空題7．已知函數(shù)SKIPIF1<0，則函數(shù)的值域是______.8．已知函數(shù)SKIPIF1<0，則SKIPIF1<0的值域?yàn)開__________．9．若實(shí)數(shù)x、y滿足SKIPIF1<0，則SKIPIF1<0的最大值是______．10．若不等式SKIPIF1<0對(duì)任意SKIPIF1<0，SKIPIF1<0恒成立，則實(shí)數(shù)SKIPIF1<0的取值范圍是________．四、解答題11．已知函數(shù)SKIPIF1<0，SKIPIF1<0．(1)當(dāng)SKIPIF1<0時(shí)，求SKIPIF1<0的最小值；(2)對(duì)任意SKIPIF1<0，SKIPIF1<0恒成立，求a的取值范圍．12．設(shè)函數(shù)SKIPIF1<0滿足SKIPIF1<0.（1）求SKIPIF1<0的解析式；（2）若SKIPIF1<0恒成立，求實(shí)數(shù)SKIPIF1<0的取值范圍.考點(diǎn)六指、對(duì)數(shù)復(fù)合型一、單選題1．函數(shù)SKIPIF1<0的值域?yàn)椋?/p>

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．若函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，則該函數(shù)的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．函數(shù)SKIPIF1<0的值域?yàn)椋?/p>

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．R C．SKIPIF1<0 D．SKIPIF1<06．函數(shù)SKIPIF1<0，SKIPIF1<0的值域?yàn)椋?/p>

）A．SKIPIF1<0B