高中數(shù)學(xué)第一章集合與函數(shù)概念1.1集合1.1.3集合的基本運(yùn)算第2課時補(bǔ)集練習(xí)新人教A版.docx

第2課時補(bǔ)集課時過關(guān)能力提升基礎(chǔ)鞏固1.設(shè)集合U=1,2,3,4,5,6,M=1,2,4,則UM等于()A.UB.1,3,5C.3,5,6D.2,4,6答案:C2.設(shè)集合U=1,2,3,4,5,A=1,2,B=2,3,4,則U(AB)等于()A.2B.5C.1,2,3,4D.1,3,4,5答案:B3.已知全集U=x|x是小于9的正整數(shù),A=1,2,3,4,B=3,4,5,6,則(UA)B等于()A.1,2B.3,4C.5,6D.3,4,5,6,7,8解析:U=1,2,3,4,5,6,7,8,A=1,2,3,4,UA=5,6,7,8.(UA)B=3,4,5,6,7,8.答案:D4.設(shè)全集U=R,集合A=x|0x9,B=xZ|-4x4,則集合(UA)B中元素的個數(shù)為()A.3B.4C.5D.6解析:全集U=R,集合A=x|0x9,UA=x|x0,或x9.B=xZ|-4x4,B=-3,-2,-1,0,1,2,3,(UA)B=-3,-2,-1,0.故(UA)B中元素的個數(shù)為4.答案:B5.已知U=x|x是三角形,A=x|x是銳角三角形,B=x|x是等腰三角形,則UA=,UB=.答案:x|x是直角三角形或鈍角三角形x|x是不等腰三角形6.已知全集U=R,A=x|1xb,UA=x|x1,或x2,則實數(shù)b=.解析:UA=x|x1,或x2,A=x|1x0,B=-2,-1,0,1,則(RA)B=.解析:A=x|x+10,A=x|x-1,RA=x|x-1,(RA)B=-2,-1.答案:-2,-16.已知全集U=R,A=x|x-3,或x2,B=x|-1x5,則集合C=x|-1x2=(用A,B或其補(bǔ)集表示).解析:如圖所示,由圖可知CUA,且CB,C=B(UA).答案:B(UA)7.已知集合A=x|2a-2xa,B=x|1x2,且ARB,則a的取值范圍是.解析:易得RB=x|x1,或x2.ARB,A=或A.若A=,此時有2a-2a,a2.若A,則有2a-2a,a1或2a-2a,2a-22,a1.綜上所述,a的取值范圍是a1或a2.答案:a|a1,或a28.已知集合S=1,3,x3+3x2+2x,A=1,|2x-1|,當(dāng)SA=0時,實數(shù)x是否存在?若存在,求出x的值;若不存在,請說明理由.分析解決問題的關(guān)鍵是正確理解SA=0的意義,它有兩層含義,即0S,且0A.解:SA=0,0S,且0A.S=1,3,0.x3+3x2+2x=0,即x(x+1)(x+2)=0,解得x1=0,x2=-1,x3=-2.當(dāng)x=0時,|2x-1|=1,則A=1,1,x=0不符合題意;當(dāng)x=-1時,|2x-1|=3,則A=1,3,SA=0.x=-1