計算機等級考試三級PC技術(shù)上機16

1、2013年計算機等級考試三級pc技術(shù)上機（16）請編制程序，其功能是：對經(jīng)常上下波動的數(shù)據(jù)可采用只記錄峰值的數(shù)據(jù)壓縮方法。即每次將采樣到的當(dāng)前值和前一次值比較，如數(shù)據(jù)變化方向改變(原變大現(xiàn)變小或原變小現(xiàn)變大)，說明已過峰值，這時就將前一值(峰值)記錄下來。例如(下例數(shù)據(jù)均為無符號數(shù))：原數(shù)據(jù)： 23h,45h,89h,67h,5ch,36h,3ch壓縮后： 23h,89h,36h內(nèi)存中從source連續(xù)存放著48個八位無符號數(shù)，假定無相鄰兩數(shù)相等的情況，編程按上述方法進行壓縮，結(jié)果保存在result開始的內(nèi)存單元中。部分程序已給出, 其中原始數(shù)據(jù)由過程load從文件input1.dat中讀入s

2、ource開始的內(nèi)存單元中。運算結(jié)果要求從result開始存放,由過程save保存到文件output1.dat中。填空begin和end之間已給出的一段源程序使其完整(空白已用橫線標(biāo)出,每行空白一般只需一條指令, 但采用功能相當(dāng)?shù)亩鄺l指令亦可),或刪除begin和end之間原有的代碼并自行編程來完成要求的功能。對程序必須進行匯編,并與io.obj鏈接產(chǎn)生prog1.exe執(zhí)行文件,最終運行程序產(chǎn)生結(jié)果(無結(jié)果或結(jié)果不正確者均不得分)。調(diào)試中若發(fā)現(xiàn)整個程序中存在錯誤之處, 請加以修改。試題程序：extrn load:far,save:farn equ 40stac segment stackdb

3、 128 dup(?)stac endsdata segmentsource db n dup(?)result db n dup(0)name0 db input1.dat,0name1 db output1.dat,0data endscode segmentassume cs:code,ds:data,ss:stacstart proc farpush dsxor ax,axpush axmov ax,datamov ds,axmov es,ax ;置附加段寄存器lea dx,source ;數(shù)據(jù)區(qū)起始地址lea si,name0 ;原始數(shù)據(jù)文件名mov cx,n ;字節(jié)數(shù)call lo

4、ad ;從input1.dat中讀取數(shù)據(jù);*begin*lea si,sourcelea di,resultcldmovsbxor ax,axxor bx,bxlodsbmov bl,si-2sub ax,bxmov dx,axmov cx,n-2filter: xor ax,axxor bx,bxlodsb ;xnmov bl,si-2 ;xn-1sub ax,bx ;xn-xn-1_ ;相鄰兩差值(ax,dx)符號位是否相同_j_ skip ;相同，數(shù)據(jù)方向未變_ ;不同，數(shù)據(jù)變化，保存峰值stosbskip: _loop filter;*end*lea dx,result ;結(jié)果數(shù)據(jù)區(qū)首

5、址lea si,name1 ;結(jié)果文件名mov cx,n ;字節(jié)數(shù)call save ;保存結(jié)果到文件retstart endpcode endsend startqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3p tgz7r4i30ka1dkaghn3xtkknbycudxqa7fhy

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