范德蒙行列式的相關(guān)應用畢業(yè)論文外文翻譯

1、分類號：_ 學校代碼：11059 學 號：0907021021畢業(yè)論文外文翻譯材料 學生姓名： 學 號： 0907021021 專業(yè)班級： 數(shù)學一班 指導教師： 正文：外文資料譯文 附 件：外文資料原文 指導教師評語： 簽名： 年 月 日范德蒙行列式的相關(guān)應用（一）范德蒙行列式在行列式計算中的應用范德蒙行列式的標準規(guī)范形式是：根據(jù)范德蒙行列式的特點，將所給行列式包括一些非范德蒙行列式利用各種方法將其化為范德蒙行列式，然后利用范德蒙行列式的結(jié)果，把它計算出來。常見的化法有以下幾種：1.所給行列式各列（或各行）都是某元素的不同次冪，但其冪次數(shù)排列與范德蒙行列式不完全相同，需利用行列式的性質(zhì)（如提取

2、公因式，調(diào)換各行（或各列）的次序，拆項等）將行列式化為范德蒙行列式。例1 計算解 中各行元素都分別是一個數(shù)自左至右按遞升順序排列，但不是從0變到。而是由1遞升至。如提取各行的公因數(shù)，則方冪次數(shù)便從0變到. 例2 計算解 本項中行列式的排列規(guī)律與范德蒙行列式的排列規(guī)律正好相反，為使中各列元素的方冪次數(shù)自上而下遞升排列，將第列依次與上行交換直至第1行，第行依次與上行交換直至第2行第2行依次與上行交換直至第行，于是共經(jīng)過次行的交換得到階范德蒙行列式： 若的第行（列）由兩個分行（列）所組成，其中任意相鄰兩行（列）均含相同分行（列）；且中含有由個分行（列）組成的范德蒙行列式，那么將的第行（列）乘以-1加

3、到第行（列），消除一些分行（列）即可化成范德蒙行列式：例3 計算解 將的第一行乘以-1加到第二行得：再將上述行列式的第2行乘以-1加到第3行，再在新行列式中的第3行乘以-1加到第4行得：例4 計算 （1）解 先加邊，那么再把第1行拆成兩項之和，2.加行加列法各行（或列）元素均為某一元素的不同方冪，但都缺少同一方冪的行列式，可用此方法：例5 計算解 作階行列式：=由所作行列式可知的系數(shù)為，而由上式可知的系數(shù)為：通過比較系數(shù)得：3.拉普拉斯展開法運用公式=來計算行列式的值：例6 計算 解 取第1，3，2行，第1，3，列展開得：=4.乘積變換法例7 設，計算行列式解 例8 計算行列式解 在此行列式中

4、，每一個元素都可以利用二項式定理展開，從而變成乘積的和。根據(jù)行列式的乘法規(guī)則，其中 對進行例2中的行的變換，就得到范德蒙行列式，于是 = =5.升階法例9 計算行列式解 將升階為下面的階行列式即插入一行與一列，使是關(guān)于的階范德蒙行列式，此處是變數(shù)，于是故是一個關(guān)于的次多項式，它可以寫成另一方面，將按其第行展開，即得比較中關(guān)于的系數(shù)，即得 (二) 范德蒙行列式在多項式理論中的應用例1 設若至少有個不同的根，則。證明 取為的個不同的根，則有齊次線形方程組 (2)其中看作未知量因為方程組（2）的系數(shù)行列式是vander monde行列式，且所以方程組（2）只有零解，從而有即是零多項式。例2 設是數(shù)域

5、f中互不相同的數(shù)，是數(shù)域f中任一組給定的不全為零的數(shù)，則存在唯一的數(shù)域f上次數(shù)小于n的多項式，使=，證明 設由條件，知 （3）因為互不相同，所以方程組（3）的系數(shù)行列式則方程組（3）有唯一解，即唯一的次數(shù)小于的多項式使得，例3設多項式， ，則不可能有非零且重數(shù)大于的根。證明 反設是的重數(shù)大于的根，則=0， 進而即（4）把（4）看成關(guān)于為未知量的齊次線形方程組則（4）的系數(shù)行列式 = 所以方程組（4）只有零解，從而，所以必有這與矛盾，故沒有非零且重數(shù)大于的根。附件：(外文資料原文)new proof of the vander monde determinant and some applica

6、tions(a): a new method of proof: mathematical inductionwe on the n for that the inductive method.（1）when ， when the result is right.（2）the vander monde determinant conclusion assumptions for the class, now look at the level of.in ，subtracting the rows times, the first rows by subtracting times, that

7、 is, a bottom-up sequentially subtracted from each row on row timeshare有the latter determinant is a van dear mind determinant, according to the induction assumption, it is equal to all possible difference ；contains difference all appear in front of the consequent conclusion van dear mend determinant

8、 of the level n the establishment of mathematical induction, the proof is completed this result can be abbreviated as even the multiplication signimmediately by the results obtained necessary and sufficient condition for van der mond determinant is zeroat least two equal number nthe application of t

9、he vander monde determinant（一）vander monde determinant in the determinant calculationthe vander monde determinant standards form：according to the characteristics of the vander monde determinant given determinant using various methods, including some non-vander monde determinant into the vander monde

10、 determinant, and then use the results of the vander monde determinant, it calculated. the common method of following：1. given determinant of the columns (or rows) are different powers of an element, but the number of power arrangement with the vander monde determinant is not exactly the same, the n

11、eed to use the nature of the determinant (such as extraction common divisor, change each line (or column) order, the dissolution of items, etc.) as the determinant of the vander monde determinant.example 1.solutions of elements of each row are a number from left to right in ascending order, but not

12、from 0 to. but by a delivery ros. the common factor, such as extraction of each line number of a power from zero change to. example 2solution the law of the law of the determinant arranged with the arrangement of the vander monde determinant on the contrary, to make the columns in the elements of a

13、power of frequency from top to bottom in ascending order, the columns uplink switch in turn until the first line, rows sequentially exchanged with the uplink until the second row 2nd row sequentially with uplink switch until the first rows, so after a total ofsub-line exchange vander monde determina

14、nt of order ： if th row (column) consists of two branches (column), any two adjacent lines (columns) contain the same branch (column); and contains the vander monde ranks n branches (column)type, then the i-th row (column) multiplied by -1 added to the -row (column) to eliminate some of the branches

15、 (column) into the vander monde determinant：example3solution will be the first line of the d multiplied by -1 to the second line we have:then the second row of the above determinant is multiplied by -1 added to line 3, the new determinant line 3 line 4 was multiplied by -1 added:2 plus line to add l

16、aw待添加的隱藏文字內(nèi)容1each row (or column) the different square a power of the whose elements are all the of an element, but are the lack of the the determinant of the same party a power of, available this method:example 4 solution for order determinant：= seen by made determinant coefficient, by the coeffici

17、ents of the above equation :by comparing the coefficients obtained:3 laplace expansion methodsapply the formula = to calculate the value of the determinant：example 5dereference lines 1，3，2, 1，3， series expansion：=4 product transformation methodexample 6set up ，compute the determinantsolution . ascen

18、ding orderexample 7 compute the determinantthe solution l order for the following -order determinantinsert a row with a , order vander monde determinant, where is the variable, so therefore g h polynomial, it can be written ason the other hand, the started their first -line, that wascompare factor t

19、hat was (b) the vander monde determinant polynomial theoryexample 1 set is at least type root, 。proof of different root, homogeneous linear equations (2)where as unknown amountvander monde determinant is because the coefficients of the equations (2), and equations (2) only the zero solution, thus is zero polynomial.example 2 let number different from each other in the number field f, is any number field f group given not all zero number, then there exists a unique numb