




版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
1、Chapter 1 Answers1.6 (a.NoBecause when t<0, (1t x =0.(b.NoBecause only if n=0, 2n x has valuable.(c.Yes Because -=-+-+=+k k m n k m n m n x 414444 -=-=k m k n m k n (41(4 -=-=k k n k n 414 N=4.1.9 (a. T=/5Because 0w =10, T=2/10=/5.(b. Not periodic.Because jt t e e t x -=(2, while t e -is not peri
2、odic, (2t x is not periodic.(c. N=2Because 0w =7, N=(2/0w *m, and m=7.(d. N=10Because n j j e e n x 5/3(10/343(=, that is 0w =3/5, N=(2/0w *m, and m=3.(e. Not periodic. Because 0w =3/5, N=(2/0w *m=10m/3 , it s not a rational number.1.14 A1=3, t1=0, A2=-3, t2=1 or -1dtt dx ( is Solution: x(t isBecaus
3、e -=-=k k t t g 2(, dt t dx (=3g(t-3g(t-1 or dtt dx (=3g(t-3g(t+1 1.15. (a. yn=2xn-2+5xn-3+2xn-4Solution: 3212222-+-=n x n x n y321211-+-=n y n y44322134221111-+-+-+-=n x n x n x n x423522111-+-+-=n x n x n xThen, 423522-+-+-=n x n x n x n y(b.No. For it s linearity. the relationship between 1n y an
4、d 2n x is the same in-out relationship with (a. you can have a try.1.16. (a. No.For example, when n=0, y0=x0x-2. So the system is memory. (b. yn=0.When the input is n A ,then, 22-=n n A n y , so yn=0. (c. No.For example, when xn=0, yn=0; when xn= n A , yn=0. So the system is not invertible.1.17. (a.
5、 No.For example, 0(x y =-. So it s not causal.(b. Yes.Because : (sin(11t x t y = ,(sin(22t x t y = (sin(sin(2121t bx t ax t by t ay +=+1.21. Solution:We have known: (a. (b. (c. (d.1.22. Solution: We have known:(a. (b. (e.(g 1.23. Solution:For (21(t x t x t x E v -+= (21(t x t x t x O d -= then,(a. (
6、b. (c .1.24.Solution: For: (21n x n x n x E v -+= (21n x n x n x O d -= then, (a. (b. (c. 1.25. (a. Periodic. T= /2. Solution: T=2 /4= /2. (b. Periodic. T=2. Solution: T=2 / =2. (d. Periodic. T=0.5. Solution: x(t = E v cos( 4t u (t So, T=2 /4 =0.5 1.26. (a. Periodic. N=7 Solution: N= (b. Aperriodic.
7、 Solution: N= 1 = cos(4t u (t + cos(4 (t u (t 2 1 = cos(4t u (t + u (t 2 1 = cos(4t 2 2 * m =7, m=3. 6 / 7 2 * m = 16m , its not rational number. 1/ 8 (e. Periodic. N=16 Solution as follow: xn = 2 cos( n + sin( n 2 cos( n + 4 8 2 6 in this equation, 2 cos( n , its period is N=2 *m/( /4=8, m=1. 4 sin
8、( n , its period is N=2 *m/( /8=16, m=1. 8 2 cos( n + , its period is N=2 *m/( /2=4, m=1. 2 6 So, the fundamental period of xn is N=(8,16,4=16. 1.31. Solution Because x2 (t = x1 (t x1 (t 2, x3 (t = x1 (t + 1 + x1 (t . According to LTI property , y2 (t = y1 (t y1 (t 2, y3 (t = y1 (t + 1 + y1 (t Extra problems: 1. Supp
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 2025至2030年中國刨冰刀片數(shù)據(jù)監(jiān)測(cè)研究報(bào)告
- 2025至2030年中國鳳嘴花雕酒壺?cái)?shù)據(jù)監(jiān)測(cè)研究報(bào)告
- 2025至2030年中國光十熱光子嫩膚機(jī)數(shù)據(jù)監(jiān)測(cè)研究報(bào)告
- 2024年農(nóng)業(yè)植保員備考指導(dǎo)試題及答案
- 農(nóng)業(yè)植保員考試中的問題解決方法與思維方式試題及答案
- 企業(yè)內(nèi)部辦公自動(dòng)化與區(qū)塊鏈的深度融合
- 回收汽車合同協(xié)議
- 堡坎合同協(xié)議范本
- 大棚換膜合同協(xié)議
- 國外火電合同協(xié)議
- 2024重慶三峰環(huán)境集團(tuán)股份有限公司招聘15人筆試參考題庫附帶答案詳解
- 2024年吉林銀行總行招聘筆試真題
- 供應(yīng)鏈管理師考試的終極試題及答案
- 2025安徽中醫(yī)藥大學(xué)輔導(dǎo)員考試題庫
- 我愛刷牙幼兒課件
- 智慧樹知到《演講學(xué)(同濟(jì)大學(xué))》2025章節(jié)測(cè)試附答案
- 高等數(shù)學(xué)(慕課版)教案 教學(xué)設(shè)計(jì)-3.4函數(shù)的單調(diào)性與極值;3.5函數(shù)的最值及其應(yīng)用
- 2024-2025年第二學(xué)期一年級(jí)語文教學(xué)進(jìn)度表
- 3.1《百合花》課件 統(tǒng)編版高一語文必修上冊(cè)
- 會(huì)展?fàn)I銷學(xué)知到智慧樹章節(jié)測(cè)試課后答案2024年秋上海旅游高等專科學(xué)校
- 政府審計(jì) 課件 第五章 金融審計(jì)
評(píng)論
0/150
提交評(píng)論