高中物理必修二全冊復習

高中物理必修2全冊復習教案一、第五章曲線運動曲線運動x0yy02xl;動殊的曲線運動T,;tTv222rTnv2ar122rTnvt。xx002yyvvsxy2與vv22，2t0txyv與x2v。002ht0g2hv。0g列22v=臨v臨gR運動(設水不流時船的運動,即在靜水中的運動),一是隨水流的運動(水沖船的運動,等于水2例vv12d=短1v>vx121當v<v12vvv212vd1vθ22dvd2v1x=2=sin可xvy0tvtOxαxtyyx0yTv2yvV=vt2v0xyx023ygy2=tx2vtx0xtx和yt2vg20gx或x=2y22v20vv01vxy0thxsvxx1vvv,10yxOxshy1yv21v20而v=gt則v22120220yygvg·1v2=1220v21v22g2g02vv021v200gvvvv20214041x2h2=2gs4v2v20h=x1v0v2v20vxx112g10v2v20vvvv2v2220101012gggvvvvvvvv20240422022111vx=v112g02g00222s2:皮帶(齒軸,靠背輪nTrrACBcb·BACv=v或v①aba由得ω:ω=r:rb②abBAω或ω:ω③bcb由得vc④bcB:ω:ωCabcvabc5BACAω:ω:ωAABcvABcTCBABCOO/O1則Tv=T211112221222T22223456123456ObOa6二、第六章萬有引力與航天2r222322322G232Mmv2G=m2rr271M*5.98*1024s23(6730*10)2R2s22hGMg'又g＝＝R2R()2g(Rh)2Rh()RhR2g23GM'GM，R'g'M'RR22?()∴＝g2。MR'122Mmv()(2f)22F2r2rTn2r1MmF；r2r2nM1,;r2r2GMr1;rGM1，∝；＝r3r3r33周期：T＝2。rGM3v與rr811和∝v與rr3Mmr2r3()k2∴TT22r3kT2Mm()12r2T4r23＝22MV3＝R343r3面M2R3GT2GMR2G2MV3gGRm1。2r2229rh。h2GMmR4R2m1r2r2m12r2Cm12r2Gm121212102()22Mr2rTTGMm4r23mr()2Mr2T2MM后,R,利用天體的體積4M3r3RVV3.,則3R23GT2①②③2()22r2rTGMmmgR2TRGMm24r23mr()2，Mr2TGT23rM342R3R33114rr233；MGT2R23Th14(Rh)Rh()233M；GT22R321vm6m×mmm2πT2G律2g=9.8ms2Gm=Rg226.4××24××RTg6222=m334π2=4.2×m4×3.1427h=4.2×106.4×10m=3.56×10m767124πR2小時，其向心加速度T20.034ms24π2GRRT22R3T=2πRGMGMTa==9.8ms2R2g=9.8ms2MmG=mg①R22πT2G②2224RTg3222mm3334π243.142m7MmR+hv2G=m③R+h22Rg32ms3.1ms337h3.5610mv3.110ms73Mm2πT2G=mgGR2213）ABCD第七章機械能守恒定律功0F與Lα0機械能守定律2221f隨vvavmva保持vmFv達到最大vm14由aFP隨vv=Pm額在P增至P額t=vP=P00額(這個vv,它是車的功率增至P)計算時,先計算出額0m額求t額在P增至Pv額m定額定v即Fmvmvvm注意:中的僅是機車的牽引力.Pf或W=mv表示一個過程的末動能mv222合合2E122115WKKKKK①②③E和E。④W合⑤⑥⑦⑧f隨vvavm16vaFv達到最大vm由aFP隨vv=Pm額在P增至P額t=vP=P00額(這個vv,它是車的功率增至P)計算時,先計算出額0m額求t額在P增至Pv額mva定額定v即Fmvmvvmv0PfP30）vm1722）2[],