三角函數(shù)圖象的平移和伸縮(后面有高考題練習(xí))

三角函數(shù)圖象的平移和伸縮函數(shù)y=Asin(ω%+φ)+kOOOOOO y=sin%00000000000 A,ωθφθkDDDODO A□ωDOOOODDO φθkD0000 %ODDODDOD ADDOOODDDOOODωDDOOODDDOOODODDDOOOOD φDDOOODDDOOO由kDdooodddddooododdddoooDOODDDOOOOODDDDDODOODDDDODDDOooddddodddddo—M—(φ口口)口向——(φ?W~>丁=sin%000 DD∣φ∣□□□□□得y=sin(%+φ)000得y=sin(ω%+φ)000 -得y=Asin(ω%+φ)000得y=Asin(%+φ)+k0000DDODDD橫坐― (0<ωl≡———(?ω≡—DDDO1(DDDDO)ωDDDDD □A>□)□O□——(0L4<1)~>ODDO AD(000D0 )——M—(k>0)或向——(—0')~>DDIklDODDDy=sin%000≡≡ (A>1)或O□——(0<A<1)~>ODDO ADDDDDDO)得y=Asin%000≡≡ (0<ω<1)或O□——(ω>)TDDDO 1(DDDDO )ω—M-(φ>0兒向——(φk0)~>得V=Asin(ω%)000 φ' DDφDODω得V=Asin%(ω%+φ)000向——(k>0)□□□ (k<0)——>π■?/ \7口口口口DDkkZD— '口V=Asin(ω%+φ)+k0000例11V=sin%00000000D00解：0000000 V=sin%00000000DDD0000DD0DDDD0V=2sin2%+-1+10000I4J%OODDDπDODODODV=sin%+-04 I4J1 I π}-ODV=sin2%+-00000DDD0002 I 4JDDDDDDDDO1DODDDDD2DODV=2sin2%+-00000DD0DD000I4J一一C π、 V=2sin2%+—+10000I 4JVOODDD000D000V=sin%0000DDDDDDDDO2DODV=2sin%00000DDD0000DD0DDDD02OD V=2sin2%00000DDD000%OODDDπ—DODODD8(π?y=2sin2%+—DODOOOOOODO8JyODDDD1DODODDD(π?y=2sin2%+—4J+1DODO0D0D00000DD00DD%OODOOy=sin2%DODDDDDDDDDDDODDDDDD.Jy=sin2%+卜π)8JODDy=一(一π、一=Sin2%+—018JODDD坐標(biāo)縮小DDDD102得DD函數(shù)ODD解口口D一Jπ、.y=sin2%+—OI4JOdoodoooddoddddo例21y=sin2%DODDOOODDDDπy=cos2%——4Jddooddooodddoddddddo口：在π(y=sin2%=cos——2%127πy=cos2%——2Jπ、=cos2X——2J0中以%—a1%ODπy=cos2(%-a)——2DDODOD2%—2a=2%—OD24α=——0000 y=sin2%DODDDDDπ—DODODDDDDD8練習(xí)1ODDDDDy=2cos(x+注OsinO6?θX00y=-?in2x+—cos2xDODO20AODDDD-Q位BODDDDCODDDD爭(zhēng)單位DODDDD2ODDDy=3sin(DDDOODODDODF2ODDOM=_-ODOD2πBO節(jié)π—DODO8( k、—y=Sin%+-I4JD(π?y=Sinl2%+—ODDDODOπ4J、=cos2%-2a——(π2JO?y=cos2%——?4JDODO1DODODDDDD-Q位-和位F1DDDDDDDODθDDDDDDODO5兀DO05兀F2O3、將函數(shù) Y=EnfOOOOOO!二平?-3）OOOD到y(tǒng)=f□x）OOOO則f(x)=()AOFin（2工+-^~）+3BOER（2工+3~）+3COEn +3D、sin（2x）+34、把函數(shù)cos3x□sin3x)O圖象適當(dāng)變化就可以得到y(tǒng)=□sin3x的圖象這個(gè)變化可以是()AOO XOOOOOOOπ4BOOXOOOOOOOπ4COOXOOOOOOOπ5、為了到函數(shù)12y=-?in2γ--^c□≡2kooo°DOO xOOOOOOO可以將函數(shù)()AOOOOO--ODODOBOOOOOπ12y=sin2x的圖象--ODODOCOOOOO?oooooDOOOOO-六個(gè)單位長(zhǎng)度6、把函數(shù)y=