法學(xué)案例分析模版課件6

案例分析

Harrigan大學(xué)學(xué)生背景之探討指導(dǎo)教授：楊錦洲教授學(xué)生：９４２４１０７李佳璟９４２４１０８連豈浩９４２４１１０黃郁智９４２４１２３陳大翔1大綱研究問題研究背景研究動(dòng)機(jī)案例敘述題目探討總結(jié)2研究問題Harrigan大學(xué)對(duì)高中生來說是否比主要的競(jìng)爭(zhēng)大學(xué)更具有選填志願(yuàn)的吸引力，並且能比主要的競(jìng)爭(zhēng)大學(xué)更能吸引到名列前矛的學(xué)生。3研究背景在這個(gè)年代大學(xué)林立，學(xué)生所能夠選擇的志願(yuàn)也相對(duì)的多，為了使學(xué)校能夠持續(xù)的發(fā)展，以及能夠吸收優(yōu)良的學(xué)生使學(xué)校能夠保持競(jìng)爭(zhēng)力。4研究動(dòng)機(jī)為了達(dá)到學(xué)校的持續(xù)發(fā)展和保持學(xué)校的競(jìng)爭(zhēng)力這兩個(gè)主要的目的，所以對(duì)我們來說高中生是否對(duì)我們學(xué)校的興趣比我們的主要敵對(duì)大學(xué)還大。5案例敘述6案例敘述HarriganuniversityisaliberalartsuniversityintheMidwestthatattemptstoattractthehighestqualitystudents,especiallyfromitsregionofthecountry.Ithasgathereddataon178applicantswhowereacceptedbyHarrigan(arandomsamplefromallacceptableapplicantsoverthepastseveralyears).ThedataareinthefileHARRIGAN.XLS.Thevariablesare:7設(shè)定參數(shù)Accepted:whethertheapplicantacceptsHarrigan’soffertoenrollMainRival:whethertheapplicantenrollsatHarrigan’smainrivaluniversityHSClubs:numberofhighschoolclubsapplicantservedasanofficerHSSports:numberofvarsitylettersapplicantearnedHSGPA:applicant’shighschoolGPAHSSize:numberofstudentsinapplicant’sgraduatingclassSAT:applicant’scombinedSATscoreCombinedScore:acombinedscorefortheapplicantusedbyHarrigantorankapplicant8案例敘述ThederivationofthecombinedscoreisacloselykeptsecretbyHarrigan,butitisbasicallyaweightedaverageofthevariouscomponentsofhighschoolperformanceandSAT.Harriganisconcernedthatitisnotgettingenoughofthebeststudents,andworseyet,itisconcernedthatmanyofthesebeststudentsaregoingtoHarrigan’smainrival.Solvethefollowingproblemsandthen,basedonyouranalysis,commentonwhetherHarriganappearstohavealegitimateconcern.9題目探討10第一題Finda95%confidenceintervalfortheproportionofallacceptableapplicantswhoacceptHarrigan’sinvitationtoenroll.Dothesameforallacceptableapplicantswithacombinedscorelessthan330;withacombinedscoregreaterthan375.(Notethat330and375areapproximatelythefirstandthirdquartilesoftheScorevariable.)11求出交集NMeanStDevSEMean103345.7230.022.9695%CI(339.92,351.52)330以下和95%信賴區(qū)間的交集為0。375以上和95%信賴區(qū)間的交集為0。12第一題結(jié)論第一小題，主要是要讓我們了解到，錄取生的成績(jī)分佈，我們看這個(gè)圖可以看到落在四分位差和信賴區(qū)間中間的人數(shù)分布。此外我們?cè)傺a(bǔ)充個(gè)圓餅圖，來更了解到整體的分佈13第二題Find95%confidenceintervalsforthemeancombinedscore,themeanhighschoolGPA,andthemeanSATscoreofallacceptablestudentswhoacceptHarrigan’sinvitationtoenroll.Dothesameforallacceptablestudentswhochoosetoenrollelsewhere.Thenfind95%confidenceintervalsforthedifferencesbetweenthesemeans,whereeachdifferenceisameanforstudentsenrollingatHarriganminusthesimilarmeanforstudentsenrollingelsewhere.141.CombinedScore比較Two-sampleTforC12vsC13NMeanStDevSEMeanC12104346.430.73.0C1328376.124.64.6Difference=mu(C12)-mu(C13)Estimatefordifference:-29.7195%CIfordifference:(-40.82,-18.60)T-Testofdifference=0(vsnot=):T-Value=-5.37P-Value=0.000DF=52152.SAT比較Two-sampleTforC15vsC16NMeanStDevSEMeanC15103118013513C1628118913024Difference=mu(C15)-mu(C16)Estimatefordifference:-9.095%CIfordifference:(-65.2,47.1)T-Testofdifference=0(vsnot=):T-Value=-0.32P-Value=0.748DF=44163.GPA比較Two-sampleTforC18vsC19NMeanStDevSEMeanC1810384.607.340.72C192887.375.921.1Difference=mu(C18)-mu(C19)Estimatefordifference:-2.7695%CIfordifference:(-5.44,-0.09)T-Testofdifference=0(vsnot=):T-Value=-2.07P-Value=0.043DF=5117第二題結(jié)論一開始我們先以總和分?jǐn)?shù)來做分析，很明顯的發(fā)現(xiàn)，Harrigan的總和分?jǐn)?shù)輸對(duì)方一節(jié)，因此我們?cè)侔阉痖_成學(xué)測(cè)分?jǐn)?shù)和平時(shí)分?jǐn)?shù)來看，學(xué)測(cè)分?jǐn)?shù)的表現(xiàn)上，Harrigan和競(jìng)爭(zhēng)大學(xué)幾乎相差無幾，可是在平時(shí)成績(jī)上就輸了不少，所以想要在招收更優(yōu)秀的學(xué)生的話，在平時(shí)成績(jī)上的入學(xué)要求，要在更加的提高。18第三題Harriganisinterested(asaremostschools)ingettingstudentswhoareinvolvedinextracurricularactivities(clubsandsports).Doesitappeartobedoingso?Finda95%confidenceintervalfortheproportionofallstudentswhodecidetoenrollatHarriganwhohavebeenofficersofatleasttwoclubs.Findasimilarconfidenceintervalforthosewhohaveearnedatleastfourvarsitylettersinsports.19體保生分?jǐn)?shù)的信賴區(qū)間Theassumedstandarddeviation=24.84NMeanStDevSEMean60358.8524.843.2195%CI(352.56,365.14)20體保生和全部學(xué)生的分?jǐn)?shù)比較圖NMeanStDevMeanSPORT60117314018SAT103118013513Difference=mu(SPORTSAT)-mu(SAT)Estimatefordifference:-7.595%CIfordifference:(-52.0,36.9)T-Testofdifference=0(vsnot=):T-Value=-0.34P-Value=0.738DF=11921第三題結(jié)論這題我們求出了，體育優(yōu)良的學(xué)生綜合分?jǐn)?shù)的信賴區(qū)間。此外我們還另外把體育優(yōu)良的學(xué)生的學(xué)測(cè)成績(jī)，和所有學(xué)生的學(xué)測(cè)成績(jī)做比較，發(fā)現(xiàn)在學(xué)測(cè)成績(jī)上，學(xué)生們的成績(jī)幾乎相差無幾。也就是說，目前Harrigan大學(xué)，對(duì)於招收體育較為優(yōu)良學(xué)生的方案可以說是非常的成功。22第四題ThecombinedscoreHarrigancalculatesforeachstudentgivessomeadvantagetostudentswhotankhighlyinasmallhighschool.Therefore,Harriganwonderswhetheritisrelativelymoresuccessfulinattractingstudentsfromlargehighschool.Developoneormoreconfidenceintervalsforrelevantparametersshedsomelightonthisissue.23區(qū)分大小學(xué)校VariableNN*MeanSEMeanC121030266.110.9StDevMinimumQ1MedianQ3110.745.0193.0271.0346.0以平均數(shù)266做區(qū)分出大小學(xué)校241.大小學(xué)校的GPA比較NMeanStDevSEMeanGPA15286.907.431.0GPA25182.266.520.91Difference=mu(GPA1)-mu(GAP2)Estimatefordifference:4.6495%CIfordifference:(1.90,7.37)T-Testofdifference=0(vsnot=):T-Value=3.37P-Value=0.001DF=99252.大小學(xué)校的SAT比較NMeanStDevSEMeanSAT.52120714220SAT251115312317Difference=mu(SAT1)-mu(SAT2)Estimatefordifference:53.295%CIfordifference:(1.4,105.0)T-Testofdifference=0(vsnot=):T