獨(dú)立基礎(chǔ)計(jì)算(帶公式)

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獨(dú)立基礎(chǔ)計(jì)算,,,,,,,,,,,,

基礎(chǔ)編號(hào):,#8-3,,,,,,,,,,,

單位：,"m,kN,kPa",,(綠色為需輸入數(shù)據(jù)，紅色為計(jì)算結(jié)果),,,,,,,,,

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"1.地基承載力,基礎(chǔ)底面積計(jì)算:",,,,,,,,2.基礎(chǔ)抗沖切計(jì)算：,,,,

,,,,,,,,,(僅考慮柱對(duì)底板沖切，且基礎(chǔ)為一階，四邊沖切面在基礎(chǔ)內(nèi)):,,,

地基承載力特征值fa:,,,,,,,,,,,,

,fa=fak+ηbγ(b-3)+ηdγm(d-0.5)=,,,95,kPa,,,,計(jì)算公式：,FL=0.7βhpftμmh0,,

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,,fak=,80.00,kPa,,,,,基礎(chǔ)假定高度h=,,300,mm

,,ηb=,0.00,,,,,,保護(hù)層厚度as=,,75,mm

,,γ=,10.00,,,,,,,,,

,,b=,3.30,m,,,,,,h0=H-as-10=,215,mm

,,ηd=,1.00,,,,,,,ft=,1.43,MPa

,,γm=,20.00,,,,,,,βhp=,1.0,

,,d=,1.25,m,,,,,"柱截面寬高bc,hc:",,,

,,,,,,,,,,bc=,600,mm

,,,,,,,,,,hc=,600,mm

,,,,,,,,,臨界截面的周長μm:,,,

基礎(chǔ)底面積試算A:,,,,,,,,,,μm=2*(bc+hc)+4h0=,3260,mm

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軸心荷載作用,,A0=Fk/(fa-γm*d)=,,1.842105263,m2,,,,基礎(chǔ)抗沖切承載力R:,,,

,,,,,,,,,,R=0.7βhpftμmh0=,701.6009,kN

,標(biāo)準(zhǔn)荷載,Fk=,150.00,kN,,,,,,,,

,,Gk=A*γm*d=,272.25,kN,,,,,柱軸力設(shè)計(jì)值N:,,,

,,,,,,,,,,N=1.25*Fk=,187.5,kN

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"試取基礎(chǔ)長寬為b,L",,(用迭代法自動(dòng)重新計(jì)算地基承載力),,,,,,,柱底土反力設(shè)計(jì)值N1:,,,

沿彎矩作用方向高度,,b=,3.30,m,,,,,,N1=,18.26618457,kN

垂直彎矩作用方向?qū)挾?,L=,3.30,m,,,,,沖切荷載設(shè)計(jì)值FL:,,"(未扣除基礎(chǔ)及以上土重,也沒有考慮彎矩影響)",

,A=b*L=,,10.89,,,,,,,FL=N-N1=,169.2338154,kN

,Pk=(Fk+Gk)/A=,,38.77,kPa,"<fa,OK",,,,,,,

偏心荷載作用:,,,,,,,,,判斷:,"FL<R,OK!",,

,抵抗矩W=Lb2/6=,,5.9895,,,,,,,,,

,標(biāo)準(zhǔn)荷載,Mk=,5.98,kN*m,,,,,沖切計(jì)算基礎(chǔ)高度h=,,300,mm

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偏心距e=Mk/(Fk+Gk)=,,,0.014162226,m,,,,,,,,

,,a=b/2-e=,1.635837774,,,,,,,,,

,,[e]=b/6=,0.550,,,,,3.基礎(chǔ)配筋計(jì)算：,,,,

,Pkmax=Pk+Mk/W(用于e≤[e]),Pkmax=2/3*(Fk+Gk)/(L*a)(用于e>[e]),39.8,kPa,"<1.2fa,OK",,,,,,,

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,Pkmin=Pk-Mk/W