




版權(quán)說(shuō)明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
專題05利用函數(shù)極值求參(取值范圍)一、單選題1.函數(shù)SKIPIF1<0在SKIPIF1<0處有極大值SKIPIF1<0,則SKIPIF1<0的值等于(
)A.0 B.6 C.3 D.22.已知f(x)=SKIPIF1<0x3+(a-1)x2+x+1沒(méi)有極值,則實(shí)數(shù)a的取值范圍是(
)A.[0,1] B.(-∞,0]∪[1,+∞)C.[0,2] D.(-∞,0]∪[2,+∞)3.若函數(shù)SKIPIF1<0有兩個(gè)不同的極值點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.若SKIPIF1<0,SKIPIF1<0是函數(shù)SKIPIF1<0SKIPIF1<0兩個(gè)相鄰的極值點(diǎn),則SKIPIF1<0(
)A.3 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.已知SKIPIF1<0沒(méi)有極值,則實(shí)數(shù)SKIPIF1<0的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.設(shè)函數(shù)f(x)=lnx+SKIPIF1<0在SKIPIF1<0內(nèi)有極值,求實(shí)數(shù)a的取值范圍(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.已知函數(shù)f(x)=x3+ax2+bx+a2在x=1處的極值為10,則數(shù)對(duì)(a,b)為(
)A.(-3,3) B.(-11,4)C.(4,-11) D.(-3,3)或(4,-11)8.已知函數(shù)SKIPIF1<0,若SKIPIF1<0是SKIPIF1<0的極小值點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.若函數(shù)SKIPIF1<0在R上有小于0的極值點(diǎn),則實(shí)數(shù)a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0有且僅有2個(gè)極值點(diǎn),則m的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<011.已知函數(shù)SKIPIF1<0SKIPIF1<0有兩個(gè)極值點(diǎn),則實(shí)數(shù)a的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<012.已知函數(shù)SKIPIF1<0在其定義域的一個(gè)子區(qū)間SKIPIF1<0上有極值,則實(shí)數(shù)a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<013.已知函數(shù)SKIPIF1<0在SKIPIF1<0處取極小值,且SKIPIF1<0的極大值為4,則SKIPIF1<0(
)A.-1 B.2 C.-3 D.414.已知SKIPIF1<0為常數(shù),函數(shù)SKIPIF1<0有兩個(gè)極值點(diǎn),其中一個(gè)極值點(diǎn)SKIPIF1<0滿足SKIPIF1<0,則SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<015.已知函數(shù)SKIPIF1<0有兩個(gè)極值點(diǎn)m,n,且SKIPIF1<0,則SKIPIF1<0的最大值為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多選題16.已知函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0在SKIPIF1<0上有極值,則實(shí)數(shù)SKIPIF1<0可以?。?/p>
)A.1 B.2 C.3 D.417.函數(shù)SKIPIF1<0在SKIPIF1<0處取得極大值,則a的值可以是(
)A.-1 B.0 C.3 D.4三、填空題18.已知函數(shù)SKIPIF1<0在SKIPIF1<0處取得極值,則a=______.19.若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上恰有一個(gè)極值點(diǎn),則SKIPIF1<0的取值范圍是___________.20.若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上有兩個(gè)極值點(diǎn),則實(shí)數(shù)a的取值范圍是______.21.已知函數(shù)SKIPIF1<0(SKIPIF1<0)在SKIPIF1<0處有極大值,則實(shí)數(shù)SKIPIF1<0的值為_(kāi)_____.22.若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)存在極小值,則SKIPIF1<0的取值范圍是___________.23.函數(shù)SKIPIF1<0在SKIPIF1<0上存在極值點(diǎn),則a的取值范圍是______.24.設(shè)函數(shù)SKIPIF1<0,若SKIPIF1<0是函數(shù)SKIPIF1<0的一個(gè)極大值點(diǎn),則實(shí)數(shù)b的取值范圍為_(kāi)_________.25.已知函數(shù)SKIPIF1<0在SKIPIF1<0上恰有一個(gè)極值,則SKIPIF1<0___________.26.若函數(shù)SKIPIF1<0在SKIPIF1<0處取得極小值,則實(shí)數(shù)m的取值范圍為_(kāi)_____.四、解答題27.已知定義在R上的函數(shù)SKIPIF1<0SKIPIF1<0,在SKIPIF1<0處取得極值.(1)求SKIPIF1<0的解析式;(2)討論SKIPIF1<0在區(qū)間SKIPIF1<0上的單調(diào)性.28.已知函數(shù)SKIPIF1<0(1)當(dāng)SKIPIF1<0,證明:SKIPIF1<0;(2)若函數(shù)SKIPIF1<0在SKIPIF1<0上恰有一個(gè)極值,求a的值.29.已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),證明:當(dāng)SKIPIF1<0時(shí),SKIPIF1<0;(2)若SKIPIF1<0,函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在極大值,求a的取值范圍.30.若函數(shù)SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),函數(shù)SKIPIF1<0取得極值SKIPIF1<0.(1)求函數(shù)SKIPIF1<0的解析式;(2)若方程SKIPIF1<0有3個(gè)不同的實(shí)數(shù)根,求實(shí)數(shù)k的取值范圍.31.已知函數(shù)SKIPIF1<0(其中SKIPIF1<0,SKIPIF1<0…為自然對(duì)數(shù)的底數(shù))(1)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的單調(diào)區(qū)間;(2)當(dāng)SKIPIF1<0時(shí),若SKIPIF1<0是SKIPIF1<0的兩極值點(diǎn)且SKIPIF1<0,求實(shí)數(shù)a的取值范圍.32.設(shè)函數(shù)SKIPIF1<0.(1)若曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線與SKIPIF1<0軸平行,求SKIPIF1<0;(2)若SKIPIF1<0在SKIPIF1<0處取得極大值,求SKIPIF1<0的取值范圍.33.已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間;(2)設(shè)函數(shù)SKIPIF1<0,若SKIPIF1<0在SKIPIF1<0上存在極值,求a的取值范圍.34.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0,求函數(shù)SKIPIF1<0的單調(diào)區(qū)間;(2)若SKIPIF1<0存在兩個(gè)極小值點(diǎn)SKIPIF1<0,求實(shí)數(shù)SKIPIF1<0的取值范圍.35.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性;(2)若SKIPIF1<0有且只有一個(gè)極值點(diǎn),求a的取值范圍.36.已知函數(shù)SKIPIF1<0,曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線斜率為0.(1)求b的值;(2)若函數(shù)SKIPIF1<0的極大值為SKIPIF1<0,證明:SKIPIF1<0.37.已知函數(shù)f(x)=ax2+xlnx-ex,其中e是自然對(duì)數(shù)的底數(shù).(1)求證:當(dāng)SKIPIF1<0時(shí),函數(shù)f(x)是減函數(shù);(2)若函數(shù)f(x)存在極值,求實(shí)數(shù)a的取值范圍.38.已知函數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.(
溫馨提示
- 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒(méi)有圖紙預(yù)覽就沒(méi)有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 二零二五年度保健用品應(yīng)急配送與救援服務(wù)合同
- 火鍋合伙合同范本
- 房屋拆卸合同范本
- 修路結(jié)賬合同范本
- 簡(jiǎn)短企業(yè)合同范本
- 魚(yú)池承包合同范本
- 電子游戲機(jī)軟件開(kāi)發(fā)及整機(jī)生產(chǎn)合作合同范本
- 建筑安裝工程分包合同管理與風(fēng)險(xiǎn)控制
- 有限責(zé)任公司勞動(dòng)合同范本
- 石油管道工程合同范本
- 保險(xiǎn)產(chǎn)說(shuō)會(huì)(養(yǎng)老主題)課件
- 風(fēng)景園林工程初步設(shè)計(jì)文件編制深度規(guī)定
- 六年級(jí)心理健康導(dǎo)學(xué)案-10真正的朋友 |大象版
- 大專建筑工程畢業(yè)論文6000字
- 【古鎮(zhèn)旅游發(fā)展研究國(guó)內(nèi)外文獻(xiàn)綜述3200字】
- SolidWorks全套入門(mén)教程
- 企業(yè)財(cái)務(wù)會(huì)計(jì)(第二版)高職PPT完整全套教學(xué)課件
- 3dsMax20223維動(dòng)畫(huà)制作標(biāo)準(zhǔn)教程PPT完整版全套教學(xué)課件
- NXT上的PoP貼裝課件
- 2023-2024蘇教版小學(xué)數(shù)學(xué)5五年級(jí)下冊(cè)(全冊(cè))教案設(shè)計(jì)
- 批評(píng)他人發(fā)言稿(通用12篇)
評(píng)論
0/150
提交評(píng)論