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1、信息安全排列碼編程實(shí)現(xiàn)（Information security permutation code programming implementation）/ * n = 4 permutation source program c + + programming * /# include # include Int reverse (int); / / inverse functionVoid encode (); / / encryption functionVoid decode (); / / decryption functionInt a 8, c 8, 16 d, e, f 4,

2、8 remainder;/ / the main functionInt main ()Char bite0 bite1, bite4 bite5, key0 4, the key 12, zkey 12.File_name2 char file_name1 200, 200, file_name3 200, file_name4 200.Int I, j, k, choose, zijie2 = 0, zijie3 = 0;Choose the operation you want: - - - - - - - - - - - - - - - - - - - - - - - - - - -

3、- -Please press 1 button for the encrypted file. endl;Please press 2 for the decryption file. endl;Cout to exit please press 3. endl;Cout - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -;Cout choose;/ / encryption processIf (choose = = 1)Cout enter the file name and its path to be

4、 encrypted: endl;Cout file_name1;The file name and its path to be saved after encryption: endl;Cout file_name2;Ifstream fs0 (file_name1, the ios: : binary);If (! Fs0)Cout file open failed! endl;Return 1;Ofstream fs1 (file_name2, the ios: : binary);If (! Fs1)Cout file open failed! endl;Return 1;Cout

5、enter your 4-bit key endl key0;While (fs0. Get (bite0)For (I = 0; I 1;For (k = 0; k 12; k+)The key k = key0 (k + 4) / 4;For (j = 0; j 12; j+)Zkey j = key j;For (I = 0; I 10; I = I + 3)/ / mod 24The remainder = key I 0 + % 24;/ / see which path needs to be reversed, the first eight pathsFor (j = 0; j

6、 1;/ / eight pathsFor (j = 8; j 1;Encode ();For (j = 0; j 4; j+)E j = j;For (j = 0; j 4; j+)C = c + 4 j j;Encode ();For (j = 0; j 4; j+)E = a + 4 j j;For (j = 0; j = 0; j -)Zijie2 = zijie2 1;Zijie2 = zijie2 | c j;Bite4 = char (zijie2);Fs1. Put (bite4);For (j = 0; j 12; j+)The key j = zkey j;Fs0. Clo

7、se ();Fs1. Close ();/ / cout = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = endl ;/ / decryption processIf (choose = = 2)The name of the file to be decrypted and its path: endl;Cout file_name3;The file name and its path to be saved after decryption: endl;Cout file_name4;

8、Ifstream fs2 (file_name3, the ios: : binary);If (! Fs2)Cout file open failed! endl;Return 1;Ofstream fs3 (file_name4, the ios: : binary);If (! Fs3)Cout file open failed! endl;Return 1;Cout enter your four decryption key (same as the encryption key) : endl;Cout key0;/ / cout = = = = = = = = = = = = =

9、 = = = = = = = = = = = = = = = = = = = = = = = = = endl ;While (fs2. Get (bite1)For (I = 0; I 1;For (k = 0; k 12; k+)The key k = key0 (k + 4) / 4;For (j = 0; j = 0; I = I - 3)/ / mod 24The remainder = key I 0 + % 24;/ / see which path needs to be reversed, the first eight pathsFor (j = 0; j 1;/ / ei

10、ght pathsFor (j = 8; j 1;Decode ();For (j = 0; j 4; j+)E = f j j;For (j = 0; j 4; j+)A j = a + 4 j;Decode ();For (j = 0; j 4; j+)E = f + 4 j j;For (j = 0; j = 0; j -)Zijie3 = zijie3 1;Zijie3 = zijie3 | a, j.Bite5 = char (zijie3);Fs3. Put (bite5);For (j = 0; j 12; j+)The key j = zkey j;Fs2. Close ();

11、Fs3. Close ();If (choose = = 3)Its over. endl;Cout - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - endl ;Return 0;/ / inverse functionInt reverse (int x)X = x;X = x & 1;Return the x;The permutation table used in the encryption functionVoid encode ()開(kāi)關(guān)(剩余部分)例0:/ / 3 2 1 0一個(gè)0= c3

12、;如果(d12= = 1)0=反向(0);c1=2;如果(d9= = 1)1=反向(1);2= c1;如果(d6= = 1)2=反向(2);3= c0;如果(d3= = 1)3=反向(3);打破;案例1:/ / 3 2 0 1一個(gè)0= c2;如果(d8= = 1)0=反向(0);c1=3;如果(d13= = 1)1=反向(1);2= c1;如果(d6= = 1)2=反向(2);3= c0;如果(d3= = 1)3=反向(3);打破;情形2:/ / 3 1 2 0一個(gè)0= c3;如果(d12= = 1)0=反向(0);1= c1;如果(d5= = 1)1=反向(1);2= c2;如果(d10=

13、= 1)2=反向(2);3= c0;如果(d3= = 1)3=反向(3);打破;案例3:/ / 3 1 0 2一個(gè)0= c2;如果(d8= = 1)0=反向(0);1= c1;如果(d5= = 1)1=反向(1);2= c3;如果(d14= = 1)2=反向(2);3= c0;如果(d3= = 1)3=反向(3);打破;案例4:/ / 3 0 2 1一個(gè)0= c1;如果(d4= = 1)0=反向(0);c1=3;如果(d13= = 1)1=反向(1);2= c2;如果(d10= = 1)2=反向(2);3= c0;如果(d3= = 1)3=反向(3);打破;案例5:/ / 3 0 1 2一個(gè)0

14、= c1;如果(d4= = 1)0=反向(0);c1=2;如果(d9= = 1)1=反向(1);2= c3;如果(d14= = 1)2=反向(2);3= c0;如果(d3= = 1)3=反向(3);打破;案例6:/ / 2 3 1 0一個(gè)0= c3;如果(d12= = 1)0=反向(0);c1=2;如果(d9= = 1)1=反向(1);2= c0;如果(d2= = 1)2=反向(2);3= c1;如果(d7= = 1)3=反向(3);打破;案例7:/ / 2 3 0 1一個(gè)0= c2;如果(d8= = 1)0=反向(0);c1=3;如果(d13= = 1)1=反向(1);2= c0;如果(d2

15、= = 1)2=反向(2);3= c1;如果(d7= = 1)3=反向(3);打破;案例8:/ / 21,3 0一個(gè)0= c3;如果(d12= = 1)0=反向(0);1= c1;如果(d5= = 1)1=反向(1);2= c0;如果(d2= = 1)2=反向(2);3= c2;如果(d11= = 1)3=反向(3);打破;案例9:/ / 2 1 0 3一個(gè)0= c2;如果(d8= = 1)0=反向(0);1= c1;如果(d5= = 1)1=反向(1);2= c0;如果(d2= = 1)2=反向(2);3= c3;如果(d15= = 1)3=反向(3);打破;案例10:/ / 2 0 3 1

16、一個(gè)0= c1;如果(d4= = 1)0=反向(0);c1=3;如果(d13= = 1)1=反向(1);2= c0;如果(d2= = 1)2=反向(2);3= c2;如果(d11= = 1)3=反向(3);打破;情形11:/ / 2 0 1 3一個(gè)0= c1;如果(d4= = 1)0=反向(0);c1=2;如果(d9= = 1)1=反向(1);2= c0;如果(d2= = 1)2=反向(2);3= c3;如果(d15= = 1)3=反向(3);打破;情形12:/ / 1 3 2 0一個(gè)0= c3;如果(d12= = 1)0=反向(0);c1=0;如果(d1= = 1)1=反向(1);2= c2

17、;如果(d10= = 1)2=反向(2);3= c1;如果(d7= = 1)3=反向(3);打破;案例13:/ / 1 3 0 2一個(gè)0= c2;如果(d8= = 1)0=反向(0);c1=0;如果(d1= = 1)1=反向(1);2= c3;如果(d14= = 1)2=反向(2);3= c1;如果(d7= = 1)3=反向(3);打破;案例14:/ / 1 2 3 0一個(gè)0= c3;如果(d12= = 1)0=反向(0);c1=0;如果(d1= = 1)1=反向(1);2= c1;如果(d6= = 1)2=反向(2);3= c2;如果(d11= = 1)3=反向(3);打破;案例15:/ /

18、 1 2 0 3一個(gè)0= c2;如果(d12= = 1)0=反向(0);c1=0;如果(d9= = 1)1=反向(1);2= c1;如果(d6= = 1)2=反向(2);3= c3;如果(d3= = 1)3=反向(3);打破;案例16:/ / 1 0 3 2一個(gè)0= c1;如果(d4= = 1)0=反向(0);c1=0;如果(d1= = 1)1=反向(1);2= c3;如果(d14= = 1)2=反向(2);3= c2;如果(d11= = 1)3=反向(3);打破;案例17:/ / 1 0 2 3一個(gè)0= c1;如果(d4= = 1)0=反向(0);c1=0;如果(d1= = 1)1=反向(1

19、);2= c2;如果(d10= = 1)2=反向(2);3= c3;如果(d15= = 1)3=反向(3);打破;案例18:/ / 0 3 2 1一個(gè)0= c0;如果(d0= = 1)0=反向(0);c1=3;如果(d13= = 1)1=反向(1);2= c2;如果(d10= = 1)2=反向(2);3= c1;如果(d7= = 1)3=反向(3);打破;案例19:/ / 0 3 1 2一個(gè)0= c0;如果(d0= = 1)0=反向(0);c1=2;如果(d9= = 1)1=反向(1);2= c3;如果(d14= = 1)2=反向(2);3= c1;如果(d7= = 1)3=反向(3);打破;

20、情形20:/ / 0 2 3 1一個(gè)0= c0;如果(d0= = 1)0=反向(0);c1=3;如果(d13= = 1)1=反向(1);2= c1;如果(d6= = 1)2=反向(2);3= c2;如果(d11= = 1)3=反向(3);打破;案例21:/ / 0 2 1 3一個(gè)0= c0;如果(d0= = 1)0=反向(0);c1=2;如果(d9= = 1)1=反向(1);2= c1;如果(d6= = 1)2=反向(2);3= c3;如果(d15= = 1)3=反向(3);打破;案例22:/ / 0 1 3 2一個(gè)0= c0;如果(d0= = 1)0=反向(0);1= c1;如果(d5= =

21、 1)1=反向(1);2= c3;如果(d14= = 1)2=反向(2);3= c2;如果(d11= = 1)3=反向(3);打破;案例23:/ / 0 1 2 3一個(gè)0= c0;如果(d0= = 1)0=反向(0);1= c1;如果(d5= = 1)1=反向(1);2= c2;如果(d10= = 1)2=反向(2);3= c3;如果(d15= = 1)3=反向(3);打破;默認(rèn)值:打破;/ /解密函數(shù)中使用的排列碼表空白decode()開(kāi)關(guān)(剩余部分)例0:/ / 3 2 1 0如果(d12= = 1)0=反向(0);f3=0;如果(d9= = 1)1=反向(1);f2=1;如果(d6= =

22、 1)2=反向(2);f1=2;如果(d3= = 1)3=反向(3);f0=3;打破;案例1:/ / 3 2 0 1如果(d8= = 1)0=反向(0);f2=0;如果(d13= = 1)1=反向(1);f3=1;如果(d6= = 1)2=反向(2);f1=2;如果(d3= = 1)3=反向(3);f0=3;打破;情形2:/ / 3 1 2 0如果(d12= = 1)0=反向(0);f3=0;如果(d5= = 1)1=反向(1);f1=1;如果(d10= = 1)2=反向(2);f2=2;如果(d3= = 1)3=反向(3);f0=3;打破;案例3:/ / 3 1 0 2如果(d8= = 1)

23、0=反向(0);f2=0;如果(d5= = 1)1=反向(1);f1=1;如果(d14= = 1)2=反向(2);f3=2;如果(d3= = 1)3=反向(3);f0=3;打破;案例4:/ / 3 0 2 1如果(d4= = 1)0=反向(0);f1=0;如果(d13= = 1)1=反向(1);f3=1;如果(d10= = 1)2=反向(2);f2=2;如果(d3= = 1)3=反向(3);f0=3;打破;案例5:/ / 3 0 1 2如果(d4= = 1)0=反向(0);f1=0;如果(d9= = 1)1=反向(1);f2=1;如果(d14= = 1)2=反向(2);f3=2;如果(d3=

24、= 1)3=反向(3);f0=3;打破;案例6:/ / 2 3 1 0如果(d12= = 1)0=反向(0);f3=0;如果(d9= = 1)1=反向(1);f2=1;如果(d2= = 1)2=反向(2);f0=2;如果(d7= = 1)3=反向(3);f1=3;打破;案例7:/ / 2 3 0 1如果(d8= = 1)0=反向(0);f2=0;如果(d13= = 1)1=反向(1);f3=1;如果(d2= = 1)2=反向(2);f0=2;如果(d7= = 1)3=反向(3);f1=3;打破;案例8:/ / 21,3 0如果(d12= = 1)0=反向(0);f3=0;如果(d5= = 1)

25、1=反向(1);f1=1;如果(d2= = 1)2=反向(2);f0=2;如果(d11= = 1)3=反向(3);f2=3;打破;案例9:/ / 2 1 0 3如果(d8= = 1)0=反向(0);f2=0;如果(d5= = 1)1=反向(1);f1=1;如果(d2= = 1)2=反向(2);f0=2;如果(d15= = 1)3=反向(3);f3=3;打破;案例10:/ / 2 0 3 1如果(d4= = 1)0=反向(0);f1=0;如果(d13= = 1)1=反向(1);f3=1;如果(d2= = 1)2=反向(2);f0=2;如果(d11= = 1)3=反向(3);f2=3;打破;情形1

26、1:/ / 2 0 1 3如果(d4= = 1)0=反向(0);f1=0;如果(d9= = 1)1=反向(1);f2=1;如果(d2= = 1)2=反向(2);f0=2;如果(d15= = 1)3=反向(3);f3=3;打破;情形12:/ / 1 3 2 0如果(d12= = 1)0=反向(0);f3=0;如果(d1= = 1)1=反向(1);f0=1;如果(d10= = 1)2=反向(2);f2=2;如果(d7= = 1)3=反向(3);f1=3;打破;案例13:/ / 1 3 0 2如果(d8= = 1)0=反向(0);f2=0;如果(d1= = 1)1=反向(1);f0=1;如果(d14

27、= = 1)2=反向(2);f3=2;如果(d7= = 1)3=反向(3);f1=3;打破;案例14:/ / 1 2 3 0如果(d12= = 1)0=反向(0);f3=0;如果(d1= = 1)1=反向(1);f0=1;如果(d6= = 1)2=反向(2);f1=2;如果(d11= = 1)3=反向(3);f2=3;打破;案例15:/ / 1 2 0 3如果(d12= = 1)0=反向(0);f2=0;如果(d9= = 1)1=反向(1);f0=1;如果(d6= = 1)2=反向(2);f1=2;如果(d3= = 1)3=反向(3);f3=3;打破;案例16:/ / 1 0 3 2如果(d4= = 1)0=反向(0);f1=0

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