第二章線(xiàn)性表及其順序存儲(chǔ)結(jié)構(gòu)1

1、體現(xiàn)在體現(xiàn)在順序關(guān)系上順序關(guān)系上記錄排列為記錄排列為順序關(guān)系順序關(guān)系A(chǔ)DR(ai) = ADR(a1) + (i-1) k轉(zhuǎn)圖示 意 圖操作演示操作演示n-1ai a0 ai-1。前移前移n-i-1個(gè)元素個(gè)元素 0 i-1 i i+1 n-1 m-1an-1刪除它刪除它ai+1ain-1操作演示操作演示2) 1(1,2)(1100ninnAninnAnidelniins先進(jìn)后出先進(jìn)后出 (FirstInLastOut) 的線(xiàn)性表的線(xiàn)性表 棧底棧頂a1a4a2a3NULLa5template class Stack public: virtual bool flag() const=0; vir

2、tual bool readTop(T ) const=0; virtual bool push(T )=0; virtual bool pop()=0; virtual bool print() const=0; ;an-1a1a0topn-110m本課完a a* *b+cb+ca a* *b/cb/ca a* *b b* *c c* *d d* *e e* *f fa+(ba+(b* *c+d)/ec+d)/ea a* *(b+c)/(d-e)-f)(b+c)/(d-e)-f)a/(b-c)+da/(b-c)+d* *e eabab* *c+c+abab* *c/c/abab* *c c*

3、 *d d* *e e* *f f* *abcabc* *d+e/+d+e/+abc+de-/fabc+de-/f- -* *abcabc-/de-/de* *+ +表表2.2 2.2 中綴表達(dá)式和后綴表達(dá)式中綴表達(dá)式和后綴表達(dá)式中綴表達(dá)式中綴表達(dá)式后綴表達(dá)式后綴表達(dá)式/-DECB*+A;TOPvTOPp+*()-*T2 = A + T1T1/T2T1 = B * C；;-T3 = D / ET3/T4 = T2 T3T4;=結(jié)果：結(jié)果：T4T4本課完a1a2a3a4a5隊(duì)列空隊(duì)列空隊(duì)列滿(mǎn)隊(duì)列滿(mǎn)l 邏輯上循環(huán)：front=(front+1)%6; fear=(rear+1)%6a1a2a3a4

4、a5ABABCACABABCBCCAi,0i,0j,0j,0AABCBACB Ai,1i,1j,1j,1j,0j,0i,2i,2AAi,3i,3j,1j,1i,4i,4j,2j,2BBi,5i,5j,3j,3CCi,6i,6j,4j,4串串S, n=10串串P, m=5匹配成功，匹配成功，耶！耶！演示j,0j,00000000000000000000000000000000000000000001S S00000001P P由于每趟比較都是在p的最后一個(gè)字符才出現(xiàn)不等，i將回溯到i-6的位置，再重新從p的第一個(gè)字符開(kāi)始比較。整個(gè)匹配過(guò)程中i 需回溯需回溯36（即：（即：43- 81）次）次。4

5、242個(gè)個(gè)0 0 ija b a b c a b c a c b a ba b c a c1a b a b c a b c a c b a b a b c a c2a b a b c a b c a c b a b (a) b c a c3S3=a再重新與再重新與P中中哪個(gè)字符比較？哪個(gè)字符比較？S7=b再重新與再重新與P中中哪個(gè)字符比較？哪個(gè)字符比較？a b a b c a b c a c b a b a b c a cK可分三可分三種情況種情況a a a a b c a b c a c b a b a a a b cj=3i=43K=3j=4i=4a a a a b c a b c a c

6、 b a ba a a b cK=1,2,3i=4, j=4時(shí)失配時(shí)失配a a a a b c a b c a c b a b a a a b cj=2i=42K=2a a a a b c a b c a c b a b a a a b cj=1i=41K=1失敗！失?。∈?！失敗！成功！成功！結(jié)論：結(jié)論：K應(yīng)應(yīng)取最大的！取最大的！本課完a b a b c a b c a c b a b a b c a c2i=7j=5a b a b c a b c a c b a b (a) b c a c3i=7-i=11j=2- j=6i=7, j=5時(shí)失配時(shí)失配得得K=2K=2a b a b c a

7、b c a c b a ba b cj=3i=31得得K=1i=3, j=3時(shí)時(shí)失配失配失配失配a b a b c a a a a b c a a a a c c a a a a c1 2 3 4 5 6 7 8 9 i=10 1 2 3 4 5 j=6 失配失配 | | | | |失配失配1 2 3 4 5 6 7 8 i=91 2 3 j=4 a b a b c a a a a b c a c b a b a a a b cSPa b a b c a a a a b c ( i=9 ) a a a b c ( j=4 ) a a a b c1 2 3 4 5 6 7 8 i=9SPP k= 3兩序列增加兩序列增加一相同字符一相同字符 a a a b c