電容補(bǔ)償?shù)挠?jì)算公式

1、電容補(bǔ)償?shù)挠?jì)算公式電容補(bǔ)償?shù)挠?jì)算公式未補(bǔ)償前的負(fù)載功率因數(shù)為COS / 1。負(fù)載消耗的電流值為 11負(fù)載功率（KW）*1000則 11 =V 3*380*COS 為 1負(fù)載功率（KW） *1000則 12 =V 3*380*COS 為 2補(bǔ)償后的負(fù)載功率因數(shù)為COS為2,負(fù)載消耗的電流值為I2則所需補(bǔ)償?shù)碾娏髦禐椋?= 11 - I2所需采用的電容容量參照如下：得到所需COS / 2每KW負(fù)荷所需電容量（KVA R）0.701.270.970J10.62Q.540.460,390J10.250480J20.060.750*80QK20.040.860.880.900.920.940+960.9

2、8LOG1.411+54L60L651J01.76LSI1.871.932.002,092.291J11.241”西1.341.401.4&1.501.56L62l+69L781.如0.850.981.04L091.141.20L25L31L371.441.531.730.760,890*95L00L051.11bib1.22L281-351.44L640.680.810.86Q+920.97L021.03L14L201,271.36K560J30.780.040.890+94LOflLOSL121.19L200.520.660J10J60.810.870.920.90L04LUL2Q

3、L410.450.580.640®0.740.800.850.910+97L04L131330.390.520.570,620/670.730.760.840-900*971.061.270.320.450.510+560.610-670J20.780.84091.001.200.260.390.450.490.550.600.660.710.780.050-Q4hl40.200.330,380*430.490.540.600.650.720.790.881.080.140.270.330.360.430.490/540 * 600,660.730.821.020.080.220.2

4、70.320.37(M30.480+540.600.67GJ60.970.030J60.210必0.320.370.430,480.650,620.710.910.110.160.210.260.320-370.430.500.560,650.師0.050.110460.210.270,320.360.440.510.600.800.050400.160.210,270.330.390.460.550+750.050.100460.220.270.33(M00.490700-050.110.160.220.260.350.440.65Q460410,170.23OJQ0J90*590.060.

5、110.170.250+330.540.060.120J90.280.4B0.060430.220.430-070J60J6COS也例：現(xiàn)有的負(fù)載功率為 1500KW，未補(bǔ)償前的功率因數(shù)為COS/ 1 = 0.60,現(xiàn)需將功率因數(shù)提高到COS為2=0.96。則1500*1000則 I1 = = 3802 （安培）V 3*380*0.601500*1000則 I2= = 2376（安培）V 3*380*0.96即未進(jìn)行電容補(bǔ)償?shù)那闆r下， 功率因數(shù) COS/ 1= 0.60，在此功率因數(shù)的狀況下，1500KW 負(fù)載所需消耗的電流值為 I1 = 3802 安培。進(jìn)行電容補(bǔ)償后功率因數(shù)上升到 COS/ 2= 0.95，在此功率因數(shù)的狀況下， 1500KW 負(fù)載所需消耗的電 流值為 I2 = 2376 安培。所以功率因數(shù)從 0.60升到 0.96。所需補(bǔ)償?shù)碾娏髦禐镮1I2= 1426安培1.04KVA R，現(xiàn)負(fù)載為 1500KW，則180KVAR ，則需電容柜的數(shù)量查表COS/仁0.60, COS / 2=0.96時(shí)每KW負(fù)載所