最優(yōu)化方法大作業(yè)答案

1、32模型。z x x 2x x 2x x121323s.t 5123112313s2x +x -x 2123-2x +x -5x -61234x +x +x 6123x0iMinzx123123412354x x x x 6123622411 11500111210010026132110100100026110022224231110010421 032011310042212360001022 412取初始點(diǎn) （，9） ，梯度精度 =0.01。T 解：取TH I0f (x) 4(x 5)2212246f (x) f (x ) Td0 (8 24 ,9 6 )T0022000)(0)08(8

2、 5 ) ( ) 2(3 6 ) ( 6) 0 0001308x(1)91.10784f (x ) 4.43077x(1) 0.784631 (f x(0) ( ) TH110110 T1T H10 80 .03172T11 632 .86614HT10119.85005T112.46249H1T HT01011所以：0.12695 0.03149H 1 0.031491.00380.12695 0.03149 1.10784 d (1)1 0.031491.00384.430760.28018 4.48248(1) xx1d (x(1) d (1) 0d0.13848x(2) x(1) 0.

3、49423 d (1) 2.2153856因f (x ) 04. 某廠生產(chǎn)甲乙兩種口味的飲料，條件如下：設(shè)生產(chǎn)甲飲料錯(cuò)誤！未找到引用源。百箱生產(chǎn)乙飲料 百箱,x2百箱數(shù)錯(cuò)誤！未找到引用源。為生產(chǎn)乙飲料的百箱數(shù)x2錯(cuò)誤！未找到引用源。max z 10 x 9x121212121121212310 x 20 x x 150124x x 815610150200170202110002010000702011000201081351122021457301711771350222145173577x12a=6,5;10,20;1,0;-1,0;0,-1;b=60,150,8,0,0;x=linpro

4、g(f,a,b)運(yùn)行結(jié)果：Optimization terminated.x =6.4286 ans=f*xans =222S =50 x +60 x約束條件：4 x +6 x 600（材料）1220 x +18 x （工時(shí)）12x ，x 512minz12123124 x x 8152661801000000000100 50000129500000102100018000020024010 515再從底行中選元素，和第2 列元素18，迭代一次得：7320160 201800240015000120033180000133314023343編寫M 文件，代碼如下： f=-50,-60;a=4,6;20,18;-1,0;0,-1;b=600,400,-8,-5;x=linprog(f,a,b)