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26.1
IntroductionSinusoidalcarrier: orwhereA
-amplitude(V);f0
-frequency(Hz);
0=2f0
-angularfrequency(rad/s);
-initialphase(rad).Basicmodulationsystems:ASKFSKPSK3Vectorrepresentationandvectordiagram46.2
2ASK(Binaryamplitudeshiftkeying(二進制信號)6.2.1BasicprincipleExpression:
where0
=2f0---istheangularfrequencyofcarrier
andA(t)isarectangularwaveform.
ModulationmethodsMultipliermethod:
envelopemaybenonrectangularSwitchingmethod:envelopemustberectangular5DemodulationmethodsEnvelopedetectionmethod
-carrierphaseinformationisnotused.Coherentdemodulationmethod-carrierphaseinformationisused.RemovenoiseRemovenoise76.2.2PowerSpectralDensityAssumethegeneralexpressionofthe2ASKrandomsignalis
an
-binaryunipolarrandom
amplitude,itequalsto0or1
g(t)-symbolwaveform
T
-durationofthesymbol
thenthepowerspectraldensityofthe2ASKsignalcanbecalculatedas
式中,Ps(f)-powerspectraldensityofs(t)
PA(f)
-powerspectraldensityofA(t)
∴IfPA(f)hasbeenfound,thenPs(f)canbecalculatedbysubstitutingPA(f)intotheaboveequation.8FindPA(f):fromeq.(5.5-29):
wherefc
=1/T
G1(f)-frequencyspectrumofg1(t) G2(f)-frequencyspectrumofg2(t)
∵Now,g1(t)=0,∴Theaboveequationbecomes
whereG(f)=G2(f)
Andifg2(t)isrectangularpulse,thenSowehaveSo9Find
Ps(f):fromtheaboveequation:
When
P=?,theaboveequationbecomesAndTherefore,wehaveFinally,weobtain10CurvesofPA(f)
andPs(f)(b)CurveofPs(f)(b)CurveofPA(f)Aftermodulation,thebandwidthistwiceofbasebandsignal.116.2.3SymbolErrorProbabilityAssumethesignalafterbandpassfilteringequalstowhere
∵n(t)isanarrowbandGaussianprocess,wehaveSubstitutingtheabovetwoequationsintoy(t),weobtain:
.12
Coherentdemodulation
Thevoltagex(t)atthesampling&decisionpointis
wherenc(t)-Gaussianprocess
∴When1istransmitted,theprobabilityofx(t)
is
When0istransmitted,theprobabilityofx(t)is13Let
h
be
thedecisionthreshold,thentheprobabilityofthewrongdecisionof0as1
isequaltowhere
Theprobabilityofwrongdecisionof0as1is14WhenP(1)=P(0),thetotalsymbolerrorprobabilityis
Whenhequalstheoptimumthresholdh*,—signaltonoiseratioWhenr>>1,
15Envelopedetection
∵Theoutputistheenvelopeofitsinputvoltage
y(t),wehave
Ifthedecisiontheresholdequalsh,anditisprescribedthatwhenV>h,thedecisionisreceived1,andwhenV
h,thedecisionisreceived0,thenitssymbolerrorprobabilitycanbefiguredout.Whenthesignaltonoiseratioislarge,thesymbolerrorprobabilityis:16
【Example
6.1】Fora2ASKsignaltransmissionsystem,assumethesymbolrateisRB=4.8106Baud,theamplitudeofthereceivedsignalA=1mV,thesingle-sidepowerspectraldensityoftheGaussiannoisen0=210-15W/Hz.Find:1)theoptimumsymbolerrorprobabilitywhenenvelopedecisionisused;2)theoptimumsymbolerrorprobabilitywhencoherentdemodulationisused.
17Solution:Thebandwidthofthebasebandrectangularpulsecanbeselectedas1/THz.Thebandwidthofthe2ASK
signalshouldbetwiceofit,i.e.,2/THz.Henceaccordingtothesignalrate,theoptimumbandwidthofthebandpassfilterinthereceivershouldbeselectedas:B2/T=2RB=9.6106Hz
Thereforethemeanpoweroftheoutputnoiseofthebandpassfilteris:
Henceitsoutputsignaltonoiseratiois:
∴(1)thesymbolerrorprobabilityfortheenvelopedetectionis
(2)thesymbolerrorprobabilityforthecoherentdemodulationis186.3
2FSK 6.3.1BasicPrincipleExpression:GenerationmethodsFrequencymodulationmethod:
phasecontinuousSwitchingmethod:
phasediscontinuous20ReceptionmethodsCoherentreceiving:Noncoherentreceiving:Envelopedetection:22Zero-crossingpointdetection24
6.3.2
PowerSpectralDensity
2FSKsignalcanberegardedasthesuperpositionoftwo2ASKsignalswithdifferentfrequencies:
where∵Powerspectraldensityof2ASKsignalis ∴
thepowerspectraldensityof2FSKsignalshouldbethesumofthepowerspectraldensitiesoftwo2ASKsignals:
6.3.2
PowerSpectralDensity
∵
Substitutingitintotheaboveequation,thepowerspectraldensityof2FSKsignalisobtainedas:26
Whentheprobabilitiesoftransmitting1andtransmitting0areequal,P=?,theaboveequationcanbereducedas:WhereG(f)isthefrequencyspectrumofbasebandpulseand
Sowehave
27
Ascanbeseenfromtheaboveequation,theforgoing4termsarethecontinuousspectrumpartandthelatter4termsarethediscretespectrumpart.Curves:Bandwidth:28
6.3.3MinimumFrequencySpace
Inprinciple,iftwosignalsareorthogonal,thentheycanbeseparatedcompletely.
Fornoncoherentreception:let2FSKsignalbe
forsatisfactionoforthogonalcondition,require:
i.e.,require
29
6.3.3MinimumFrequencySpace
Theintegratedresultoftheaboveequationis
Assumethefirstandthirdtermsequalzero,thentheaboveequationcanbereducedtoSince1
and0
arearbitraryconstants,itmustsimultaneouslyhave
Hencewehave
So
30
itequalswhenm=1,itgivestheminimumfrequencyspace1/T.Forcoherentreceiving,letthentheequationcanbereducedto
Hence,itisonlyrequiredthati.e.,theminimumfrequencyspaceequals1/2T
.316.3.4
SymbolErrorProbabilityAssumetheoutputvoltagewaveformofthefilterisSymbolErrorProbabilityofCoherentDemodulation
Whenthesymbol1istransmitted,thetworeceivedvoltagesafterpassingthetwobandpassfiltersis:Theyaremultipliedbythelocalcarrier,andthenlow-passfiltered.Hence,weobtain
andNormalvariablewith(A,n2)Normalvariablewith(0,
n2)33Duringdecision,once
V1<V0,thesymbolerrorwillbeoccurred.Thereforethesymbolerrorprobabilityis
Let
(A+n1c-n0c)=z,then
z
isalsoanormalrandomvariable,anditsmeanequalsA,itsvarianceis
Hence,wehave
where
—signaltonoiseratio
∵Pe0
andPe1
areequal,thetotalsymbolerrorprobabilityis:34SymbolErrorProbabilityofEnvelopeDetectionWhenthesymbol1istransmitted,thetwovoltagesatthesampling&decisiondeviceinputrespectivelyare
and
whereV1(t)-envelopeofthesignalinthepathoffrequencyf1;(generalizedRayleighdistribution)
V0(t)-envelopeofthesignalinthepathoffrequencyf0;(Rayleighdistribution)35weobtainwhere —signaltonoiseratio
When0istransmitted,thesituationoferroroccurringisthesameasabove.So,thetotalsymbolerrorprobabilityis36Comparisonofsymbolerrorprobabilitiesofcoherentdetectionandenvelopedetection:Thereisnobigdifferencebetweenthemundertheconditionoflargesignaltonoiseratio.Inpracticalapplication,envelopedetectionismoreoftenused.
Comparisonofsymbolerrorprobabilitiesof2FSK
and2ASKsignals:Envelopedetection2ASK:
3dBdiference2FSK:Coherentdetection2ASK:
3dBdifference2FSK:37【Example6.2】Assumethereisa2FSKtransmissionsystem,itstransmissionbandwidthis2,400Hz;theapparentcarrierfrequenciesofthe2FSKsignalarerespectivelyf0=980Hz,f1=1580Hz;thesymbolrateisRB=300Baud,andthesignaltonoiseratioattheinputofthereceiveris6dB.Find: (1)Thebandwidthofthe2FSKsignal; (2)Theerrorsymbolprobabilityduringtheenvelopedetection; (3)Theerrorsymbolprobabilityduringthecoherentdemodulation.
38Solution:1.Thebandwidthofthesignal:2.Thesymbolerrorprobabilityofenvelopedetection:
Bandwidthofthebandpassfilter:B=2RB=600Hz
Thebandwidthratioattheinputandoutputofthebandpassfilter:2400/600=4
Thesignaltonoisepowerratioattheoutputofthebandpassfilter:r=4×4=16
∴39
3.ThesymbolerrorprobabilityofcoherentdemodulationUsingtheerrorfunctiontableinAppendixB,weobtain
Iftheapproximationequation(6.3-27)isused,thenobtainTheresultsareapproximatelythesame.406.4
2PSK 6.4.1BasicPrincipleExpression:
where
or41Waveform
-“101”Discontinuousphase:
Fig.(a)andFig.(c) Thereisintegernumberofcarrierperiodsonasymbol.Continuousphase:Fig.(b)andFig.(d)
Thenumberofcarrierperiodsinasymbolisonehalfperiodlargerthanintegernumberofperiods.42Theaboveexampleillustrates:
Onlywhenasymbolcontainsintegernumberofcarrierperiods,(discontinuouscase),thephasejumpattheboundaryoftheadjacentsymbolsisthephasevariationproducedbymodulation.45 6.4.2PowerSpectralDensity
Ascanbeseenfromthe2PSKsignalequation:
The2PSKsignalcanberegardedasaspecial2ASKsignalwiththeamplitudesA
and–A.
∴Therandomsymbolsequenceofthe2PSKsignalcanalsobedescribedbytheexpressionofthe2ASKsignal:
where
Forthesimplificationoftheequationwithoutlostofthegenerality,wewillletA=1.46
Directlyfromtheequation:
where
for2PSKsignal,g(t)=-g(t),G1(f)=-G2(f),andifP=?,
theaboveequationbecomesand
Thereisnodiscretefrequencycomponentintheaboveequation.--can’tuseenvelopedetectionmethodbecausethereisnocarrierinfo.47
With
thefrequencyspectrumofarectangularpulse:
weobtainthefinalexpressionofthepowerspectraldensityofthe2PSK
signal:Comparisonofthepowerspectraldensitiesof2PSK
and2ASKsignals
Recallthatthepowerspectraldensityof2ASK
signalis:Thebandwidthsofbothareidentical.2PSKsignalhasnodiscretecomponent:
(f+f0)+(f-f0)48(a)Powerspectraldensityof2ASK
signal(b)Powerspectraldensityof2PSK
signal49 6.4.3SymbolErrorProbability
Thesampling&decisionvoltageis
Theprobabilityofwrongdeciding0as1is
Pe0=P(V<0/when0istransmitted)
Theprobabilityofwrongdeciding1as0is
Pe1=P(V>0/when1istransmitted)
SinceherePe0=Pe1
,∴Thetotalsymbolerrorprobabilityis
50
TheareaoftheleftshadowinthefigureisHence,thetotalsymbolerrorprobabilityis
or
Undercoherentdemodulationcondition,forobtainingthesamesignaltonoiseratio,therequiredpowerofthe2FSKsignalis3dBlargerthanthatofthe2PSKsignal;andthatofthe2ASKsignalis6dBlarger.516.5
2DPSK
6.5.1BasicprincipleExpression:
Assume
isthephasedifferenceofthecurrentsymbolandtheprevioussymbol,andlet
then,thesignalsymbolcanbeexpressedas
where0
=2f0
---istheangularfrequencyofthecarrier
---phaseoftheprevioussymbol
Example:52Indirectgenerationof2DPSK
signalsFromviewpointofreceiver:can’tdistinguish2DPSK
and2PSKsignals.Forexample:ifthereceivedsymbolphaseis:
0
0
0for
2DPSK:
A=111001101(initialphase0)for2PSK:
B=
101110110(1)IfthesequencetobetransmittedisA,andconvertittothesequenceB,thenthelatterisusedtomodulatethecarrierby2PSK.Theresultisthesameas2DPSKmodulationdonedirectlybyA:Basebandsequence:
A=
111001101(Absolutecode)Sequenceafterconversion:B=(0)101110110(Relativecode)Phaseafter2PSK
modulation:
(0)00
0Conversionrule:1)
Absolutesymbol“1”changestherelativesymbol;
Absolutesymbol“0”doesn’tchangetherelativesymbol.2)53Conversionmethod:usingabistabletrigger
Blockdiagramofindirectmodulationof2DPSKsignal57Codeinverseconverter586.5.2PowerSpectralDensityThepowerspectraldensityof2DPSKsignalisthesameasthatof2PSKsignal.6.5.3SymbolErrorProbabilitySymbolerrorprobabilityofphasecomparisonmethodAssumethecontinuouslyreceivedtwosymbolsare00,then
Where
s0(t)-delayedwaveformoftheprevioussymbol
s1(t)-waveformofthecurrentreceivedsymbol59
Aftermultiplicationandlowpassfiltering,thesetwosymbolsbecome
Decisionrule:
IfV>0,thenthedecisionis0;
IfV<0,thenthedecisionis1.
Therefore,whenthecurrenttransmittingsymbolis0,theprobabilityofwrongreceivingequals
Byusingtheidenticalequation
theaboveequationcanberewrittenas
where60
-obeysgeneralizedRayleighdistribution;
-obeysRayleigh
distribution,
So
where.
So61SymbolErrorProbabilityofPolarityComparisonMethod
Ascanbeseenfromtheabovefigure,thefrontalpartofthedemodulationprocessisquitethesameasthatofthecoherentdemodulationofthe2PSK,soonlythesymbolerrorprobabilityintroducedbytheinversecodeconversion.
62【Example6.3】Assumetherateof1Mb/sisrequiredtotransmitdatabyusingthe2DPSKsystem,andthesymbolerrorprobabilitydoesnotexceed10-4,aswellasthesingle-sidepowerspectraldensityofthewhiteGaussiannoiseatthereceiverinputisn0
=
110-12W/Hz.Find:(1)
therequiredreceivedsignalpowerforthephasecomparisonmethod;(2)
therequiredreceivedsignalpowerforthepolaritycomparisonmethod.
Solution:
Nowthesymbolrateis1Mb/s.Thebandwidthoccupiedbythe2DPSKsignalisthesameasthatbytheASKsignal.Thus,thebandwidthofthereceivingbandpassfilteris
B
2/T=2106Hz
Theoutputnoisepowerofthebandpassfilteris63Whenphasecomparisonmethodisused:accordingtotherequirementtherequiredsignaltonoiseratioisandtherequiredsignalpowerisWhenpolaritycomparisonmethodisused,accordingtothesamerequirement,
i.e.,
Fromtheerrorfunctiontableweget:
Thereforetherequiredsignalpoweris646.6PerformanceComparisonofBinaryDigitalKeyingTransmissionSystemSymbolerrorprobabilitycurves656.7M-aryDigitalKeying
6.7.0signaltonoiseratio
r
-symbolenergytonoisesingle-side
spectraldensityratio
FortheM-arysystem,
onesymbolcontainskbitsofinformation:
k=log2
M
TheenergyEbofeachbitequalsE/k
,wherethesymbolenergyE
isequallydistributedineachbit.Consequently,
whererb
istheenergyperbittonoisesingle-sidepowerspectraldensityratio.
.666.7.1M-ASKMulti-levelunipolarNRZsignal
M-ASKsignal
(Fig.aFig.b)
Multi-levelbipolarNRZsignal
Suppressedcarrier
M-ASKsignal
(Fig.cFig.d)Theseareactually4ASK
signals:
Eachsymbolcontains2bits.67
68SymbolerrorprobabilityofsuppressedcarrierMASK
signal
whereM-magnitudeofthebase,orthenumberofamplitudes
r-signalmeanpowertonoisepowerratio
When
M=2,theaboveequationbecomes
696.7.2M-FSKBasicprincipleThesymbolsofM-FSKusethecarrieswithMdifferentfrequencies.70NoncoherentDemodulationBlockdiagram71 6.7.3M-PSKBasicprinciple:the
M-PSK
signalsymbolcanbeexpressedas wherek-themodulatedphase,itsvalueisdecidedbythevalueofthebasebandsymbol;
A-thesignalamplitude,aconstant
k=1,2,…,M
Let
A=1,thenthisequationcanbeexpandedas
where ThesymbolofM-PSKsignalcanberegardedasasignalcomposedoftwoorthogonalcomponentswithMkindsofamplituderespectively,i.e.,thesumoftwoM-ASKsignalwiththesamecarrierfrequency,henceitsbandwidthisthesameasthatofM-ASKsignal.
72QPSKCodingrule:A
modeandB
mode
GraycodeOnlyonebitdifferencebetweenadjacentkAdvantage:biterrorprobabilitysmallGrayBinary123400000010001100010000000100100010567801010111011001000100010101100111910111213141516110011101111110110011011101010001000100110101011110011011110111173GenerationmethodsThefirstmethod:multiplicationmethod
Binarysymbol1
Bipolarpulse+1
Binarysymbol0
Bipolarpulse-1BmodecodingNRZbipolarbasebandbinarysignal74Thesecondmethod:selectionmethod75Demodulationmethod-Coherentdemodulation76SymbolErrorProbability
Ifthephaseofthetransmittingsignal11is45,thenthedecisionthresholdsshouldbeat0
and90.
Assume:f()-probabilitydensityofthereceivedvector,thenthesymbolerrorprobabilityis:
Thecalculationresultoftheaboveequationis:776.7.4
M-DPSKBasicprinciple
Touse4-aryDPSK(QDPSK)
signalasexample,
Inthetable,k
isthephasechangerelativetotheprecedingadjacentsymbol.78Generationmethod TheinputsofmultipliersshouldbebinaryNRZbipolarrectangularpulses1and-1,thecorrespondingrelationshipis:
Binarysymbol0
+1
Binarysymbol1
-1Amodecoding79Conversionre
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