工程力學(xué)自測(cè)題一及答案

經(jīng)典word整理文檔，僅參考，雙擊此處可刪除頁眉頁腳。本資料屬于網(wǎng)絡(luò)整理，如有侵權(quán)，請(qǐng)聯(lián)系刪除，謝謝！精品文檔工程力學(xué)自測(cè)題（一）21、三力平衡匯交定理F是BA。、如圖所示系統(tǒng)在力F作用下處于平衡。欲使All成30o。題圖。、和。。和8FAsmax。maxl、，i和2d/D.精品文檔）；）；b和Ph(1(1。）；）34PABhl/2l/2bPABh/2l/2l/2b題圖6248）2010201020A2020C20B20201010D20102010題圖BMqCAB題圖）50,30,0；））））505012350,30,50；；12350,30,50301230,30,50題圖。123.精品文檔D20kN/m8kN.m20kNDCAB1m1m1m1m題三圖分）如圖所示變截面桿件，A300mm2，1A200mmEGPa22ABC題四圖I10000cm]5MPa]12MPa）4zACBzy單位：mm題五圖分）如圖所示傳動(dòng)軸ADB、CM800Nm，F(xiàn)3000N]140d。.精品文檔FMADBCM題六圖16cmlmd，GPa200MPaFE，比例極限。pcr.精品文檔工程力學(xué)自測(cè)題答案（一）、60o。3F、s2A；；；；A；D；；；；A20kN/m8kN.m20kND20kN/m8kN.m20kNDCABCABFAx1m1m1m1mFFByAy題圖圖）F0F0xAxF0FF2010yAyByM(F)0F282010.52030AByF0,F19kN,FkNAxAyBy用和設(shè)與2F和FN1N2AB2C）.精品文檔12FN1FN230kN1））F20kNN1F302010kNN220103300106F66.710Pa66.7MPa段段N1612A110103FN2APaMPa50105062001062FlFllllN1N21211339696m3A以MAFCABAxFAy圖）FFxAxFFFAyyAyM(F)MM7MmAAA.精品文檔7KN(+)））危A右A即M=M2KNmy60mm-+maxAmax220mmy-max5KNmy60mmM++maxmax220mmy-maxA221022010-My-33.]44010Pa=44MPa<max4+maxI10000108maxz106010-My+33.]12010Pa=12MPa<max4-maxI10000108maxz551022010+My-33]110010Pa=11MPa<max4-maxI10000108maxz106010+My+33]+30010Pa=3MPa<max4maxI10000108maxz.精品文檔M在M的F2FADBCBCADMM1.5kN.m1.2kN.m+-800N.m））BBM1500N,T800NmBB。dMT22]BWBr322106d322dm49.8得62d350mmd1.0d2i4m244l1.05125i4102.精品文檔