題庫語言歷年試卷2000答案

下框由教師填寫—二三四五(2分,20分123456789ABADCABDCC(324分118，14，A27,-13340,1,3,510,41,7063,7,7g=4,g=3,k=68typedefint(520分143427-1541623132，1，4，3，6，（4，1，2，3，6，j）4(220分sqrt(point[k].x*point[k].x+point[k].y*point[k].ypoint[k].length>sub=strcpy(string,str[0]);（5）strcat(string,str[k]chars[]chard=d*16+s[k]-d=d*16+s[k]-'a'+yearday-=k(1521116分)intsum_fact(intnumber)2{intk,sum=if(number<0)number=-for(k=1;k<=number;k++)1分if(number%k0sumk;2分returnsum;}2includestdio.h>1{FILE*fpin,intiffpinfopen("input.txt","r"NULL2printf("Can'topenfileinput.txt"}iffpoutfopen("output.txt","wNULL2printf("Can'tcreatfileoutput.txt"}whilefeof(fpin1fscanf(fpind&x2fprintf(fpoutdsum_fact(x2}fclose(fpin);1fclose(fpout}1999~2000學年“程序設計基礎--C”試卷考試時間20006238:30-10:30注:請將答案寫在答卷紙上試題一、單項選擇題（每小題2分，共20分） 結構ABCD若x是單精度實型變量，表達式(x=10/4)的值 。A、2.5B2.0C3D表達式!x等價 A、x==0B、x==1C、x0D、x若變量已正確定義且k的值是4，計算表達式(j=k--)后 A、j=3,k=3B、j=3,k=4C、j=4,k=4D、j=4,k=35.算術運算符、賦值運算符和關 AB、關系運算、賦值運算、算術運算 AautoB、staticCregisterD、7．下列語句定義pf為指向float類型變量f的指針 A、floatf,*pff;B、floatf,*pf&f;C、float*pf&f,f;D、floatf,pf8．表達式sizeof(“key”)的值 oworld*(*(argv+2)) A、’pB、C、‘hD、10．若a是整型變量，表達式~(a^~a)等價 A、~aB、1C、0D、試題二、填空題（324分1printfdox0x1212012);#defineF(x)x-#defineD(x)printf("%d,%d",D(3),D(D(3)))intk;char*s=“ABC”;for(k=10;k!=0;k--);printf("%d",kwhile(*sputchar(*s);4．寫出下列程序的輸出結果。voidfun(intk) staticintprintf(”%d,”,a+=}{intfor(k=1;k<=3;}main(){structst{intx,y;}structstprintf("%d",(a+3)-}#include"stdio.h"voidmain(){intk,j,m,n,a[6][6],b[6];m=3,for(k=0;k<m;for(j=0;j<n;a[k][j]=for(k=0;k<m;b[k]=0;for(j=0;j<n;j++)b[k]+=a[k][j];}for(k=0;k<m;k++)printf("%d,",b[k]);}#include<stdio.h>longfib(intg){switch(g){case0:return(0);case1:case2:return(2);}printf("g=%d,",g);return(fib(g-1)+fib(g-2));}{longk=}用typedef10的整型數(shù)組NUM試題三、程序閱讀題（520分#include<stdio.h>intx,y,voidp(int*x,int{--z=}void{x=5;y=2;p(&x,printf("%d,%d,%d--",printf("%d,%d,%d--",x,y,p(&y,printf("%d,%d,%d",x,y,} #includevoid{intx,xfor(k=0;x!=0;x&=x-1printf("%d",}#include<stdio.h>voidmain(){intv[]={6,3,4,1,2};intn=5;intgap,j,k,temp;for(gap=n/2;gap>1;gap/=2)for(j=gap;j<n;j++for(k=j-gap;k>=0&&v[k]>v[k+gap];k-=gaptemp=v[k]=v[k+gap]=}for(k=0;k<5;k++)printf("%d,",}4123450#defineLENsizeof(struct#defineNULLstructintnumstructline*next}{structline*p1,*p2,*headintj,k=p1=p2=head=(structline*)malloc(LEN)scanf("%d",&p1->num)whilewhile(p1->num!=p1=(structline*)malloc(LEN)scanf("%d",&p1->num)if(p1->num==0)p2->next=NULLelse{p2->next=p1p2=p1}}p2->next=head;p1=head->next;p1=p1->nextfor(j=1;j<=k;printf("-->%d",p1->num)p1=p1->next}}試題四、程序填空題（220分110個點的坐標(設坐標為整數(shù)值輸出距原點最遠的點(設唯一)的坐標及該點距原點#includevoid{intx,float}intk,for(k=0;k<10;point[k].length=}for(k=1;k<10;if((2))(3)printf("(%d,%d)%f",point[sub].x,point[sub].y,}n1,然后輸出該字符串{charstr[10][20],intk,scanf("%d",for(k=0;k<n;gets(str[k]);for(k=1;k<n;k++)(5)xtoi的功能是將放在字符串中的十六進制數(shù)（可以出現(xiàn)’0’~’9’、’a’~’f）轉換成十進制整數(shù)。例如：調(diào)用xtoi("1f")31。xtoi((6){intk,for(k=0;s[k]==’’||s[k]==’’;while(s[k]>=’0’&&s[k]<=’9’||s[k]>=’a’&&s[k]<=’f’if(s[k]>='0'&&s[k]<='9')(7)if(s[k]>='a'&&s[k]<=}return}函數(shù)month_day(year,yearday,&month&day)的功能是將給定的某年第幾天轉換為相應的月和日。例如：調(diào)用month_day(1988,60,&m,&d)后，m2,d的值是29(即 年月29日)。判別閏年的條件：能被4整除但不能被100整除或能被400整除。voidmonth_day(intyear,intyearday,int*pmonth,int*pday){staticint{0,31,29,31,30,31,30,31,31,30,31,30,31}};intk,leap;leap=year%4==0year%100!=0||year%400==0;for(k=1;yearday>day_tab[leap][k];k++)(9)*pmonth=(10)*pday=}(共16分1．[程序說明5分sum_