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2014屆高三年級(jí)八校聯(lián)合調(diào)研考試試卷

數(shù)學(xué)(理科)

一、填空題(本題滿分56分)本大題共有14題,要求在答題紙相應(yīng)題序的空

格內(nèi)直接填寫(xiě)結(jié)果,每個(gè)空格填對(duì)得4分,否則一律得零分.

3

1.在復(fù)平面匕復(fù)數(shù)----對(duì)應(yīng)的點(diǎn)到原點(diǎn)的距離為_(kāi)_________.

(2-0-

2.已知函數(shù)/々"sin"gx-cos45(。>0)的最小正周期是兀,則0=.

3.向量2=(3,4)在向量右=(1,-1)方向上的投影為.

1+-1

4.已知正數(shù)。力滿足a+匕=2,則行列式^的最小值為.

5.閱讀右邊的程序框圖,如果輸出的函數(shù)值y在區(qū)間-,1內(nèi),則輸入

_4_

的實(shí)數(shù)x的取值范圍是.

6.設(shè)a、£是一元二次方程/一2工+m=0的兩個(gè)虛根.若[3|=4,

則實(shí)數(shù)機(jī)=.

7.集合4=卜言<0卜8=卜卜-6|<a}.若“a=l"是“APIBW。"

的充分條件,則實(shí)數(shù)b的取值范圍是.

8.已知橢圓的焦點(diǎn)在x軸上,一個(gè)頂點(diǎn)為A(0,-1),其右焦點(diǎn)到直線x—y+2近=0的

距離為3,則橢圓的方程為.

9.在△48C中,A、B、C所對(duì)邊分別為a、匕、c.若1+也■+空=0,則4=_______

tan8b

10.已知數(shù)列{怎}的首項(xiàng)q=2,其前n項(xiàng)和為S,,.若=25?+1,貝ijan=.

11.某地球儀上北緯30。緯線長(zhǎng)度為12%cm,該地球儀的表面上北緯30。東經(jīng)30。對(duì)應(yīng)點(diǎn)

A與北緯30。東經(jīng)90。對(duì)■應(yīng)點(diǎn)6之間的球面距離為cm(精確到0.01).

12.已知直線),=M》+2)與拋物線。:丁=8%相交于4、B兩點(diǎn),尸為拋物線。的焦

點(diǎn).若|福|=2|而I,則實(shí)數(shù)左=.

13.將/(x)=2、-烏的圖像向右平移2個(gè)單位后得曲線將函數(shù)y=g(x)的圖像向下

2

平移2個(gè)單位后得曲線。2,G與關(guān)于X軸對(duì)稱.若F(x)="D+g(x)的最小值

a

為加且機(jī)>2+近,則實(shí)數(shù)4的取值范圍為.

14.已知“a,b,c,d,e,于”為"1,2,3,4,5,6”的一個(gè)全排列.設(shè)x是實(shí)數(shù),若

“(x—”)(x—b)<0”可推出“(x—c)(x—d)<0或(x-e)(x-/)<0",貝U滿足條

件的排列“a,b,c,d,ej”共有個(gè).

二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有

且只有一個(gè)結(jié)論是正確的,必須把答題紙上相應(yīng)題序內(nèi)的正確結(jié)論代號(hào)涂黑,選對(duì)

得5分,否則一律得零分.

15.函數(shù)/(x)=1x2+l(x<-2)的反函數(shù)是

()

(A)y=V2x-2(1<A:<3).(B)y=J2x-2(x>3).

(C)y=->/2x-2(l<x<3).(D)y=-J2x-2(x>3)?

16.直線/的法向量是1=(a,〃).若ab<0,則直線/的傾斜角為

()

(A)arctan||(B)arctan||(C)^-+arctan—(D)+arctan—

a)\b)ba

17.已知A、B、C是單位圓上三個(gè)互不相同的點(diǎn).若|而|=|前I,則而就的最小值

是()

113

(A)0.(B).(C).(D)—.

424

18.等差數(shù)列{%}的公差d*0,aneR,前〃項(xiàng)和為S“,則對(duì)正整數(shù)〃Z,下列四個(gè)結(jié)論

中:

(1)S,“,S2,“-S,“,S3m—S2,“成等差數(shù)列,也可能成等比數(shù)列;

(2)S,“,S2,“一黑,53,”一$2,“成等差數(shù)列,但不可能成等比數(shù)歹U;

(3)S,“,§2,“,S3,,,可能成等比數(shù)列,但不可能成等差數(shù)列;

(4)S,“,52,“,邑”,不可能成等比數(shù)列,也不可能成等差數(shù)列;

正確的是

()

(A)(1)(3).(B)(1)(4).(C)(2)(3).(D)(2)(4).

三.解答題:(本題滿分74分)本大題共有5題,解答下列各題必須在答題紙

的規(guī)定區(qū)域(對(duì)應(yīng)的題號(hào))內(nèi)寫(xiě)出必要的步驟.

19.(本題滿分12分;第(1)小題滿分6分,第(2)小題滿分6分)

在直三棱柱A8C-A4G中,4BC=90°,AB=BC=\,BB]=2,求:

(1)異面直線與AC所成角的大小;

(2)直線與C1到平面的距離.

20.(本題滿分14分;第(1)小題滿分6分,第(2)小題滿分8分)

已知力)=曲412+4+2X),其中b是常數(shù).

(1)若y=/(x)是奇函數(shù),求6的值;

(2)求證:y=/(x)的圖像上不存在兩點(diǎn)A、B,使得直線AB平行于x軸.

21.(本題滿分14分;第(1)小題滿分7分,第(2)小題滿分7分)

如圖,制圖工程師要用兩個(gè)同中心的邊長(zhǎng)均為4的正方形合成一個(gè)八角形圖形.由對(duì)

稱性,圖中8個(gè)三角形都是全等的三角形,設(shè)44&修=a.

(1)試用a表示的面積;

(2)求八角形所覆蓋面積的最大值,并指出此時(shí)a的

大小.

22.(本題滿分16分;第1小題滿分4分,第2小題滿分6分,第3小題滿分6分)

2

已知點(diǎn)居、尸2為雙曲線C:??-%=10>0)的左、右焦點(diǎn),過(guò)此作垂直于X軸的

直線,在X軸上方交雙曲線C于點(diǎn)M,且/〃與尸2=30°.圓。的方程是,+>2=^2.

(1)求雙曲線C的方程;

(2)過(guò)雙曲線C上任意一點(diǎn)尸作該雙曲線兩條漸近線的垂線,垂足分別為P2,

求麗?麗的值;

(3)過(guò)圓。上任意一點(diǎn)0G0,打)作圓。的切線/交雙曲線C于4、B兩點(diǎn),A8中

點(diǎn)為M,求證:|而|=2|麗卜

23.(本題滿分18分;第(1)小題滿分4分,第(2)小題滿分6分,第(3)小題滿分8

分)

在等差數(shù)列{%}和等比數(shù)列也,}中,%=4=2,a2=b2=2+b,S.是也,}前〃項(xiàng)

和.

(1)若limS“=3—b,求實(shí)數(shù)b的值;

?—>00

(2)是否存在正整數(shù)〃,使得數(shù)列物,}的所有項(xiàng)都在數(shù)列產(chǎn)中?若存在,求出所有

的!!EMBEDEquation.3年占若不存在,說(shuō)明理由;

(3)是否存在正實(shí)數(shù)!!EMBEDEquation.DSMT4使得數(shù)列!!EMBED

Equation.DSMT451rL中至少有三項(xiàng)在數(shù)列!!EMBEDEquation.DSMT451rl■中,但!!EMBED

Equation.DSMT451rL中的項(xiàng)不都在數(shù)列!!EMBEDEquation.DSMT451rL中?若存在,求出一

個(gè)可能的!!EMBEDEquation.DSMT451rL的值,若不存在,請(qǐng)說(shuō)明理由.

2014屆高三年級(jí)八校聯(lián)合調(diào)研考試試卷

數(shù)學(xué)(理科)

一、填空題(本題滿分56分)本大題共有14題,要求在答題紙相應(yīng)題序的空格內(nèi)直接

填寫(xiě)結(jié)果,每個(gè)空格填對(duì)得4分,否則一律得零分:

題號(hào)?1?2?3?4?5?6?7??答案?!!EMBEDEquation.351r1*!*!!EMBEDEquation.DSMT4

號(hào)?1?2?3?4?5?6?7??答案?!!EMBEDEquation.3cli占1?!!EMBEDEquation.DSMT451r1*(-2,2)

?1?2?3?4?5?6?7??答案?!!EMBEDEquation.3Hr1*”!!EMBEDEquation.DSMT4卬4(-2,2)

1?2?3?4?5?6?7??答案?!!EMBEDEquation.351r1*!*!!EMBEDEquation.DSMT451rL*(-2,2)?3?!!

EMBEDEquation.3??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBEDEquation.DSMT4

年占!!EMBEDEquation.DSMT451r1*I!EMBEDEquation.DSMT4Tlr1*!!EMBEDEquation.3Yr1。!!

EMBEDEquation.DSMT451r1,!!EMBEDEquation.DSMT451rL?224??二.選擇題(本題滿分20

?2?3?4?5?6?7??答案?!!EMBEDEquation.351rL?:!?!!EMBEDEquation.DSMT451rLe(-2,2)?3?!!

EMBEDEquation.3小44??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBEDEquation.DSMT4

平占!!EMBEDEquation.DSMT4cli'!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.31產(chǎn)川!

EMBEDEquation.DSMT4Hr1*!!EMBEDEquation.DSMT45]rL*224**~.選擇題(本題滿分20

2?3?4?5?6?7??答案”!EMBEDEquation.351rL<1?!!EMBEDEquation.DSMT4(-2,2)?3?!!

EMBEDEquation.351rL*4??題號(hào)??答案?!!EMBEDEquation.DSMT4

?占!!EMBEDEquation.DSMT4cHrL*!!EMBEDEquation.DSMT4$占!!EMBEDEquation.37什?!!

EMBEDEquation.DSMT4EMBEDEquation.DSMT4(Hr1*224?*~.選擇題(本題滿分20

?3?4?5?6?7??答案?!!EMBEDEquation.351rL*1?!!EMBEDEquation.DSMT451r1*(-2,2)?3?!!

EMBEDEquation.3$44??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBEDEquation.DSMT4

工占!!EMBEDEquation.DSMT4cHrL*!!EMBEDEquation.DSMT49#?!!EMBEDEquation.3?#?!!

EMBEDEquation.DSMT4卬r1*!!EMBEDEquation.DSMT49rL?224??二.選擇題(本題滿分20

3?4?5?6?7??答案?!!EMBEDEquation.3卬41?!!EMBEDEquation.DSMT451rLe(-2,2)?3?!!

EMBEDEquation.3??題號(hào)??答案?!!EMBEDEquation.DSMT4

卬占!!EMBEDEquation.DSMTA^r1-*!!EMBEDEquation.DSMT4$占!!EMBEDEquation.3$#?!!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT451rL?224??二.選擇題(本題滿分20

?4?5?6?7??答案?!!EMBEDEquation.3341?!!EMBEDEquation.DSMT451r1*(-2,2)?3?!!

EMBEDEquation.3Yr1”??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBEDEquation.DSMT4

平占!!EMBEDEquation.DSMT4clir1*!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.31產(chǎn)川!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4If24??二.選擇題(本題滿分20

4?5?6?7??答案?!!EMBEDEquation.351r1*!*!!EMBEDEquation.DSMT451-2,2)*3*!!EMBED

Equation.311rL*4??題號(hào)?8?9?10?11?12?13?14??答案?!!EMBEDEquation.DSMT451占!!

EMBEDEquation.DSMT4Yr1。!!EMBEDEquation.DSMT451r1*"EMBEDEquation.351r1*!!EMBED

Equation.DSMT4cli4!!EMBEDEquation.DSMT4cl1rL*224??二.選擇題(本題滿分20分)本

?5?6?7??答案?!!EMBEDEquation.351rL?:!?!!EMBEDEquation.DSMT4Hr1*(-2,2)?3?!!EMBED

Equation.3』也??題號(hào)??答案?!!EMBEDEquation.DSMT4512

EMBEDEquation.DSMT4Yr1。!!EMBEDEquation.DSMT451r1*-EMBEDEquation.351r1*!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分20分)本

5?6?7??答案?!!EMBEDEquation.3EMBEDEquation.DSMT451r1*(-2,2)?3?!!EMBED

Equation.3?占4??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBEDEquation.DSMT4Yp1*!!

EMBEDEquation.DSMT4卬r1。!!EMBEDEquation.DSMT4EMBEDEquation.3r1*!!EMBED

Equation.DSMTM^r1*!!EMBEDEquation.DSMT4cl1rL*224"二.選擇題(本題滿分20分)本

?6?7??答案?!!EMBEDEquation.351rl?1?!!EMBEDEquation.DSMT451r1*(-2,2)?3?!!EMBED

Equation.351rL*4??題號(hào)?8?9?10?11?12?13?14??答案?!!EMBEDEquation.DSMT4小'!!

EMBEDEquation.DSMT4c11rLMEMBEDEquation.DSMT451r1*-EMBEDEquation.3clir1*!!EMBED

Equation.DSMT4514!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分20分)本

6?7??答案?!!EMBEDEquation.351-EMBEDEquation.DSMT4(4(-2,2)?3?!!EMBED

Equation.351rle4??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBEDEquation.DSMT451r1*!!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT49rL?!!EMBEDEquation.351r1*!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT451rL?224??二.選擇題(本題滿分20分)本

?7??答案?!!EMBEDEquation.351rL?:!?!!EMBEDEquation.DSMT451rLe(-2,2)?3.!!EMBED

Equation.3944??題號(hào)??答案?!!EMBEDEquation.DSMT4Yr1*!!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.351r1*!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分20分)本

7??答案?!!EMBEDEquation.351rL-:!?!!EMBEDEquation.DSMT451rLe(-2,2)?3?!!EMBED

Equation.3??題號(hào)??答案?!!EMBEDEquation.DSMT451*

EMBEDEquation.DSMT4r1,!!EMBEDEquation.DSMT4EMBEDEquation.3clir1*!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT451rL*224??二,選擇題(本題滿分20分)本

??答案?!!EMBEDEquation.351rL*1?!!EMBEDEquation.DSMT451rLe(-2,2)?3?!!EMBED

Equation.351rx*4??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBEDEquation.DSMT451r1*!!

EMBEDEquation.DSMT4c11rLMEMBEDEquation.DSMT451r1*-EMBEDEquation.3clir1*!!EMBED

Equation.DSMT4clir1*!!EMBEDEquation.DSMT4tl1rL?224??二.選擇題(本題滿分20分)本

?答案?!!EMBEDEquation.33占1?!!EMBEDEquation.DSMT4'Hr1*(-2,2)?3?!!EMBED

Equation.311rL*4??題一號(hào)?8?9?10?11?12?13?14??答案?!!EMBEDEquation.DSMT451占!!

EMBEDEquation.DSMT4Yr1。!!EMBEDEquation.DSMT451r1*"EMBEDEquation.351r1*!!EMBED

Equation.DSMT4cli4!!EMBEDEquation.DSMT4cl1rL*224??二.選擇題(本題滿分20分)本

答案?!!EMBEDEquation.3Hr1*!*!!EMBEDEquation.DSMT451-2,2)?3*!!EMBEDEquation.3

工占4??題號(hào)??答案?!!EMBEDEquation.DSMT4斗占!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.3m占!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分20分)本

案?!!EMBEDEquation.351rL*1?!!EMBEDEquation.DSMT451r1*(-2,2)?3?!!EMBEDEquation.3

卬占4??題號(hào)??答案?!!EMBEDEquation.DSMT4年—!!EMBED

Equation.DSMT4舟占口EMBEDEquation.DSMT451rL?!!EMBEDEquation.3卬4!!EMBED

Equation.DSMTM^r1*!!EMBEDEquation.DSMT4cl1rL*224"二.選擇題(本題滿分20分)本

?!!EMBEDEquation.3EMBEDEquation.DSMT451r1*(-2,2)?3?!!EMBEDEquation.3

51rx*4??題號(hào)答案?!!EMBEDEquation.DSMT451—!!EMBED

Equation.DSMT4$'!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.39人!!EMBED

Equation.DSMT4clir1*!!EMBEDEquation.DSMT4tl1rL?224??二.選擇題(本題滿分20分)本

!!EMBEDEquation.31rL?:!?!!EMBEDEquation.DSMT41rl?(-2,2)?3?!!EMBEDEquation.3

平占4??題號(hào)答案?!!EMBEDEquation.DSMT4小占!!EMBED

Equation.DSMT451rLEMBEDEquation.DSMT451r1,-EMBEDEquation.3印占!!EMBED

Equation.DSMT4cli4!!EMBEDEquation.DSMT4cl1rL*224??二.選擇題(本題滿分20分)本

Jl。!!EMBEDEquation.DSMT451rLe(-2,2)?3?!!EMBEDEquation.3??題號(hào)

1*!!EMBEDEquation.DSMT4Hr1*(-2,2)?3?!!EMBEDEquation,3$占4??題號(hào)

?!!EMBEDEquation.DSMT451r1,(-2,2)?3?!!EMBEDEquation.351rL*4??題號(hào)

!!EMBEDEquation.DSMT4$占(-2,2)?3?!!EMBEDEquation.311rl?4??題號(hào)

J(-2,2)?3?!!EMBEDEquation.3年44??題號(hào)??答案?!!EMBED

Equation.DSMT4514!!EMBEDEquation.DSMT4514!!EMBEDEquation.DSMT44r1*!!EMBED

Equation.3引'!!EMBEDEquation.DSMT4Yr1。!!EMBEDEquation.DSMT451rl'?224??二.選擇

(-2,2)?3?!!EMBEDEquation.3??題號(hào)?8?9?10?ll?12?13?14??答案?!!EMBED

Equation.DSMT451r1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4用r1*!!EMBED

Equation.351r1,!!EMBEDEquation.DSMT451r1,!!EMBEDEquation.DSMT451rl?224??二.選擇

-2,2)?3?!!EMBEDEquation.3UN”題號(hào)?8*9*10*ll*12*13*14?*答案?!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT4Hr1*!!EMBED

Equation.351r1*!!EMBEDEquation.DSMT4EMBEDEquation.DSMT474224??二.選擇

2,2)?3?!!EMBEDEquation.351rL*4??題號(hào)??答案?!!EMBED

Equation.DSMT4Hr1*!!EMBEDEquation.DSMT4小占!!EMBEDEquation.DSMT4年占“EMBED

Equation.351r1*!!EMBEDEquation.DSMT4?產(chǎn)?!!EMBEDEquation.DSMT471?224??二.選擇

,2)?3?!!EMBEDEquation.351rL*43題號(hào)?8*9*10*ll*12*13*14?*答案?!!EMBED

Equation.DSMT4Hr1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT44r1*!!EMBED

Equation.3Hr1*!!EMBEDEquation.DSMT4Hr1*!!EMBEDEquation.DSMT451rl?224??二.選擇

2),3,!!EMBEDEquation.3題號(hào)?8?9*10*ll*12?13*14?*答案?!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT47占!!EMBED

Equation.3年r1*!!EMBEDEquation.DSMT451r1,!!EMBEDEquation.DSMT47#?224??二.選擇

)?3?!!EMBEDEquation.3單題號(hào)?8*9*10*ll*12?13*14??答案?!!EMBED

Equation.DSMT4Hr1*!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.3c04!!EMBEDEquation.DSMT4Tlr1*!!EMBEDEquation.DSMT4?1?224??二.選擇

?3*!!EMBEDEquation.351rL*4??題號(hào)??答案?!!EMBEDEquation.DSMT4

?占!!EMBEDEquation.DSMT4cHrL*!!EMBEDEquation.DSMT4$占!!EMBEDEquation.37什?!!

EMBEDEquation.DSMT4EMBEDEquation.DSMT4(Hr1*224?*~.選擇題(本題滿分20

3.!!EMBEDEquation.3年44??題號(hào)?8?9?:10?ll?:12?13?14??答案?!!EMBEDEquation.DSMT4

Yr1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.3mr1。!!

EMBEDEquation.DSMT4(Hr1*!!EMBEDEquation.DSMT451rL?224??二.選擇題(本題滿分20

?I!EMBEDEquation.31rL*4??題號(hào)??答案?!!EMBEDEquation.DSMT4

平占!!EMBEDEquation.DSMT4cHrL?!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.3m產(chǎn)?!!

EMBEDEquation.DSMT4r1,!!EMBEDEquation.DSMT49rL?224??二.選擇題(本題滿分20

!!EMBEDEquation.3?占4??題號(hào)?8?9?10?11?12?13?14??答案?!!EMBEDEquation.DSMT4

514!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.351r1*!!

EMBEDEquation.DSMT45]r1-*!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分20

工?4??題號(hào)?8?9?10*ll?12?13*14?*答案?!!EMBEDEquation.DSMT451r1*!!EMBED

Equation.DSMT4$'!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.39人!!EMBED

Equation.DSMT4clir1*!!EMBEDEquation.DSMT4tl1rL?224??二.選擇題(本題滿分20分)本

4”題號(hào)?8?9?10?11?12?13*14??答案?!!EMBEDEquation.DSMT4年占"EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT4年產(chǎn)?!!EMBEDEquation.3Yr1*!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分20分)本

??題號(hào)答案?!!EMBEDEquation.DSMT4[4!!EMBED

Equation.DSMT4印占!!EMBEDEquation.DSMT4Hr1,-EMBEDEquation.3Yr1*!!EMBED

Equation.DSMT451r1*!!EMBEDEquation.DSMT4cl1rL?224??二.選擇題(本題滿分20分)本

?題號(hào)??答案?!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4

Yr1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.351rl?!!EMBEDEquation.DSMT4Yr1*!!

EMBEDEquation.DSMT451rL?224??二.選擇題(本題滿分20分)本大題共有4題,每題都

題一號(hào)??答案?!!EMBEDEquation.DSMT49占!!EMBEDEquation.DSMT4

卬占!!EMBEDEquation.DSMTA^r1-*!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT451r1*!!

EMBEDEquation.DSMT4c11rL?224??二.選擇題(本題滿分20分)本大題共有4題,每題都

號(hào)?8?9?10?11?12?13?14??答案?!!EMBEDEquation.DSMT451r1*-EMBEDEquation.DSMT4

51r1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT41'!!

EMBEDEquation.DSMT441?224??二.選擇題(本題滿分20分)本大題共有4題,每題都

??答案?!!EMBEDEquation.DSMT44占!!EMBEDEquation.DSMT4

EMBEDEquation.DSMT451r1*!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT451r1*!!

EMBEDEquation.DSMT451r1*224**Zl.選擇題(本題滿分20分)本大題共有4題,每題都

8?9?10?11?12?13?14??答案?!!EMBEDEquation.DSMT4$r1*!!EMBEDEquation.DSMT44占!!

EMBEDEquation.DSMT4(HrL?!!EMBEDEquation.3Hr1*!!EMBEDEquation.DSMT4年占!!EMBED

Equation.。51\/1丁4牛4224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

??答案?!!EMBEDEquation.DSMT4514!!EMBEDEquation.DSMT4Hr1*!!

EMBEDEquation.DSMT4r1,!!EMBEDEquation.351rLEMBEDEquation.DSMT4Tlr1*!!EMBED

Equation.DSMT4514224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

9?10?11.12?13?14??答案?!!EMBEDEquation.DSMT44r1*!!EMBEDEquation.DSMT41rL>!!

EMBEDEquation.DSMT451r1-*!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT4clir1*!!EMBED

Equation.DSMT451rL*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

?10?11?12?13?14??答案?!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT4午r1*!!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.351rL>!!EMBEDEquation.DSMT4clir1*!!EMBED

Equation.DSMT4年占224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

10?11?12?13?14??答案?!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT4卬r1。!!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.351r1*!!EMBEDEquation.DSMT4Pr1*!!EMBED

Equation.DSMT451rL?224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

0?11?12?13?14??答案?!!EMBEDEquation.DSMT4$占!!EMBEDEquation.DSMT4?#?!!

EMBEDEquation.DSMT4Yr1。!!EMBEDEquation.3$占!!EMBEDEquation.DSMT4小占!!EMBED

Equation.DSMT4514224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

?11?12?13?14??答案?!!EMBEDEquation.DSMT451rl?!!EMBEDEquation.DSMT4Hr1*!!EMBED

Equation.DSMT4與占!!EMBEDEquation.351r1*-EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451rl*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

11?12?13?14??答案?!!EMBEDEquation.DSMT4平白!!EMBEDEquation.DSMT4EMBED

Equation.DSMT494!!EMBEDEquation.311rLEMBEDEquation.DSMT4Hr1*!!EMBED

Equation.DSMT451—224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

1?12?13?14”答案?!!EMBEDEquation.DSMT4Hr1*!!EMBEDEquation.DSMT411rMEMBED

Equation.DSMT4*占!!EMBEDEquation.351r1*!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451rL*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

?12?13?14??答案?!!EMBEDEquation.DSMT49占!!EMBEDEquation.DSMT451rL?!!EMBED

Equation.DSMT451rLEMBEDEquation.3用占!!EMBEDEquation.DSMT4印占!!EMBED

Equation.DSMT4cli4224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

12?13?14??答案?!!EMBEDEquation.DSMT4111*!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451r1*!!EMBEDEquation.3$r1*!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT4CI1rL*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

2?13?14??答案?!!EMBEDEquation.DSMT451rMEMBEDEquation.DSMT4Hr1*!!EMBED

Equation.DSMT4$占!!EMBEDEquation.3印占!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451^224??-.選擇題(本題滿分20分)本大題共有4題,每題都給出四

?13?14??答案?!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT4Hr1*!!EMBED

Equation.DSMT4引占!!EMBEDEquation.351r1*!!EMBEDEquation.DSMT4中4!!EMBED

Equation.DSMT451rL*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

13?14??答案?!!EMBEDEquation.DSMT44以!!EMBEDEquation.DSMT4514!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.3*'!!EMBEDEquation.DSMT4514!!EMBED

Equation.DSMT451rL*224*?Zl.選擇題(本題滿分20分)本大題共有4題,每題都給出四

3?14??答案?!!EMBEDEquation.DSMT4Hr1*!!EMBEDEquation.DSMT4$占!!EMBED

Equation.DSMT451r1*!!EMBEDEquation.351r1*!!EMBEDEquation.DSMT4引占!!EMBED

Equation.DSMT4511?224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

?14??答案?!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT451rL?!!EMBED

Equation.DSMT4$占!!EMBEDEquation.3印占!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451rJ<224?*-.選擇題(本題滿分20分)本大題共有4題,每題都給出四

14??答案?!!EMBEDEquation.DSMT45]4!!EMBEDEquation.DSMT4引占!!EMBED

Equation.DSMT4與占!!EMBEDEquation.351rL?!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451rL*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

4??答案?!!EMBEDEquation.DSMT4Hr1*!!EMBEDEquation.DSMT47產(chǎn)?!!EMBED

Equation.DSMT4$'!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT49人!!EMBED

Equation.DSMT4年占224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

??答案?!!EMBEDEquation.DSMT4年占!!EMBEDEquation.DSMT4Yr1。!!EMBED

Equation.DSMT4Yr1*!!EMBEDEquation.351r1*!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451rL*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

?答案?!!EMBEDEquation.DSMT4514!!EMBEDEquation.DSMT451rL?!!EMBED

Equation.DSMT4印占!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT4Yr1*!!EMBED

Equation.DSMT451rL*224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四

答案?!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4

Yr1*!!EMBEDEquation.3叩r1*!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT4

51rL?224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有

案?!!EMBEDEquation.DSMT44內(nèi)!EMBEDEquation.DSMT4」'!!EMBEDEquation.DSMT4

卬r1e!!EMBEDEquation.3印占!!EMBEDEquation.DSMT4514!!EMBEDEquation.DSMT4

平4224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有

?!!EMBEDEquation.DSMT4EMBEDEquation.DSMT4'占!!EMBEDEquation.DSMT4

51rl■*!!EMBEDEquation.351rl?!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4

卬4224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有

!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT4Hr1*!!

EMBEDEquation.3小占!!EMBEDEquation.DSMT451rMEMBEDEquation.DSMT4$占224”

J!!EMBEDEquation.DSMT4叩r1*!!EMBEDEquation.DSMT4514!!EMBEDEquation.3Yr1>!!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT451rL?224??二.選擇題(本題》書(shū)分20

!!EMBEDEquation.DSMT4Yr1*!!EMBEDEquation.DSMT451r1*!!EMBEDEquation.3Yr1*!!

EMBEDEquation.DSMT451r1*!!EMBEDEquation.DSMT4$1?224??二.選擇題(本題滿分20

-1-*!!EMBEDEquation.DSMT4年占!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT4Yr1*!!

EMBEDEquation.DSMT45]選擇題(本題滿分20分)本大題共有4題,每題都

!!EMBEDEquation.DSMT451rl?!!EMBEDEquation.3Yr1*!!EMBEDEquation.DSMT4Pr1*!!

EMBEDEquation.DSMT451rL?224??二.選擇題(本題滿分20分)本大題共有4題,每題都

-1-*!!EMBEDEquation.3Hr1*!!EMBEDEquation.DSMT4印r1*!!EMBEDEquation.DSMT4

[#?224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有

!!EMBEDEquation.351r1*!!EMBEDEquation.DSMT4Tr1*!!EMBEDEquation.DSMT451rL-224??

,?!!EMBEDEquation.DSMT4Hr1*"EMBEDEquation.DSMT444224??二.選擇題(本題滿分

!!EMBEDEquation.DSMT4Tr1*!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分

■*■?!!EMBEDEquation.DSMT451rL*224??二.選擇題(本題滿分20分)本大題共有4題,每

!!EMBEDEquation.DSMT451rL?224??二.選擇題(本題滿分20分)本大題共有4題,每題

工?224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且

224??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只

24??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有

4??二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有

選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一

選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一

二.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有個(gè)

.選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)

選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論

選擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論

擇題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是

題(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正

(本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確

本題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,

題滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,

滿分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必

分20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須

20分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把

。分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答

分)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題

)本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有?個(gè)結(jié)論是正確的,必須把答題紙

本大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上

大題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上相

題共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上相應(yīng)

共有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上相應(yīng)題

有4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上相應(yīng)題序

4題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上相應(yīng)題序內(nèi)

題,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上相應(yīng)題序內(nèi)的

,每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙上相應(yīng)題序內(nèi)的正

每題都給出四個(gè)結(jié)論,其中有且只有一個(gè)結(jié)論是正確的,必須把答題紙

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