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文檔簡(jiǎn)介
x1(t)x2(t)aL[x1(t)]+y(t-C)=L[x(t-y(t)=x(t)*h(t)=
y(w)=H
¥x(w)¥H(w)
Y(s)=H(s)Xs=s+t0
h(t)0 y(n)=x(n)*h(n)=x(n-k)h(k)=x(k)h(n-k
¥¥
y(z)=x(z)H(z)z=e如果當(dāng)n<0時(shí), h(n)=0,那么該系統(tǒng)稱為因果系統(tǒng)。¥1t*f2¥
12t-tdtf1-*=
¥¥¥
f1f2tttfft-¥ ftt=ftftt-
=f1dt-t1¥tdt=dfttdt¥
¥ ¥=ftftdt-t1=ft-t1)
出為 y(t)=h(t)*x(t)= h(t)x(t-?:?:000 0¥0=h(t)E[X(t-0¥=h(t)m(t-
X(t)為平穩(wěn)SP =mX(t)*
mY=mX0
2h(u)X(t-20¥0=h(u)E[X(t1)X(t2-0¥=0h(u)RX(t1,t2-¥
00
h(u)RX(t-
RY(t1,t2)=E[Y(t1)Y(t2)]=h(t1)*h(t2)*RX(t1,t2RY(t1,t2)=E[Y(t1)Y(t2)]=h(t1)*h(t2)*RX(t1,t2 h(v)X(t2- ¥¥=00h(u)h(v)E[X(t1-u)X(t2-¥=00h(u)h(v)RX(t1-u,t2-=¥
Rt-u,t-
=X1-u,t2- 0=0Y1-u,t20
=¥X,t2-vdv=1*RXY,t2
ht2*1RY(t1,t2)=E[Y(t1)Y(t2)]=h(t1)*h(t2)*RX(t1,t2¥¥ X(tn)]*h(t1)*h(t2)**h(tn
小mt=
¥ ¥
XRY(t1,t2)=h(t1)*h(t2)*RX(t1,t2
cos20t t=10e- mt=Yt=E
XtY
¥Xt-¥0t0t+M=0mYt=50
hudu=5¥10e-10tdt=2X(t)是相關(guān)函數(shù)為2
N0
系統(tǒng)的沖激響應(yīng)為t=be-btUtb=t=tt
mt=Yt=E
XtY
¥Xt-¥¥=mX
¥RY=YtYtt¥=E=E
Xt-uu
hv
¥ XtXt¥=00
t+u-vdudv¥=¥
N
dt+u-vdudv¥ ¥¥¥=N¥¥
dt+u-vdvdu0=N0
¥t+udu=¥
¥be-bube-bt+udu 0N0=2
e-bt0
e-2bu
4由自相關(guān)函數(shù)的偶函數(shù)特性<0RY
N0b4
RY
N0b4
e-bQ=RY
N0b4¥RXY=RX)=¥
t-¥=N¥
dt-
,=2=
=N0t£
N02 =R=
N
dt- =N0, =2 NN0
R= 0e-0e-t沖激響應(yīng)為tbe-btUt
b,Dfbb RY=YtYtt¥=0
R
t+u-vdudv¥=¥b2e-bue-¥
¥N¥N bu
t+udv
t+u
¥ ¥
e-bt-e-bt2 R
e-bt-e-bt
bNb2
N0b
RY? X(t也是寬遍歷性的,且Y(tX(t)聯(lián)合遍歷)mXtmX ¥mY=mX0¥
= =0h(u)RX(t-
¥¥¥
RY(t1,t2)=0
Xt¥因?yàn)閅(t)=
Y(t+T)=0
輸出Y(t+T) 和Y(t)分別是輸入X(t+T) 和X(t)與h(t)的卷積,即可以表示成級(jí)數(shù)和的形式。由于隨機(jī)信號(hào)X(t)是嚴(yán)平穩(wěn)的,所以X(t)與X(t+T)具有相同的n維概率密度函數(shù),這樣Y(tT)與Y(t)也應(yīng)該具有相同的n也是寬遍歷性的,且Y(tX(t)聯(lián)合遍歷由X(t)X(t)=則輸出
Y(t)=lim1
TYTTfi¥ T¥=lim1[h(u)X(t-T¥Tfi¥ ¥=[lim1¥
X(t-T Tfi¥ T¥
X(tY(t)Y(t+t)=lim1
Y(t)Y(tTTfi¥ T¥¥=[lim1¥¥
T Tfi¥ T¥=0 X(t)Y(t+t)=lim1
X(t)Y(tTTfi¥ TT¥=lim1[h(u)X(t+t-T¥Tfi¥ ¥=[lim1¥
T Tfi¥ T¥=0RX(t-
mYt=mXtt)mYw=mXwHw¥mY=mX0h(t)dt=mXH(w)w=0=mXH¥SY(w)=SX(w)H(w)H(-w)=SX(w)H(w)SY(s)=SX(s)H(s)H(-Y=RXX=RX
SY(w)=SXY(w)H(-w)=SYX(w)H(w)SY(s)=SXY(s)H(-s)=SYX(s)HF(s)
f(t)e-stdt¥¥
¥¥s=s+f(tf(t)e-例3.
2X(t)是相關(guān)函數(shù)為2
N0
系統(tǒng)的沖激響應(yīng)為t=be-btUtb=t=tt
(1)0mY=mX¥0
w=0=mXH(0)=(2)2SYw=
wHw = 2b2+wRY
N0b4
e-b(3)Q=
N0b4(4) w= wHw= (
,
RYX=RXYt=N0t£ y(t)=0h(t)x(t- Y(n)=h(k)X(n-k ¥mY(n)=E[Y(n)]=h(k)E[X(n-k¥¥X(n)SP¥¥¥¥¥RXY(n,n+m)=E[X(n)Y(n+¥¥
XX
h(k)E[X(n)X(n+m-k¥
k
(nk=0+k RY(n,n+m)=E[Y(n)Y(n+ =E[(h(k)X(n-k))(h(j)X(n+m-¥ ¥=h(k)h(j)EX(n-k)X(n+m-k=0j¥=h(k)h(j)RX(n-k,n+m-¥k=0j¥RY=h(k)h(j)RX(m+k-¥k=0j¥
=h(k)h(j)RX(k-k=0j =m[h(k - k
z=1=H
SX(z)=H(z)S SX(SX(z)=H(z)S SX(z)=H(z-1z=eSYX(w)=H- X S(z)=H(z)H(z-1 (z)
S(w)=H(ejw)H(e-jw (w)=H(ejw
S2 2 =H(z-1 (z)=H RY(m)
S(z)zm-1dzYlY2R(m)=1 pH(ejw)S(w)ejmw 2p- EY2(n)= H(z)H(z-1 (z)z- 2pj 2EY2(n)=1 pH(ejw)S 2p- lz=HH-H- SY=SXHH =HH
SYw=Hw SY =H SYS,它的極點(diǎn)在Y-YSY)=S-+ Y-Y SYz)=S-zS+z =H- SY=S-+s YH=S-Yz=H-
SY=S-S+ YH=S-YSw
S
-25s2+
7-7+ s4
+ =sss-s+YS-Y
7+ss+YH=S-Y
7+ss+w4-
SYw=w
s4-s4-10s2+9
s-8+8- 8 ssssYS-Y-
s+8+ sss+8+ H=
ss=HH-=1
S= HHz H-=
H1
SX )S-+
S
XS-X
1XS-X
w=1.04+0.4cosw的白化濾波器SXw
1.04+e=e=
+e-jw+e-jw
z
z2 5z
z5+XS-X
X)XSXw
wSXw=w2+ww2+w2+
-s2+
3
+9
33+XS-X
33
XS-X
ss+S(w)=H2Yw)N02GY(w)
H(w)
wR(t)=N0
¥H¥
2jwt¥ 4p-¥
)
2
0h(u)h(u¥¥2p
H(w) )KDw)KDwe
H
DweY2t=N0
¥w2dw¥
2
NKYt=0 Kdw= Dwe
2¥0¥
H(w)max=H
ww
Dwe
H
H2¥0¥
Dwe
2
H-2jH)-
2t=N0¥2p¥
H2
(實(shí)際系統(tǒng)P=N0
(理想系統(tǒng) 和H(w) w
由Hw=
知H
w)=
+w
Hw
=Dwe
Hw
w2¥0¥
w¥=0
+w2
=barctanb =2 =Dwe= 2p
Hwb2b2+wb2+w2=2
Df=b例3.11計(jì)算低通濾波器Hw=2-w,w0 由Hw=2-w
Hw2=2-w,Hw)
=Dwe
Hw
Hw2¥0¥1=41
2-w2w=¥3¥ =Dwe= 2p
Hw2=(2-w(2Dw)22
Hw 22
Df=222H(w)= 0 A
GX(w)=
2
wH(w)= 0 A N0
GY(w)
GX(w)=
設(shè)設(shè)GX(w)=
H(w)= 0R(t)=
¥G(w)
1 1
Dw/2N02p2
coswdw2
Dwt
sinDwt
=N0ADw 設(shè)GX(w)=設(shè)
2
H(w)= 0GX(w)=
A0N0=
wH(w)= 0 A
KYKY
2
sinDwt= Dwt2
w GX(w)=H(w)=AsinDwt
¥t=r(t)dt
¥ dt=p=
Dwt2
Dww設(shè)設(shè)GX(w)=
¥x¥
dx=2
a>
H(w)=w–w0£Dw/2A
w–w0£Dw/2GX(w)=
0 0 N
w-
G(w)=H G(w)= R(t)=1 ¥G(w) = w0+Dw/2A2 cosww2p0-Dw/2 A2NDwsin(Dwt/= Dwt/2A2NDwsin(Dwt/ Dwt/2與a(tcosw0t相比,a(tcosw0t是
E[Y2(t)]
N00sinDwt
r(t)
KY
= coswt K R
Dwt 2sinDwtt=¥ dt=p=
Dwt2
DwE[Y2(t)]
N00sinDwt
r(t)
KY
= coswt K R
Dwt 2sinDwtt=¥ dt=p=
Dwt2
Dw
+exp
(w)= N 2
SX(w) Aexp
b2
b2
+exp
(w)= ¥
0+exp(w+w)20+exp
R(t)0A2exp0R(t)0A2exp0
b2
b2 e
+exp-
4p-¥
b2
b2 0N0=
¥¥
-2 w2e-2b b0
4
+exp
(w)=
+exp
(w)=
R(0)=A2N0
+exp
(w)= H(w)2
-2Dwe= dw=pb-22b2
H(w0 ¥-b t0=0
dt=難 nY(t)= nfi隨)隨)
w
2 0d 22解:2()()(
SX
wH
2b2+wR=1 wejwtdw YY2t=R)Y
N0b4
Yt=f
2y20 =pNbexp-Nb0
Xi為 量,它是 的
Dti?
nn
ty>>ty>>
即ty 設(shè)有一個(gè)實(shí)值函數(shù)x(t),它 ?(t(H[x(tx(t)=?(t)
p-¥t- =p-
ttdt h(t)=1? (jw)=-jsgn(w)=
f(t)?Fjw)F(jt)?2pf(-w)因?yàn)閟gn(t)
jw
2?2psgn(-w)=-2p
hH(t)=p
?HH(jw)=-j[x(t)=H-1 ?(t[ =-p-
?
?(t (t)=-
?(t)hH1(t)x(t)=?(t)*hH1(t)=x(t)*hH(t)*
?(thH1(t)x(t)=?(t)*hH1(t)=x(t)*hH(t)* HH(jw)HH1(jw) HH1(jw)
HH(
=
(t)=-
?(t) h(t)=1/
H(w) |H(w)| H(w) H(w)=
H(w)=
= w£w0>
tsw0tHt=-a(t)cosw0t 令t=a(t)cos=pw++dw- =1w+w+w-w =-w=-jw-w-w+w t=
t0
-t-jw0t=-
t2jsinw
=tnw 令1t=a(tsins=1*pw+w-dw-w s=jw+w-w-w 11=1-jsgnw1=-2w-w0+w+w0
1tejw
t-=tcos1=- 12 定義:給定任一實(shí)隨機(jī)過(guò)程X定義一復(fù)隨機(jī)過(guò)程%(t)%(t)j??(t)=H[X(t)]= ¥Xp-¥t-
是X(t) (1)X(t?
?(t)=X(t)* (w)= (w)H(w) =SX(w)22?XH( X(t? (3)R
R?(t)=?X ?代入?(tp¥X(h)dht-h令t-h p¥ p¥l (3)R
R?(t)=?X p¥l=1p1p¥Xt)1l=¥l=R?X X(t? (3)R
R?(t)=?XX (-t)=E[?(t)X(t-t)]=Ep¥ ¥p1Xll=p¥l=1p¥l=X=-R 3.5.2R?(-t)=-R? (5)RX?X(-t)=-RX?X
%jRj?XX[%%(tXXj?j?[RX=2[RX(t)+jRX? R R()=2[R()+
(w)=-jSX 證明:由性質(zhì)3,證明:由性質(zhì)3, (t)=R(t)*hXXH兩邊取付氏變換得SX?(w)jsgn(w)SX(w)S(w)=-jSX X
352352 證明:由性質(zhì) %X?S%jSX?=2[SX(w)+sgn(w)SX4SX(w)0 (w)=4SX 例3.14設(shè)平穩(wěn)隨機(jī)過(guò)程X(t)的功率譜密度為SX?t是X(t) 變換,求Vt=Xtt+?tst,t+t=VtVtt=Xtt+?tsw0t·Xt+tsinw0t+t+?ttcosttXtXt+t0t+?t?ttstcosw0t?tXt+tsw0tsinw0t+Xt?ttnw0tcosw0tXtXt+t0t+?t?ttstcosw0t?tXt+tsw0tsinw0t+Xt?ttnw0tcosw0t
in0tsinw0t+t+
sw0tR
sw0tsinw0t+t+R
nw0t=RXt-RXX?pw+dwsinw0t?pw+w0-dw-w0SV=SXpw+w+dw- -1 *pw+w-dw- 2pX? =1Sw+w+ w j w+w-
w-w
X? = *
?=-jSX?
ptXX S=1
w+w+ w
-sgnw
w
+sgnw
w-w0=1 w-sgnw +1 w-w+w- 例3.15設(shè)平穩(wěn)隨機(jī)過(guò)程X(t)的功率譜密度為SX?t是X(t) 變換,求Vt=Xtt-?tst,tt=VtVtt=Xtt-?tsw0t·Xt+tsinw0t+t-?ttcosttXtXt+t0t+?t?ttstcosw0t?tXt+tsw0tsinw0tXt?ttnw0tcosw0tXtXt+t0t+?t?ttstcosw0t?tXt+tsw0tsinw0tXt?ttnw0tcosw0t
0tsinw0t+t+
sw0t-R?X
st+t-
nw0t=RXt+RX?pw+dwsinw0t?pw+w0-dw-w0SV=SXpw+w+dw- +1 *pw+w-dw- 2pX? =1Sw+w+ w +j w+w-
w-w
X? = *
?=-jSX?
ptXX S=1
w+w+ w
-sgnw
w
+sgnw
w-w0=1 w+w+w+ +1 w-sgnw h(t)=1? (jw)=-jsgn(w)=
f(t)?Fjw)F(jt)?2pf(-w)因?yàn)閟gn(t)
jw
2?2psgn(-w)=-2p
hH(t)=p
?HH(jw)=-j定義:給定任一實(shí)隨機(jī)過(guò)程X定義一復(fù)隨機(jī)過(guò)程t%(t)j??(t)=H[X(t)]= ¥Xp-¥t-
是X(t) 3.5.2X(t? (3)R
R?(t)=?XX (5)RX?X(-t)=-RX?X
%jRj?X
(w)=-jSX
(w)=4SX
x(t) (w) w-w£w£w+w (w)= wcw0)SXSXt3.6X(t)=a(t)cosw0t-b(t)sinw0tXX(t)=a(t)cosw0t-b(t)sinw0ta(a(t)=X(t)cosw0t+?(t)sinb(t)=-X(t)sinw0t+?(t)
?(t)=a(t)sinw0t+b(t)
3.6將X(t)表示成解析形式tX(t? 同時(shí)又 jw0tXt+?wt- =Xtcosw0t+?tnw0t+-Xtnw0t+?tcosw0t] t=tcosw0t?tnt=tn?tcosw0t~Xt-jw0t=t+~t=at+~~
t=t+jb(t)cosw=atcosw0t-b(t)sinw0t+tnw0t+b(t)cosw0tXt=atcosw0t-b(t)sinw0t3.6 b(t)E[a(t)]=E[b(t)]=
X(t)為平穩(wěn)過(guò)程,且假設(shè)其均值為0 ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3 b(t)證明:因?yàn)閄(t)和?(t)都是實(shí)過(guò)程。 a(t)=X(t)cosw0t+?(t)sinb(t)=-X(t)sinw0t+?(t)所以 b(t)都是實(shí)隨機(jī)過(guò)3.63.6.3
b(t)E[a(t)]=E[b(t)]= ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3E[a(t)]=E[b(t)]=E[X(t)]= E[?(t)]=E[a(t)]=E[X(t)]cosw0t+E[?(t)]sinw0t=3.63.6.3
b(t)E[a(t)]=E[b(t)]= ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3 Ra(t)E[a(t)a(t+t)]??=RX(t)cosw0tcosw0(t+t)+RXX?(t)cosw0tsinw0(t+RX?X(t)sinw0tcosw0(t+t)+RX?(t)sinw0tsinw0(t因?yàn)椋?/p>
E[a2(t)]=Ra(0)=RX(0)<¥3.63.6.3 b(t)E[a(t)]=E[b(t)]= ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3證明:由性質(zhì)3t3.63.6.3 b(t)E[a(t)]=E[b(t)]= ?X
Sa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3?X
=E[{X(t)cosw0t+?(t)sin?R?X
(t)sinw0tsinw0(t+t)+RXX?(t)cosw0tcosw0(tR(t)=R ?X
3.63.6.3 b(t)E[a(t)]=E[b(t)]= ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3證明:由性質(zhì)3.63.6.3
b(t)E[a(t)]=E[b(t)]= ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3X
=E[{a(t)cosw0t-b(t)sinw0t}?{a(t+t)cosw0(t+t)-b(t+t)sinw0(t=Ra(t)cosw0tcosw0(t+t)-Rba(t)sinw0tcosw0(t-Rab(t)cosw0tsinw0(t+t)+Rb(t)sinw0tsinw0(t 3.63.6.3
b(t)E[a(t)]=E[b(t)]= ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3Sa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0 1Rew+e-iw
ew-e-iwt 2
SX?(w)=-jsgn(w)SX
3.63.6.3Sa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0S(w)=1S(w-w)+ +1-jsgn(w-w 2 =1 +1-sgn(w-w SS[SX(w+w0)+SX(w-w03.63.6.3Sa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0 0 2 0 2 23.63.6.3 b(t)E[a(t)]=E[b(t)]= ?XSa(w)=Sb(w)= SS[SX(w+w0)+SX(w-w0Sab(w)=- SS[SX(w+w0)-SX(w-w03.63.6.3Sab(w)=- SS[SX(w+w0)-SX(w-w0?X =-1Rew-e-iwt
ew+e-iwt2
S?(w)=-jsgn(w)SX(w)
3.6Sab(w)=- SS[SX(w+w0)-SX(w-w0 (w)=-1 (w-w)- (w+w 2 +1-jsgn(w-w
)SX(w+w0=-j{-1
(w+w0+1sgn(w-w
)SX(w+w0=- SS[SX(w+w0)-SX(w-w03.6Sab(w)=- SS[SX(w+w0)-SX(w-w0ttcosw0ttnff和Sabf): f0= f0=
=1f+f解:
S=1 pw+w+dw- 2p +1 *pw+w-dw- 2pX? =1Sw+w+ w +j w+w-
w-w
X? = *
?=-j
X?
ptXXS=1
w+w+ w
-sgnw
w
+sgnw
S
w =1 w+w+w+ +1
w
-w ?X =-1 *pw+w-dw- 2p +1 pw+w+dw- 2pX? =-jSw+w- w +1
w+w+
w-w
X
X? 由于S
=-j
=-jSw+w- w -sgnw
w
-sgnw
S
w =1Sw+w- w +1w+w
w
+w
S
w =1 w+w+w+ -1 w-sgnw 例3.17設(shè)平穩(wěn)隨機(jī)過(guò)程Xt=twt+q-twt+q) p解 RX=ttt=twt+q-twt+qt+tw0t+t+q-t+tw0tt+qwt+qw0t+t+q+wt+qnw0tt+qwt+qnw0t+t+q+wt+qw0tt+q=Rnw-Rnwt+w0t+q=RnwRX=nw w=1Sw+w+Sw-w 3.6X(t)=A(t)cos[w0t+f(t)]
~t-
t+
t+Atejfttt+~
t=t)a(t))Xt-jw0t=tejft)~t=tejfteAt[cosw0t+jt+w0t+jtt=twt+3.6X(t)=A(t)cos[w0t+f(t)] X(t)=A(t)cos[w0t+f(t)]=A(t)cosw0tcosf(t)-A(t)sinw0tsina(t)=A(t) b(t)=A(t)sinX(t)=a(t)cosw0t-b(t)sinw0t
A(t)=a2(t)+b2f(t)=arctg工程上應(yīng)用最多的窄帶隨機(jī)過(guò)程是窄帶過(guò)程,因?yàn)椴粌H熱噪聲是過(guò)程,很多寬帶噪聲通過(guò)窄帶系統(tǒng)后也成為窄帶過(guò)程。因此,重點(diǎn)討論窄帶過(guò)程是很有必要的,當(dāng)中放定理:當(dāng)X(t為窄帶隨機(jī)過(guò)程,即X(tDww0,A(t)和f(t) b(t)是低頻限帶隨機(jī)過(guò)程即它們的功率譜只在0£w£wc wcw0 E{[a(t+t)-a(t)]2}=E[a2(t+t)+a2(t)-2a(t)a(t=2Ra(0)-2Ra
=1wc
wc wc
jwt
p-wc Sa(w)dw-
Sa dw]
1
cc
Sac= S(w)(1-e cp-
aaSa(w)(1-
2 2 p p-
S(w)2sin
wt2
E{[a(t+t)-a(t)]}£wctRa(0)=wctE[aa a
S(w)2(wt )p- w此式說(shuō)明:若t1,在tt+ta(t)wca(t)因?yàn)閣
,即T2pT
,令t t=T<< wt=w
由 不等式:P{x-E(x)
令xa(t+T0a(t),注意E(x)E[a(t+T0E[a(t
P{[a(t+T0)-a(t)]-
E{[a(t+T0)-
w2T2E[a2 P{a(t+T0)-
足夠小時(shí),對(duì)于給定的e>右式趨近于0x(t為窄帶隨機(jī)過(guò)程時(shí),在一個(gè)高頻周期T0內(nèi),a(t)的變化大于e的概率趨于0。也就是說(shuō),a(t t X(t)=a(t)cosw0t-b(t)sinw0t
a(t)=A(t)b(t)=令t固定,
tb= t
3.6節(jié)性質(zhì)
fab(at,bt)=fa(at)fb(bt
+b2 t A2 exp- J=
= =
A2
A exp-
A?0,0£f£22
0
A2 A2= exp- 2p=texp-
¥s¥
ff (A,f)dA=
0£
(A,f)=f(f)f(f Xt=twt-twt=twt+ A
fAt=texp- ¥
A2t=
AtfAtt
texp- 0s
A2
=-Ad
=2ps
AtA
=
=ps 2
A2fA
A2¥ =¥
t
exp- 02 2
A2
=-A2d
AA
t=¥2At
=¥ AAt AAt
2s ¥
2s2 0 0s =2-E2A=2s
2 X(t)=A(t)cos[w0t
A2
u=
= texp(- ),At? At=h(ut)=+
At?f
)=
h(u
exp(-
exp(-ut t t
fA,At,At
f,f
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