實(shí)驗(yàn)三-回歸分析

1歡迎下載精品文檔4453621798yyt函數(shù)回歸模型；②在同一坐標(biāo)系內(nèi)做出原始數(shù)據(jù)與擬合結(jié)t=1:15;y=[3522111971601421061046056383632211915];rstool(t',y','purequadratic')rmse=22.2649Y=polyconf(p,t,y);plot(t,y,'k+',t,Y,'r')2歡迎下載精品文檔350-十300-200-(.亠十4+廿十丄十丄十丄十丄十------J------------------------------------[0510+4十++:(3)當(dāng)t=16時(shí)，計(jì)算程序如下：[p,s]=polyfit(t,y,2);Y=polyconf(p,16);⑷用二次函數(shù)計(jì)算出細(xì)菌殘留數(shù)為39.0396，顯然與實(shí)際不相符合。根據(jù)因(5)由⑵散點(diǎn)圖可知，可以假設(shè)將要擬合的的非線性模型為y=aeb/t對將要functionyhat=volum(beta,t)yhat=beta(1)*exp(beta(2).*t);%輸入數(shù)據(jù)t=1:15;y=[3522111971601421061046056383632211915];beta0=[150,0]';淋回歸系數(shù)[beta,r,J]=nlinfit(t',y','volum',beta0);tay=nlpredci('volum',16,beta,r,J)y=11.1014，很顯然這樣的結(jié)果會(huì)更令人滿意！3歡迎下載精品文檔2.某銷售公司將庫存的費(fèi)用、員工薪酬以及銷售額等方面的數(shù)據(jù)作了匯總(表2),該公司試圖根據(jù)這些數(shù)據(jù)找到銷售額與其他變量之間的關(guān)系，以便進(jìn)行銷售額售額的庫存資金額、廣告投入、員庫存資金額、廣告投入、員工薪酬月份------庫存資金額(X1)--------廣告投入(X2)-------員工薪酬總額(X3)--------銷售額(y)123456789解：首先，作出因變量與各自變量的樣本散點(diǎn)圖，如圖3所示，程序如下:x1=[75.277.680.776.079.581.867.798.374.0151.090.8102.3115.6125.0137.8175.6155.2174.3];x2=[30.631.365.4];33.929.632.527.924.823.633.927.745.542.640.045.851.767.265.0x3=[21.121.426.8];22.921.421.521.721.521.022.424.723.224.323.129.124.627.526.5y=[1090.41133.01242.11003.21283.21012.21098.8826.31003.31554.61199.01483.11407.11551.31601.22311.72126.72256.5];subplot(1,3,1),plot(x1,y,'g*');subplot(1,3,2),plot(x2,y,'k+');subplot(1,3,3),plot(x3,y,'ro');2400_________”________c2400_________”_______c2400i■'■*4歡迎下載800200800800￡800200800800￡-20t0擊擊-2200--2000-1800*辛1600十++-1400o袒;*■1000-16002200200020002200?>-十■-----00250025較好的線性關(guān)系，X1=[75.277.680.776.079.581.867.798.374.0151.090.8102.3115.6125.0137.8175.6155.2174.3];X2=[30.631.365.4];X3=[21.121.426.8];33.929.632.527.924.823.622.921.421.521.721.521.033.927.745.542.640.045.851.767.265.022.424.723.224.323.129.124.627.526.5y=[1090.41133.01242.11003.21283.21012.21098.8826.31003.31554.61199.01483.11407.11551.31601.22311.72126.72256.5];n=18;m=3;x=[ones(n,1),x1',x2',x3'];[b,bint,r,rint,s]=regress(y',x,0.05);b,bint,r,rint,s精品文檔5歡迎下載903.4].9，64.1]殘差列向量r=[44.039459.326496.5750-35.3239179.3461-36.41161521-184.560067.5082-33.4048-89.1104-[-75.9312,434.6233]、[-313.1813,240.3581][-69.6357,430.0762]、[-449.7576,-38.9240][-428.0384,58.9185]、[-208.3399,343.3563][-312.3682,245.5587]、[-199.0870,20.8662][-172.6973,312.1875][-172.6973,312.1875]7547]、額為27萬葛洲壩機(jī)組發(fā)電耗水率的主要6歡迎下載精品文檔 2005-10-15:002005-10-15:022005-10-15:042005-10-15:062005-10-15:082005-10-15:1005-10-15:1205-10-15:142005-10-15:1605-10-15:1805-10-15:202005-10-15:222005-10-16:0005-10-16:0205-10-16:042005-10-16:06庫水位(米x1=[65.0865.1065.1265.1765.2165.3765.3865.3965.4065.4365.4765.5365.6265.5865.7065.84];x2=[156071556515540155071543215619155361551415519155101548915437163551470814393y=[60.4660.2860.1059.7859.4459.2558.9158.7658.7358.6358.4858.3157.9657.0656.4355.83];subplot(1,2,1),plot(x1,y,'g*');subplot(1,2,2),plot(x2,y,'k+');L5\5L5\十七_(dá)士七_(dá)+9.59.5--+■8.58.58.58.57.57.57.57.5--+--6.56.5r6.56.5--十5.555.5rx1047歡迎下載精品文檔出機(jī)組發(fā)電耗水率y與庫水位捲有較好的線性關(guān)系，而與出庫2211,k<mx=[x1',x2'];rstool(x,y,'interaction'，0.05)%包含線性項(xiàng)和完全二次項(xiàng)(交叉)結(jié)果得到交互式化面，如圖5所示beta850.0611-0.0009