




版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進(jìn)行舉報或認(rèn)領(lǐng)
文檔簡介
CHAPTER-6
SamplingerrorandconfidenceintervalsCHAPTER-6
SamplingerrorandcpopulationsamplestatisticParametererrorpopulationsamplestatisticParamSection1samplingerrorofmeanSection2tdistributionSection3confidenceintervalsforthepopulationmeanSection1samplingerrorofSection1
samplingerrorofmean
Section1
samplingerroroAsimplerandomsampleisasampleofsizendrawnfromapopulationofsizeNinsuchawaythateverypossiblerandomsamplesnhasthesameprobabilityofbeingselected.Variabilityamongthesimplerandomsamplesdrawnfromthesamepopulationiscalledsamplingvariability,andtheprobabilitydistributionthatcharacterizessomeaspectofthesamplingvariability,usuallythemeanbutnotalways,iscalledasamplingdistribution.Thesesamplingdistributionsallowustomakeobjectivestatementsaboutpopulationparameterswithoutmeasuringeveryobjectinthepopulation.Asimplerandomsampleisa[Example1]ThepopulationmeanofDBPintheChineseadultmenis72mmHgwithstandarddeviation5mmHg.10adultparticipantswaschosenrandomlyfromtheChineseadultmen,herewecancalculatethesamplemeanandsamplestandarddeviation.Supposingsampling100times,what’stheresult?[Example1]linkageNlinkageNIfrandomsamplesarerepeatedlydrawnfromapopulationwithameanμandstandarddeviationσ,wecanfind:1thesamplemeansaredifferentfromtheothers2Thesamplemeanarenotnecessaryequaltopopulationmeanμ3ThedistributionofsamplemeanissymmetricaboutμHOWTOEXPLORETHESAMPLINGDISTRIBUTIONFORTHEMEAN?IfrandomsamplesarerepeaThedifferencebetweensamplestatisticsandpopulationparameterorthedifferenceamongsamplestatisticsarecalledsamplingerror.ThedifferencebetweensamplInreallifewesampleonlyonce,butwerealizethatoursamplecomesfromatheoreticalsamplingdistributionofallpossiblesamplesofaparticularsize.Thesamplingdistributionconceptprovidesalinkbetweensamplingvariabilityandprobability.Choosingarandomsampleisachanceoperationandgeneratingthesamplingdistributionconsistsofmanyrepetitionsofthischanceoperation.InreallifewesampleonlyonWhensamplingfromanormallydistributedpopulationwithmeanμ,thedistributionofthesamplemeanwillbenormalwithmeanμCentrallimitTheoremWhensamplingfromanormally
=50
=10XPopulationdistributionn=4SamplingdistributionXn=16=50=10XPopulationdistriWhensamplingfromanonnormallydistributedpopulationwithmeanμ,thedistributionofthesamplemeanwillbeapproximatelynormalwithmeanμaslongasnislargerenough(n>50).CentrallimitTheoremWhensamplingfromanonnormalXXStandarderror(SE)canbeusedtoassesssamplingerrorofmean.Althoughsamplingerrorisinevitable,itcanbecalculatedaccurately.Standarderror(SE)canbetheoreticalvalueofSEestimationofSECalculationofstandarderror(SE)s↑→SE↑n↑→SE↓linkagetheoreticalvalueofSEestimatExample5.2Oneanalystchoserandomlyasample(n=100)andmeasuredtheirweightswithameanof72kgandstandarddeviationof15kg.Question:whatisthestandarderror?Example5.2Solution:Solution:
Exercise5.1Considerasampleofmeasurement100withmean121cmandstandarddeviation7cmdrawnfromanormalpopulation.Trytocomputeitsstandarderror.Exercise5.1Solution:Solution:Section2
tdistributionSection2
tdistribution1.Definition
N(μ,
2)N(0,1)1.DefinitionN(μ,2)N(0,RandomsamplingRandomsamplingUsuallystandarddeviationσisunknown,sowecanonlygets,thenwecancalculateUsuallystandarddeviationσiThissamplingdistributionwasdevelopedbyW.SGossettandpublishedunderthepseudonym“student”in1908.itis,therefore,sometimescalledthe“student’stdistributionandisreallyafamilyofdistributionsdependentonthen-1.Thissamplingdistribution
=n-1Zdistributiontdistribution=n-1Zdistributiontdistribu2.thecharacteristicsoftdistributiongraphFIG4thegraphoftdistributionwithdifferentdegreesoffreedom2.thecharacteristicsoftdi1symmetricabout0;2theshapeoftcurveisdeterminedbydegreeoffreedom,df=n-1.3t-distributionisapproximatedtostandardnormaldistributionwhennisinfinite.
1symmetricabout0;總體特征抽樣調(diào)查的設(shè)計與分析課件tcriticalvaluewithone-sidedprobability→t(α,
)tcriticalvaluewithtwo-sidedprobability→t(α/2,
)tcriticalvaluewithone-sideExample5.2Withn=15,findt0suchthatP(-t0≤t≤
t0)=0.90Example5.2Withn=15,findsolutionFromtvaluetable,df=15-1=14,thetwo-tailedshadedareaequals0.10,so
-t0=-1.761and
t0=1.761solutionFromtvaluetablSection3confidenceintervalsforthepopulationmeanSection3StatisticalmethodsdescriptivestatisticsinferentialstatisticsparameterestimationhypothesistestIntervalsestimationPointestimationStatisticalmethodsdescriptive1.Basicconcepts
Parameterestimation:Deducethepopulationparameterbasingonthesamplestatistics1.BasicconceptsPointEstimateAsingle-valuedestimate.Asingleelementchosenfromasamplingdistribution.Conveyslittleinformationabouttheactualvalueofthepopulationparameterabouttheaccuracyoftheestimate.PointEstimateConfidenceIntervalorIntervalEstimationAnintervalorrangeofvaluesbelievedtoincludetheunknownpopulationparameter.ConfidenceIntervalorIntervaPointestimationLowerlimitUpperlimitIntervalsestimationPointestimationLowerlimitUpp1-aa/2a/21-aa/2a/2
2.MethodsZdistribution1.σ
isknown2.σ
isunknown,n>50
tdistributionσ
isunknown,n≤50CICI2.MethodsZdistribution1.σExample5.3
Ahorticulturalscientistisdevelopinganewvarietyofapple.Oneoftheimportanttraits,inadditiontotaste,color,andstorability,istheuniformityofthefruitsize.Toestimatetheweightshesamples100maturefruitandcalculatesasamplemeanof220gandstandarddeviation5gDevelop95%confidenceintervalsforthepopulationmeanμfromhersampleExample5.3solution95%confidenceintervalsforthepopulationmeanisbetween219.02and220.98gsolution95%confidenceinteExerciseAforesterisinterestedinestimatingtheaveragenumberof‘counttrees’peracre.Arandomsampleofn=64oneacreisselectedandexamined.Theaverage(mean)numberofcounttreesperacreisfoundtobe27.3,withastandarddeviationof12.1.Usethisinformationtoconstruct95%confidenceintervalforμ.Exercisesolution95%confidenceintervalsforthepopulationmeanisbetween24.36and30.24solution95%confidenceinteTheforesteris95%confidentthatthepopulationmeanfor“counttrees”peracreisbetween24.36and30.24Theforesteris95%confidenExample5.4Theecologistsamples25plantsandmeasurestheirheights.Hefindsthatthesamplehasameanof15cmandasampledeviationof4cm.whatisthe95%confidenceintervalforthepopulationmeanμExample5.4solutiondf=25-1=24solutiondf=25-1=24Theplantecologistis95%confidentthatthepopulationmeanforheightsoftheseplantsisbetween13.349and16.65
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 第十二課 轉(zhuǎn)動的風(fēng)車-齒輪傳動 教學(xué)設(shè)計 -2023-2024學(xué)年大連版(2015)初中信息技術(shù)七年級下冊
- 建筑裝飾理論??荚囶}與參考答案
- 第4課《燈籠》 教學(xué)設(shè)計2024-2025學(xué)年統(tǒng)編版語文八年級上冊
- 高中信息技術(shù)粵教版必修教學(xué)設(shè)計 -6.3.3 活動過程
- 第18課 辛亥革命 教學(xué)設(shè)計-2023-2024學(xué)年高一上學(xué)期統(tǒng)編版(2019)必修中外歷史綱要上
- 2025年中成藥制藥生產(chǎn)線項目發(fā)展計劃
- 2025年湖北生態(tài)工程職業(yè)技術(shù)學(xué)院單招職業(yè)適應(yīng)性測試題庫及答案一套
- 2025年造紙完成工段智能裝備項目發(fā)展計劃
- 2025年河南應(yīng)用技術(shù)職業(yè)學(xué)院單招職業(yè)傾向性測試題庫匯編
- 2025至2030年中國棉帆布輸送帶數(shù)據(jù)監(jiān)測研究報告
- 空調(diào)維保服務(wù)項目質(zhì)量保障措施
- 《馬克思主義與社會科學(xué)方法論》課后思考題答案全
- 急性心肌梗塞
- 八年級地理下期教學(xué)計劃(星球地圖版)
- 藍(lán)色科技風(fēng)半導(dǎo)體產(chǎn)業(yè)PPT模板
- 院感手衛(wèi)生培訓(xùn)課件
- 鑄牢中華民族共同體意識學(xué)習(xí)PPT
- 多重耐藥鮑曼不動桿菌治療課件
- 物理光學(xué)-第二章-光波的疊加與分析-課件
- PID圖(工藝儀表流程圖)基礎(chǔ)知識培訓(xùn)課件
- 《澳大利亞特有動物》課件
評論
0/150
提交評論