新高考數(shù)學(xué)一輪復(fù)習(xí)講義 第14講 導(dǎo)數(shù)的概念及其意義、導(dǎo)數(shù)的運(yùn)算(原卷版)_第1頁
新高考數(shù)學(xué)一輪復(fù)習(xí)講義 第14講 導(dǎo)數(shù)的概念及其意義、導(dǎo)數(shù)的運(yùn)算(原卷版)_第2頁
新高考數(shù)學(xué)一輪復(fù)習(xí)講義 第14講 導(dǎo)數(shù)的概念及其意義、導(dǎo)數(shù)的運(yùn)算(原卷版)_第3頁
新高考數(shù)學(xué)一輪復(fù)習(xí)講義 第14講 導(dǎo)數(shù)的概念及其意義、導(dǎo)數(shù)的運(yùn)算(原卷版)_第4頁
新高考數(shù)學(xué)一輪復(fù)習(xí)講義 第14講 導(dǎo)數(shù)的概念及其意義、導(dǎo)數(shù)的運(yùn)算(原卷版)_第5頁
已閱讀5頁,還剩4頁未讀 繼續(xù)免費(fèi)閱讀

下載本文檔

版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進(jìn)行舉報或認(rèn)領(lǐng)

文檔簡介

第14講導(dǎo)數(shù)的概念及其意義、導(dǎo)數(shù)的運(yùn)算(精講)題型目錄一覽①導(dǎo)數(shù)的定義②導(dǎo)數(shù)的運(yùn)算③導(dǎo)數(shù)中的切線問題Ⅰ-求在曲線上一點(diǎn)的切線方程④導(dǎo)數(shù)中的切線問題Ⅱ-求過一點(diǎn)的切線方程⑤導(dǎo)數(shù)中的切線問題Ⅲ-求參數(shù)的值(范圍)★【文末附錄-導(dǎo)數(shù)的概念及其意義和導(dǎo)數(shù)的運(yùn)算思維導(dǎo)圖】一、知識點(diǎn)梳理一、知識點(diǎn)梳理一、導(dǎo)數(shù)的概念和幾何性質(zhì)1.概念函數(shù)SKIPIF1<0在SKIPIF1<0處瞬時變化率是SKIPIF1<0,我們稱它為函數(shù)SKIPIF1<0在SKIPIF1<0處的導(dǎo)數(shù),記作SKIPIF1<0或SKIPIF1<0.注:增量SKIPIF1<0可以是正數(shù),也可以是負(fù),但是不可以等于0.SKIPIF1<0的意義:SKIPIF1<0與0之間距離要多近有多近,即SKIPIF1<0可以小于給定的任意小的正數(shù);2.幾何意義函數(shù)SKIPIF1<0在SKIPIF1<0處的導(dǎo)數(shù)SKIPIF1<0的幾何意義即為函數(shù)SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線的斜率.二、導(dǎo)數(shù)的運(yùn)算1.求導(dǎo)的基本公式基本初等函數(shù)導(dǎo)函數(shù)SKIPIF1<0(SKIPIF1<0為常數(shù))SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<02.導(dǎo)數(shù)的四則運(yùn)算法則(1)函數(shù)和差求導(dǎo)法則:SKIPIF1<0;(2)函數(shù)積的求導(dǎo)法則:SKIPIF1<0;(3)函數(shù)商的求導(dǎo)法則:SKIPIF1<0,則SKIPIF1<0.3.復(fù)合函數(shù)求導(dǎo)數(shù)復(fù)合函數(shù)SKIPIF1<0的導(dǎo)數(shù)和函數(shù)SKIPIF1<0,SKIPIF1<0的導(dǎo)數(shù)間關(guān)系為SKIPIF1<0:【常用結(jié)論】1.在點(diǎn)的切線方程切線方程SKIPIF1<0的計算:函數(shù)SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程為SKIPIF1<0,抓住關(guān)鍵SKIPIF1<0.2.過點(diǎn)的切線方程設(shè)切點(diǎn)為SKIPIF1<0,則斜率SKIPIF1<0,過切點(diǎn)的切線方程為:SKIPIF1<0,又因?yàn)榍芯€方程過點(diǎn)SKIPIF1<0,所以SKIPIF1<0然后解出SKIPIF1<0的值.(SKIPIF1<0有幾個值,就有幾條切線)二、題型分類精講二、題型分類精講題型一導(dǎo)數(shù)的定義策略方法對所給函數(shù)式經(jīng)過添項、拆項等恒等變形與導(dǎo)數(shù)定義結(jié)構(gòu)相同,然后根據(jù)導(dǎo)數(shù)定義直接寫出.【典例1】已知函數(shù)SKIPIF1<0在SKIPIF1<0處的導(dǎo)數(shù)SKIPIF1<0,則SKIPIF1<0(

).A.SKIPIF1<0 B.1 C.SKIPIF1<0 D.SKIPIF1<0【題型訓(xùn)練】一、單選題1.設(shè)SKIPIF1<0為SKIPIF1<0上的可導(dǎo)函數(shù),且SKIPIF1<0,則曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線斜率為(

)A.2 B.-1 C.1 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0的導(dǎo)函數(shù)是SKIPIF1<0,若SKIPIF1<0,則SKIPIF1<0()A.SKIPIF1<0 B.1 C.2 D.4二、填空題3.已知函數(shù)SKIPIF1<0,則SKIPIF1<0______.題型二導(dǎo)數(shù)的運(yùn)算策略方法對所給函數(shù)求導(dǎo),其方法是利用和、差、積、商及復(fù)合函數(shù)求導(dǎo)法則,直接轉(zhuǎn)化為基本函數(shù)求導(dǎo)問題.【典例1】求下列函數(shù)的導(dǎo)數(shù).(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0(4)SKIPIF1<0;(5)SKIPIF1<0(SKIPIF1<0為常數(shù));(6)SKIPIF1<0.【題型訓(xùn)練】一、解答題1.下列函數(shù)的導(dǎo)函數(shù)(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0;(4)SKIPIF1<0.2.求下列函數(shù)的導(dǎo)數(shù).(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0(4)SKIPIF1<0;3.求下列函數(shù)的導(dǎo)數(shù):(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<0;(4)SKIPIF1<0;(5)SKIPIF1<0;(6)SKIPIF1<0.題型三導(dǎo)數(shù)中的切線問題Ⅰ-求在曲線上一點(diǎn)的切線方程策略方法已知切點(diǎn)A(x0,f(x0))求切線方程,可先求該點(diǎn)處的導(dǎo)數(shù)值f′(x0),再根據(jù)y-f(x0)=f′(x0)(x-x0)求解.【典例1】設(shè)曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線與直線SKIPIF1<0平行,則實(shí)數(shù)SKIPIF1<0(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【題型訓(xùn)練】一、單選題1.已知函數(shù)SKIPIF1<0,則SKIPIF1<0的圖象在SKIPIF1<0處的切線方程為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0,若SKIPIF1<0的圖象在SKIPIF1<0處的切線與坐標(biāo)軸圍成的三角形的面積為1,則SKIPIF1<0(

)A.SKIPIF1<0 B.2 C.±2 D.SKIPIF1<03.已知SKIPIF1<0為實(shí)數(shù),函數(shù)SKIPIF1<0是偶函數(shù),則曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、填空題4.已知曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線與曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線互相垂直,則SKIPIF1<0________.5.已知函數(shù)SKIPIF1<0的圖象在SKIPIF1<0處的切線在y軸上的截距為2,則實(shí)數(shù)SKIPIF1<0____________.6.已知函數(shù)SKIPIF1<0,則曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程為__________.7.已知函數(shù)SKIPIF1<0,直線SKIPIF1<0,SKIPIF1<0是SKIPIF1<0的兩條切線,SKIPIF1<0,SKIPIF1<0相交于點(diǎn)SKIPIF1<0,若SKIPIF1<0,則SKIPIF1<0點(diǎn)橫坐標(biāo)的取值范圍是________.三、解答題8.已知函數(shù)SKIPIF1<0,其中SKIPIF1<0.若曲線SKIPIF1<0在SKIPIF1<0處的切線過點(diǎn)SKIPIF1<0,求SKIPIF1<0的值;題型四導(dǎo)數(shù)中的切線問題Ⅱ-求過一點(diǎn)的切線方程策略方法設(shè)切點(diǎn)為SKIPIF1<0,則斜率SKIPIF1<0,過切點(diǎn)的切線方程為:SKIPIF1<0,又因?yàn)榍芯€方程過點(diǎn)SKIPIF1<0,所以SKIPIF1<0然后解出SKIPIF1<0的值【典例1】過原點(diǎn)且與函數(shù)SKIPIF1<0圖像相切的直線方程是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【題型訓(xùn)練】一、單選題1.若直線SKIPIF1<0為曲線SKIPIF1<0的一條切線,則實(shí)數(shù)k的值是(

)A.e B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.過坐標(biāo)原點(diǎn)作曲線SKIPIF1<0的切線,則切線方程為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.若過點(diǎn)SKIPIF1<0可以作曲線SKIPIF1<0的兩條切線,則(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.過坐標(biāo)原點(diǎn)作曲線SKIPIF1<0的切線,則切線有(

)條A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、填空題5.過坐標(biāo)原點(diǎn)作曲線SKIPIF1<0的切線,則切點(diǎn)的橫坐標(biāo)為___________.6.已知直線SKIPIF1<0與曲線SKIPIF1<0相切,則SKIPIF1<0_________.7.過點(diǎn)SKIPIF1<0作曲線SKIPIF1<0的兩條切線,則這兩條切線的斜率之和為______.8.若曲線SKIPIF1<0有兩條過坐標(biāo)原點(diǎn)的切線,則實(shí)a的取值范圍為______.題型五導(dǎo)數(shù)中的切線問題Ⅲ-求參數(shù)的值(范圍)策略方法1.利用導(dǎo)數(shù)的幾何意義求參數(shù)的基本方法利用切點(diǎn)的坐標(biāo)、切線的斜率、切線的方程等得到關(guān)于參數(shù)的方程(組)或者參數(shù)滿足的不等式(組),進(jìn)而求出參數(shù)的值或取值范圍.2.求解與導(dǎo)數(shù)的幾何意義有關(guān)問題時應(yīng)注意的兩點(diǎn)(1)注意曲線上橫坐標(biāo)的取值范圍.(2)謹(jǐn)記切點(diǎn)既在切線上又在曲線上.【典例1】已知函數(shù)SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線為SKIPIF1<0,則SKIPIF1<0的值為(

)A.1 B.2 C.3 D.4【題型訓(xùn)練】一、單選題1.已知曲線SKIPIF1<0在點(diǎn)P處的切線與直線SKIPIF1<0垂直,則點(diǎn)P的橫坐標(biāo)為(

)A.1 B.SKIPIF1<0 C.2 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0與SKIPIF1<0的圖象在SKIPIF1<0處有相同的切線,則SKIPIF1<0(

)A.0 B.SKIPIF1<0 C.1 D.SKIPIF1<0或13.若點(diǎn)P是函數(shù)SKIPIF1<0任意一點(diǎn),則點(diǎn)P到直線SKIPIF1<0的最小距離為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.動直線SKIPIF1<0分別與直線SKIPIF1<

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
  • 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
  • 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負(fù)責(zé)。
  • 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
  • 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。

評論

0/150

提交評論