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專題15函數(shù)零點(diǎn)問(wèn)題真題呈現(xiàn)1.(2021·天津·統(tǒng)考高考真題)設(shè)SKIPIF1<0,函數(shù)SKIPIF1<0,若SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)恰有6個(gè)零點(diǎn),則a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.(2023·全國(guó)·統(tǒng)考高考真題)已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0有且僅有3個(gè)零點(diǎn),則SKIPIF1<0的取值范圍是________.3.(2023·天津·統(tǒng)考高考真題)若函數(shù)SKIPIF1<0有且僅有兩個(gè)零點(diǎn),則SKIPIF1<0的取值范圍為___.4.(2022·天津·統(tǒng)考高考真題)設(shè)SKIPIF1<0,對(duì)任意實(shí)數(shù)x,記SKIPIF1<0.若SKIPIF1<0至少有3個(gè)零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍為______.5.(2021·北京·統(tǒng)考高考真題)已知函數(shù)SKIPIF1<0,給出下列四個(gè)結(jié)論:①若SKIPIF1<0,SKIPIF1<0恰有2個(gè)零點(diǎn);②存在負(fù)數(shù)SKIPIF1<0,使得SKIPIF1<0恰有1個(gè)零點(diǎn);③存在負(fù)數(shù)SKIPIF1<0,使得SKIPIF1<0恰有3個(gè)零點(diǎn);④存在正數(shù)SKIPIF1<0,使得SKIPIF1<0恰有3個(gè)零點(diǎn).其中所有正確結(jié)論的序號(hào)是_______.6.(2022·北京·統(tǒng)考高考真題)若函數(shù)SKIPIF1<0的一個(gè)零點(diǎn)為SKIPIF1<0,則SKIPIF1<0_____;SKIPIF1<0__.考點(diǎn)一函數(shù)零點(diǎn)的定義一、單選題1.函數(shù)SKIPIF1<0的零點(diǎn)為(
)A.2,3 B.2 C.SKIPIF1<0 D.SKIPIF1<02.若SKIPIF1<0是二次函數(shù)SKIPIF1<0的兩個(gè)零點(diǎn),則SKIPIF1<0的值是()A.3 B.15 C.SKIPIF1<0 D.SKIPIF1<03.關(guān)于SKIPIF1<0的函數(shù)SKIPIF1<0的兩個(gè)零點(diǎn)為SKIPIF1<0,且SKIPIF1<0,則SKIPIF1<0=()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.若向量SKIPIF1<0,SKIPIF1<0,則函數(shù)SKIPIF1<0的零點(diǎn)為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0,SKIPIF1<05.函數(shù)SKIPIF1<0有且只有一個(gè)零點(diǎn),則實(shí)數(shù)m的值為(
)A.9 B.12 C.0或9 D.0或12二、填空題6.函數(shù)SKIPIF1<0的零點(diǎn)為________.7.若函數(shù)SKIPIF1<0有且僅有兩個(gè)零點(diǎn)SKIPIF1<0,且SKIPIF1<0,則SKIPIF1<0_______.三、解答題8.求下列函數(shù)的零點(diǎn).(1)SKIPIF1<0;(2)SKIPIF1<0.考點(diǎn)二零點(diǎn)存在定理判斷零點(diǎn)所在區(qū)間一、單選題1.函數(shù)SKIPIF1<0的零點(diǎn)所在區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.已知方程SKIPIF1<0的解在SKIPIF1<0內(nèi),則SKIPIF1<0(
)A.3 B.2 C.1 D.03.已知函數(shù)SKIPIF1<0,則SKIPIF1<0的零點(diǎn)所在的區(qū)間為(
).A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的零點(diǎn)必屬于區(qū)間(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.已知SKIPIF1<0唯一的零點(diǎn)同時(shí)在區(qū)間SKIPIF1<0和SKIPIF1<0內(nèi),下列說(shuō)法錯(cuò)誤的是(
)A.函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)有零點(diǎn) B.函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)無(wú)零點(diǎn)C.函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)有零點(diǎn) D.函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)無(wú)零點(diǎn)6.已知函數(shù)SKIPIF1<0,若方程SKIPIF1<0的實(shí)根在區(qū)間SKIPIF1<0上,則k的最大值是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.已知函數(shù)SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)的圖象過(guò)定點(diǎn)SKIPIF1<0,則函數(shù)SKIPIF1<0的零點(diǎn)所在區(qū)間為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、填空題8.函數(shù)SKIPIF1<0的零點(diǎn)所在區(qū)間(取整數(shù))是_________.考點(diǎn)三求函數(shù)零點(diǎn)個(gè)數(shù)一、單選題1.函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的零點(diǎn)個(gè)數(shù)是(
)A.3 B.4 C.5 D.62.函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為(
)A.1 B.3 C.5 D.73.函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為(
)A.0個(gè) B.1個(gè) C.2個(gè) D.3個(gè)4.函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為(
)A.2 B.3 C.4 D.55.已知函數(shù)SKIPIF1<0,則函數(shù)SKIPIF1<0零點(diǎn)個(gè)數(shù)為(
)A.0 B.1 C.2 D.36.設(shè)函數(shù)SKIPIF1<0若SKIPIF1<0,SKIPIF1<0,則關(guān)于SKIPIF1<0的方程SKIPIF1<0的解的個(gè)數(shù)為(
)A.1 B.2 C.3 D.47.方程SKIPIF1<0,SKIPIF1<0實(shí)根的個(gè)數(shù)為(
)A.6 B.5 C.4 D.38.已知函數(shù)SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0在區(qū)間SKIPIF1<0上的零點(diǎn)個(gè)數(shù)為(
)A.1 B.2 C.3 D.49.已知定義域?yàn)镾KIPIF1<0的偶函數(shù)SKIPIF1<0滿足SKIPIF1<0,且當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,若將方程SKIPIF1<0實(shí)數(shù)解的個(gè)數(shù)記為SKIPIF1<0,則SKIPIF1<0(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、填空題10.函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)是__________.11.已知SKIPIF1<0,方程SKIPIF1<0的實(shí)根個(gè)數(shù)為__________.12.定義在R上的函數(shù)SKIPIF1<0滿足SKIPIF1<0,SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,則函數(shù)SKIPIF1<0有__________個(gè)零點(diǎn).考點(diǎn)四根據(jù)函數(shù)零點(diǎn)求參一、單選題1.函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0,若SKIPIF1<0恰有兩個(gè)零點(diǎn),則正數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.已知函數(shù)SKIPIF1<0(e為自然對(duì)數(shù)的底數(shù),a∈R)有3個(gè)不同的零點(diǎn),則實(shí)數(shù)a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.已知函數(shù)SKIPIF1<0,若SKIPIF1<0有3個(gè)不同的解,則a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.已知函數(shù)SKIPIF1<0若函數(shù)SKIPIF1<0有五個(gè)零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<06.已知函數(shù)SKIPIF1<0,若方程SKIPIF1<0有四個(gè)不同的實(shí)數(shù)根,則實(shí)數(shù)a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.若函數(shù)SKIPIF1<0SKIPIF1<0恰有2個(gè)零點(diǎn),則實(shí)數(shù)a的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多選題8.已知函數(shù)SKIPIF1<0,實(shí)數(shù)SKIPIF1<0、SKIPIF1<0是函數(shù)SKIPIF1<0的兩個(gè)零點(diǎn),則下列結(jié)論正確的有(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<09.已知函數(shù)SKIPIF1<0且方程SKIPIF1<0的6個(gè)解分別為SKIPIF1<0SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0三、填空題10.設(shè)函數(shù)SKIPIF1<0在區(qū)間[SKIPIF1<0上有零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是___________.11.函數(shù)SKIPIF1<0在SKIPIF1<0上存在零點(diǎn),則整數(shù)t的值為______.12.若函數(shù)SKIPIF1<0
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