《面向?qū)ο蠓椒ㄅcC++》作業(yè)參考答案學(xué)習(xí)資料VIP

第1頁共1頁以上僅為參考答案，簡答、論述題均只列及主要的解題知識點，請您結(jié)合自我理解和課本內(nèi)容進行知識掌握和鞏固。如對答案等有疑義，請及時登錄學(xué)院網(wǎng)站“輔導(dǎo)論壇”欄目，與老師交流探討！《面向?qū)ο蠓椒ㄅcC++》作業(yè)參考答案一、填空題1．cout<<(void*)string;2．成員3．public，protected4．05．成員6．0xa7．Private8．嵌套9．fstream.h10．static11．類名,::12．共享二、判斷題1．（√）2．（×）3．（×）4．（×）5．（×）6．（√）7．（√）8．（×）9．（√）10．（×）11．（√）12．（×）三、讀程題1．109876543212．before:count=65increment=7after:1count=72increment=7after:2count=79increment=7after:3count=86increment=73．03310334．0 6 16 65．14710131619222528Error四、編程題1．(1)fstream.h(2)intnum(3)float(4)s(5)ostream&(6)(7)void(8)student.txt(9)i++(10)cin>>n2．(1)iostream.h(2)rpart=r(3)int(4)returnso(5)ipart*ipart(6)c1.rpart-c2.rpart(7)returnres(8)c1.abs()>=c2.abs()(9)c1.rpart!=c2.rpart(10)complex3．#include<fstream.h>#include<stdlib.h>classpatient{ intnum,count,*pc,ave;public: patient(){pc=0;ave=0;} ~patient(){delete[]pc;} patient(intnu,intc){ num=nu;ave=0;pc=newint[count=c];}friendistream&operator>>(istream&s,patient&st){ s>>st.num>>st.count; st.pc=newint[st.count]; for(inti=0;i<st.count;i++) {s>>st.pc[i];st.ave+=st.pc[i];}st.ave/=st.count;returns;}friendostream&operator<<(ostream&s,constpatient&st){ s<<st.num<<""<<st.ave<<endl;returns;}};voidmain(){ patients[15]; ifstreamf("patient.dat"); if(!f){ cerr<<"Can'topenpatient.datforinput.\n"; exit(1);} inti=0;while(!f.eof()) f>>s[i++]; for(intj=0;j<i;j++) cout<<s[j];}4．(1)0(2)bool(3)friend(4)out(5)false(6)i++(或++i)(7)--res.card(8)setres(9)s1.elems[i](10)s1,s2,s35．(1)left(2)0(3)publicinte_algo(4)voidintegrate()(5)simp