第5章-計(jì)算機(jī)組成_第1頁(yè)
第5章-計(jì)算機(jī)組成_第2頁(yè)
第5章-計(jì)算機(jī)組成_第3頁(yè)
第5章-計(jì)算機(jī)組成_第4頁(yè)
第5章-計(jì)算機(jī)組成_第5頁(yè)
已閱讀5頁(yè),還剩8頁(yè)未讀, 繼續(xù)免費(fèi)閱讀

下載本文檔

版權(quán)說(shuō)明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)

文檔簡(jiǎn)介

1、如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按鈕下載!Chapter 5 Computer OrganizationBy 黃永平,權(quán)勇,孫永雄,王智,豐小月,孫銘會(huì)Knowledge point:5.1. three subsystems that make up a computer5.2. functionality of each subsystem5.3. memory addressing and calculating the number of bytes5.4. addressing system for input/output devices.5.5. the systems used

2、 to connect different components together.Multiple-choice Questions39. The _ is a computer subsystem that performs operations on data.( Knowledge point 5.1)a. CPUb. memoryc. I/O hardwared. none of the above40. _ is a stand-alone storage location that holds data temporarily. ( Knowledge point 5.1)a.

3、An ALUb. A registerc. A control unitd. A tape drive41. _ is a unit that can add two inputs. ( Knowledge point 5.2)a. An ALUb. A registerc. A control unitd. A tape drive42. A register in a CPU can hold _.( Knowledge point 5.2)a. datab. instructionsc. program counter valuesd.all of the above43. A cont

4、rol unit with five wires can define up to _ operations. ( Knowledge point 5.2)a. 5b. 10c. 16d. 32 44. A word is _ bits. ( Knowledge point 5.3)a. 81 / 9如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按鈕下載!b. 16c. 32d. any of the above45. If the memory address space is 16 MB and the word size is 8 bits, then _ bits are needed to acc

5、ess each word. ( Knowledge point 5.3)a. 8b. 16c. 24d.3246. The data in _ are erased if the computer is powered down. ( Knowledge point 5.5.3)a. RAMb. ROMc. a tape drived. a CD-ROM47. _ is a memory type with capacitors that need to be refreshed periodically. ( Knowledge point 5.3)a. SRAMb. DRAMc. ROM

6、d. all of the above48. _ is a memory type with traditional flip-flop gates to hold data. ( Knowledge point 5.3)a. SRAMb. DRAMc. ROMd. all of the above 49. There are _ bytes in 16 terabytes. ( Knowledge point 5.3)a.216b. 240c.244d. 25650. _ can be programmed and erased using electronic impulses but c

7、an remain in a computer during erasure. ( Knowledge point 5.3)a. ROMb. PROMc. EPROMd. EEPROM51. _ is a type of memory in which the user, not the manufacturer, stores programs that cannot be overwritten. ( Knowledge point 5.3)2 / 9如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按鈕下載!a. ROMb. PROMc. EPROMd. EEPROM52. CPU registers s

8、hould have _ speed memory. ( Knowledge point 5.3)a. highb. mediumc. lowd. any of the above53. Main memory in a computer usually consists of large amounts of _ speed memory. ( Knowledge point 5.3)a. highb. mediumc. lowd. any of the above54. The _ memory contains a copy of a portion of main memory. (

9、Knowledge point 5.3)a. CPUb. cachec. maind. ROM55. The _ is nonstorage I/O device. ( Knowledge point 5.4)a. keywordb. monitorc. printerd. all of the above56.A _ is an optical storage device. ( Knowledge point 5.4)a. CD-ROMb. CD-Rc. CD-RMd. all of the above57. The _ is a storage device in which the m

10、anufacturer writes information to the disc. ( Knowledge point 5.4)a. CD-ROMb. CD-Rc. CD-RMd. all of the above58. The _ is a storage device in which the user can writes information only once to the disc. ( Knowledge point 5.4)a. CD-ROMb. CD-Rc. CD-RMd. all of the above59. The _ is a storage device th

11、at can undergo multiple writings and erasings.4 / 9如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按鈕下載! ( Knowledge point 5.4)a. CD-ROMb. CD-Rc. CD-RMd. all of the above60. The smallest storage area on a magnetic disk that can be accessed at one time is a _.( Knowledge point 5.4)a. trackb. sectorc. framed. head61. For a magnetic

12、disk, the _ time is the time it takes for the read/write head to move to the desired track where the data are stored. ( Knowledge point 5.4)a. rotationb. seekc. transferd. location62. Polycarbonate resin is used in _ . ( Knowledge point 5.4)a. CD-ROMsb. CD-Rsc. CD-RWsd. all of the above63. In a _, a

13、 high-power laser beam simulates pits in an alloy of silver, indium, antimony, and tellurium. ( Knowledge point 5.4)a. CD-ROMb. CD-Rc. CD-RMd. all of the above64. In a _, a high-power laser beam simulates pits in the dye layer. ( Knowledge point 5.4)a. CD-ROMb. CD-Rc. CD-RMd. all of the above65. Whi

14、ch optical storage device has the highest capacity ? ( Knowledge point 5.4)a. CD-ROMb. CD-Rc. CD-RMd. DVD66. In a DVD, a _ beam reads the disk. ( Knowledge point 5.4)a. high-power laserb. infrared4 / 9如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按鈕下載!c. red laserd. blue laser67. A _ bus connects the CPU and memory. ( Knowledge

15、point 5.5)a. datab. addressc. controld. all of the above68. If the word size is 2 bytes, a data bus with _ wires is needed. ( Knowledge point 5.5)a. 2b. 4c. 8d. 1669. If the memory has232words, the address bus needs to have _ wires. ( Knowledge point 5.5)a. 8b. 16c. 32d. 6470. A control bus with eig

16、ht wires can define _ operations. ( Knowledge point 5.5)a. 8b. 16c. 256d. 51271. The _ controller features a parallel interface and daisy-chained connection for I/O devices. ( Knowledge point 5.5)a. SCSIb. Fire Wirec. USBd. IDE72. The _ controller is a serial device that connects slow devices such a

17、s the keyboard and mouse to the computer. ( Knowledge point 5.5)a. SCSIb. Fire Wirec. USBd. IDE73. The _ controller is a high-speed serial interface that transfers data in packets. ( Knowledge point 5.5)a. SCSIb. Fire Wirec. USBd. IDE5 / 9如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按鈕下載!74. The three steps in the running of a

18、program on a computer are performed _ in this specific order. ( Knowledge point 5.5)a. fetch, execute, and decode b. fetch, execute, and fetchc. fetch, decode, and executed. decode, fetch, and execute75. In the _ method to synchronize the operation of the CPU with the I/O device ,the I/O device info

19、rms the CPU when it is ready for data transfer. ( Knowledge point 5.5)a. programmed I/Ob. interrupt-driven I/Oc. DMA d. isolated I/O76. In the _ method to synchronize the operation of the CPU with the I/O device, the CPU is idle until the I/O operation is finished. ( Knowledge point 5.5)a. programme

20、d I/Ob. interrupt-driven I/Oc. DMA d. isolated I/O77. In the _ method to synchronize the operation of the CPU with the I/O device, a large block of data can be passed from an I/O device to memory directly. ( Knowledge point 5.5)a. programmed I/Ob. interrupt-driven I/Oc. DMA d. isolated I/OReview que

21、stions:1. What are the three subsystems that make up a computer?(Knowledge point 5.1)Answer: the CPU, main memory, and the input/output (I/O) subsystem.2. What are the parts of a CPU? (Knowledge point 5.1)Answer: The CPU performs operations on data and has a ALU, a control unit, and a set of registe

22、rs.3. Whats the function of the ALU? (Knowledge point 5.2)Answer: The ALU performs arithmetic and logical operations.Exercises:78. A computer has 64MB of memory. Each word is 4 bytes. How many bits are needed to address each single word in memory? (Knowledge point 5.3)Solution:6 / 9如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按

23、鈕下載!The memory address space is 64 MB, that is 2 raised to the power 26. The size of each word in bytes is 2 raised to the power 2. So we need 24(subtract 2 from 26) bits to address each single word in memory.79. How many bytes of memory are needed to store a full screen of data if the screen is mad

24、e of 24 lines with 80 characters in each line? The system uses ASCII code, with each ASCII character store as a byte. (Knowledge point 5.3)Solution:The quantity of bytes in a full screen is 1920 (24*80) while the system uses ASCII code with each ASCII character store as a byte. So we need 1920 bytes

25、 of memory to store the full screen of data.80. An imaginary computer has four data registers(R0 to R3), 1024 words in memory, and 16 different instructions(add, subtract, etc.). What is the minimum size of an instruction in bits if a typical instruction uses the following format: add 565 R2. (Knowl

26、edge point 5.5)Solution:The number of data registers in this computer is 4, that is 2 raised to the power 2. The number of words in this computer is 1024, that is 2 raised to the power 10. The number of instructions in this computer is 16, that is 2 raised to the power 4. So the minimum size of an i

27、nstruction in bits is 16 (2+10+4) bits.81. If the computer in Exercise 80 uses the same size of word for data and instructions. What is the size of each data register? (Knowledge point 5.5)Solution:The size of an instruction in bits is 16. Data size is the same with that of an instruction. So 16 is

28、the size of each data register.82. What is the size of the instruction register of the computer in Exercise 80? (Knowledge point 5.5)Solution:The size of an instruction in bits is 16. So the size of the instruction register of the computer is also 16.83. What is the size of the program counter of th

29、e computer in Exercise 80? (Knowledge point 5.5)Solution:The number of words in this computer is 1024, that is 2 raised to the power 10. So the size of the program counter of the computer is 10.84. What is the size of the data bus in Exercise 80? (Knowledge point 5.5)7 / 9如果您需要使用本文檔,請(qǐng)點(diǎn)擊下載按鈕下載!Soluti

30、on:Data size of this computer in bits is 16. So the size of the data bus is 16.85. What is the size of the address bus in Exercise 80? (Knowledge point 5.5)Solution:The number of words in this computer is 1024, that is 2 raised to the power 10. So the the size of the address bus is 10.86. What is the minimum size of the control bus in Exercise

溫馨提示

  • 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒(méi)有圖紙預(yù)覽就沒(méi)有圖紙。
  • 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
  • 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
  • 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
  • 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。

評(píng)論

0/150

提交評(píng)論