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1、Lab4 Looping StructuresOBJECTIVESAfter completing this experiment, you will be able to:l Use incrementing and decrementing operatorsl Use while structure and do-while structure l Use for structurel Use break and continue statementsPROCEDURESPART 1 use + and -. #include <stdio.h> void main() in

2、t a=5,b=5;printf(“value a=%dn”,a+);/printf(“value b=%dn”,+b);printf(“value a=%dn”,-a); printf(“value b=%dn”,b-);(1) Print Screen of Result: (2) Summarize the the difference between a+ and +a in your words. a+是先運行后加一,+a是先加一后運行PART2 use while and do while structure./*Get the number that can not be div

3、ided by 3 between 100 and 200 */#include <stdio.h>main()int i=100;while (i<=200)if(i%3)printf("%5d",i);i+;(1) Print Screen of Result: (2) Rewrite it using do-while loop.Print Screen of code: PART 3 use for structure.1.Write a program to give the result of 1!+2!+3!+n!#include "

4、;stdio.h"void main() long int s=1,t; int i,j,n; printf("n="); scanf("%d",&n); for(i=2;i<=n;i+) for(t=1,j=1;j<=i;j+) t*=j; s+=t; printf("s=%ldn",s);(1) Print Screen of Result: (2) Use different data to test the program, find the number on which the result

5、number will overflow(3) Try to use only one loop to solve the problemPrint Screen of code: 2. Print out the following table using nested for loop.Print Screen of code: PART 4 use break and continue structure.1.Prompt the user to input an integer, get the number of the users input between 0 and 100 .

6、#include "stdio.h"void main() int m,counter=0; while(1) printf("input a positive integer (0 means end):"); scanf("%d",&m); if(m=0) break; if(m<100)counter+; printf("n"); printf("n numbers less than 100: %dn",counter);Print Screen of Result: 2.

7、#include "stdio.h"void main() int m,counter=0; char ask; while(1) printf("input a positive integer:"); scanf("%d",&m); if(m>0&&m<100)counter+; printf("Want continue?(Y/N)"); getchar(); ask=getchar(); if(ask!='y'&&ask!='Y')break; printf("n"); printf("n numbers less than 100: %dn",counter);(1)Print Screen of Result: (2)Tell the reason for putting the statem

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