微機原理及應(yīng)用(第3版)_吳寧_馬旭東_部分習(xí)題_解答

1、微機原理習(xí)題3-3解：（1）立即數(shù)尋址 （2）基址尋址，EA=BX+DISP，PA=DS*16+EA（3）寄存器尋址 （4）基址加變址尋址，EA=BX+SI，PA=DS*16+EA（5）基址尋址，EA=BP，PA=SS*16+EA （6）基址尋址，EA=BX+10H，PA=DS*16+EA（7）基址尋址，EA=BX，PA=ES*16+EA （8）基址加變址尋址，EA=BX+SI+20H，PA=DS*16+EA3-5解：(1)X （2） （3）X （4）X （5）X (6) (7)X (8) (9)X (10) (11) (12) (13) (14)X (15) (16)X3-6解：(1) X

2、BX和BP不能同時使用(2) X 源操作數(shù)和目的操作數(shù)不能同時為存儲器(3) X 不能將立即數(shù)賦值給段寄存器(4) X 不能給CS賦值(5) X 立即數(shù)不能為目的操作數(shù)(6) (7) X 段寄存器不能互相賦值(8) X 移位指令中的移位次數(shù)只能是1或者為CL(9) X NOT指令是單操作數(shù)指令(10) (11) X 不可以把立即數(shù)入棧(12) 直接端口地址必須小于等于 0FFH(13) (14) 不能用減法(15) 不能用減法(16) 3-7解：（1）AX=3355H，SP=1FFEH（2）AX=3355H，DX=4466H, SP=1FFEH3-8解： BX= 4154H, 2F246H=6

3、F30H3-9解： SI=0180H, DS=2000H3-10解：(1) CL=0F6H(2) 1E46FH=5678H(3) BX=56H, AX=1E40H(4) SI=00F6H, SI=0024H(5) AX=5678H, 09226H=1234H3-11解：MOVAX,2C0HMOVAX,100DIMOVAX,BPMOVAX,80HDIBX3-13解：(1)MOVCX, BLOCK+12(2)MOVBX, OFFSET BLOCKADDBX,12MOVCX,BX(3)MOVBX, OFFSET BLOCKMOVCX,12BX(4)MOVBX, OFFSET BLOCKMOVSI,7

4、MOVCX, BXSI3-14解：MOVBX,0A80HMOVAL,5XLAT3-16解：(1) LEA SI, NUM1 LEA DI, NUM2MOV CX,2 CLCAGAIN:MOV AX, SIADC AX, DIMOV DI, AXINC SIINCSIINC DIINCDILOOP AGAINADCAX,0MOV DI, AX(2)LEASI, NUM2MOVCX,3CLCMOVAL,SIAGAIN:INCSIADCAL,SIADCAH,0LOOPAGAINMOVRES,AX3-17解：(1) MOVBX, OFFSETNUM2MOVCX, 4MOVAX, 0AGAIN:ADDA

5、L, BXDAAMOVDL,ALMOVAL,AHADCAL,0DAAMOVAH,ALMOVAL,DLINCBXLOOPAGAINMOVRES,AX(2)MOVAL, NUM1SUBAL, NUM2DASMOVRES,ALMOVAL,NUM1+1SBBAL, NUM2+1DASMOVRES+1,AL3-18解：(1) MOVAL,NUM1MULBYTE PTR NUM2MOVRES,AX(2)MOVAX,NUM1IMULWORD PTR NUM2MOVRES,AXMOVRES+2,DX(3)MOVAL,NUM1MOVAH,0MOVBL,46HDIVBLMOVRES, AX(4)MOVAX,NUM

6、1CWDMOVBX, NUM2IDIVBXMOVRES,AXMOVRES+2,DX3-23解：(1) ANDBX,0F7AFH(2)ORCX, 01H(3)XORAX, 4020H(4)TESTDX, 0201H(5)XORAL, 55HORAL, 0AAH(6)MOVCL,4SHLAX,CLMOVCL,4SHRAL,CL3-26解：STRINGDB20 DUP(?)DESTINDB 20 DUP(?)LEASI, STRINGLEADI, DESTINMOVCX, 20CLDREPMOVSB3-29解：IP=009AH, CS=2000H, SP= 0F178H, SP=8FH, SP+1=

7、3DH, SP+2=50H, SP+3=40H3-32解：XDW ?YDW ?ZDW ?SDW?MOVAX, XCMPAX, YJNZXNEYCMPAX, ZJNZ SEQ1MOVS,2JMPEXITXNEY:CMPAL,ZJZSEQ1MOVS,0JMPEXITSEQ1:MOVS,1EXIT:3-37解：MOVAX, 0B800HMOVDS, AXMOVBX,0MOVCX,100MOVDX,0MOVAX,0AGAIN:ADDAX, BXADCDX, 0INCBXINCBXLOOPAGAIN4-4解：41H42H43H0AH10H45H46HFFH?444FFH?44410H00HFBHFFH4

8、6H45H?15H00H11H00H(SEG VAR2)L(SEG VAR2)H VAR1 VAR2 VAR3 VAR44-7解：（1）VAR1的偏移地址是 30H VAR2的偏移地址是 3AH VAR3的偏移地址是 40H(2) DATA1=50H, CNT= 16(3) VAR2+2 =02H4-10解：DATASEGMENTORG100HVARWDW1234H,5678HVARDDD 12345678HBUFFDB 10 DUP(?)MESSDB HELLOBEGIN:MOVAX, OFFSET MESS;AX=112HMOVAX, TYPE BUFF+TYPE MESS+TYPE VA

9、RD;AX=1+1+4=6MOVAX, SIZE VARW+SIZE BUFF +SIZE MESS;AX=2+10+1=13MOV AX, LENGTH VARW+LENGTH VARD;AX=1+1=2MOV AX, LENGTH BUFF+SIZE VARW;AX=10+2=12MOVAX, TYPE BEGIN;AX=FFFFH （-1）MOVAX, OFFSET BEGIN;AX=04-12解：DATASEGMENT WORDDABUFDB100 DUP(?)DATAENDSSTACKSEGMENT PARA STACKDB 100 DUP(?)STACK ENDSCODE SEGM

10、ENT CODEASSUME CS:CODE,DS:DATA,ES:DATA,SS:STACKSTART:MOV AX, DATAMOV DS,AXMOVES,AXMOVAX,STACKMOVSS,AXMOVCX,100CLDMOVBX,OFFSET DABUFMOV AL,64HREP SCASBMOVAH,4CHINT21HCODE ENDSEND START4-16解：DATASEGMENTXDB4 DUP(?)YDB4 DUP(?)ZDB4 DUP(?)DATAENDSCODE SEGMENTSTART:MOVAX,DATAMOVDS,AXMOVSI, OFFSET XMOVDI, OFFSET YMOVBX, OFFSET ZMOVCX,4CLCAGAIN:MOVAL,SIADCAL,DIMOVBX,ALINCSIINCDIINCBXLOOPAGAIN4-20解：DATASEGMENTFIRSTDB99 DUP(？),$DATAENDSCODESEG