實(shí)驗(yàn)設(shè)計(jì)與數(shù)據(jù)處理課后題答案

1、第六章正交實(shí)驗(yàn)設(shè)計(jì)iJiiAfr?iJiiAfr?水溶液分離某種廢弄農(nóng)件物屮的木康髭考察r r二個(gè)W W素（溶劑濃度.隘度和時(shí)劉木質(zhì)索科率的彩響，因奈水平如卜衣所示.將WM.WM. B*B* C C依 次安川化IEIE交喪4 4屮）的1,2,31,2,3列、不也兇索間的交互作用。9 9個(gè)試鯊綃果 （ W W率/%低次為：5.3.5.3. 5.0,5.0,4,9.4,9.乩4 4、6.4.6.4. 3.7,3.7, 3.9,3.9, 3.3,3.3, Z4Z4試用直觀分析汰0000&W&W索i i次利優(yōu)方案.并廁;卄趨坍隆U U水平3）溶列#0釘反應(yīng)船呦 P(C)fttftiir

2、nui/h(C)fttftiirnui/h1 160601401403 32 280801601602 23 31001001801801 1%下占展示分析討程空冷.rr.rr .-.-.A0 0C CL LL LI IL L5.55.5!-!-In nn13 33 3i.gi.g 12 2I I:11 15 5小F.nr3 3I Ie.e. J J6n51 1dJ-J-1313 3r r3.33.3S3口1 1J JJ,J,JgnJ3 312.J JK1K110,210,21 be12.12. j j11* 1K：LJ.5 5Li.Li.；12.12. S SLLLL 6 6陷9.69.61

3、11115,15,：116116kiki5.075.07l.S；1.1. 1010J.J. rorok k：5.175.171,901,90J,J, ?.2020ki3.203.203.3. 7 61.79,61.79, 60.15,60.15, 73,97.73,97. 91.31,91.31, 7M.52,7M.52, 87.19,87.19, 97.2697.26；松HfHf度/(g/mL):/(g/mL):2 2.0080.693r.0080.693r 1.769,1.769, 1 1 269269 1.613,1.613, 2.775.2.775. 1.542,1.542, 1.11

4、5,1.115, 1.824.1.824.試用綜介十衡秒、對(duì)劭果進(jìn)行分析，找;I；址好的試鯊力耒.S.SS.S對(duì)轉(zhuǎn)化甲逬fjfj正交分折;試鯊號(hào)K4.K4.轉(zhuǎn)化率A AB Bc c1 11 11 11 11 1g g 26261n n u uc cc cJ J0.0. 16163 313 33 33 361.61. 79791 1n n1 1c c60.60. 1515n nn n3 3173-9773-976 6n n3 31 1n n91.3191.311 13 31 13 3沖73.73. 5252S S3 3n n1 13 3ST.ST. L9L9g g3 33 31 197.97.

5、2626KiKiItIt 5151173.173. 9393?1S.?1S. 7676c c】i i igigK.K.岀.1313F F S2S2197.197. STST20S.20S. 2929IGIG257-257- 9797250.250. 5656209,209, 2S2S209-209- 1313匕1?.1?. 505057.9857.989270.70. 5050krkr7R7R 1111ft?ft? 1 1師QAQAftafta B Bk.k.AS.AS. QQQQR3.R3. InInfig.fig. TfiTfifiQ.fiQ. 7171ffff水平A.A.B.B.G GW

6、 W勞R R38.38.旳25.25. ISIS6.6. 9696107107卞次昨屮A A、B.B. C C對(duì)鋼粉松密度進(jìn)行正交分析:試鯊號(hào)制粉松密度A A5 5C C1 11 11 1I I1 1:.oosn n1 1n nc c0.0. 6936933 31 13 33 33 31.7691.7691 1n n1 1r3 31.2691.2690 0r3 31 11.6131.6136 6*1*13 31 1n n2.2. 775775i3 31 13n nL512L512$ $3 3I3 31.1. 1151159 93 33 3c c1 11.81.8：1 1KiKiL170L170

7、1-8191-8195.5. 3983985.5. 1 115156 63.3. LiLi3.3. 7Rfi7Rfi5.5. 010010KnKnL L ISlISl6-36S6-36Sh h 9219211.1. 153153k.k.1.1. 190190k606k6061.1. 9669661.1. SicSic1,SS61,SS6k k 1101101.1. 2622621,6701,670k.k.1.1. 1911912.1232.1231.1. 611611L L 381381f/f.Atf/f.AtAlAlB B，G G榊V V R R0.3960.3960.9S20.9S2a a

8、 7017010.0. 131131卞次M M r-r-B B ( (:.:.A A対十轉(zhuǎn)化率指標(biāo)進(jìn)行K K觀分析對(duì)干銅椅松哥度指標(biāo)進(jìn)行n;n;規(guī)彷祐閔叢主次！B.B. C.C. A A優(yōu)方AA B B：、C C：而通過(guò)綜介半衡法可嘆得到平衡后的方案対:缶、BBCl即反應(yīng)溫fSfS取mere,mere, tt/Ett/E與氨水質(zhì)龜比取1 1：6565 550550屛祥液濃S S 0505仞mLmL卜3.L L通過(guò)正交試臉對(duì)對(duì)木澤草臺(tái)的P-P-環(huán)縄精包合工藝進(jìn)行擾化,離要考察的因數(shù)及水平如下：試蓋増析有兩個(gè)：包臺(tái)率和包含物收率，這兩個(gè)指標(biāo)都是越大越好.用正交裏LmLm(少)安擠試臉，將3 3個(gè)因

9、臺(tái)依次故在123123列上,不考定因素間的交互作用t t 9 9次試驗(yàn)結(jié)果依決如下:包合率丿 :1 12.102.101 1J5.86J6.95.8.60JJ5.86J6.95.8.60J 3*73*71,7,22,6.&4,778,5431,7,22,6.&4,778,543包合物收率/瞬:61.S061.S0 , , S4.3b&0,15,67.2377.2676.53,53.6176.1277.60S4.3b&0,15,67.2377.2676.53,53.6176.1277.60這兩個(gè)指標(biāo)的重要性不相同J J如果化成數(shù)S S,包合率和包含物收率重舉性之比

10、為3:23:2 , ,試連過(guò)綜合評(píng)分法確宦有方案D D解：tt 題意.這是一個(gè)3 3a a素3 3水平的試驗(yàn)，由于不考慮交互作用.所以可選 ffi 正交表LMLM 3 3耳)來(lái)安排試驗(yàn)。衾頭設(shè)計(jì)、試驗(yàn)萬(wàn)桑廉實(shí)驗(yàn)結(jié)果如下裘所不：*平( (A)A)原料配比( (B B ) )包奇鼠度噸1 11:11:150502 21.5:11.5:170703 32;12;16060( (C C) )包合時(shí)間卅試驗(yàn)方事&其試總結(jié)杲試驗(yàn)號(hào)A AB BC C芟列 包合率/%包合/%包合率隸S S度包合翎收率弟易爰蹤合分1 11 11 11 11 112.0112.0161.8061.800.570.570,

11、120,120 0 39392 21 12 22 22 215.6815.6884.3184.31 0.890.891.001.000030033 31 13 33 33 316.9516.9580.1580.15 1.001.000,840,840.940.944 42 21 12 23 38.608.6067.2367.230,280,280.340.340.300.305 52 22 23 31 11371137177.2677.26 0720720-730-730720726 62 23 31 12 27.227.2276.5376.530.160.160700700.380.387

12、73 31 13 32 26.546.5458.6158.610.100.100-000-000.060.068 83 32 21 13 377877878.1278.120200200760760420429 93 33 32 21 15.435.4377.6077.60 0000000740740.300.30KiKi2262260.750.75 1-191-191.411.41K KI I1401402,072,07 1 1 5353137137KsKs0780781 1 6262172172166166極臺(tái)R R1461461,321,320 0 53530.290.29因素蘭次A A

13、B BC C優(yōu)方羞AAKiKiKiKi匚因弟列：KjKzKi所以有粽合書廿S S欝罡憂方星対/VB/VB 、4.5.阻 苞m m斗站誑訐品神試?yán)L慶百4 4個(gè)閃盍：A A打釘越、B B（氮肥呈飛人C C:右 備、即 吧比例）*DfDf規(guī)S S人閃盤AtrAtr以牛水耶.*外三個(gè)閑畫陷trtr兩亍水平具體就值釦下去 麗小。處鑒指標(biāo)是產(chǎn)呈-聶值遊兀越好-試驗(yàn)第黑（嚴(yán)呈隹 I 依次為：1919靈205.205. 220.220.223223、JIO.JIO. 215215、J&J&；i.i. 190,190,試找出最好的案臉?lè)絹?lái).水平A AE ECn n1 1甲3:3: 3:3: L

14、Lex6ex62 2乙30302J1 1； 2 27X73 3內(nèi)1 1J J實(shí)驗(yàn)設(shè)計(jì)如s s下序號(hào)1川秦i-li-lA A1 1B B3 3C C4 4D D1 111 1i1L95L952 212 29 99 9J J9L19 92204 4z_2 22 212?52?5耳3L L212106 632 212 22Lo2Lo7 741 12c cLHIScS S42 211140140K1JK1J400400GIOGIOS20S20G20G20K2iK2i445S33S33S2ae帖K3K3J J425K41K4137S37SkJkJ7 7J_l4 44 44 4KlLliKlLli2002

15、00J02,5J02,520?20?205205K2LliK2Lli222.5222.52020&巧206.25206.25206.25206.25KariiKarii212.5212.5fUiAifUiAi1S51S5W W眾35356,256,25L25L251.251.25從上表可以療出閃素久的!臉崖員大囚此丸對(duì)實(shí)驗(yàn)的影I I舸最大.開索B B的至僅 次丁A A對(duì)丈驗(yàn)影咆也儀次丁A,A, W W素 6D D對(duì)實(shí)驗(yàn)歩眄較小*都以2 2水平校好.W W此最 憂空驗(yàn)方Y(jié) Y為A2B2C2D2.A2B2C2D2.6.6.4 4鋼片在鍍鋅前要用酸洗的方法除銹為了提高除鐫效率，縮短酸洗時(shí)間，

16、先安排酸洗述臉，考察描標(biāo)是酸a a時(shí)間 U 住除銹效果達(dá)到要求的情況下，酸洗時(shí)間越駆趣好，要垮慮的同素及苴水平加表4 4一1 1所示.采期擬水平法，將闔素C C的第 1 水平虛擬匚選取iHiH交表3 3列.務(wù)闔素C C B,B, A A、D D依次安排在1 1、2 2、乳4 4劌，試驗(yàn)結(jié)果(酸挽時(shí)間Anin)Anin)依坎為36,36, 32,32, 30,30, 21,21, U,U, 21,21, 16,16, 19.19. VLVL試找出較好的試驗(yàn)方幕 井進(jìn)行方曇分析口0=00=0亦)表牛1題4 4因素水平表水平(A)(A)硫酸抿度/倍L)L)iBlCHNzS/iBlCHNzS/值L L

17、）(C)(C)洗濟(jì)列種超(D(D謳度1 13 3（M M）1212屮書2 22002004 4乙90903 3250250乙7070解：直觀分析法采用擬水平法，將因素C C的第-水平虛擬選取正交表19(3),19(3),將因素G G B B、A A、D D依次女拝在1 1、2.2. 3.3. 4 4列，依據(jù)意，在ExcelExcel中列出正交表和認(rèn)臉結(jié)果。K K值的計(jì)算.K K值表示同一水平下對(duì)應(yīng)試臉結(jié)杲之和，以BPIBPI素列的K|K|計(jì)算為例，KiKi計(jì)算公式為=SUMTF(C$2:CS10J,SFS2:$FS10)SUMTF(C$2:CS10J,SFS2:$FS10)同理求得其它K K值

18、注意 由于將禺素C C的第 1 水平虛擬，所以CWCW素列K2K2計(jì)算的其它因素不同，K2K2計(jì)算公式-SUMTF(B$2:B-SUMTF(B$2:B 102SF$2:SFS10)+SUMTF(BS2:BS10,3102SF$2:SFS10)+SUMTF(BS2:BS10,3，$F52:$FS10)$F52:$FS10)(如圖4 4 1 1九 k k的計(jì)算。k k枕是K K的算術(shù)平均值本題中除了C C陽(yáng)素列k k2 2為k2=K2/6,k2=K2/6,其它k k值為k=K/3.k=K/3.fi 羞R R的計(jì)算。在B18B18單元格中輸入；=MAX(B15;B17)-MTN(B15;B17).=

19、MAX(B15;B17)-MTN(B15;B17).回 車后得到5 5。同理，可以求得其它因素列的R R值根撕極差R R值的大小可以劌出因素次順為D D、A A、C C、B.B.由于酸沈時(shí)間 越短越好， 所以本題確定的優(yōu)方案為DjAsGbDjAsGb， 即溫度70C,70C,硫酸濃度250gZL,250gZL,洗 滌劑種類為乙，CH4N2CH4N2S S為1212匹。1 1A A ! !試臉號(hào)B B1 1 C CB BJ廠E ED D4 4F F滋洗時(shí)面c c 1 1 H HC C2 21 11 11 11 11 136362 21 12 22 22 232323 31 1333 320204

20、 42 21 12 232222 , ,I I5 52 22 231 134346 62 23 31 12 22121 1 1J J7 73 31 13 32 216169 98 83 32 21 13 319191 110109 93 33 32 21 137371L1L888874747676lOTlOTT T2372371212& 1491491 1858591916969P=TVnP=TVn624162411313KjKj787870706161Q Q678767871414SSSS40.40. 50050020.20. 66766778.78.0000004Q2.6674Q2

21、.667SSSS * *5465461515kiki29292525252536361616血2525282830302317172626232320201818榜弄R R5 54 47 715151919因栄主D D A A C C B B2020優(yōu)方案DjACBDjACB；冷=5U=5U IF(B$2IF(B$2：BMOBMO Z$F$2Z$F$2：$F$10)tSlBIF(B$2$F$10)tSlBIF(B$2：b$163,$F$2b$163,$F$2：$F$10)$F$10)B12B12方差分析法計(jì)算離羞平方和SS.SS.計(jì)算A A由度dfodfo計(jì)算均方MS.MS.計(jì)算F F值. F

22、 F檢驗(yàn)（如圖4-24-2人2424差異糠SSSSdfdfISF Ffl 著性2525 _ _ _ -L-LA A73.73.0000002 21 1 39.39.0000009.369.362fB B 20,66720,6672 210,33310,3332.2. 48482727C C也5005001 140*40* 5005009.9. 72722S2S=:=-=:=-D D402.402. &67&672 2201.333201.333也32322929誤差匕4.4.1571571 14.4. 16716730302Lh=w(2J)1992Lh=w(2J)199 5Q0

23、5Q0 F FG G心(2J)(2J) 49994999 5005003273270 0 osos(1,1)(1,1) 16L16L 44S44S FyoJbFyoJb 1111 4052.4052. ISlISl圈*2*2制用ExcelExcel誑行方菱分析所以對(duì)于給定顯著性水平a=0,03a=0,03 W W索A A、EkEk C C、D D對(duì)試驗(yàn)結(jié)果沒(méi)有顯著的影響 H7.1 1為了通過(guò)正交試驗(yàn)訐找從茱礦物中提取稀上元的最憂T TK K條件*便秫土 元素提取率最奇.選取的W W素水平如下（見(jiàn)表IJIJ）表1 1 1因素表需要考慮的交蟲作用有AX&AXCBXC,AX&AXCB

24、XC,如果將人BCBC分別安排在正童表J J（，）（，）的1,201,20列上，試驗(yàn)結(jié)果提耽就/ml/ml）依次:L:L 1 1.0.01 1J J J J 3 3 J J J J 3,13,1.06,.06,1 1.05.05 A A SO,0,76,0.SO,0,76,0.5656 o o試用方差分析法CaCa =0.05=0.05）分析試驗(yàn) 結(jié)果，確左較優(yōu)工藝條件CA)SCA)SHIHI a a/mlCB)CB) A A HIHI S S/ml00反 應(yīng)時(shí)問(wèn)ZhZh1 155552C2C1 12 22020402 2解：列岀正交表LaLa (2)(2)和試驗(yàn)結(jié)果，見(jiàn)表1212*1-2*1

25、-2例1 1試驗(yàn)結(jié)果及分析試驗(yàn) 號(hào)1 12 23 34 45 56 67 7提取 fiyi/(ml)yi/(ml)A AB BAXBAXBC CAXCAXCBXCBXC空列1 11 11 11 11 11 11 11 11.011.012 21 11 11 12 22 22 22 21.331.333 31 12 22 21 11 12 22 21,131,134 41 12 22 22 22 21 11 11.061.065 52 21 12 21 121 12 21.031.036 62 21 12 22 21 12 21 10.80.8n n J J2 22 21 11 12 22 21

26、 1O O 76768 82 22 21 12 21 11 12 20.560.56K,K,4.4. 5305304.1704.1703.6603.6603.3. 9309303.5003.5003.6603.6603.6303.630K K 3.3. 1501503.3. 5105104.0204.0203.3. 7507504.1804.1804.0204.0204.4. 050050k,k,1.1. 133133LO43LO43O.9L5O.9L50.0. 9839830.8750.8750.9150.9150.0. 9089080 0 7887880.0.8788781.0051.00

27、50 0 9389381.0451.0451-1- 005005L013L013T=7.T=7. 6868極差R R1.1. 3803800.0.6606600.3600.3600.0. 1801800.6800.6800.3600.3600,4200,4200=7.78160=7.7816P=7P=7 37283728因素 丄次A,BXC,BA,BXC,B扎BXCpBBXCpB因素AiBiGAiBiG秦(2)(2)T=SUM(I3;II0)=7.68;Q=SUM(yi/)=7.7816(i=b2,3A5,6,7,8);T=SUM(I3;II0)=7.68;Q=SUM(yi/)=7.7816(

28、i=b2,3A5,6,7,8); P=TVn=7.68V8=7.3728;P=TVn=7.68V8=7.3728;計(jì)算力差平方和:總離差平方和:SSr=Q-P=7.78SSr=Q-P=7.781 16-7.3728=0.40886-7.3728=0.4088；因素與交互作用的離差平方和！SSSSA A=SS=SSI I=(1Z8)R=(1Z8)RA AS SI IZ ZTITIXK-K2)=(I/8)(4.53-3.15)=0.238()5;XK-K2)=(I/8)(4.53-3.15)=0.238()5;SSB=SS2=(l/8)RB=(l/r)(Kl-K2)Sl/8)(4.17-3.5iy

29、=0.05445;SSB=SS2=(l/8)RB=(l/r)(Kl-K2)Sl/8)(4.17-3.5iy=0.05445;SSgBSSgB尸冊(cè)3=13=r-l=2-l=l=(lfr-l=2-l=l；或dfi=dfr(dfk+dfdfi=dfr(dfk+df；j+df(AxB)-*-dfc-*-df(Axc)+df(BxC)=7(l+l+l+H-H-lj+df(AxB)-*-dfc-*-df(Axc)+df(BxC)=7(l+l+l+H-H-l ) ) =1=1(4)(4)計(jì)算均方：由于齊因素、交A A作用和盪差的門由度都為1,1,所以它們的 均方應(yīng)該等于它們備自的離羞平方和，B B卩；MSM

30、SA A=SS=SSA A=0.23805;MS=0.23805;MSB B=SS=SSB B=0.05445;=0.05445; MS(Ax8rSS(AxB)=0.0162;MSc=SSc=0.00405;MS(Ax8rSS(AxB)=0.0162;MSc=SSc=0.00405;MSMSAXCAXC,=SS(,=SS(AXCAXC)=O.0578;MS()=O.0578;MS(B B. .XCXC)=SS()=SS(BXCBXC-0162;MS-0162;MSC C=SS=SSC C=0.C2205;=0.C2205;可知：MS(AxB)vMSeMS(AxB)vMSe、MScMSc MS(

31、Bxc)Mse,MS(Bxc)AXC B B這與極善份析結(jié)果 是一致的.U） 憂方案的確11因?yàn)閲焖谹 A對(duì)試驗(yàn)結(jié)果有顯署影響，因素B、C和交旦作用AXGAXG AXAXB B對(duì)試驗(yàn)蠟果無(wú)顯著影響，所以從冇利利于障低涓耗，提髙效 益等目的來(lái)考慮別的水平，所以，因素B B取 df f用水雖2 2臥爪 內(nèi)素C C取珈反 應(yīng)時(shí)間IhhIhh因素八取K K值對(duì)應(yīng)的最大水平，即A A酸用25Tnk25Tnk所以最優(yōu)方案 為I I AlBjClaAlBjCla8.2 2、為了提高陶?；炷恋目钩鈴?qiáng)度*考察了他yCDEFyCDEF六個(gè)因素，每個(gè) 丙索有六個(gè)水平，丙索水平表如下（見(jiàn)表2-12-1）：）：表2J

32、2J因素木平（A A）水鐮拆號(hào)水/kg/kg槍用址伽秒車/%Ch）廉 護(hù)方式b）攬 捋時(shí)用A A1 1300300iHQ1501503空氣1 12 2400400HQHQ1801804040水1.51.53 350050020020020020042422 2根據(jù)經(jīng)驗(yàn)還要考案交i i作HJHJ如果將A A，E,GDE,GD f f俄次女并在正便表 切（護(hù)）的1,2,512331,2,51233列上，試驗(yàn)結(jié)果（抗跖亦?）依次為1 100,9,97,95,96,99,94,9%!00,9,97,95,96,99,94,9%!0101, ,遼陸9 9&陸90,90,陸91/291/2甌7 7

33、玄沁力朋禹久7 7砧9,79,7處5,5,訕用方菱分析法（a a =0.05=0.05）分析試驗(yàn)結(jié)果，確定較冇水平組合.解：（1 1）實(shí)驗(yàn)設(shè)計(jì)：本實(shí)驗(yàn)要考慮靑個(gè)因索ff 三種交互作用.且毎種變A A作用占兩列， 這樣因素和交互作用在正交表中總共片冇1212列， 所以應(yīng)該選 ff 正 空表匚 （Jb,Jb,根粥 5.（3 3門）的交互作用表和題日豊求a a行表頭詵計(jì)，然后進(jìn) 疔試臉，得別試臉結(jié)果yiyi CL2.CL2.F F 2727）. .試驗(yàn)設(shè)計(jì)及結(jié)果列于表2 2 2 2 表2 2 2 2試驗(yàn)設(shè)計(jì)及結(jié)果試M1 11 1A A1 12 2B B1 13(A(AX X B),B),1 14 4

34、(A(AX X B),B),1 15 5C C1 16 6(A(AX X0,1 17 7(A(AX X0,1 18 8(K(KX X c)c)：1 19 9D D1 11010空 列1 11111(B(BX XC)iC)i1 11212E E1 11313F F1 11001002 21 11 11 11 12 22 22 22 22 22 222 22 298983 31 11 1I I1 13 33 33 33 33 33 33 33 33 397974 4J J2 22 22 21 11 11 12 22 22 23 33 339595a a1 12 22 22 22 22 22 23

35、33 33 31 11 1L9696t tJ J2 22 22 23 33 33 31 11 11 122 22w w1J J3 33 33 31 11 11 13 33 33 322 22 29494a a1 13 33 33 32 22 22 21 11 11 13 33 33 399g g1 13 33 33 33 33 33 32 22 221 11 1i i101101LOLO2 21 12 23 31 12 23 31 12 23 31 12 23S5S5n n21 12 23 32 23 31 12 23 31 12 23 3I828212122 21 12 23 33 31 1

36、2 23 31 12 23 3I I2 29S13132 22 23 31 11 12 23 32 23 31 13 31 12 28585u u2 22 23 31 12 23 31 13 31 12 21 12 23 390ISIS2 223 31 13 3I IZ1 12 23 323 3i i拓IKIK2 23 31 121 12 23 33 31 19 92 23 31 19191171723 31 12 223 31 11 12 23 33 31 12 28989l l 23 31 12 23 31 12 22 23 3I I1 12 23 38080IVIV3 31 13 32

37、21 13 32 2I I3 32 21 13 32 2737320203 31 13 32 22 21 13 32 21 132 21 13 3909021213 31 13 323 32 2I I3 32 21 13 32 21 17777i23 32 21 13 31 13 32 22 21 13 33 32 21 1B4B423233 32 21 13 32 21 13 33 32 21 11 13 32 2808024243 32 21 13 33 32 21 11 13 32 22 21 13 3767625253 33 32 21 11 13 32 23 321 12 21 13

38、 3898926263 33 32 21 12 2I I3 3I I3 32 23 32 21 1787827273 33 32 21 13 32 21 12 21 13 31 13 328282 879879BOOBOO795795807807796796800800788788784784836836791791790790824824794794T=2396,T=2396,KiKi785785700700807807790790802802702702802802800800709709800800804804786786801801P-212622,P-212622,82K.K.732

39、732B06B06794794799799798798801801806806812812761761805805802802787787801801Q-214418Q-214418k,k,293.0293.0266.7266.7265.0265.0269.0269.026S.326S.3266.7266.7262.7262.7261.3261.3278.7278.7263.263. 7 7263.3263.3274.7274.7264.7264.7kiki261.7261.726X326X3269,0269,0263.3263.3267.3267.3264.0264.0267.3267.32

40、66,7266,7266266 3 3266.7266.7Z6S.0Z6S.0261.7261.7267.0267.0kiki244.0244.026B.26B. 7 7264.7264.7266-3266-3266.0266.0268.0268.07 7270-7270-725X725X726B.26B. 3 3267_3267_3262-3262-3267.0267.0極1471471616131317176 612121818282875751414141439397 7兒D,D, E,E, BXC,BXC, B,B, AXCAXB,AXCAXB, F,F, C C(2(2+y27)=2

41、596,Q=SUM(y,+y27)=2596,Q=SUM(y,+yi+yi+ -+y2214418,P=T/n=2396/27=212622.82-+y2214418,P=T/n=2396/27=212622.82所以離差平方和：SSSST T=Q-P=21441=Q-P=214418-212622.82=1796.7398-212622.82=1796.739SSB=l/9(Kf+KSSB=l/9(Kf+K*K K)=l/9(8(K)2T902+8062)l/9(8(K)2T902+8062) 212622.Ji2=14.518212622.Ji2=14.518, ,SS(AxB)i=l/9

42、(K/+K2+K32)=l/9(795+80r+7S4212622.82=11.629,SS(AxB)i=l/9(K/+K2+K32)=l/9(795+80r+7S4212622.82=11.629,SSSSAXBAXB)2=V9(K/+K2*1C/)=1/9(807V790+799)-212622,82=16,074,)2=V9(K/+K2*1C/)=1/9(807V790+799)-212622,82=16,074,SSc=l/9(K?+K22+K/)=i/9(7962+8022+79*4212622$2=2.074SSc=l/9(K?+K22+K/)=i/9(7962+8022+79*4

43、212622$2=2.074, ,SS(ASS(A X X GiT/9(Kr+KGiT/9(Kr+K+K32)=1/9(8OO2+7922+8042).212622.82=&296,+K32)=1/9(8OO2+7922+8042).212622.82=&296, SS(ASS(A X X 02=1/9(17+02=1/9(17+陶2 2+K$2)=1/9(7882+K$2)=1/9(7882十80248062)-212622.82=19.852,80248062)-212622.82=19.852,SS212622.82-3.852,SS212622.82-3.852,SSS

44、SO O=1/9(=1/9(K K7+K22+K,)=1/9(83627+K22+K,)=1/9(8362+7992+7612)-212622.82=312-51+7992+7612)-212622.82=312-51 R R , ,SSc=V9K/4-K22+K3)=l/9(79p+800M12)-212622.82=ll.l85SSc=V9K/4-K22+K3)=l/9(79p+800M12)-212622.82=ll.l85, ,SS(SS(BMBM)2=1/9(K)2=1/9(KI I2+2+K K22+22+K K,)F/9(7902+804,)F/9(7902+804；十80280

45、2 212622.82=12.741,212622.82=12.741, SSb=lSSb=l /9(K/+K22-/9(K/+K22-K KK/)=1K/)=1/9(824247852/9(824247852 872)872) 212622.82=107.182212622.82=107.182, ,SSSSF FT/9(K2+KT/9(K2+KZ Z2 2亠&2&2戸i/9(7942+goi2+g02)212622.82-3.629i/9(7942+goi2+g02)212622.82-3.629所以：SS(AXB)=SSSS(AXB)=SS(從B B) )I I+SS(+

46、SS(AXBAXB)2=11)2=11 629+1629+1 6.074-27.703,6.074-27.703, SS(SS(AXCAXC)SS()SS(AXQIAXQI*-SS(*-SS(AXAX02=8-296+19.852=28.148,02=8-296+19.852=28.148, SSgc:SSgc:尸SS(SS(BMHBMH十SS(Bxq2=43.852+12.741=56.593SS(Bxq2=43.852+12.741=56.593(3)(3)計(jì)算口由度：總自由度：dfrFdfrF仁27J=26,27J=26,各囲素A A由度：da=df=lt=dfiy=dfE=dft.=r

47、-1=3-1da=df=2=2+2H,gB2=2+2H,同理dfiAxc=dfXdf=2dfiAxc=dfXdf=2X X 2=4,2=4, d&Bxcd&Bxc尸d d綣X XdC=2dC=2X2=4,X2=4,平方和s s T=SUM(OIOT=SUM(OIO算離差5 5O36)=(yi+y2O36)=(yi+y2+ +渓差自由度：dfdf；=r-I=3-l=2=r-I=3-l=2或dfdfrdfkdfirdSdbd6d*dfiAxBrUAxcdfdfrdfkdfirdSdbd6d*dfiAxBrUAxc廠dfgdfg c)=2d2c)=2d2 222222 2444=22

48、444=2：(4)(4)計(jì)算均方：各W W素和交A A作用的均方為：MSMSA A二SSA/lfi=1231SSA/=28.148/4=7.037,MS(AxcrSS(Axc/dfiAxc=28.148/4=7.037,MSc=SSc/dt=2.074Z2=lMSc=SSc/dt=2.074Z2=l .037.037.MSiy=SSD/dfo-312.518/2-156.259,MSE=SSE/dfe=107.I82y2=53.59bMSiy=SSD/dfo-312.518/2-156.259,MSE=SSE/dfe=107.I82y2=53.59bMSrSSF/dfk=3.629/2=lMS

49、rSSF/dfk=3.629/2=l .81,.81, M&M&B BM M尸S SS S伽cyd&Bg=5cyd&Bg=56 6 593/4=1593/4=14 4 1414& &但渓差的均方為s s MSc-SS/dfc-1MSc-SS/dfc-11 1J J85/2-5,59385/2-5,593 計(jì)算到這里，我們發(fā)現(xiàn)M&M&V VMSMSG GMSMSFVFVM&M&P P這說(shuō)明因素C C、F F對(duì)試驗(yàn)結(jié)果的彩響較小，可以將它們歸 入差，這樣新渓差離差平方和為：SScSSc =SSc+SSF+SSc=3.6

50、29+n.185+2.074=16.888,=SSc+SSF+SSc=3.629+n.185+2.074=16.888,新溟 差自由 度為；叫 =dfi+dt+d=dfi+dt+df2f2十2 2十2=6,2=6,新 差均方為：MSeSSfMSeSSf/1/1仏1 16.6.888/6=2888/6=2.8.81515(5)(5)計(jì)算F F值：F FA A=MS=MSA AZMSZMSC C=61=61 5.815/2.815.815/2.815=25=2 18-762J18-762JB B-MS-MSB B/MS/MSC C=7.259/2.8=7.259/2.8 15=2.579,15=2

51、.579,F(AxB)=MS(AxB)/MSe=6.926/2.815=2.46O,F(AxB)=MS(AxB)/MSe=6.926/2.815=2.46O,F(Axc)=MStAxc)/MScM.037/2.815=2.500,F(Axc)=MStAxc)/MScM.037/2.815=2.500,F(Bxc)=MS(Bxc)/MSe=lF(Bxc)=MS(Bxc)/MSe=l 4.148/2.815=5.026,4.148/2.815=5.026,F FD D-MS-MSD D/MS/MSC C-56.259/2.815=55.5O9,F-56.259/2.815=55.5O9,FB B=

52、MS=MSI IAIS?=53.592.815=19.037AIS?=53.592.815=19.037(6)(6)檢驗(yàn)査得臨界值F FO O. .O O5 5 (2,6)(2,6) =5.14,=5.14, ?0.01(2,6)=10.92,?0.01(2,6)=10.92, Ftm(4,6)=4.53,Ftm(4,6)=4.53, F FO O.(.(.I I(4,6)=9.15,(4,6)=9.15,所以對(duì)于給定的顯著性水平a a =0.05,=0.05,因素A,D,EA,D,E對(duì)試驗(yàn)結(jié)果有 非常顯著的影響，交互作用BXCBXC對(duì)試驗(yàn)結(jié)果有顯著彩響，肉素B,C,FB,C,F和交互作 用A

53、XBAXCAXBAXC對(duì)試驗(yàn)結(jié)果為沒(méi)有顯著影響。最后將分栃結(jié)果列于方分析表中(見(jiàn)表2-3)2-3)表23方差分析表址異源SSSSdfdfMSMSF F顯著性A A1231.6291231.6292 2615.615. 815815218.218. 762762*B B14.14. 5185182 27.2597.2592.3792.379AXBAXB27.27.70346.9266.9262.462.46AXCAXC2&2& 1481484 47.0377.0372.2. 5 5BXCBXC56,56, 5935934 414.14814.1485-0265-026D D312

54、.312. 5185182 2156.156. 25925955.50955.509*E E107.107. 1821822 253.53. 595919.03719.037*c c2.0742.0742 2F F3.6293.6292 22,8152,815俁花e e12.12. 7417412 2總和1796.1796. 7357352626（7 7）優(yōu)方梟的確定：山丁試驗(yàn)指標(biāo)足抗壓強(qiáng)皮，抗樂(lè)強(qiáng)皮足越大越好，從灤2 2 2 2可 以看出， 在不考慮交互作用的悄況下， 優(yōu)方案収各岡素a a大K K之所對(duì)應(yīng)的水平， 即為AiBjCDiEiFAiBjCDiEiF：或A AI IDGDEDGDEI

55、 IF F）。從方墾分析結(jié)果可以看出，W W素AQ.EAQ.E對(duì)試驗(yàn)結(jié)果有非 常顯著的彫響;因素B,GB,GF F和交互作用BXCBXC對(duì)試驗(yàn)結(jié)果有顯著彫響，但遠(yuǎn)不及岡索岡紊A4EA4E對(duì)試驗(yàn)結(jié)果的影響，所以對(duì)丁閃素BQ,BQ, F F應(yīng)從有利T T降低消範(fàn)，提高效率的 的來(lái)方別的水平，分別取水泥fflSfflS180kg,C,:180kg,C,: filfil用雖150kg,150kg, FlFl攪拌時(shí)rnilhrnilh：而又交互作m m AXB,AXCAXB,AXC對(duì)試驗(yàn)結(jié)果無(wú)顯著影響.綜上=本例任確定閔索A A佩C,D,EFC,D,EF優(yōu)水T T足可以不芳慮交互作用，即優(yōu)*棠為A,B,

56、C,DiE,FicA,B,C,DiE,Fic7-1.7-1. 啤 ffi 生產(chǎn)的某項(xiàng)T T藝試驗(yàn)中，選取了底水?ft（A A）和吸氮時(shí)間（B B）兩個(gè)因素,都選取了8 8個(gè)水平.進(jìn)行均勻認(rèn)驗(yàn)設(shè)ihih m m索水平如下表所示”弒獨(dú)指標(biāo)為吸氨雖， 越大趙爪選用均勻表叭（霽安排試驗(yàn).e e個(gè)試驗(yàn)結(jié)果（吸鼠杲AiAi）依次九*5.5. 8,8, 6.6. 3,3, 4.4. 5.5. 1 1 4.4. 0,0, 4.4. 5,5, 3.3. 0,0, 3.3. 6.6.已知試驗(yàn)指際與兩因秦之間成一元線性關(guān)系，試用回0 0分析法找出較好工藝條件，解；根粥使用表可以知，當(dāng)囲素為2 2時(shí)，應(yīng)將小 7 分別

57、放在表的1*31*3列匕，婦圖所示，序號(hào)底水量UD/UD/呂吸氨時(shí)間aM/minaM/min吸氨量盹_1 11(136.5)1(136.5)4(200)5*85*82 22 2 C137.C137. 0)0)3(240)3(240)6.36.33 33(3( 90)90)4.94.94 44 4 C13S.C13S. Q)Q)7(20)7(20)5 5 g g5 55 5 C13C13&引2(130)2(130)4 46 66 6 039.039. 0)0)6(220)6(220)4,54,57 77(139.5)7(139.5)1(170)1(170)3 3S8 8 C140,C14

58、0, 0)0)5 50)0)3*63*6由題總知 :閡變呈丫與口變量葢1,1, KmKm之間的近似函數(shù)關(guān)系式為：yF+hxyF+hx也X2X2口JMJM轍OUTPLT刮戒計(jì)Q.即咖6 旳炯測(cè)12O;W&1?63160.032403703S1.第七章均勻設(shè)計(jì)水平號(hào) 底水量txiyytxiyy吸氨時(shí)間（耳2 2血11115 51輒5 52102106 639.039.02202207139.5139.5230230百1401402 2屯）底水雖（xlj/gxlj/g吸竝苛間（x2x2）/niin/niin136L5171)171)137.C137.CISOISO137.5137.51901

59、9013K.13K.200200lulTiplflulTiplfK K SquaareSquaareAdjuFTfldAdjuFTfld R RScjuareScjuareSJfS方S S分祈0 0歸怖裁皚flSflS P P SiBitifiar.zeSiBitifiar.ze I IS 訂話肛蚊舐S. 3GE-09C. 00K5IntcKCftIntcKCft卷星(iD/e答SU2Efl,fl, O3K5O3K5 L刃歹5灘S S差.1.1 S:atS:atf皿丘LowerLower埶lrplrpr r蚓確液 硝矗葩芒妙lflO.3351也丫燒g咖門監(jiān)1弋伽g-0,粘9帥-rq弋罰側(cè)0,0

60、血920,025175亂謔!）救 何1托CoefficitniECoefficitniE9LSJ5g3333 1.燈鬆俎戎.凹L劑乜0鄒總礙饒T 0.013470.0.573.3. fifi：92.丈LCflLCfl:.:.DODO：.9O.9O1.001.00-1. D-1.30300.0.37a a；T3.13S3. 36l.CO1. Mj.00j.00-:.oo-:.oo1.1. ODOD-LOO037037a a ? ?亂巧sr.sosr.sol.CO：.M.Mj.OOj.OO= 1.00=h H1.001.000,0,J?0.0. 3737乩 STST73, L ：L Lco：.Mi.i.coco1.051.050,0,QDQD0 0 00000.0.茸7 叼；9393師二i1.1.M MQ WLOOLOO-J-J 噸d d ODODO.MO.M0.0. 53534 撫30.16161.:Eth W)7.007.000.000.001.1. 03030