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2009年貴州省高考數(shù)學(xué)重點(diǎn)內(nèi)容分類精析)Ma,a,aa,aMa,a,a,a.M2123412312aPa,bPab,ab,ab,P.設(shè)b0數(shù)bPQ,M1QM)2xfxfgx.yx1f12.Rfxfxyfxfy2xy(,R),f361,111516xx2f.fx2x2,x1xf2③b;②ba;③cab;④bca①afx3,fx23(xR,p,pfxxpxp121212fx,fxfxx,fx112fx,fxfx212fxp,p1)求fxx12fx,bab,,abfafb)設(shè)a且pp12ba,n,banm)2(x)fxx()()ffx1fxfxx32312xpxp123323xpxp2x.)12xpxp(x)p(x)pp(pR由于,的最大值為121212pp12322pp,即pp21123pp2f(x)f(x)x[a,b])1231abyfafbapbp1及,213,xp)px)f(x)113,xp1xp11f(x)[a,b]abba為b)Ox圖122pp2pppplog2)當(dāng)12312,213xpf(x)3p3pf(x)f(x)f(x)xx;121121xpf(x)31333xp233xp2f(x)當(dāng)xpppxppplog2121221322f(x)f(x);2pxp1f(x)31f(x)232323當(dāng)xp1pxxp2px122f(x與f(x)y12pp1xlog2⑴122203100pxp[(pp)log2]p,21022132xpp在與20121Oxf(x),pxxf(x)110圖2f(x),xxp202f(x),axx[a,b]f(x))10f(x),xxb20f(x)f(x)f(x)在區(qū)間[a,b]及12(xp)(bp)f(a)fb)323pabp21012ppablog2⑵1231ba(xp(p)b[plog2]22012123ba(x)[a,b]f。2x216xq.fx)qt0),x當(dāng)fxD)問:是否存在常數(shù)t為12t.9ttt1(tt40)e50,0t10,tVt)244(10)(341)50,1012.tt1ti(Ⅰ)該水庫的蓄求量小于的時(shí)期稱為枯水期.以i表示第1月份(i2.7e..10t10時(shí),Vt()(tt02,xtte244t100t100t4t.②當(dāng)10t12Vt)4(tt50tt0,41解得10t10t1210t12.故3或0t410t12;1235..1311414ct(tt4)cttt由=2424令當(dāng)t)與Vt+80))在8;BByAx)32fxxx3,f(x)3x)cos(x)0π0(,π.yf(x)2πf8πyf(x)6yg(x)g(x)4f(x)3sin(x)cos(x)231πx)x)x.226f(x)xRf(x)f(x),ππsin(x)x.66ππππxxxx即,6666ππx000.xR66πππ0πf(x)xx.6222ππππ22f(x)2x2.f284ππ(x)ffx.66πππ(x)fx2cos2x2cos2xg663π≤2π2x≤2ππkZ(當(dāng)3π2π≤≤即ππxk()(kZgx63π2πg(shù)(x)kπ,πkZ(k63B及P,BOPDC.OBAO將表示成yABxOP將yx)AQ10OA,coscos10=1010tan故OB,cos1010110costan,所求函數(shù)關(guān)系式為所以O(shè)ABOPycs2010sincos0y104xxxx-x222x2x220x2000x10ycos1y'2210令y'0得=,246,y是0y當(dāng)當(dāng)'6,0103。yy',是=y646min33P邊(AAxxRfx1)(,323f,,fffx知2511A1f(x)x)M(,)sin(),323250f(x)sin(x)cosx而,,;3362212cos,cos,(0,),51323451(),sin1()22,55312455651351365f))coscossinsin。)2,AC2BCABCAB5ABC.,B,Ca,b,ca,2bAB,2DcosB則C交于。EAB。BCD9060150,CBACCD000150,062cosCBEcos4530042在12AE2300故0262sin4515sin9015cos150620004(,2)(x)x)((0,)17f則在633B)(02)B(2)C(31)218ABCDA,,點(diǎn)D722,48(1,2)b(2,m),2ab=aa//bc△ABCCa為m(1),n(cossin)mnacosBbcosAcsinC,,,BA3622131,b,m(m,,使21a22atan23,dmabtan,且cd.cff,m63)12345678926nnn33n3n2ana1aa23aaa456aaaa97810,a,a,a,bba1Sa.,.b124711nnnbn≥nnbSS2nnn1bSnn481k(k≥3)91b≥n21Sbbb,nbSS2n12nnnn2(SS)2(SS)111211,nn1nn1(SS)SSSSSSn2nn1nnn1nn111又Sba12111Sn11n121(n,S.221nnSn222≥n1nn2bSS.n(nnnn1,n,2b,n≥.nn(n1)qq0.1213因?yàn)?21278,21aan8142bqbq2.a(chǎn)2911314k(k≥3)S,bq)22)2kkS2)(k≥.則kk1qk(k12k(k,a,,an≥40d24a(n12na4n1dnn(n≥4b,b12n,a,a,a,a1234。aaaaa(a)a4d01142,即(a2)22314111da1(ad)a(a3d)ad011aaaa322214111da1a或14。dd,a,a,a,aa,a,a,a,a123451245aaaaad)(ad)(a)d02aa3152411110為da3,a,a,,a,a,a當(dāng)6a123n2n1n0aaaa,則必有a,這與d21n3n20a,,aaaa去aan1d1n3n23n20aaaadn61n2n1)nd的nb4。,bb,12n,b,b01xyzn2bbbb(,x1y1z1y1x1z1(byd)(bxd)(bzd)(yxz)d(xz2y)bd即222)11110yxzxz2y與00由bd12xzxz2y與xyz當(dāng)y20by2xzxz2y與故y21dxz2yb0xyzn1z1dbn要1d222,n1)2,)x2,x0(x)()fxxf2x2,x0x00Ay21ayx2xyaAa3(x)xx(ax1,af3232(x)x1在af(x)xxa1a(0,)xf'2y2,y,zx2y3z03)i3(1i)21ibi(a,bR,iab1ia1.1,30a2zaz(ai)2iia2(a3a2)(a1)ia21i)3iR()aiiaa2zi=.)x1y(3y10ax11xbyx(xbln1y21(x)ax(,bZ)yf(x)(2f39f.xb(x)ff(x)f(x)yy=x12b1,1a2aa,9a,48b.3()fxa或(xb)2b,,b)21因,bZf(x)x.x11xy,y21x1g(x)xx1f(x)x11g(x)a(11)f(x)x1(x)(11)f1,xx.100x01xx1120()11()由fxyxx.0(x201x(1)0x20001x1x1得yx1,0令x.0x101x0yx得y2x1yx(2x2x1)令.000x1yx(11).1112x12x112x22.02x12x100002.ii1),i4n6an3m,否(注:框圖中的賦值符號(hào)“namaam和n是數(shù)i3。pp0.8n.1110.8n4.248否是nnn1)f(x)logx(a0,a1)alog20則②alog20f(x)logx(a0,a1)aalog20f(x)logx(a0,a1)aalog20f(x)logx(a0,a1)aalog20f(x)logx(a0,a1)aa:q:pD).(p)qpq.(p)(q)D.(p)(q).qp(p)(q)為)0a0aa1a(nN)a,a,,22.1n1n1nnn記Saaa.n12n111Tn.1aaa)aa)a)11212nnNaaSn2T3。nn1nn1xx102aana.212k(kN)aakn*,k1a(aa1)(aa1)(aa)(aa1)a2222k1kk2k2k1k1k2k1k2k1aa.k1k2k1aannn1nN*aann1a1an),得,,1(n≥2(Ⅱ)證明:由a2,k2k1k1ka(aaa)(n1)a.221n23n0Sn1a2.a(chǎn)1nnaa1a2a1a1Sn2.n由a及得22nn1n1nn1n1aa1a≥2a≤(kn1na22k11a2ak1k1kkk1k1a≤(a≥,naa)(1a)2an234n211aa≤(n≥,nnn2aa)a)2(aa)22n2n22223n211n≥3T11n3,22n2TTT3T.123n);),18的33C171633,318121P.17163681與p221.16p;12.AB121PB1p2163534p或4411314,PA,PB,PBPA2241112P0PAPBB24321112P1PAPBBCPBPBPA1224321131172224442321392P3PAPBB2432153221013PPPP01231715329P3232321715901232E32323232D2的E1DED412EP44)CGHI1A2AFAHEGDBBBBCBCBIEEEEDE①②③④F圖1圖222S11213.223)22ABCD中,CBCDADBD,F(xiàn)分BABBDEF//ACDEFCBCD面.面ABBD,DCA∥

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