高中物理知識點 【全】

必修1知識點txxtxttvato22ov0t2t2v2v20t2x2x20g122R2FNNNNa與FFm必修2知識點WFLcos0WFL90W0WFL.WP；tEPE。WGPE。P1Emv22k表達式：WEE或合合kpEEEEE()EE1t02vltrad/stTvr/T,/,Tvr。v2.2r2rnF2gRraTF2r22R2r222r2T2rv23Tv7.9km/s；v11.2km/s；v16.7km/s。GR2RGMmmgR2e192r2K10N·mC。922qFFF值qEqEE與FE與qKQEEFEqqqUdb；末b增；12vvxvt，x00vat,ay2y0y200經(jīng)一定加速電壓（U122yU有224dU21Lv0EUF和aC(UUSbCkdQCQCUSCCCKdXqt12UIR；UUU。IRrRRRrOOr，rIUUU，1rRrUr第11頁共55頁2R22RR=r2R22rrI24r2r當I。PI11PIU2224rrr2U24rURr。U2IrnRnrURISLRSSURIIURIUUURxA內(nèi)IIxAxURRR和RRV外IxxAVxxVxVxAxRRRVRxAx0A0RR0RR0AV0R<Rx0RRAV阻RRRrRxzgI隨RxRRrRRRxgxzxR=xI0Rxgz當Rxx1RRRxzxgzzzRRR1IzzgRnRnR。zzRz1—3RR3zz12n1或Unn；或n1；121RURPR2總總22總總ggUIRI或ggggRg串U串ggb1并R12nRRR或I總總；2n1RIRPRPR1總n21總nggg1RnIn1并并IggggU1測出路端電壓UI11U22IUIU21121121r221221UU是IUtgr。IWPUIt2U22RU2PIR2R2222S=S=4=S（2）nB）+==）=－12LBBIF=為B與為BILF.=F=m=F=0f=vBv與B=f==s=v與B=：RRPTVfBqmT21P2BqREmV22Kf、ff6ABf+=121:,,有22EvB2R22,BqBBq。qBBqdd122212.v2得R2R22=2mD4則v=mm1E=mv22222m22TB22m2=·u（是B與SSS、、BSvLB。FBIL以vF'FBILS時，外力功W。·L·S·ttB、、vSLv·tB·SBLv·tt/:nt/有關,t:Blvsin:1),B)為v與Bl即lB:/:LIt/ItntB:S,,由,S,ntBtBt,若是恒定的,,B·S,,Bt,,,磁21,t,大,及tttvIt及,,及也vaIvtBlv,,1,l繞A動,,,求,顯然,,vvl,且,ACv,即。2vACCBl22212BLL2OtS20增·L到2122At/2OSnB勻md·v2d·BLvBL，ab221BS。c端2aeb．c．MNMNmvv.m···cosnBS如是即時速度，則為即時感應電動勢。如是平均速度，則為平均感應電動勢。tto122···cosnBS（··線圈平面與磁場平行時有感應電動勢最大值nBSm····cos瞬時值公式，是線圈平面與磁場方向夾角nBS,,,在為ttR,,產(chǎn)生建立I感原感感感感原,2,,L與L,I和I,ALAS,燈A,AIAL,L,ILIL,A;,IIALAAI和I,LLALA,RR，。IILALALALALtLL（。圖2NmeiI·tm若從線圈平面與磁力線平行開始計時，則感應電動勢瞬時值表達式為：I·tmmmII。mU；mT1。f：秒Te·t3mmmm；．n即1n2·IU·I1122I即2IUUII1221123123112233PP入出11221212UnUnUn11223312入出1231221nInI+nI+1122334nn）一定時，輸出電壓U1222211nnU121121221PPPP負221222222總線U11R()UnUP22I11211221115/Δt“123I2損線出2P出損線IBU．dHH電路傳感器）角頻率1T,f。fTF=－axAt)Asin(t)tTT00。Lg1中LLLm，123LL<23dd21LOT11g12d(LLsin)212.gMR22g值=g+a=gxyvv，Tv.1.2::①②穩(wěn).fX的成③1110.0:ld1220tv1()2ctVu'2mm2cmvm00E2Emc2）2,,啊為I=或P21PPABAB:,,,,1111+mv22mvm1212mvmv=mvmv＇1122112212PM；過12mmO+m12N例3B使AGBAGBB中ORBOB．BAO點ABGAAsBmmAmsBmsms，BAm、BAAAABBAmsss．BAABAmBmAB．Avv6.950.695m/s/0.0250.025AAmv··AAABA、非彈性碰完全非彈性12122121212mv，22．．．④9當0，00h、）。1R()n3,4,5,...22巴耳末公式R=1.1010m里德伯常量71212的整數(shù)倍，即：軌道半徑跟電了動量的乘積等于2的整數(shù)倍，即nErnnE1n22n1ErE－111rm)1性質(zhì)成份組成很較很類型