C語言第二次作業(yè)答案

. .. .. .. .........C語言第二次作業(yè)1.4100400年是閏年。判斷從鍵盤輸入的年份是否為閏年。ifelse#include<stdio.h>intmain(){intx;printf("請輸入年份：\n");scanf("%d",&x);if(x%4==0&&x%100!=0||x%400==0)printf("是閏年.\n");elseprintf("不是閏年.\n");return0;}三：調(diào)試結(jié)果：. .. .. .. .........2、某個自動加油站有‘a(chǎn)’三種汽油品種，單價分別為(元/5%10my和服務(wù)類型‘‘’—協(xié)助加（’—自動加無優(yōu)惠，pay（switch。switch二、實驗容：#include<stdio.h>#include<math.h>intmain(){floatp,q,m,pay;chary,z;printf("請輸入汽油品種(y)，服務(wù)類型(z)，加油量(m)\n");scanf("%c,%c,%f",&y,&z,&m);switch(y){case'a':p=6.92;break;case'b':p=7.37;break;case'c':p=7.64;break;}switch(z){case'f':q=1;break;case'm':q=0.95;break;case'e':q=0.9;break;}pay=p*q*m;printf("pay=%.2f\n",pay);return0;}三：調(diào)試結(jié)果：3、輸入三角形三邊，判斷該三角形是什么三角形（等邊，等腰，普通和直角）switch二、實驗容：#include<stdio.h>intmain(){inta,b,c;printf("請輸入三角形的三邊長：\n");scanf("%d,%d,%d",&a,&b,&c);if(a==b&&b==c)printf("此三角形是等邊三角形");elseif(a==b||b==c||a==c)printf("此三角形是等腰三角形");elseif(a*a+b*b==c*c||a*a+c*c==b*b||b*b+c*c==a*a)printf("此三角形是直角三角形");elseprintf("此三角形是普通三角形");return0;}三、調(diào)試結(jié)果........... .. .. .. .........1~3（語句）1、FindNum2、Diamond3、Goodbye!Input1-3:switch二、實驗容：#include<stdio.h>intmain(){intm;printf(1-3scanf("%d",&m);switch(m){case1:printf("FindNum\n");break;case2:printf("Diamond\n");break;case3:printf("Goodbye!\n");break;default:printf("error!\n");}return0;}三、調(diào)試結(jié)果:4if二、實驗容：#include<stdio.h>intmain(){inta,b,c,d,m;printf("請輸入四個數(shù):\n");scanf("%d,%d,%d,%d",&a,&b,&c,&d);if(a>b){m=a;a=b;b=m;}. .. .. .. .........if(a>c){m=a;a=c;c=m;}if(a>d){m=a;a=d;d=m;}if(b>c){m=b;b=c;c=m;}if(b>d){m=b;b=d;d=m;}if(c>d){m=c;c=d;d=m;}printf("%d,%d,%d,%d\n",a,b,c,d);return0;}三、調(diào)試結(jié)果:ax2+bx+c=0b2-4ac>0b2-4ac=0. .. .. .. .........if【#include<stdio.h>#include<math.h>intmain(){doublea,b,c,x1,x2,m,n;scanf("%lf,%lf,%lf",&a,&b,&c);if(a==0)printf(aelseif((b*b-4*a*c)>=0){x1=(-b+sqrt(b*b-4*a*c))/(2*a);x2=(-b-sqrt(b*b-4*a*c))/(2*a);printf("x1=%lf,x2=%lf\n",x1,x2);}else((b*b-4*a*c)==0);{x1=x2=(-b)/(2*a);printf("x1=%lf,x2=%lf\n",x1,x2);}elseif((b*b-4*a*c)<=0));{x1=(-b+sqrt(b*b-4*a*c)i)/(2*a);x2=(-b-sqrt(b*b-4*a*c)i)/(2*a);printf("x1=%lf+%lfi,x2=%lf-%lfi\n",m,n,m,n);}】#include<stdio.h>#include<math.h>intmain(){doublea,b,c,x1,x2,m,n;scanf("%lf,%lf,%lf",&a,&b,&c);if(a==0)printf(aelseif((b*b-4*a*c)>=0){x1=(-b+sqrt(b*b-4*a*c))/(2*a);x2=(-b-sqrt(b*b-4*a*c))/(2*a);printf("x1=%lf,x2=%lf\n",x1,x2);}. .. .. .. .........else{m=(-b)/(2*a),n=sqrt(4*a*c-b*b)/(2*a);printf("x1=%lf+%lfi,x2=%lf-%lfi\n",m,n,m,n);}}三、調(diào)試結(jié)果:7、編制程序要求輸入整數(shù)ab,a2+b2100,百位以上的數(shù)字，否則輸出兩數(shù)之和實驗?zāi)康模赫莆読f,else語句。能夠正確運用！實驗容：#include<stdio.h>intmain(){inta,b;printf("請輸入兩個整數(shù)a,b,:\n");scanf("%d,%d",&a,&b);if((a*a+b*b)>=100)printf("%d\n",(a*a+b*b)/100);elseprintf("%d\n",a+b);return0;}調(diào)試結(jié)果：8a,b,c實驗?zāi)康模篿f,else#include<stdio.h>intmain(){inta,b,c;printf(a,b,c：\n");scanf("%d,%d,%d",&a,&b,&c);if(a>b&&a>c)printf("%d\n",a);elseif(b>a&&b>c)printf("%d\n",b);elseprintf("%d\n",c);}調(diào)試結(jié)果：x(x<1)2x-1x(x<1)2x-1(1<=x<1)3x-1103x-11(x>=10). .. .. .. .........xyif,else語句。能夠正確運用！實驗容：#include<st