2020屆高三化學三月沖刺對題必練-化學反應原理大題必練【答案解析】

2020屆屆屆屆屆屆屆屆屆屆屆屆屆——屆屆屆屆屆屆屆屆屆屆屆屆屆+屆屆屆

3

3

3

3

3

3

________

2L

333H

3

(3)3

2

2CO2

2CO

2H

________2222________ 2 2 2B________________92.9(2)2CO

2

，故答

％，則

eq

\o\ac(△,H)<0

eq

\o\ac(△,H)<0

H=___________(eq

\o\ac(△,用含)

eq

\o\ac(△,H)

K=___________K_________(

I

EEE_____E><=

___________(

,

A,B____(AB),B__________

+H

1L

__________(

KK

__________

A

+4e+

A

+4e+

kk

1

?k

?k1

ggg+Oggg+Oggeq

\o\ac(△,）的)

H=+eq

\o\ac(△,=)

eq

\o\ac(△,+)

×

c(NOc(NO

×k

c(NO)?c(O

k

=

k

1

?k

1

?k

k

eq

\o\ac(△,H)eq

\o\ac(△,+)

k

1

?k?k1

g+Oggeq

\o\ac(△,）的)

g+Oggeq

\o\ac(△,）的)

c(NO)?c(OE

AB

+4e+A+4e+

1LL

=c=cKLKL

ggg+Ogg+c(NO

×

g+OggEE

+H

1L=c

L

=c

22

22 C?OH?ON?HC?N

______(2)2H2

2

______b______Y______2

2______22+

sp2

______sp2

?52(s)2I

2(s)2Cl

______(5)

n(SO

n(SO4

4

b____________

______YY(4)4n(I

eq

\o\ac(△,，故)

463

Y

Y

X3

Y33

Y(3)234

3PbI2

2

4H22

222

2+2I2+

?3

2.0?3sp

2

2+2

?3

(2.0?32

422I

22ClKsp(PbI

2

2Ksp(PbI

22

2

2+

Ksp(PbCl

2

?5

2

2+

2

2H2

3H

2

2H2

3H

?4

2I2

3

n(I2

n(SO23

n(SO2(5)①2

22

b3:2

n(SO23?43:b333n(I2n(I2 2

2________________________________________________

2

29.5

10.6

______________________________________________________________________________

1L

AB

______

b______________

______

2B

A2B2

b2A225%

2

2

2

2

c(N2O)c(CO)

c(N2O)c(CO)

c(N2)c(CO2

220%c(N2

c(CO)

c(N2

c(CO2

0.02

k

k

c(N2)c(CO2

Kc(N2O)c(CO)

k

kc(N2O)c(CO)

c(N2)c(CO2 222

22H2

kJ/mol

2N222H2

kJ/mol2

2

kJ/mol2222________(2)2

2NO2

22

k

c2

k

c(N22

________

________

________

________

________

________

AB

E

F________

4

(4)M

4

4

BF44NO

4

4

44

4

c(NO)

0.030mol/L×0.030mol/L

c(NO)

0.030mol/L×0.030mol/L

c(CO)c(N(0.040mol/L)②30minc(N

0.034mol/Lc(CO

0.017mol/Lc(NO)=

0.032mol/L

c(CO)c(N

0.034mol/L×0.017mol/L

c(NO) (0.032mol/L)

NQc

c(CO)c(N

0.068mol/L×0.017mol/L

0.28

c(NO) (0.064mol/L)(4)(4)

2v(N

O

v(NO

4

v(NO

v(NO4

NO4

2NONO4NOBFv(NO

v(NO4

NO4

2NOBF POPO PONaHPOPO PO4

③NaHPO PO4Ba(OH)POSO4Ba(OH) PO

32 3232 32

22

①+134

2P4

2

2

222

2PH3

2H2

4e

2

+4H232

2323232

22

32

4

3432223222

44

4e

4H

44H

______

b

______

H?H

C=

C?H

H?O

______A______

______

B

____________

X

(4)

____________

0.375×1540.25×0.75(4)2H4e

4H

4

n(H

n(H

n(CO

4eq

\o\ac(△,，)

4

4H

4E(C

4E(C

4

4414kJ/mol464kJ/mol

4

4H

0

BC

n(CO

B75%n(CO

75%

0.75mol0.25mol0.75mol0.375mol

4

4H

0.75 2.25 0.375 1.5

0.75

0.375

1.5

0.375×1540.25×0.750.375×1540.25×0.75bX

d(4)

4

4e

4H

4

4

4e

4H

4

4

4

______

4

______

______A. (4)__________________

______

121

2 2CH312e

2H2

2CO2

12H32

2

2Cu2OH

2e

2242

3H2

2

2

+131kJ/mol4

2H2

(2)1

1.04

?12

?1

?12

2mol?1

1.5×23

1.02H2

32A.

AB.B

2(4)1

22

1

1

2121

22CH312e

2H2

2CO2

+12H，或3

2

2

2CH312e

2H2

2CO2

12H

32

2

2Cu2

22

2Cu2OH2e

222Cu2OH2e

2242

3H2

2

2

+131kJ/mol4

2H2(2)(3)(4)

xxx

4

______

0.45

3.60

3.05

________________________

1L22

2

2

2

22SO22

2SO

2______A.

2Q(B.p

2p(

22

2

____________2sp

2.822

2222

2______ s) 2CO2NO

2

2CO2eq

\o\ac(△,的)

eq

\o\ac(△,，時)

2

2 AC 2CO2

12H12e

2

2

2

2NO

2

2

2O2

22H2

2

2

22

22

2s

2s

2s

s)2s22

2

s)

s)

2.70s)2CO2NO

2

2CO22

2

c(NO)c(CO)

?3c(NO)c(CO)

?3

?3

c(CO)c(N

?3

?3

1.875

2CO+2NO

N

2CO

2CO+2NO

N

2CO

eq

\o\ac(△,的)

eq

\o\ac(△,，時)

(3)A.

AB.

BO 2molSO1molO1molSOO 0.5molOSO

SO3SO0.50.5

41L

5

4

SOO

44

SO

44

50.5

0.4，根據(jù)

c(COc(Ca

，根據(jù)

c(COc(Ca

c(Ca

?4ACb2CO

C4

4HO2CO

C4

4HO3(5)NaCO3c(CO

33CaClc(Ca

CaCl

5.65.6

?3

?3

(CO)

(CO2CO

2CO

(3)A.B.1L3CO3c(CO

3

c(CO3c(Cac(CaCaClc(Ca

COCO______C______Cr

____________CO

______

______Cr3

______CO)CO(g)

CH3

CO(g)

CO

CO______

1L

______

____________

______

gSP

______ SO4

4L

4e

+4H

+4

SO4

SO4

(SO4

SO4

②ⅰ)

ⅰ)

2

2

2

3

2

2

2

232+

2.82+

22222

2

222e2H

2Ag2 23.2g

223.2g2

2

23.23232?

2.8322+

22

2.02.0+3222

322222e

2H

2Ag233232?

2.833

22+2+22+

2H2

2H2

4

4

4

4

4

4

eq

\o\ac(△,的) 4

______ 4

______

4

A.

4B.

2L4

4

41L

8______30.8

8

eq

\o\ac(△,，則)

AB.B

ABC4

4

1L (4) 4 4

8 4

8

HCN______