電路分析模擬試題及答案

附錄2模擬測試

4

110

12

A6B7C8D9

23100010002421

A01010101B10000101C10111011D11101011

31.1000

A+1.0111B?1.0111C?0.1001D–0.1000

4-

ABCD

5F(AC))E

AF[ACC(DE)]BFACC(DE)

CF(ACCDE)DFACC(DE)

643

ABCD

7JKJK

A00B01C10D11

84

A8B9C10D11

98

A1B3C5D8

104

A1B2C3D4

210

1

2F(A,B,C)M(1,3,4,6,7)F(A,B,C)m(0,2,5)

3

4

5

4

210

10

A0.00B1.00C0.11D1.11

2F=ABG=AB

AFGBFGCFGDFG13F(A,B,C)m(1,2,3,6),G(A,B,C)m(0,2,3,4,5,7),FG

A

mmB1CABDAB

23

42xyzz

AxyBxy

CxyDxy

5

ABCD

10

1F(A,B,C)ABACB-4

2

F(A,B,C,D)=∑m(2,3,9,11,12)+∑d(5,6,7,8,10,13)--6

20

1T.110

1F3F2F1F0

2

3ABCD4

T.11

2T.2a10

1

2

QQ00xCPT.2b

12

Q?Q

12

T.22

30

113

T.315

1T.1

T.31

T.1

ABCDWXYZABCDWXYZ

0000

0001

1000

1001

00101010

00111011

0100

0101

1100

1101

01101110

01111111

2-

3PLA

2DTT.2

15

T.2

y2n+1y1n+1/z

y2y1

x=0x=1

0001/011/1

0110/000/0

11

10

00/1

11/0

10/0

01/0

1T.4

2-

T.42

10

1T.5F1F25

T.51

23-874138T.6

5

T.62

4

220

16

A32B63C64D128

2

AB

CRCD

3BCD

A8421BGrayC2421D3

4F(A,B,C)m(0,3,5,6)

AFABCBFABCCFABCDFA⊙B⊙C

5/

A2/2B3/3C3/2D4/2

6

AB

CD

7

AJKBRS

CDDRS

8

ABCD

9EEPROM

AB

CD

10

A74153B74193

C74283D74194

210

116.5

211111013

3

4

54

1

10

1

2F(A,B,C)M(0,3,4,6,7)F(A,B,C)m(1,2,5)

3RSRS101

4

5RS

6

7

8

9

10.PLA

25

1T.78

1

2ABCD1010～1111T.3

3

T.71

T.3

ABCDWXYZABCDWXYZ

0000

0001

0101

0110

00100111

00111000

01001001

2T.810

T.82

1

2T.4

3T.5

400T.9Q1Q2Z

T.4

XQ2Q1J2K2J1K1Q2n+1Q1n+1Z

000

001

0

0

1

10

11

00

101

1

1

10

11

T.5

Q2n+1Q1n+1

Q2Q1X=0X=1Z

00

01

10

11

T.9

3T.10--74290T.6

7429000007

1T.1074290

2T.10

3F

T.103

T.674LS290

9

R0AR0BR9AR9BCPACPBQDQCQBQA

110ddd0000

11d0dd0000

dd11dd10019

d0d0

0d0d

0dd0

1

d00d

25

1T.11ABCD8421

ABCD5F

1F010

1T.7

T.1112

3

T.7

ABCDFABCDF

0000

0001

0010

0011

0100

1000

1001

1010

1011

1100

0101

0110

0111

1101

1110

1111

2TT.8

10

1T.9

2T.12

T.8T.9

y2n+1y1n+1/Z

xy2y1T2T1Zxy2y1T2T1Z

y2y1

00

01

11

10

x=0x=1

11/010/1

11/001/0

00/010/0

01/100/1

000100

001101

010110

011111

T.122

30001T.135

Mealy

10

1T.145

1F1F2

2

2EPROMT.145

F1F2

T.133T.14

110

1B2C3D4C5A6D7D8A9B

10C

210

1

2F(A,B,C)m(1,3,4,6,7)

3

4

5

210

1AD2ABD3AC4ABC5AC

10

14

F(A,B,C)ABACB

ABACB(CA)

ABACBAC

ABACB

AACB

AB26

T.15

T.15

-FACBC

-F(AC)(BC)

20

110

1

FA;FAB;FBC;FCD

3210

2T.10

T.10

ABCDF3F2F1F0ABCDF3F2F1F0

0000000010001100

0001000110011101

0010001110101111

0011001010111110

0100011011001010

0101011111011011

0110010111101001

0111010011111000

34

210

1

2

Q?QT.16

12

30

T.16

115

1T.11

T.11

ABCDWXYZABCDWXYZ

0000dddd10000101

0001dddd10010110

0010dddd10100111

0011000010111000

0100000111001001

010100101101dddd

011000111110dddd

011101001111dddd

2

WABBCD

XBCBDBCD

YCDCD

ZD

3PLAT.17

T.17

215

1T.18

T.18

2-

Dxyyxyyxyyxyy

221212121

Dy

11

Txyxy

211

T1

1

Zxyyxyy

2121

10

1F1F2

F(A,B,C)ABC

1

F(A,B,C)ACABBC

2

5

23-874138

F(A,B,C)mmmmm

1

11247

F(A,B,C)mmmmm

1

21237

T.195

T.19

220

1B2AD3ACD4BCD5C

6ABD7ACD8BC9C10BD

210

110000.110.8

2125010001011000

3

4

595

110

12345

678910

25

110

1

W(CD)BAABABCABDACD

X(CD)BBCBDBCD

YCDCDCD

ZD

2T.12

T.12

ABCDWXYZABCDWXYZ

0000001101011000

0001010001101001

0010010101111010

0011011010001011

0100011110011100

384213

210

1

JXKXJQKQZQQ

11212121

2T.13

T.13

XQ2Q1J2K2J1K1Q2n+1Q1n+1Z

0000101000

0011001101

0100101000

0111001100

1000110010

1011010111

1100110010

1111010110

3T.14

T.14

Q2n+1Q1n+1

Q2Q1X=0X=1Z

0000010

0110111

1000010

1110110

4Q1Q2ZT.20

T.20

35

1T.107429060～50000～0101

26

3F110100110100

25

110

1T.15

T.15

ABCDFABCDF

0000010001

0001010011

001001010d

0011

0100

0

0

1011

1100

d

d

010111101d

011011110d

011111111d

2

FABCBD

3T.21

2T

10

1T.16

2T.22

T.21

T.16

xy2y1T2T1Zxy2y1T2T1Z

000110100101

001100101000

010

011

1