計(jì)數(shù)原理單元測試題

精品文檔第一章計(jì)數(shù)原理單元測試題12560謝謝閱讀5謝謝閱讀）10種B20種25種32種

3423感謝閱讀36種48種96種192種522精品文檔放心下載）1440種960種720種480種謝謝閱讀244謝謝閱讀）個(gè)A242610

2C4個(gè)1A2610個(gè)10A242個(gè)26C1426從54精品文檔放心下載21(A)40種60100種(D)120種謝謝閱讀感謝閱讀5()感謝閱讀7.用4.謝謝閱讀8.AB和ABmn謝謝閱讀m+n-1()精品文檔放心下載C1C21C2CmnnmC1C21C2Cmnn1mCCCCCC12121212CCmm1m1n1m1nnn2xx10axx210aa012a109.設(shè),則a0a2a2a1a2a92()1歡迎下載。精品文檔2006328,162謝謝閱讀這16,8,4精品文檔放心下載()11.9.981()謝謝閱讀5謝謝閱讀4（）感謝閱讀4416謝謝閱讀2349謝謝閱讀有.42個(gè)精品文檔放心下載x+31)=.xn53謝謝閱讀感謝閱讀674謝謝閱讀177A感謝閱讀RRRRRRRA○2。精品文檔181到9謝謝閱讀精品文檔放心下載195謝謝閱讀.）））.20.感謝閱讀3歡迎下載。精品文檔31n5分）已知a4b展精品文檔放心下載33a3na3a.C2n5n52P232n23nx2x5mm是精品文檔放心下載77.4歡迎下載。精品文檔560D5感謝閱讀2D5C3423精品文檔放心下載C96CCC2334445A52524A55BA244感謝閱讀C4A26精品文檔放心下載21AB54感謝閱讀21C225360選BB2A0A3A3233323,2A3.3A3233AA32C:比2有A36;23,30,有A22;4有1是感謝閱讀2第.D2.謝謝閱讀C:由2xxaaxa0x10:125。當(dāng)x1,精品文檔21a1a2aaa0120a1a1a2a2a10當(dāng)x1,21aaaaaa01230a102aaaaaa021292aaaaaaaaa0120123

101.2121212110A有24884,感謝閱讀4打42,11.感謝閱讀11C:9.98100.025

55C151040.02C230.022C35531020.02310510340.0699004.感謝閱讀12AC142,感謝閱讀5有C,C1202CC11CCC1.4225422413感謝閱讀C4C2C3126095314①2，精品文檔放心下載1212②1A余3330不是首位數(shù)字，則有24③，A為22102(2)A22個(gè)6歡迎下載。精品文檔1nCnr(2x3)nr157x+x(3)Tr1n7rn21x)r1636種5331人擔(dān)任文娛委員，再從4謝謝閱讀感謝閱讀A選2C123434336種7417.b、感謝閱讀b21=34分謝謝閱讀2c21=76分謝謝閱讀2AA7=6310分精品文檔放心下載43C3454C4534A77C33C4A7分457C1440063C4A5A3分455334感謝閱讀345322CCCAAA455342分9435感謝閱讀A4C3A3545分288001219.43251感謝閱讀5A4

445A3

3435A22

2分7。精品文檔A88謝謝閱讀5432AAA5432即884分

96謝謝閱讀感謝閱讀精品文檔放心下載5.8分精品文檔放心下載⑶因?yàn)?，2，3，4，5各在萬位上時(shí)都有A個(gè)五位數(shù)，所以萬位上數(shù)字的和為：精品文檔放心下載A分

AA）感謝閱讀謝謝閱讀謝謝閱讀=15分精品文檔放心下載n5n445120.因2n23n5n446n5n43分精品文檔放心下載4.5nC5C5C5C515n48分精品文檔放心下載1n12n2n22

n1nnn

n謝謝閱讀525n分4.5nC5C5C謝謝閱讀1n12n2n22nn

n515n1C25n2Cn25225,nC精品文檔放心下載nnn2n23n5n42512分感謝閱讀5

r15r1設(shè)4b4b的展開式的通項(xiàng)為TC3r3感謝閱讀r155bb15r105r45rC6r5,r6分則5r6r2,T327.3n2a中10分謝謝閱讀37a8。精品文檔73a3a4分感謝閱讀112n又nN,n22分5n2n21198CPCPC5432P2n2n272325n3n510

5a100.4分177157611576C17676C11576C17676C1777611576MMN77771519即m56分精品文檔放心下載52mr55r23232

rx的展開式的通項(xiàng)TCx2x52x5r1552rx3,r152,rr5r5C5

254則r5r3,d.T34從而等差數(shù)列的通項(xiàng)公式是：a1044nn分k01044n或，1044k1

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