語言復(fù)習備用

TOC\o"1-1"\h\z\u【1.app 2mn1<=m<=6,1<=n<=6)a（mn列）中的元素，分別求出各行元和，并輸出。輸出使用語句：printf("sumofrowdis%d\n",i,3 sumofrow0issumofrow1is-sumofrow2is#include<stdio.h>intmain(void){inti,j,m,n,intfor(i=0;i<m;i++)for(j=0;j<n;j++)scanf("%d",&a[i][j]); printf("sumofrow%dis%d\n",i,}return}mnm≥1，n≤6)mna中的元素，a中的每個元素b。23(m=2,456123New645312#include<stdio.h>intmain(void){inta[6][6],b[6][6],i,j,m,for(i=0;i<m;i++)for(j=0;j<n;j++) }printf("Newarray:\n");for(i=0;i<m;i++)for(j=0;j<n;j++)}return}repeat(0<repeat<10)repeat1n(1≤n≤6),na,元和。副對角線為從矩陣的右上角至左下角的連線。 231sum= #include<stdio.h>intmain(void){inti,j,n,sum,b;intrepeat,ri;intscanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%d",&n);for(i=0;i<n;i++)for(j=0;j<n;j++)scanf("%d",

printf("sum=%d\n",}return}repeat0<repeat<10)repeat次下列運算：輸入一個正整數(shù)n(0<n<10)n×n項。 輸出*123112243369#include<stdio.h>intmain(void){inti,j,inta[10][10];intrepeat,for(ri=1;ri<=repeat;ri++){scanf("%d",&n); elseif(j==0)for(i=0;i<=n;i++){for(j=0;j<=n;if(i==0&&j==0)printf("%-4c",elseif(i==0||j<=i)printf("%-4d",a[i][j]);}}return}repeat(0<repeat<10)repeat輸入1個正整數(shù)n(1≤n≤6)和n階方陣a中的元素，如果a是上三角矩陣,"YES",否則,輸出"NO"上三角矩陣指主對角線以下的元素都為0的矩陣,主對角線為從矩陣的左上角至右下角 #include<stdio.h>intmain(void){intflag,i,j,n;inta[6][6];intrepeat,scanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%d",&n);for(i=0;i<n;i++)for(j=0;j<n;j++)scanf("%d",

if(flag==0) }return}repeat0<repeat<10)repeat次下列運算：,day)year、month和dayintint。19813 (198131日20003 (200031日Daysofyear: (19813160天Daysofyear: (20003161天#include<stdio.h>intmain(void){intday,day_year,month,year;intrepeat,ri;intday_of_year(intyear,intmonth,intscanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%d%d%d",&year,&month,&day); day_year=day_of_year(year,month, printf("Daysofyear:%d\n",day_year);}return} intday_of_year(intyear,intmonth,int{intintreturnday;}（n≤612345700089 12345700089#include<stdio.h>intmain(void){inta[10][10],i,j,n,scanf("%d",&n);for(i=0;i<n;for(j=0;j<n;j++)

}}}}for(i=0;i<n;for(j=0;j<n;j++)printf("%5d",a[i][j]);}return}repeat(0<repeat<10)repeat1n(1≤n≤6)naa1個鞍點，如果找到a的鞍點,就輸出其下標,否則，輸出"NO"。鞍點的元素值在該行上最大,在該列上最小。 20 9214a[2][1]6#include"stdio.h"intmain(void){intflag,i,j,k,row,col,n;inta[6][6];intrepeat,scanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%d",&n);for(i=0;i<n;i++)for(j=0;j<n;j++)scanf("%d",

}if(flag!=printf("a[%d][%d]=%d\n",row,}

return}輸入一個以回車結(jié)束的字符串(80個字符)，將它的內(nèi)容逆序輸出。如"ABCD"的逆序

eto!uoyot#include<stdio.h>intmain(void){inti,k,temp;charstr[80];i=while((str[i]=getchar())!='\n')str[i]= for(i=0;str[i]!=0;return0;}輸入一個以回車結(jié)束的字符串（80個字符，把字符串中的所有數(shù)字字符（'0~'9'）轉(zhuǎn)#include<stdio.h>intmain(void){inti,char return0;}repeat0<repeat<10)repeat(下標從0開始"NotFound"。 programming(字符串"programming") index=7 NotFound #include<stdio.h>#defineMAXLEN80intmain(void){charcc,charstr[MAXLEN];intcount,flag,i,index;intrepeat,ri;scanf("%d",&repeat);for(ri=1;ri<=repeat;ri++){cc=getchar();i=while((ch=getchar())!='\n'){str[i++]=ch;}str[i]= if(flag!=printf("index=%d\n",}

printf("Notreturn}repeat(0<repeat<10)repeat寫輔音字母：除'A','E','I','O','U'以外的大寫字母。 count=3 O"中有3個大寫輔音字母)count=0 #include<stdio.h>#defineMAXLEN80intmain(void){charcharstr[MAXLEN];intcount,i;intrepeat,scanf("%d",&repeat);for(ri=1;ri<=repeat;ri++){i=0;while((ch=getchar())!='\n'){}str[i]= printf("count=%d\n",}return}repeat(0<repeat<10)repeat原字 AflagofUSAAfterreced:ZflagofFHZAfterreced:1+2=3#include<stdio.h>#include<string.h>#defineMAXLEN80intmain(void){charcharstr[MAXLEN];inti;intrepeat,scanf("%d",&repeat);for(ri=1;ri<=repeat;ri++){i=0;while((ch=getchar())!='\n'){str[i]=ch;}str[i]= printf("Afterreced:");for(i=0;str[i]!=0;i++)}return}大寫英文字母則輸出“NotFoundFONTNAMEandFILENAMEfontnameandNotintmain(void){charstr[80],newstr[80];inti,j,k,ri,repeat;scanf("%d",&repeat);for(ri=1;ri<=repeat;while((str[i]=getchar())!='\n') }printf("Not

for(i=0;newstr[i]!='\0';i++)}return}輸入一個以回車結(jié)束的字符串（80個字符ASCII碼intmain(void){charstr[80],ch;inti=0,j,k;while((str[i]=getchar())!='\n')str[i]= for(i=0;str[i]!='\0';return0;}repeat(0<repeat<10)repeat1010 A#include<stdio.h>intmain(void){intx,base,i,k,y;intri,repeat;charscanf("%d",for(ri=1;ri<=repeat;ri++{ }return}repeat(0<repeat<10)repeat programming(字符串 (字符 count2('m'在"programming"2次)count=0('a'在"1234"中沒有出現(xiàn)過)#include"stdio.h"#defineMAXLEN80intmain(void){charcc,charstr[MAXLEN];inti,count;intrepeat,scanf("%d",&repeat);for(ri=1;ri<=repeat;ri++){i=0;while((str[i]=getchar())!='\n')str[i]=0;cc=getchar(); printf("count=%d\n",}return}repeat0<repeat<10)repeat次下列運算：輸入一個正整數(shù)n(0<n<10)，輸出三角形的前n行。 11111 1111 #include<stdio.h>intmain(void){inti,j,n,repeat,ri;inta[10][10]; }}return}3先輸入學生的人數(shù)（<30人(提示：定義一個score[30][5]數(shù)組，score[0]、score[1]、score[2]分別3門課程的分數(shù)score[3]、score[4]分別每個學生的總分和平均分total和avg3門課程的總分和平均分。) 788794（1個學生的成績808080（2個學生的成績767677（3個學生的成績588766（4個學生的成績898788（5個學生的成績）總分平均分#include<stdio.h>intmain(void){intavg[3],score[30][5],total[3];inti,j,n;for{} 枃 枃{

鏁板鑻辮鎬誨 騫沖潎鍒哱} printf("\n騫沖潎鍒?");return}repeat(0<repeat<10)repeatDec=Dec=#include"stdio.h"#include"string.h"#defineMAXLEN80intmain(void){charcharstr[MAXLEN],num[MAXLEN];inti,k;intrepeat,ri;longscanf("%d",&repeat);for(ri=1;ri<=repeat;ri++){i=0;while((ch=getchar())!='\n'){}str[i]= printf("Dec=}return}repeat(0<repeat<10)repeatx和y，并通過指針運算找出兩個數(shù)中的最大值，輸出到屏幕上。 (x=3,max=#include<stdio.h>intmain(void){intmax,x,y,*pmax,*px, printf("max=return}nm(1<m<n<=10)n個整數(shù)，將這些數(shù)排成一行，向右循環(huán)移動m個位置（從右邊移出的數(shù)再從左邊移入n個整數(shù)。mov(x,n,m)x的類型是整型指針，nmintvoid。5 1234 (5個整數(shù)Aftermoved:3451#includevoidmov(int*x,intn,intm);intmain(void){inti,m,intscanf("%d%d",&n,&m);for(i=0;i<n;i++)scanf("%d", printf("Aftermoved:");for(i=0;i<n;i++)printf("%d",a[i]);return} 輸入兩個實數(shù)a和b，要求定義并調(diào)用函數(shù)sum_diff(floatop1,floatop2,floatvoidmain4-2-0.75Thesumis10.00Thediffis-2.00Thesumis-6.00Thediffis2.00Thesumis1.00Thediffis0.50#includevoidsum_diff(floatop1,floatop2,float*psum,float*pdiff);intmain(void){floata,b,sum,diff;intri,repeat;scanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%f%f",&a,&b); printf("Thesumis%.2f\nThediffis}return} repeat(0<repeat<10)repeatn1<n<=10)naa中的元sort(a，n)an個元素anint，函數(shù)的類型void。517 125432Aftersortedthearrayis:156Aftersortedthearrayis:12Aftersortedthearrayis:1234#include<stdio.h>voidsort(inta[],intn);intmain(void){inti,intrepeat,intscanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%d",&n);for(i=0;i<n;i++)scanf("%d",&a[i]); printf("Aftersortedthearrayis:");for(i=0;i<n;i++)printf("%d",a[i]);}return} repeat0<repeat<10)repeatn(1<n<=10)nax，在數(shù)a中查找x，如果找到則輸出相應(yīng)元素的最小下標，否則輸出"Notfound"。search(list,n,x)listx，若找到則返回相應(yīng)元素的最小下標，否則返回-1listnx的類型intvoid。12- 1225 index=1Notfound#include<stdio.h>intmain(void){inti,index,n,res,x;intrepeat,ri;intintsearch(intlist[],intn,intscanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%d",&n);for(i=0;i<n;i++)scanf("%d",&a[i]);scanf("%d", if(res!=-printf("index=%d\n",}

printf("Notreturn} 輸入一個正整數(shù)n（1<n<=50，有n個人圍成一圈，按順序從1到n編好號。從第一個人開始報數(shù)，報到3的人退出圈子，下一個人從1開始重數(shù)，報到3的人退出圈子。0的數(shù)，該數(shù)就是最后一個人的編號。輸出使用語句：printf("No%d:d\n",no (n個人報數(shù)，n=5)LastNois: intmain(void){intcount,i,n,no;intnum[50];intscanf("%d",&n);for(i=0;i<n;num[i]=i+1;p=num; p=num;while(*p==0)printf("LastNois:%d\n",*p);return0;}5個字符串，輸出其中最小的字符串。Minis:Jin*/#include<stdio.h>#include<string.h>intmain(void){ min[80],str[80];inti;scanf("%s", printf("Minis:%s\n",min);return0;}repeat(0<repeat<10)repeatststrcstrcst的尾部。HappyBirthday#includevoidstrc(char*s,char*t);intmain(void){charreturn} repeat(0<repeat<10)repeat5scanf("%s",sx);redbluegreenyellowThelongestis:zhangThelongestis:#include<stdio.h>#include<string.h>intmain(void){charsx[80],longest[80];inti;intrepeat,scanf("%d",for(ri=1;ri<=repeat;ri++){scanf("%s",sx); return}repeat(0<repeat<10)repeat輸入一個字符串t和一個正整數(shù)m，將字符串t中從第m個字符開始的全部字符到字符串s中，再輸出字符串s。要求定義并調(diào)用函數(shù)strmcpy(s,t,m),它的功能是將字符串t中從第m個字符開始的全部字符到字符串s中，函數(shù)形參s和t的類型是字符指針，形參m的類型是int，函數(shù)類void。happynewyearOutputis:newyear (從"happynewyear"第7個字符開始組成的新字符串為"newOutputis: (從"happy"1個字符開始組成的新字符串為error intmain(void){chars[80],t[80];intm;intrepeat,voidstrmcpy(char*s,char*t,intscanf("%d",&repeat);for(ri=1;ri<=repeat;ri++){scanf("%d",&m);if(strlen(t)<m)printf("errorinput\n"); printf("Outputis:}}return} bFaE3+8=1R大寫字母數(shù)為:小寫字母數(shù)為:空格為:數(shù)字為:其他字符為:intmain(void){chars[80];char*p;intblank,digit,lower,other,upper=lower=blank=digit=other= printf("澶у啓瀛楁瘝鏁頒負:%d\n灝忓啓瀛楁瘝鏁頒負:%d\n絀烘牸涓?%d\n涓d\n鍏朵粬瀛楃涓d\n",upperlowerblank,digit,other);return0;}/*3個字母移到最后，輸出變換后的字符串。#include<stdio.h>#include<stdlib.h>#include#defineMAXLINE100intmain(void){charline[MAXLINE],str[4];inti;if(strlen(line)<3)printf("瀛楃涓查暱搴﹀皬浜?n");} printf("%s\n",line);return0;}’或者’DAD123456789DAftersorted:1098765432#includevoidsortAsc(inta[],intn);voidsortDesc(inta[],intn);intmain(void){inti,n,a[10];charc;for(i=0;i<n;i++)scanf("%d",&a[i]);if(c=='A')sortAsc(a,n);elseif(c=='D')else{printf("theinputcharisnot'A'or'D'!,programisclosed");}printf("Aftersorted:");for(i=0;i<n;i++)printf("%d",a[i]);return} /*5個字符串，按由小到大的順序輸出。redyellowbluegreenAftersorted:#include<stdio.h>#include<string.h>intmain(void){inti,j,charsx[5][80],stemp[80];scanf("%s", printf("Aftersorted:\n");for(i=0;i<5;i++)return0;}/*repeat0<repeat<10)repeat輸入兩個字符串，調(diào)用函 p(s1,s2)，實現(xiàn)兩個字符串的比較，返回值分別為1、0-1s1>s2,s1=s2,s1<s2的情況。30#include p(char*s1,char*s2);intmain(void){intresult,ri,repeat;chars1[80],scanf("%d",&repeat);for(ri=1;ri<=repeat;{p(s1,s2);printf("%d\n",result);}return} /*repeat0<repeat<10)repeat次下列運算：findstr(char*str,char*substr)2mkloas6。 asdasasdfgasdaszx67asd am123am456amam 65#include"stdio.h"intmain(void){