DesignExpert響應(yīng)面分析實(shí)驗(yàn)的設(shè)計(jì)案例分析演示教學(xué)

精品文檔精品文檔精品文檔精品文檔精品文檔精品文檔學(xué)校學(xué)年2010-2011第一學(xué)期課程名稱食品實(shí)驗(yàn)優(yōu)化設(shè)計(jì)專業(yè)年級(jí)考試方式案例分析論文學(xué)生姓名學(xué)號(hào)成績(jī)食品科學(xué)研究中實(shí)驗(yàn)設(shè)計(jì)的案例分析—響應(yīng)面法優(yōu)化超聲波輔助酶法制備燕麥ACE抑制肽的工藝研究摘要：選擇對(duì)ACE抑制率有顯著影響的四個(gè)因素：超聲波處理時(shí)間(XI)、超聲波功率(X2)、超聲波水浴溫度(X3)和酶解時(shí)間(X4),進(jìn)行四因素三水平的響應(yīng)面分析試驗(yàn)，經(jīng)過(guò)Design-Expert優(yōu)化得到最優(yōu)條件為超聲波處理時(shí)間28.42mm.超聲波功率190.04W.超聲波水浴溫度55.051、酶解時(shí)間2.24h,在此條件下燕麥ACE抑制肽的抑制率87.36%。與參考文獻(xiàn)SAS軟件處理的結(jié)果中比較差異很小。關(guān)鍵字：Design-Expeil響應(yīng)面分析比較分析表一響應(yīng)面試驗(yàn)設(shè)計(jì)因素—水平-101超聲波處理時(shí)間-K(min)203040超聲波功率足132176220超聲波水浴溫度.tco505560的解時(shí)間X(h)123Design-Expert響應(yīng)面分析分析試驗(yàn)設(shè)計(jì)包括：方差分析、擬合二次回歸方程、殘差圖等數(shù)據(jù)點(diǎn)分布圖、二次項(xiàng)的等高線和響應(yīng)面圖。優(yōu)化四個(gè)因素(超聲波處理時(shí)間、超聲波功率、超聲波水浴溫度、酶解時(shí)間)使響應(yīng)值最大，最終得到最大響應(yīng)值和相應(yīng)四個(gè)因素的值。利用Design-Expert軟件可以與文獻(xiàn)SAS軟件比較，結(jié)果可以得到最優(yōu)，通過(guò)上述步驟分析可以判斷分析結(jié)果的可靠性。精品文檔精品文檔精品文檔ltl?lii<X??*D>?>lv精品文檔ltl?lii<X??*D>?>lvf??l?><l,精品文檔精品文檔精品文檔精品文檔2.1數(shù)據(jù)的輸入2.2Box-Behnken響應(yīng)面試驗(yàn)設(shè)計(jì)與結(jié)果憑C八Duom?aU*xndS?tQ厳度匕gtl—sGEt法H化復(fù)盧8軒如氏斜務(wù)-T.l.i-JfOrE^$>jWZUCWKarm?】Esvl^n<]Lj]nt■5附“-i]Pc?hMcW.??>1FMQ28"茨映刖53^?tw<c-fcwn?<(h)Ri120?1?￡O$60)200勢(shì)糾238132￡OS582854%S208Z?￡OS5828wee4408Z?￡OS582854566?l?veto匆?》H?今任e?l?vetoH?ei.w?l?veto匆?》3?e如譏s旳83i?34；S9208i7ca>S58103ei?ID408i7ca>S58103??11208i7ca>S58,8544012<0?veto660)3?336213?l?i?a?匆?》23勢(shì)&1<?l?Z?￡0匆?》231S132￡O伍1820)asio16308Z?￡O382817208i7ca>??28as2DIB408i7ca>??2854?19??veto23傍2220<0?veto????23今識(shí)?l?i?a?660)H?9ixe22308Z?￡OS58103a”?308132￡OS58,854?308Z?￡OS58,8?COWOT175WWOT2OT???l?veto660)23??$60)200計(jì)％|2.3選擇模型KC:\Doom?at>xnd弘<2竺*\"“\廉“1“竺1"?^莊|1扶侃化潑4農(nóng)軒如茯1|務(wù)為疹11：乞《1<丫-Dm.-ix”譏T.I.1LU.X-J，如ror卜:?：CW勿瞄SXfw?r?口G<<^CcArra0】t、—31r-#如皿債川L,-二-Bi€<*:?-百PertFttdKton>MHITuroJwr.I??;ft^mrtf|>)^zzz■fe"5|云gr>3rt?|Dto<fc4G<ya|2.4方差分析■icr?,?alt?lKC：\Ooom?atxxndSvttaaoXxc&cV^lXVxKacltiu&^fTtk^^^tfACK.dxT-Dcxt<a-ixp?rtT.!.1ltl?lii<X??*D>?>lvf??l?><l,-Jror紳如*KN:?:CW卯MEJE對(duì)g>?7UG?^Cc?r?L-.如皿Ll-二-Bl€<*：?Pc?Htck>2n2l|l)>4*Tz"|h：AiMl/tH?(*<dUMe[2U"—“—-T>f?*$UM?<5qu??aMm*Y4fi?i?-r7243043?OCCOI￡UZ?1021Eg?soCD>MHIJM/Jow02WSOW，心yew?5MW心yew?5MW0妙，曲OXi9a/1*ao?/\241\24?77aa”a咖1力“*aa?/&1?00?，T.S2R1201&2鴨W022”5Artfrtvc052PANCc<rct?i!??X940e*0<3倚44MT&0今栩M?n“p.鈴處9"河Z%0S1P>ciift-&?ar?0初Mlt551224AdMjfVeaE21^12M\CIwsaFM4M(ttirnM*??(??<■10*wrr<e<??1OX知3人電豪便靈舸和EOg1012?0藥ia>ao??<€-?5孩4,5WP<7?.?0dwsanfitta-aw.Wxwcc■><在本例中，模型顯著性檢驗(yàn)pV)?05,表明該模型具有統(tǒng)計(jì)學(xué)意義。由圖4知其自變量一次項(xiàng)A,B,D,二次項(xiàng)AC,A2.B-,C2fD2顯著30.05)。失擬項(xiàng)用來(lái)表示所用模型與實(shí)驗(yàn)擬合的程度，即二者差異的程度。本例P值為0.0861>0.05,對(duì)模型是有利的，無(wú)失擬因素存在，因此可用該回歸方程代替試驗(yàn)真實(shí)點(diǎn)對(duì)實(shí)驗(yàn)結(jié)果進(jìn)行分析。C:\Ddom?atxxndSsttx?<x\x<8kc\^|t\x?ix斤底氏^化巫戶81(內(nèi)?氏斜備凈多ME.<ixT-T.!.tBE?C:\Ddom?atxxndSsttx?<x\x<8kc\^|t\x?ix斤底氏^化巫戶81(內(nèi)?氏斜備凈多ME.<ixT-T.!.tBE?」如22?t^rJRSS,撫Cw卯S502知EVUcwKtwL卻L『RiiAn^7?OEa色Pgi.egr.V??t~y'Trtrofwt?|運(yùn)rt"wl|*>Mole!ECe(F>o>tci1[^4a(MG?afea1|IJISMC*04309^3WMrt$411"河CV<40$1M潮他務(wù)1254K912dRMBtSIm>4m4w.ciw.ar*cto?■?lOMV*gg102$知3g1012g?02$1WBQ空如mi05210120?W0%1WC?1W相&畑4)161012g011ICOd?■柏聞m1so1a121J21afDOAC2?xe-ao1021?o?02f￡OAC?1161021■1??070f￡O*￡?100g0Q1W&COttO100g0Q1WEOa燉100g0?1WCD?24XfO61021?04?04€f￡0?ite1aid?203-1271?Bi■0461aid-o??O￡P(guān)B1?ci?IX1aid?1T1?0501019"ZHU■!T4IBM<4C^kdF?ct?<s：m?az-a?052-eo怖-c?ISO*0■ri.dogsbJOa>4圖5由圖5町知：校正決定系數(shù)R：(adj)(0.9788>0.80)和變異系數(shù)(CV)為0.51%,說(shuō)明該模型只有2.12%的變異，能由該模型解釋。進(jìn)一步說(shuō)明模型擬合優(yōu)度較好，叫?用來(lái)對(duì)超聲波輔助酶法制備燕麥ACE抑制肽的工藝研究進(jìn)行初步分析和預(yù)測(cè)。精品文檔ltl?14i<X??*D>?>lv精品文檔ltl?14i<X??*D>?>lvf??l?><ly精品文檔ltl?14i<X??*D>?>lv精品文檔ltl?14i<X??*D>?>lvf??l?><ly精品文檔精品文檔精品文檔精品文檔2.5多元二次響應(yīng)面回歸分析^C:\Ducv??atxxndSirU乂&<*\*?“\裁|k\xt：A<“joaG貢It氏便化攏廬口軒內(nèi)?*2務(wù)RgML.dxY-Dw-Kx”八T.i.tLUl*Xl-J，如rorEHSXmv?LOBC^CcArrtK片*1lAf?4^ZM>4-J，如rorEHSXmv?LOBC^CcArrtK片*1lAf?4^ZM>4?***!*??^Bs「--TrirafMnKar,l|a)從Nel4妙4J4C?OOC?25XC-CCG.MHITl*Z—利覧鄉(xiāng)Cm*51JMK9R*t?wtWbw*nm^4MWeH?frw5WtBMb<*?weg>?a>s?ell*?>t?Xe*?<tse0o??e“yVkwMe?o01gJT?O<.U4f?4WhlHMW??f|tibial.Son.MHITl*Z—利覧鄉(xiāng)Cm*51JMK9R*t?wtWbw*nm^4MWeH?frw5WtBMb<*?weg>?a>s?ell*?>t?Xe*?<tse0o??e“yVkwMe?o01gJT?O<.U4f?4WhlHMW??f|tibial.Sonspot?0ams坯tty.JJC'DiXUB?'“a>4MmI?iT4f?M<4Ac?wlFxQ?I：m?-14$10642?222?於?g????滬幼QMt?."!O3?HIWSM-saiaxcce?滬後檢阿gf)?娜&功直創(chuàng)Q02KCO?處05,加乂吃咖左朋?!K?S5ie?n*rr<i?Blimi^hi.4対2涇?5,?C29XXt-W?滬彼功圧伽)??林燦小■taaaxt-w.滬紇?.鼻*或?qū)??柏假川?001^75?|￡■農(nóng)翻f$：T.2祕(mì)極g-0062160?血^才必細(xì)匸卩?0UMi4m;圖6通過(guò)Design-Expeit軟件進(jìn)行二次響應(yīng)面回歸分析，得到如下多元二次響應(yīng)面回歸模型:H%)=—146.18542+2.23483X1+0.095966^2+6.40533X3+14.56083^4一0.016775X.2+5.68182x106XX—0.023300XX+0?00025XiXi-2.49225x104Xi2-4.59229x107^>%3一0.000625X1X4-0.052150Y?-0.0005XX-3.21125XF精品文檔ltl?j4ilX??<C?i?>lv精品文檔ltl?j4ilX??<C?i?>lv[jn>cnT??l?>?l>精品文檔ltl?j4ilX??<C?i?>lv精品文檔ltl?j4ilX??<C?i?>lv[jn>cnT??l?>?l>精品文檔精品文檔精品文檔精品文檔2.6數(shù)據(jù)點(diǎn)的分布圖^C:\Duom?atxxndS?ttxa4x\x?s?\^|K\xKacl?td<A￡K.dxT-T.1.10E?l-Jror卜卑知E7LCWKtWL卻U*gn-jLL±R1iAna^7??)hPc*<hedcwn'?r?<!>.F1y'Tiarofun法nStmrrf|a>4i*口祺云C^rortcsDesign-Expert?Softv/areR1ColorpointsbyvalueofR1:187.2380.36s-enprscapczlc尋2S>?￡￡￡as開(kāi)魁?"Hl0???<?<??￡<逐“eROResidualsvs.Predicted—■■?c5icP□■口口曰■—■口■■SIOO°oEl3.0?150-160?3B818305328707eocePredicted5JC"k&XVBMtCa>4.尖C八Dutr—Q*a&4S?ttin|：x\x<M\IISI\x?n|：Hjun*|PrSiattmP^^lXMl^^4?atJUK.dxT-DcxBia-fixpotT.I.I0|B?ltl?14i*.X??*C?>K?l?yl?>sp)Y<?1>B?ly￡l^e]匹」a]?21-JWZE如MS面撫0?枷1S5QE蘭如MVL<wiCc??勺Eiatai-團(tuán)L±JXS“-22FAM????3thsw-色West初n'?r??!>.”eFly*Trmttor-jM5?tmygMmMDe$?gr>-Expert?Soft\vareR1ColorpointsbyvalueofR1：87.2380.36pcupiMQPredictedvs.Actual87.X)—仍旳一S3&5—8183—旳(B—6644I6723eoce⑥?icr???RFrw<r??81B83仍ActualSi?：々；371910精品文檔精品文檔精品文檔精品文檔精品文檔精品文檔精品文檔精品文檔決C：U>uyQ*a&4SKttin|：x\x?&c\<(ai\x?nElijun*irfltiattmPA^lXKM^^4fatACK.dxT-Kxp?rtT.I.1ltl?14i*.X??*C?>K?l?yY<?1>B?ly一PW52z^rmisA|?r0?柳yTre?tarr?::flSowr^y3MuM忑CM^cotcc?gT□1^0］」翌」&\?_2\E?：^m)rtLCWiCurr*%MuAn-1T*14An*e<二rAM?*n>9lhsw?F：伽StYSnDe$?gr>-Expert?SoftwareR1ColorpointsbyvalueofR1:■87.2380.36D-VicrasafK.4.07203OK?203<07ExternallyStudentizedResidualsRunNumberFwcr?.從圖7?9可知道，數(shù)據(jù)的分布的線性明顯，沒(méi)有出現(xiàn)異常的數(shù)據(jù)點(diǎn)。決C：U>uyQ*a&4SKttin|：x\x?&c\<(ai\x?nElijun*irfltiattmPA^lXKM^^4fatACK.dxT-Kxp?rtT.I.1EE?ltl?14i*.X??*C?>K?l?yY<?1>B?ly□I^O］」翌」&\?_2\—Ir?*MWz&如ms面常0?柳1S50E蘭如”,uCr^ftCci^fCc0】Eiatoi-團(tuán)M/ntLtRl4An."<-22rf#

bSWAomheocwn'?r??!>.”eFl頭瑟."HI￡AJWVATranitor.三"RvtmygKxM2訕/V4知2下0觀MGS/o?0?3OiT4/0120?3Sf0270?3dl!3/0130觀如92Z0?0觀$<?012o?e0^0矽?U20150?380S02&0?3MM0120?3833026o?e鱒13013o?e勢(shì)芾011o?e84?OX0￡￡60545ox0?3asa?Dice0?3MM?0400?3夠今203o?e8225.0旳o?e彷?O<3o?e切4?0400?3MM?0400?3855?OX0?3WOT?0110X5e?o?oieeg0怒We?<?Myit如F?M力”山(#?T$04?90⑷曲10181W713M04M041004M0352asee1IM(?網(wǎng)o<ee05950<M0410(?網(wǎng)昭056211雄o-<ra04W054：1OM1DIB1X2D4ia04COD4X”丸066011240刑0啖OW0?)5056n033nn?IO?1118D2Maseo1皿?0JM■ow?0410?MM?isa?1W?14?-151$?1W33?3點(diǎn)??4.”?1W0?1vn.，剜?MM?isa?1W?1515?17M?ixe?imr?OJM?031??023)0也0*?0)?Q1NOWiocce0W7ocee0W20%0的0060￡C1occeoow0妙如0E6ooeaces0D12aire01S30矽QZ0aireai?awioa*OWOWi中?.■g口燉t-ticres*^.Fwcr?.圖10實(shí)驗(yàn)實(shí)際值與方程預(yù)測(cè)值2.7等高線和三維響應(yīng)曲面圖分析做出響應(yīng)曲面，分析超聲波處理時(shí)間3)、超聲波功率(3)、超聲波水浴溫度(C)和酚解時(shí)間(D)對(duì)ACE抑制率的影響情況，結(jié)果見(jiàn)圖11?22。triiBn5*C:\Ducu*?atx4Suttinex\x<&c\^Ol\x?nElijun?硏?住代妝產(chǎn)斎碼如床創(chuàng)老冷多M2dxT-D?v*<a-KxF?ttT.I.1triiBnltl?14i*.X??*C?>K?l?yB?lyQ|a；O血|呂I?Q|y*Trmitarr??FtSuvtmvgUxM-X^nvrt-UWitKZgL?：e*9iuBMn-?MfntTM<AnW?*<-￡A*y%'AI[7；y*Trmitarr??FtSuvtmvgUxM-X^nvrt-UWitKZgL?：e*9iuBMn-?MfntTM<AnW?*<-￡A*y%'AI[7；C*?^ca>cs]'IlGM"Lv：伽?eoc他”…三2—IDesignExpert?SofhvareR1?DesignPointsX1-A-超聲渋處理時(shí)間(min)X2-B-超聲蛙功率｛w)ActualFactorsC:超聲波水浴55.00D.凰解時(shí)(sj(h)=2.00口<tit-?Z3DD31328R11用叩—154W—25(0338358208A:超聲被處湮旳間(rrtn)1913圖11A與B對(duì)ACE抑制率影響的等高線C:\Ddcv*?ntxxndS?ttJU2E.dxT-Dcxaca-fixpcctT.1.iltl?14i<X,<rD；”L?yQM“mQw?p?f??l?><lyDQIQ]"翔別釧？席I-Jr<f*5fa2?t^rJRKB,：：ICw勿■弘5<7LjG?ic*tCcArrtK0】Esvl^n-如皿LL上ft?lAmi^zMiIiCumzw*-22-b?><*<■*-#]PcM^BdKtanTitrafwr.I??;n5*?W7f|l>?3?la4Design-Expert?Softv/are|0M?三：|R1?Designpointsabovepredictedvalueo■87.2380.36874rXI=A:13*波處理時(shí)間{min}X2=B:超聲波功率(w}ActualFactorsC:趙聲廢水浴ffiS(r)■55.00廠D:B?呻時(shí)間(h)-2.00M8B55BO78^8584220001980017600B：超聲波功率{w}1M00132002000^-^4000^^-^**35003000A:超聲波處理時(shí)間(min)ii*ws?a如sEg?□r?*MWz^rtmib-:::0?柳lA^XjE巴LCW^iCOM^°】Estoi5RIMnaS—JAj-22rA<???>3ih?>**<*.勺伽內(nèi)ii*ws?a如sEg?□r?*MWz^rtmib-:::0?柳lA^XjE巴LCW^iCOM^°】Estoi5RIMnaS—JAj-22rA<???>3ih?>**<*.勺伽內(nèi)t*?nykTrmitarr?-ngHxMDesign-Expert?SoftwareR1?DesignPoints6>■—]卜嚴(yán)叫MR.卜』祁卜林，?$AJWVAI忑0??rca?ctXI=Ai超聲波址理時(shí)(fij(mm)X2=C:超聲波水浴洽度f(wàn)C}ActualFactorsB:趙聲察功率(w)?17&00D齡解時(shí)0(h)-2.00GOW5793—S5(n一5293R1900320CO25WWWA:超聲波處理旳間(min)Tfirm|AB▼[天計(jì)?r?d]/odHKfc3i1t<tlS>「熱9Ait-虬<r?，?“圖12A及B對(duì)ACE抑制率影響的響應(yīng)面KC:\Ducu*?atxa&4S?ttinCx\x?&<\<ai\x?nEliA￡￡.dxT-T.I.1ltl?14i*.X??*C?>K?l?yY<?1>B?ly□|b；H]J毗O]??y?住fntrf.圖13A與C對(duì)ACE抑制率影響的等咼線圖14A及C對(duì)ACE抑制率影響的響應(yīng)面^C:\Du.:w*?atxa&4SKttinCx\x?&-T.1.1ltl?14i*.X??*C?>K?l?yY<?1>B?ly匹」01?創(chuàng)-Jr?*MWz&如ms面::tO?s1*^X1p：如MVL'如畑ZZT**iW"<-Jr?*MWz&如ms面::tO?s1*^X1p：如MVL'如畑ZZT**iW"<Weoc他ykrrmitarr*De$?gf>-Expert?SoftwareR1?DesignPointsX1=Ai超聲強(qiáng)處理時(shí)faj(mm)X2=D:98解時(shí)間(h)ActualFactorsB:超聲披功率(w)-17600C:超R波水浴55.00?-rtSuwT^y3Mo<M2AJWVACle^ca>ci28—7SO—IK)203WW?(?A:超聲波處理旳間(min)口-ttcrasa^.圖15A與D對(duì)ACE抑制率影響的等咼線C:\Ddo??atxxnd第嗎斤|X法便化顯戶SKtt?法斜務(wù)dxT-T.I.1E|B?22?t^rJRK?,rtCw卯S50G<<^CcArrar<tfmmLL/-送2"!心-&€<*:?-為PertFttdKtonTrmfc?n^mrtC:\Ddo??atxxnd第嗎斤|X法便化顯戶SKtt?法斜務(wù)dxT-T.I.1E|B?22?t^rJRK?,rtCw卯S50G<<^CcArrar<tfmmLL/-送2"!心-&€<*:?-為PertFttdKtonTrmfc?n^mrt1|>)MoJ*|丘^tod>4G<f?aDesign-Expert?Softv/areR1?Designpointsabovepredictedvalueo■87.2380.36X1=A:i3*波處理時(shí)間{min}X2=D:凰解時(shí)FfiJ(h)ActualFactorsB:超曲波功率(w)-176.00廠C:超聲蛙水浴iffl度{C}■5500MD：酶解時(shí)間(h)4000A:超聲波處理時(shí)間(min)圖16A及D對(duì)ACE抑制率影響的響應(yīng)面5*C:\Docuxatxa&4弘”訕|：譏"&<\長(zhǎng)?\“1)|：“，1??硏耐$代比潑產(chǎn)済碼奶法農(nóng)￡越疹1￡2血丁-Dw-Kxp?”T.I.1E|B?ltl?14i*.X??*C?>K?l?yY<?1>B?ly匹js]22l-J附MWz^rmib-Kt0?枷lA^XjLiCr^fiCU￡fCcHEiataiEC*T*M4An*—IjSaw-也伽StdM卜。?*[*柯')，?'■rI<ly,frvnfiy'rrarutarn?￡nSumeygMc<MDesign-Expert?Soft\vareR1?DesignPointsX1=B超聲強(qiáng)功?(w)X2=C：超聲波水浴繪度CQActualFactorsA:趙聲蛙處理時(shí)間(min)-3000D齡解時(shí)(B](h}-2.00R1B:超聲波功率(w)圖17B與C對(duì)ACE抑制率影響的等咼線Eg?Eg?決C：U>ucwt*xndSKttsMxXxc&cX^ltVxMacltju&^fVlk^UUR^JQWiM^tltta^J^K.dxT-DKxi<a-ixp?KtT.I.1ltl?14i<X??*D>?>lvf??l?><lyoic^Q]%l￡a]?iv-Jror紳如*K麗,■Cw勿E團(tuán)g>?7L]G4<*>C€<?r?-如皿LLf-bc<*?.勺PeriElanTrarafc<nS4MW7]|*>N口祺|EC*cr>ortc4^<odriC<KtaDe$ign-Expert?Softv/areR1?Designpointsabovepredatedvalueo■87.2305.4505.4580.36X1=B:波功至(\v｝X2=C:超聲波歡浴溫麼(f)ActualFactorsA?超聲波處理時(shí)間(min}■30.00廠D:B?呻時(shí)間(h)-2.00匕60005750600057505?D0*~――__c：超聲波水矗溫度｛它｝二>泗8"^980017600—B：超聲波功率(\町5000^13200gllggel-Ir?*MWztf^WSi-■OttV，E藝LCWiCCAM^巴EiataiLt*Rl4An*XJ‘“-二FAM????3ihSW.勺伽Fudcwngllggel-Ir?*MWztf^WSi-■OttV，E藝LCWiCCAM^巴EiataiLt*Rl4An*XJ‘“-二FAM????3ihSW.勺伽Fudcwn)?rId”yr<?Fl_rranitarnDe$?gr>-Expert?Soft\vareR1?DesignPointsXI=B超聲波功率{w)X2=D:aj鮮時(shí)間(h)更rtSovtmygHxMActualFactorsA:超聲蛙處理時(shí)間(mhO■30OTC:超聲波55.00?ilt*t-tficraaafK.KC(XUMC*仏9,38R1-293—1328劭Ihm?代Frw<r?,176COB：超聲波功率(W)2RCO圖］8B及C對(duì)ACE抑制率影響的響應(yīng)面決C八Dx—t**&4SKttinex\x?ni\||ai\x?nElijun^>iattlU!!盧窩碼如痂口尙冷鄉(xiāng)32dxT-Devtca-LipotT.I.11<1?14i*.X??*C?>K?l?yImsTabtf?lyPltflOl?|MP|a|71^ll圖19BMD対ACE抑制率影響的等咼線E|&?E|&?5^C:\Doom?atxxnd厳(K'xtxnt"josJRRlk氏低化顯戶氏A4務(wù)dxT-Dcxifa-fixpcrtT.I.tltl?14i<X??<D>?>lvT??1j??!>Dltfioi>m>|p|ai?MDesign-Expert?Softv/areR1?Designpointsabovepredictedvalueo■87.2387480.36X1=B：波功至(\v}X2=D:凰解時(shí)間{h}ActualFactorsA?超聲波處理時(shí)間(min}■30.00廠C:超聲蛙水浴iffl度代}■5500匕D:酹解時(shí)間(h>2200019B0082617600B：超聲波功率{\V)'?r?<!>.{ceFlr「弟始Kt12J?“Ml<HKiilltlUK*□9^t??icro.a圖20B及D對(duì)ACE抑制率影響的響應(yīng)面se?癸C八Dy"2SirttinuxXx.M^BiNx^nKlijun^aiattUJP^itatHIA^atACR.dxT-T.I.Ise?ltl?14i*.Qih'IvImsTab駐Q\」翌J0?創(chuàng)—Ir?*MW如m面E3如”,1JCw^cairm0】Eiatoi.zgLtR1?An*"<-FFAM???>3i

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El?>**<*-色陽(yáng)mstaen'?r?<!>.”eFl三“StfVTMYgMc<M4A*y%'AC*?^ca>ciLb??WG<<*aDe$?gr>-Expert?SoftwareR1?DesignPointsxi=c：超聲波水浴x2=d：aa鮮時(shí)間(t>)ActualFactorsA:趙聲蛙處理時(shí)間{min}-3000B:超聲披功率(w)?176.00口-VlcraiafK.38203R1293?C05260?(?57WWW入Fn?r?.C：超聲波水浴盅度CC)219勺圖21C與D對(duì)ACE抑制率影響的等咼線圖22C及D對(duì)ACE抑制率影響的響應(yīng)面2.8優(yōu)化最佳因素圖23圖24

圖25圖26

口P:\iT檸論文3?恢si論itAsnclij■?即口P:\iT檸論文3?恢si論itAsnclij■?即Bi伐伍&.P啟茨鏑巾曲絃Q場(chǎng)冷a.ACE.dxT-O?xtc&-Expi:rtT.I.Iltl?{41*.VjtrQjttoiI<?1>tf?lp-J応rwM^rlfiES面HOwVKSWj七會(huì)rer,-U<*4(>riC<4rfcLjjwi仍