高等數(shù)學(xué)D（23-24-1）學(xué)習(xí)通超星期末考試答案章節(jié)答案2024年

高等數(shù)學(xué)D（23-24-1）學(xué)習(xí)通超星期末考試章節(jié)答案2024年/star3/origin/49e3cea527a8e42c0fdf2890cb593374.png

答案:由于所以。/star3/origin/35014a2a2108a318c4784c9d431114a0.png

答案:空集/ananas/latex/p/506546

答案:0/star3/origin/9f7be58cc36217e660d042c59e347e69.png

答案:0/star3/origin/a12df529cc157e8aeed6cba0149191da.png

答案:原式/ananas/latex/p/503479

答案:原式/star3/origin/09e86c1a79aab0beb4f808126a7028d1.png

答案:1;-2/star3/origin/85ddbe31dcf241a6462ec332508cf1b3.png

答案:原式/star3/origin/a616f30b91a8679e4f67a493449d973e.png

答案:原式/star3/origin/00daa623b4ab995c95c398ebb9101ff0.png

答案:與是同階但不等價的無窮小/star3/origin/ca6e5d9900ffbc830a96fb7d2c7fc1ec.png

答案:0/star3/origin/b20f9bb1763c888c2827eb707b6429ec.png

答案:無窮間斷點/star3/origin/5498faa1c5f6a78bc34ae807999365f6.png

答案:可去間斷點/star3/origin/8b1db95da4f3619831949de15ffba8ca.png

答案:跳躍/star3/origin/42cf68323f147beb858268013437c5e0.png

答案:(1)連續(xù);;(2)令則在閉區(qū)間上連續(xù),且于是由零點定理知,至少存在一個點使,也即方程至少有一個介于和之間的根./star3/origin/402d93486a194a97a15de5dc3f4c384a.png

答案:-7;5/star3/origin/5b0d8048e172b22ed7ce949697387a10.png

答案:正確初等函數(shù)在其定義域內(nèi)必定為連續(xù)函數(shù)

答案:錯誤/star3/origin/7588377b2279541061e74e0d89b865a6.png

答案:1,0/star3/origin/d346137a2d4b61091c56f5ea83b09069.png

答案:不存在/star3/origin/533f01207d327f42622e6afce8ce63f6.png

答案:./star3/origin/1b041b253efbdd8d9203056264cdea04.png

答案:./star3/origin/7191a6b19aad222dadfacb545b0d8c80.png

答案:,,./star3/origin/410d99f6ead3d65c1a070d4057020b28.png

答案:在上滿足羅爾定理,故存在使得,又在上滿足羅爾定理,故存在使得,從而在上滿足羅爾定理,故存在,使得/star3/origin/39e9e319ff4c1a9bcd5854738dc1dc89.png

答案:設(shè)函數(shù),,在上滿足羅爾定理,故存在,使得,即./star3/origin/5c95ae6e01a05e40a4789eb47bf64718.png

答案:設(shè)長方形長為,寬為,高為,則表面積為,令,則,由題意,在處取得最小值,此時長為6,寬為3,高為4,表面積最小。/star3/origin/71969a89da3e82a4c8b5a647a33d5688.png

答案:,令解得,又是不可導(dǎo)點,列表得:0(0,1)1+不存在_0+極大值極小值判定為在處取得極大值,在處取得極小值./star3/origin/e0fc3a1f45af4b4c80224eeb004f20e1.png

答案:1函數(shù)定義域2,令,則有;令,則有。3當時,;當時,;且時,。所以,單減區(qū)間,單增區(qū)間,極大值4當時,,故在整個定義域上曲線為凸。5作圖(略)/star3/origin/f2071126556950b05c5ef9e7fc623d75.png

答案:設(shè)因為是增函數(shù),故有,即單調(diào)增加,從而,則時,/star3/origin/f5ab37bee6cb8fa0b7675b4673f73d24.png

答案:取得極小值/star3/origin/7627ea58f2e51824f83efcb51880bac4.png

答案:無法確定是什么點/star3/origin/89c418e7c31118abb0a49b22ae4147db.png

答案:原式/star3/origin/cac10b9c4a059b7902c7d33de00e8dd6.png

答案:原式=/star3/origin/2cc9a23aa4843d48073feca2cf14666f.png

答案:原式=/star3/origin/f53de443c08965d6a16c4de45dc33889.png

答案:原式/star3/origin/0bf4242e616901bf4d9c481934b813a0.png

答案:3/star3/origin/d37d125d33ad26ecafc1dbbf0c026f66.png

答案:根據(jù)積分中值定理,存在使得,又根據(jù)無窮小函數(shù)與有界函數(shù)乘積的極限還是無窮小,故/star3/origin/c27a33c478cdebe844ff1d5e40f757e8.png

答案:1/star3/origin/b22a6b20b826cd84f9fb48776cff5bb9.png

答案:由于,所以。/star3/origin/a3d5d79d560db2f0d620f89d98ef870c.png

答案:./star3/origin/d0090da33367d8e9ab6e331cc4ac525d.png

答案:./star3/origin/b33cc0e007520c2c8849f1ffc20eebb1.png

答案:./star3/origin/2627fce5791884ac5214d7385f3e5cb4.png

答案:極小值/star3/origin/4ee987838563a459c56dd937f1371e12.png

答案:令,則。于是,/star3/origin/0d89c9d2998e4f0b87de895a60cf2aff.png

答案:令,則。當時,;當時,。于是,。/star3/origin/5b320f9397a3b698d0f935e3bdb06687.png

答案:令,則。當時,;當時,。于是,。/star3/origin/e2932554bf9477faff1ca594260268f9.png

答案:由于是上的奇函數(shù),是上的偶函數(shù),根據(jù)定積分的“奇零偶倍”性質(zhì),有。/star3/origin/aa27831b8c6bc4a490e02d5d8410b9d9.png

答案:。/star3/origin/fc21b7d5077c0a54245e989e3d45b69f.png

答案:令,則。當時,;當時,。于是,。/star3/origin/12f3ce0f5f9bbfc00dd884811473e43c.png

答案:令,則。于是,。/star3/origin/18b441698a7c1f9cfb475884e710bfc8.png

答案:如圖(略),。。/star3/origin/5509f48e05bd40a09f05b2f1a066a72d.png

答案:利用無窮小等價和函數(shù)的連續(xù)性計算,/star3/origin/5d7925a8488a0d06bf50c0644479a51a.png

答案:2/star3/origin/960f7a6e634d4da9b41ef0d89e61028e.png

答案:。/star3/origin/d5ca02e7f2520c63910bf4bb51939825.png

答案:不一定連續(xù)/star3/origin/46d45885cddbd1e8bbc8c6bbb58fc6ad.png

答案:-2x/star3/origin/fe97bcbe397142d74126e07ca8bf2a7a.png

答案:不一定可微,也不一定連續(xù)/star3/origin/2f69e41681fc765cfc2f344a4333b777.png

答案:積分區(qū)域的面積為.在上,有,因此,在上,,從而有,因此,即./star3/origin/3b4b989fb8c004b7721cb3472f8c66d6.png

答案:圓形閉區(qū)域的面積為.在上,即,因此,即./star3/origin/232d33e874adc18307f034cee1462496.png

答案:(上半球的體積/star3/origin/6211f145434b05360eebf00652d8b8dd.png

答案:正號/star3/origin/d460bb40e628648bd71bdbcdf53171a4.png

答案:積分區(qū)域可