新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題20 利用導(dǎo)數(shù)解決函數(shù)的極值點(diǎn)問題(原卷版)_第1頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題20 利用導(dǎo)數(shù)解決函數(shù)的極值點(diǎn)問題(原卷版)_第2頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題20 利用導(dǎo)數(shù)解決函數(shù)的極值點(diǎn)問題(原卷版)_第3頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題20 利用導(dǎo)數(shù)解決函數(shù)的極值點(diǎn)問題(原卷版)_第4頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題20 利用導(dǎo)數(shù)解決函數(shù)的極值點(diǎn)問題(原卷版)_第5頁(yè)
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專題20利用導(dǎo)數(shù)解決函數(shù)的極值點(diǎn)問題一、單選題1.已知函數(shù)SKIPIF1<0,則下列結(jié)論錯(cuò)誤的是()A.SKIPIF1<0是奇函數(shù)B.若SKIPIF1<0,則SKIPIF1<0是增函數(shù)C.當(dāng)SKIPIF1<0時(shí),函數(shù)SKIPIF1<0恰有三個(gè)零點(diǎn)D.當(dāng)SKIPIF1<0時(shí),函數(shù)SKIPIF1<0恰有兩個(gè)極值點(diǎn)2.如圖是函數(shù)SKIPIF1<0的導(dǎo)函數(shù)SKIPIF1<0的圖象,則函數(shù)SKIPIF1<0的極小值點(diǎn)的個(gè)數(shù)為()A.0 B.1 C.2 D.33.已知函數(shù)SKIPIF1<0的導(dǎo)函數(shù)SKIPIF1<0,若SKIPIF1<0在SKIPIF1<0處取得極大值,則實(shí)數(shù)SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.若函數(shù)SKIPIF1<0無(wú)極值點(diǎn)則實(shí)數(shù)a的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.已知函數(shù)SKIPIF1<0有兩個(gè)極值點(diǎn),則a的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<06.“SKIPIF1<0”是“函數(shù)SKIPIF1<0在SKIPIF1<0上有極值”的()A.充分不必要條件 B.必要不充分條件C.充要條件 D.既不充分也不必要條件7.已知函數(shù)SKIPIF1<0,若同時(shí)滿足條件:①SKIPIF1<0,SKIPIF1<0為SKIPIF1<0的一個(gè)極大值點(diǎn);②SKIPIF1<0,SKIPIF1<0.則實(shí)數(shù)a的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.若函數(shù)SKIPIF1<0(SKIPIF1<0為常數(shù))有兩個(gè)不同的極值點(diǎn),則實(shí)數(shù)SKIPIF1<0取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.已知函數(shù)SKIPIF1<0在SKIPIF1<0處取得極值,則SKIPIF1<0()A.1 B.2 C.SKIPIF1<0 D.-210.設(shè)函數(shù)SKIPIF1<0,則下列是函數(shù)SKIPIF1<0極小值點(diǎn)的是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.函數(shù)SKIPIF1<0的圖象大致是()A. B.C. D.12.已函數(shù)SKIPIF1<0的兩個(gè)極值點(diǎn)是SKIPIF1<0和SKIPIF1<0,則點(diǎn)SKIPIF1<0的軌跡是()A.橢圓弧 B.圓弧 C.雙曲線弧 D.拋物線弧13.若SKIPIF1<0是函數(shù)SKIPIF1<0的極值點(diǎn),則SKIPIF1<0的值是()A.1 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<014.已知函數(shù)SKIPIF1<0,則SKIPIF1<0)的極大值點(diǎn)為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<015.若函數(shù)SKIPIF1<0有兩個(gè)不同的極值點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、多選題16.設(shè)函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0,則()A.SKIPIF1<0 B.SKIPIF1<0是SKIPIF1<0的極值點(diǎn)C.SKIPIF1<0存在零點(diǎn) D.SKIPIF1<0在SKIPIF1<0單調(diào)遞增17.關(guān)于函數(shù)SKIPIF1<0,SKIPIF1<0,下列結(jié)論正確的有()A.當(dāng)SKIPIF1<0時(shí),SKIPIF1<0在SKIPIF1<0處的切線方程為SKIPIF1<0B.當(dāng)SKIPIF1<0時(shí),SKIPIF1<0存在惟一極小值點(diǎn)SKIPIF1<0C.對(duì)任意SKIPIF1<0,SKIPIF1<0在SKIPIF1<0上均存在零點(diǎn)D.存在SKIPIF1<0,SKIPIF1<0在SKIPIF1<0有且只有一個(gè)零點(diǎn)18.已知函數(shù)SKIPIF1<0,SKIPIF1<0,則下列說(shuō)法正確的有()A.SKIPIF1<0是偶函數(shù)B.SKIPIF1<0是周期函數(shù)C.在區(qū)間SKIPIF1<0上,SKIPIF1<0有且只有一個(gè)極值點(diǎn)D.過(0,0)作SKIPIF1<0的切線,有且僅有3條19.已知SKIPIF1<0.()A.SKIPIF1<0的零點(diǎn)個(gè)數(shù)為4 B.SKIPIF1<0的極值點(diǎn)個(gè)數(shù)為3C.x軸為曲線SKIPIF1<0的切線 D.若SKIPIF1<0,則SKIPIF1<020.設(shè)函數(shù)SKIPIF1<0,則下列說(shuō)法正確的是()A.SKIPIF1<0定義域是SKIPIF1<0 B.SKIPIF1<0時(shí),SKIPIF1<0圖象位于SKIPIF1<0軸下方C.SKIPIF1<0存在單調(diào)遞增區(qū)間 D.SKIPIF1<0有且僅有一個(gè)極值點(diǎn)三、解答題21.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0只有一個(gè)極值點(diǎn),求SKIPIF1<0的取值范圍.(2)若函數(shù)SKIPIF1<0存在兩個(gè)極值點(diǎn)SKIPIF1<0,記過點(diǎn)SKIPIF1<0的直線的斜率為SKIPIF1<0,證明:SKIPIF1<0.22.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0是奇函數(shù),且有三個(gè)零點(diǎn),求SKIPIF1<0的取值范圍;(2)若SKIPIF1<0在SKIPIF1<0處有極大值SKIPIF1<0,求當(dāng)SKIPIF1<0時(shí)SKIPIF1<0的值域.23.(1)當(dāng)SKIPIF1<0時(shí),求證:SKIPIF1<0;(2)若SKIPIF1<0對(duì)于任意的SKIPIF1<0恒成立,求實(shí)數(shù)k的取值范圍;(3)設(shè)a>0,求證;函數(shù)SKIPIF1<0在SKIPIF1<0上存在唯一的極大值點(diǎn)SKIPIF1<0,且SKIPIF1<0.24.已知函數(shù)SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性.(2)若SKIPIF1<0,設(shè)SKIPIF1<0是函數(shù)SKIPIF1<0的兩個(gè)極值點(diǎn),若SKIPIF1<0,求證:SKIPIF1<0.25.已知函數(shù)SKIPIF1<0(1)討論SKIPIF1<0的單調(diào)性;(2)若SKIPIF1<0有兩個(gè)極值點(diǎn)SKIPIF1<0,求SKIPIF1<0的取值范圍.26.已知函數(shù)SKIPIF1<0SKIPIF1<0,SKIPIF1<0是偶函數(shù).(1)求函數(shù)SKIPIF1<0的極值以及對(duì)應(yīng)的極值點(diǎn).(2)若函數(shù)SKIPIF1<0,且SKIPIF1<0在SKIPIF1<0上單調(diào)遞增,求實(shí)數(shù)SKIPIF1<0的取值范圍.27.已知函數(shù)SKIPIF1<0,其導(dǎo)函數(shù)為SKIPIF1<0,且SKIPIF1<0.(1)求a的值;(2)設(shè)函數(shù)SKIPIF1<0有兩個(gè)極值點(diǎn)SKIPIF1<0,SKIPIF1<0,求b的取值范圍,并證明過兩點(diǎn)SKIPIF1<0,SKIPIF1<0的直線m恒過定點(diǎn),且求出該定點(diǎn)坐標(biāo)SKIPIF1<0(3)當(dāng)SKIPIF1<0時(shí),證明函數(shù)SKIPIF1<0在R上只有一個(gè)零點(diǎn).28.設(shè)函數(shù)SKIPIF1<0,其中SKIPIF1<0.(1)若曲線SKIPIF1<0

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