新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題17 利用導(dǎo)數(shù)求函數(shù)的極值(原卷版)_第1頁
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題17 利用導(dǎo)數(shù)求函數(shù)的極值(原卷版)_第2頁
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題17 利用導(dǎo)數(shù)求函數(shù)的極值(原卷版)_第3頁
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題17 利用導(dǎo)數(shù)求函數(shù)的極值(原卷版)_第4頁
新高考數(shù)學(xué)二輪復(fù)習(xí)重難點(diǎn)突破專題17 利用導(dǎo)數(shù)求函數(shù)的極值(原卷版)_第5頁
已閱讀5頁,還剩1頁未讀, 繼續(xù)免費(fèi)閱讀

下載本文檔

版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)

文檔簡(jiǎn)介

專題17利用導(dǎo)數(shù)求函數(shù)的極值一、多選題1.下列命題正確的有()A.已知SKIPIF1<0且SKIPIF1<0,則SKIPIF1<0B.SKIPIF1<0,則SKIPIF1<0C.SKIPIF1<0的極大值和極小值的和為SKIPIF1<0D.過SKIPIF1<0的直線與函數(shù)SKIPIF1<0有三個(gè)交點(diǎn),則該直線斜率的取值范圍是SKIPIF1<02.對(duì)于函數(shù)SKIPIF1<0,下列說法正確的是()A.SKIPIF1<0在SKIPIF1<0處取得極大值SKIPIF1<0 B.SKIPIF1<0有兩個(gè)不同的零點(diǎn)C.SKIPIF1<0 D.若SKIPIF1<0在SKIPIF1<0上恒成立,則SKIPIF1<03.已知函數(shù)SKIPIF1<0,其導(dǎo)函數(shù)為SKIPIF1<0,下列命題中為真命題的是()A.SKIPIF1<0的單調(diào)減區(qū)間是SKIPIF1<0B.SKIPIF1<0的極小值是﹣6C.過點(diǎn)SKIPIF1<0只能作一條直線與SKIPIF1<0的圖象相切D.SKIPIF1<0有且只有一個(gè)零點(diǎn)4.材料:函數(shù)是描述客觀世界變化規(guī)律的重要數(shù)學(xué)模型,在現(xiàn)行的高等數(shù)學(xué)與數(shù)學(xué)分析教材中,對(duì)“初等函數(shù)”給出了確切的定義,即由常數(shù)和基本初等函數(shù)經(jīng)過有限次的四則運(yùn)算及有限次的復(fù)合步驟所構(gòu)成的,且能用一個(gè)式子表示的,如函數(shù)SKIPIF1<0,我們可以作變形:SKIPIF1<0SKIPIF1<0,所以SKIPIF1<0可看作是由函數(shù)SKIPIF1<0和SKIPIF1<0復(fù)合而成的,即SKIPIF1<0為初等函數(shù).根據(jù)以上材料,對(duì)于初等函數(shù)SKIPIF1<0的說法正確的是()A.無極小值 B.有極小值SKIPIF1<0 C.無極大值 D.有極大值SKIPIF1<05.設(shè)SKIPIF1<0為函數(shù)SKIPIF1<0的導(dǎo)函數(shù),已知SKIPIF1<0,SKIPIF1<0,則下列結(jié)論不正確的是()A.SKIPIF1<0在SKIPIF1<0單調(diào)遞增 B.SKIPIF1<0在SKIPIF1<0單調(diào)遞增C.SKIPIF1<0在SKIPIF1<0上有極大值SKIPIF1<0 D.SKIPIF1<0在SKIPIF1<0上有極小值SKIPIF1<06.已知函數(shù)SKIPIF1<0,其導(dǎo)函數(shù)為SKIPIF1<0,下列命題中真命題的為()A.SKIPIF1<0的單調(diào)減區(qū)間是SKIPIF1<0B.SKIPIF1<0的極小值是SKIPIF1<0C.當(dāng)SKIPIF1<0時(shí),對(duì)任意的SKIPIF1<0且SKIPIF1<0,恒有SKIPIF1<0(a)SKIPIF1<0(a)SKIPIF1<0D.函數(shù)SKIPIF1<0有且只有一個(gè)零點(diǎn)二、單選題7.設(shè)函數(shù)SKIPIF1<0在R上可導(dǎo),其導(dǎo)函數(shù)為SKIPIF1<0,且函數(shù)SKIPIF1<0的圖象如圖所示,則下列結(jié)論中一定成立的是()A.SKIPIF1<0有極大值SKIPIF1<0 B.SKIPIF1<0有極小值SKIPIF1<0C.SKIPIF1<0有極大值SKIPIF1<0 D.SKIPIF1<0有極小值SKIPIF1<08.下列關(guān)于函數(shù)SKIPIF1<0的結(jié)論中,正確結(jié)論的個(gè)數(shù)是()①SKIPIF1<0的解集是SKIPIF1<0;②SKIPIF1<0是極大值,SKIPIF1<0是極小值;③SKIPIF1<0沒有最大值,也沒有最小值;④SKIPIF1<0有最大值,沒有最小值;⑤SKIPIF1<0有最小值,沒有最大值.A.1個(gè) B.2個(gè) C.3個(gè) D.4個(gè)9.函數(shù)y=f(x)的導(dǎo)函數(shù)y=f′(x)的圖象如圖所示,給出下列命題:①-3是函數(shù)y=f(x)的極值點(diǎn);②y=f(x)在區(qū)間(-3,1)上單調(diào)遞增;③-1是函數(shù)y=f(x)的最小值點(diǎn);④y=f(x)在x=0處切線的斜率小于零.以上正確命題的序號(hào)是()A.①② B.③④ C.①③ D.②④10.已知函數(shù)SKIPIF1<0,函數(shù)SKIPIF1<0零點(diǎn)的個(gè)數(shù)為()A.1 B.2 C.3 D.411.設(shè)函數(shù)SKIPIF1<0,則()A.SKIPIF1<0有極大值且為最大值 B.SKIPIF1<0有極小值,但無最小值C.若方程SKIPIF1<0恰有3個(gè)實(shí)根,則SKIPIF1<0 D.若方程SKIPIF1<0恰有一個(gè)實(shí)根,則SKIPIF1<0三、解答題12.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0,求SKIPIF1<0在區(qū)間SKIPIF1<0上的極值;(2)討論函數(shù)SKIPIF1<0的單調(diào)性.13.設(shè)函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的極值;(2)若函數(shù)SKIPIF1<0有2個(gè)零點(diǎn),求實(shí)數(shù)SKIPIF1<0的取值范圍.14.(1)已知SKIPIF1<0,SKIPIF1<0,若SKIPIF1<0,且SKIPIF1<0圖象在點(diǎn)SKIPIF1<0處的切線方程為SKIPIF1<0,求SKIPIF1<0的值.(2)求函數(shù)SKIPIF1<0在SKIPIF1<0上的極值.15.已知函數(shù)SKIPIF1<0.(1)若函數(shù)SKIPIF1<0,求函數(shù)SKIPIF1<0的極值;(2)若SKIPIF1<0在SKIPIF1<0時(shí)恒成立,求實(shí)數(shù)SKIPIF1<0的最小值.16.已知函數(shù)SKIPIF1<0,SKIPIF1<0(其中SKIPIF1<0).(1)求函數(shù)SKIPIF1<0的極值;(2)若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)有兩個(gè)零點(diǎn),求正實(shí)數(shù)SKIPIF1<0的取值范圍;(3)求證:當(dāng)SKIPIF1<0時(shí),SKIPIF1<0.(說明:SKIPIF1<0是自然對(duì)數(shù)的底數(shù),SKIPIF1<0)17.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)設(shè)SKIPIF1<0,求函數(shù)SKIPIF1<0的極值;(2)若SKIPIF1<0,試研究函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù).18.已知函數(shù)SKIPIF1<0,在SKIPIF1<0時(shí)取得極值.(1)求SKIPIF1<0的值;(2)求函數(shù)SKIPIF1<0的單調(diào)區(qū)間.19.已知函數(shù)SKIPIF1<0,SKIPIF1<0是奇函數(shù).(1)求SKIPIF1<0的表達(dá)式;(2)求函數(shù)SKIPIF1<0的極值.20.已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的極值;(2)當(dāng)SKIPIF1<0時(shí),求不等式SKIPIF1<0的解集;(3)當(dāng)SKIPIF1<0時(shí),若當(dāng)SKIPIF1<0,恒有SKIPIF1<0成立,求實(shí)數(shù)SKIPIF1<0的取值范圍.21.已知函數(shù)SKIPIF1<0(aSKIPIF1<0R).(1)討論SKIPIF1<0的極值;(2)若a=2,且當(dāng)SKIPIF1<0時(shí),不等式SKIPIF1<0恒成立,求實(shí)數(shù)m的取值范圍.22.已知函數(shù)SKIPIF1<0.(1)求SKIPIF1<0的極值;(2)若函數(shù)SKIPIF1<0在定義域內(nèi)有三個(gè)零點(diǎn),求實(shí)數(shù)a的取值范圍.23.函數(shù)SKIPIF1<0.(1)求SKIPIF1<0的極大值和極小值;(2)已知SKIPIF1<0在區(qū)間D上的最大值為20,以下3個(gè)區(qū)間D的備選區(qū)間中,哪些是符合已知條件的?哪些不符合?請(qǐng)說明理由.①SKIPIF1<0;②SKIPIF1<0;③SKIPIF1<024.已知函數(shù)SKIPIF1<0.(1)求函數(shù)SKIPIF1<0的極小值;(2)關(guān)于SKIPIF1<0的不等式SKIPIF1<0在SKIPIF1<0上存在解,求實(shí)數(shù)SKIPIF1<0的取值范圍.25.已知函數(shù)SKIPIF1<0.(Ⅰ)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的單調(diào)區(qū)間(Ⅱ)設(shè)SKIPIF1<0,若函數(shù)SKIPIF1<0在SKIPIF1<0有兩個(gè)零點(diǎn),求SKIPIF1<0的取值范圍26.已知函數(shù)SKIPIF1<0的極大值為2.(1)求a的值和SKIPIF1<0的極小值;(2)求SKIPIF1<0在SKIPIF1<0處的切線方程.27.已知函數(shù)SKIPIF1<0.(1)討論SKIPIF1<0的極值;(2)若方程SKIPIF1<0在SKIPIF1<0上有實(shí)數(shù)解,求SKIPIF1<0的取值范圍.28.設(shè)函數(shù)SKIPIF1<0,其中SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0均為常數(shù),曲線SKIPIF1<0在SKIPIF1<0處的切線方程為SKIPIF1<0.(1)求SKIPIF1<0,SKIPIF1<0

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
  • 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
  • 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
  • 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
  • 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。

評(píng)論

0/150

提交評(píng)論