Ge04材料力學(xué)-拉伸與壓縮

1、各點位移相同各點位移相同各點應(yīng)變相同各點應(yīng)變相同各點應(yīng)力相同各點應(yīng)力相同AFN= =s sNsFANss=AFAFNsAFN= =s s= 0AM030.75)(31=FNkN23111N.= NF= 0DM0sin30230.6)(3.2o21=NN.kN17422N.= NFAF2N=s2325143101744=.MPa151s= 0.63.2mkN2 .311N=FkN1 .742N=Fd2 = 25 mm42Nss=dF4NsFd mm81516014310231431.=dmm32416043110174432.=d= 0AM030.75)(31=FN480421211N1ss=d

2、FdF.)(FNF8011N.=0.8421sdFkN298804160251432.= 0.63.2m= 0AM480421211N1ss=dFdF.)(FNF8011N.=0.8421sdFkN298804160251432.=030.75)(31=FN 0.63.2m= 0DM0sin30230.6)(3.2o21=NN.122N3752NNF.=1.9422sdFkN298.F491422222N2ss=dFdF.)(kN81=FkN081914160351432.= 0.63.2mFNF8011N.=F91.= 0AmFLbN=)tan()cos(4=sinNbFLNF=sinNss

3、=AbFLAFssinbFLAAlgG=ssincosbFLbg=sincosC= 過小過小 過大過大F)(xff =0)(0=xxxf0)(0 =xxxf0)(0 =xxxf0)(0= =xxxfN11sinFFN=N22tanFFN=sint111N1ss=AFAF)(tanc222N2ss=AFAF)(ssint1FA =stanc2FA =由結(jié)點 B 的平衡可得12cosALLAV=sscossintantcLFLF=AC12LN11sinFFN=N22tanFFN=sint111N1ss=AFAF)(tanc222N2ss=AFAF)(ssint1FA =stanc2FA =由結(jié)點

4、B 的平衡可得12cosALLAV=sscossintantcLFLF= =cossin1tan1CV0dd=)(V0cossincossinsin122222=C2tan=4454o=sscossintantcLFLFV= 隨著經(jīng)濟的發(fā)展，隨著人類文明的進步，隨著經(jīng)濟的發(fā)展，隨著人類文明的進步，也隨著環(huán)境的日益惡化和資源的日益減少，人也隨著環(huán)境的日益惡化和資源的日益減少，人們對工程結(jié)構(gòu)具有最優(yōu)性質(zhì)的要求越來越廣泛們對工程結(jié)構(gòu)具有最優(yōu)性質(zhì)的要求越來越廣泛和迫切。和迫切。結(jié)構(gòu)優(yōu)化設(shè)計結(jié)構(gòu)優(yōu)化設(shè)計Structural Optimum DesignAF=s不受影響不受影響scosNAF=sinNAF

5、=AFN=scosAA =AFp =cosAF=scosp=2cos210)(s=sinp=2sin20)(s=s20cos=ssincos0=cosAF=scos0=602cos210)(ss=2sin20)(s=cos212s=bhFkN7 .105 . 011040202cos212=sbhF2sin2=bhFkN1 .11866. 0640202sin22=bhFkN10.7=Fxxu=xxxddd=xudd=xudd=xEudds=xEAFdN=A AAxxu=xxxddd=xudd=xudd=xEudds=xEAFdN=xEudds=xEAFdN=xEAFuxuxd00N=)()(

6、xE AxFLd0Nx)()(L = =D DE ALFLN= =D DA LLDD fLLf=D0=CBNABPkN36=CBABPN= 0BMNss=AF2Nmm514=sFA)(NlEAlFlDD=2Nmm633)(=lElFAD63332= tA514.=t0.8mDNF=P=6kN0.6m0.1mABxqF =N=LLNEAqLxEAxqxEAFL0202ddDEAqLL2=DqLF =NqLF =NEAqLL22=D1212lnhhhhEbFL)(=LxLhhhhhEbFLL012112ln=)(DxLhhhxh121=)(=xLhhhbbhxA121)(xEAFLLd0N=DxL

7、xhhhEbFLd0121=)(h2h1h2h1EAPaAB =EAPAEAaPAC222=EAPaACCS2221=EAPaABuA=AKBKvA= =EAPa122ABCSCS=P2)(A 點在變形后的真實位置A 點在變形后的近似位置RR=cos=124521142R)(2O=EAFauA =EAFavA)(1sec=RPN=cos2PNN=21cos2LE1A1E1A1E2A2PNN=21cos221N1coscos2=PNF32N2cos21=PNF1122AEAE=Dcos1111111N1AELNAElFl=2222222N2AELNAElFl=DDDcos21ll =FEA EALF2=LEAF2=FEALEAF2FEAFNNCA=FFFBCAB=NN EALF2=LEAF2=LEAF2FNNCA=FFFBCAB=NN FEAFEAFNNCA=FFFBCAB=NNEALFlABAB2N=DEALFlBCBC2N=DDD=BCABllLEAFFAB=2NLEAFFBC=2Ncos212=0