版權說明:本文檔由用戶提供并上傳,收益歸屬內容提供方,若內容存在侵權,請進行舉報或認領
文檔簡介
1、上機報告題目I姓名學號第一題Questions:Q3,lWhalislheexpressionofIlieDTFTbeingevaluatedinProgramP3_l?WhatisthefunclionoflheMATLABcommandpause?Q3.2RunProgramP3_landcomputelherealandimaginarypartsoftheDTFT,andlhemagnitudeandphasespectra.IstheDTFTaperiodicfunctionoflj?Ifitis,whatistheperiodExplainlhetype01symmclricsex
2、hibitedbylhelourplots.Q3.3MixlilyProgramP3loevalualeinlherange0ttlhefollowingDTFT:y_0,7-0.血”+碁+E-仙1+0.3e_Jw0.5ej2+0.7e_J3wandrepciUQuestion(J3.2.CommenIonyourresults.Cunyouexplainlhejumpinlhephasespectru111?ThejumpcanberemovedusingtheMATLABcommandunwrap.Evaluatelhephusespeclruniwithlhejumpremoved.Q3
3、.4ModiIyProgramP3toevaluulclheDTFTofthefollowinglinile-lengtlisequence:gn=1357911131517,andrepcal(ucslionQ?.2.Commentonyourresults.Canyouexplainlhejumpsinlhephase斗卩eclrum?Q3,5HowwouldyoumodifyProgramP3_ltoplotthephaseindegrees?Answers.Q3.1TheexpressionoftheDTFTbeingevaluatedinProgramP3_1is-Hej32+ejs
4、106qjsThefunctionofthepausecommandispause命令用于暫時中止程序的運行。當程序運行到此命令時,程序暫時中止,然后等待用戶按任意鍵繼續(xù)進行。在本程序中,pause用來顯示兩組不同的圖(實虛部圖和幅頻相頻圖),并在中間暫停以供用戶查看。Q3.2TheplotsgeneratedbyrunningProgramP3_1areshownbelow:44Realpartof-2-1012343山ImaginarypartofHi:)TheDTFTisa_周期MagnitudeSpectrumH(e)|-2-1012343/tTPhaseSpectrumargH(e)
5、|-2-1012wAt_functionofItsperiodis-2piThetypesofsymmetriesexhibitedbythefourplotsareasfollows:共軛對稱Q3.3TherequiredmodificationstoProgramP3_1toevaluatethegivenDTFTofQ3.3aregivenbelow:num=--0.5TheplotsgeneratedbyrunningthemodifiedProgramP3_1areshownbelow:15051a心-Dpn七-dEHi-10123心/ttIm白ginarypart
6、ofH(d)CDpn七-dE15051a4;/ttMagnitudeSpectrumH(eM)|PhaseSpectrumargH(ejLL,)Itsperiodis-2piDTFT經過虛部等于0,實Thejumpinthephasespectrumiscausedby-部小于0的點o5-20-253023Thephasespectrumevaluatedwiththejumpremovedbythecommandunwrapisasgivenbelow:3ITTPhaseSpectrumargH(eJQ,)Q3.4TherequiredmodificationstoProgramP3_1to
7、evaluatethegivenDTFTofQ3.4aegivenbelow:h=freqz(1357911131517,1,w);TheplotsgeneratedbyrunningthemodifiedProgramP3_1areshownbelow:RealpartofH(ej)oo5QP2一-duj-3-2u;/Z伽ImaginarypartofTheDTFTisa_周期如p-dEfunctionofItsperiodis-2pi實areThejumpinthephasespectrumiscausedby-DTFT經過虛部等于0,部小于0的點Q3.5Therequiredmodifi
8、cationstoProgramP3_1toplotthephaseindegreesindicatedbelow:%PlottheDTFTsubplot(2,1,1)plot(w/pi*180,real(h);gridtitle(RealpartofH(eAjomega)xlabel(omega/degree);ylabel(Amplitude);subplot(2,1,2)plot(w/pi*180,imag(h);gridtitle(ImaginarypartofH(eAjomega)xlabel(omega/degree);ylabel(Amplitude);pausesubplot(
9、2,1,1)plot(w/pi*180,abs(h);gridtitle(MagnitudeSpectrum|H(eAjomega)|)xlabel(omega/degree);ylabel(Amplitude);subplot(2,1,2)plot(w/pi*180,angle(h)/pi*180);gridtitle(PhaseSpectrumargH(eAjomega)xlabel(omega/degree);ylabel(Phaseindegrees);MagnitudeSpectrumupm一-dlulc-zcroplotolarulionalz-lRinsibrinG(z)canb
10、ereadilyobtainedusinglheliinclionzplane.Therearetwoversionsolthisfunclion.IIlhe-IrLinsIbrinisiveninlhelbrmofamlionallundionasinEq.(3.32).lhecommmidlouseiszplane(num,den)wheienumanddenarcixnvvectorscontaininglheeocflieienlsoflhenumcRiloranddcnoniiiiLilorpolynoniialsofG(z)inascending|xweil()nlheoilier
11、hand,iflhezerosandpleisindictUcdbvlhesvmbolxandlhelocalionofazeroisindiciUedbvlhesymbolG(z).Theprogramslalcmenllouseisz,p,k=tf2zp(num,den)wheicnumanddenarcixwvcelorseonlaininglhecocflicienlsoflhenunicraloranddcnoniiiiLilorpolynoniialsofinusccnding|xwersofs_1andlheoulpullileeonlainslhegainconstantkan
12、dthecomputedzerosandpolesgivenascolumnvectorszandp,respectively.Thefactoredformofthez-transformcanbeobtainedfromthezero-poledescriptionusinglhelunclionsos=zp2sos(z,p.Thefunclioncomputesthecoefficientsofeachsecond-orderfactorgivenasanLx6matrixsoswhere臥ii切1剛1盹1H212切2剛2125sos=boLbLb-2LfOLflL2Lwherethet
13、hrowcontainsthecoefficientsofthenumeratorandthedenominatorofthe&hsecond-orderlacloroflhe2-lraiislbrniG(z).血+b-2(z2Q12_1+口2?_2Questions:Q3,47WriteaMATLABprogramlocoinpuleunddisplaythepolesandzeros,lowmpiileanddisplaythefactoredtbrni,andtogeneratethepole-zeroplotofa-transformthatisaratiooftwopolynomia
14、lsin:_1.Usingthisprogram,analyzethez-lrunsformGofEq.(3.32).Q3.48Fromthepole-zeroplotgeneratedinQuestionQ3.47,determinethenumberofregionsofconvergence(R()C)訂G.SIkwexplicitlyallpossibleR()Cs.Canyoutelllionithepole-zeroplotwhetherornottheDTFTexists?Thereverseprocessofconvertinga2-transformgiveninthefor
15、mofzeros,poles,andthegninconstrmIloaralionalIbrmcanbeimpleinciilcdusinglhelimclioiizp2tf.TheprogramsliUemenllouseisnumjden=zp2tf(z,k).Question:Q3,49WriteaMATLABprogranilocoinpuleanddisplaylheralional2-Irunsformfromitszeros,polesandgainconstant.Usingthisprogram,determinetherationalformofaz-transformw
16、hosezerosareat4i=0.3,fa=2.5,3=0.2+j0.4,and4=0.2j0.4;lhepolesarcalAi=0.5.=(175.A:CL6+jCl7,andA4=0,6j0,7:andIliegainconslanlkis3.9.Answers:Q3.46Thefrequencyresponseofthez-transformobtainedusingProgramP3_1isplottedbelow:Q3.47TheMATLABprogramtocomputeanddisplaythepolesandzeros,tocomputeanddisplaythefact
17、oredform,andtogeneratethepole-zeroplotofarationalz-transformis21012七Ed當匸一Emlu-0X0-II0Q-9-8-7-654-3-2-101RealPartQ3.48Fromthepole-zeroplotgeneratedinQuestionQ3.47,thenumberofregionsofconvergence(ROC)ofG(z)are-4AllpossibleROCsofthisz-transformaresketchedbelow:|z|0.27180.2718|z|0.28660.2866|z|8.9576存在8
18、.9576|z|Fromthepole-zeroplotitcanbeseenthattheDTFTQ3.49TheMATLABprogramtocomputeanddisplaytherationalz-transformfromitszgros,polesandgainconstantisgivenbelow:z=0.32.5-0.2+0.4j-0.2-0.4j.;p=0.5-0.750.6+0.7j0.6-0.7j.;k=3.9;num,den=zp2tf(z,p,k);numdennum=3.9000-9.3600-0.6630-1.01400.5850den=1.0000-0.950
19、00.17500.6625-0.3187Therationalformofaz-transformwiththegivenpoles,zeros,andgainisfoundtobe3.99.36zi0.663z21.0140z-3+0.5850z-4G(z)=10.95z-i+0.1750z-2+0.6625z-30.3187z-4第三題Questions:Q44ModifyProgramP3_ltocomputeundplotthemagnitudeandphasespectraofamovingaveragefilterofEq.(2.13)forthreedifferentvalues
20、oflengthMandfor0wJuslilyIlietypeofsymmclricsexhibiledbytheinagiiiludemidphasespectra.Wh:iltypeoffilterdoesitrepresent?CanyounowexplaintheresultsofQuestionQ2.1?ThemodifiedProgramP3_lcanalsobeusedtocomputelhefrequencyresponseofanLTIJiscrclc-liinesyslcnifromitsiRinsfcrliincliondescriptionasinEq.(4.12).
21、Questions:Q4,2UsinglhemodiliedProgramP3_lcomputeandplotlhefrequencyresponseofacausalLTIdiscrclc-limcsystemwithaIrunsIcrluiicliongivenby(4.36)lor0a;esilrcprcsenl?Project2.1TheMovingAverageSystemExjLiriLnLLionofEq.f1.21reveals;thatthethree-pointjinioothingtillerconfiiJrcdix1TlFIRMoreover,川“l(fā)eprriiiKti
22、nniLhEihrtrinpLifsample.?|n+Inthenonciual.AcausalversinnofThethree-pcintmn(xhingtillerisnbiainedbysimplydekiyinLheouipuibyonesiiinpl.epcriinj.resultininhi?FIRliberdesciihcdbj/n(工審+工代f1+日“2)r(2-12)CiLhiii?raizinglheabnvtwetibuin1站仏=和e*-虬(2+13)it0whichtlchnesaCiuiHulA/-pointsiinoolTiinFIRfilterThesyst
23、emofEq.(2.Ealsokiion;恬lirHavingtiverticfiifcr.WeilltLslndci低ttseitilillcrin*;hii.h-frcquencjcoitifxincnlsironiacomposctjoE7asutnofwveralsinusoidulsignah.Answers:Q4.1ThemodifiedProgramP3_1tocomputeandplotthemagnitudeandphasespectraofamovingaveragefilterofEq.(2.13)for02兀isshownbelow:w=-4*pi:8*pi/511:4
24、*pi;M=5;h=freqz(ones(1,M)/M,1,w);subplot(2,1,1)plot(w/pi,abs(h);gridtitle(MagnitudeSpectrum|H(eAjomega)|)xlabel(omega/pi);ylabel(Amplitude);subplot(2,1,2)plot(w/pi,angle(h)/pi);gridtitle(PhaseSpectrumargH(eAjomega)xlabel(omega/pi);ylabel(Phaseinrad);Thisprogramwasrunforthefollowingthreedifferentvalu
25、esofMandtheplotsofthecorrespondingfrequencyresponsesareshownbelow:M=5:11A-3-2-1012345a也pn三dujid/7TPhaseSpectrum古gH(R)M=10:PE=邊EL-dM=20:o-Opm-l匚一們ineqdMagnitudeSpectrum-2-101234PhaseSpectrum白rgH(J)-0.5V-3-2-101iU/T234-1012MagnitudeSpectrumH佗5aaipn七-duJ0pe匚一DZJeud低通濾波器Thetypesofsymmetriesexhibitedbyth
26、emagnitudeandphasespectraaredueto-滑動窗口平均濾波器的單位脈沖響應序列是實偶對稱序列。ThetypeoffilterrepresentedbythemovingaveragefilterisTheresultsofQuestionQ2.1cannowbeexplainedasfollows-波器實際上是一種低通濾波器,所以能夠去掉信號中的高頻正弦波而保留低頻正弦波。Q4.2TheplotofthefrequencyresponseofthecausalLTIdiscrete-timesystemofQuestionQ4.2obtainedusingthemod
27、ifiedprogramisgivenbelow:Thetypeoffilterrepresentedbythistransferfunctionis帶通濾波器gpa-dlLJVdMagnitudeSpectrum|H(e)|(J/TPhaseSpectrumargH(e)(J/T第四題Questions:Q4.23UsingMATLABgcnemlethepole-zeroplotsoflhefollowingtwocausalIransIcrfunctions.Hi11-18z-1+0,S5-2並=11-L851Z-1+0.S52-3Canyouinfertheirstabilitybye
28、xaminingthegeneratedpole-zeroplots?Q4,24TesttheslabililyolIheIrunsIerfunclionsin(JucslionQ4.23usingProgmmP4_4.Whichoneofthetwotransferfunctionsisstable?Q4.25UsingProgramP4_4determinewhetherornotalltherootsofthefollowingpolynomialareinsidetheunitcircle:D(z)=1+2,52_1+2,5.7-3+0.3125+0,03125Answers:Q4.2
29、3Thepole-zeroplotsofH1(z)andH2(z)obtainedusingzplaneareshownbelow:zplane(1,1-1.8480.85);pausezplane(1,1-1.8510.85);-O.B-O.S-13B42d.240.亡rodAJEBBLU一-0.6-0.B-1-0.50.5186420240.0.000.0.-ii一md已raUWPE-異-050051RealPart0RealPartFromtheabovepole-zeroplotsweobservethatH1(z)的所有極點都在單位圓內,穩(wěn)定;H2(z)有一個極點在單位圓外,不穩(wěn)定。
30、Q4.24UsingProgramP4_4wetestedthestabilityofH1(z)andarriveatthefollowingstabilitytestparametersk,:Denominatorcoefficients=1-1.8480.85Stabilitytestparametersare-0.99890.8500FromtheseparametersweconcludethatH1(z)is_.UsingProgramP4_4wetestedthestabilityofH2(z)andarriveatthefollowingstabilitytestparamete
31、rs$:Denominatorcoefficients=1-1.8510.85Stabilitytestparametersare-1.00050.8500FromtheseparametersweconcludethatH2(z)is_.Q4.25UsingProgramP4_4wetestedtherootlocationsofD(z)andarriveatthefollowingstabilitytestparameterski:Denominatorcoefficients=50.31250.03125Stabilitytestparametersare0.96300.87260.62
32、250.23460.0313_theunitFromtheseparametersweconcludethatallrootsofD(z)are_circle.第五題Questions:Q5,lRunProgramP5_ltogenerateboththecontinuous-limesignalanditssampledvcrsioiLanddisplaythem.Q5,2Wh;uisiliefrequencyinHzofthesinusoidalsignal?Whalisthesamplingperiodinseconds?Q5.3Explaintheeffectsofthetwoaxis
33、commands.Q5,4RunProgramP5_lforfourothervaluesofthesamplingperiodwithtwolowerandtwohigherthanthatlistedinProgramP5_l.Commentonyourresults.Q5,5RepeatProgramP5_lbychangingthefrequencyofthesinusoidalsignalto3Hzanil1Hz.rcspcclivcly.Is(hereanydifferencebetweenthecorrcsixnidingequivalentdiscrete-timesignal
34、sandtheonegeneratedinQuestionQ5.1?Ifnot,whynol?Answers:A,copyofProgramP51isgivenbelow:%ProgramP5_1%IllustrationoftheSamplingProcess%intheTime-Domainclf;t=0:0.0005:1;f=13;xa=cos(2*pi*f*t);subplot(2,1,1)plot(t,xa);gridxlabel(Time,msec);ylabel(Amplitude);title(Continuous-timesignalx_a(t);axis(01-1.21.2
35、)subplot(2,1,2);T=0.1;n=0:T:1;xs=cos(2*pi*f*n);k=0:length(n)-1;stem(k,xs);grid;xlabel(Timeindexn);ylabel(Amplitude);title(Discrete-timesignalxn);axis(0(length(n)-1)-1.21.2)Q5.1Theplotsofthecontinuous-timesignalanditssampledversiongeneratedbyrunningProgramP5_1areshownbelow:ao.p2-dEV012345678910Timein
36、dexn-0.1SQ5.2ThefrequencyofthesinusoidalsignalinHzis13HzThesamplingperiodinsecondsisQ5.3Theeffectsofthetwoaxiscommandsare使圖像邊緣留有一定空隙不至于變成這樣:uprl七一dEVOPFI4一-dulvDiscrete-timesignalxnQ5.4Theplotsofthecontinuous-timesignalanditssampledversiongeneratedbyrunningProgramP5_1forthefollowingfourvaluesofthesa
37、mplingperiodareshownbelow:Ts=0.01s:ContinuOLis-timesignalxit)3.5051o.o-=0705一-dEOOJ0.201Time,msecDiscrete-timesignalxnTs=0.03s:Continuous-timesignalx(I)呂1505*uprq_duj0510250.102030.4050.60.7OBD.91Tim已msecDiscrete-timesignalxnDpn_=dul1520TimeindexnTs=0.2s:Gontinuous-timesignetlx(t)tlup2-duj述flL7c3Tim
38、e,msecDiscrete-timesignalxn15050a00.511.522.533.544.55TimeindexnTs=0.25s:ContinuouE-timgsignalx(t)a-O.pnlKEQ0OJ00.91Time,msecDiscrete-timesignalxnoep5-dlu0051L522533.54TimeindexnBasedontheseresultswemakethefollowingobservations-只要采樣頻率低于于信號最高頻率的兩倍,就不能根據采樣信號還原原信號了。Q5.5Theplotsofthecontinuous-timesinus
39、oidalsignaloffrequency3HzanditssampledversiongeneratedbyrunningamodifiedProgramP5_1areshownbelow:Continuous-timesignalx(t)日15051a-O.-mpB-dluv0010.20.3OX0.80.91Time,rnsecDiscrete-timesignalxno-Oopr!4=dE012345678910TimeindexnTheplotsofthecontinuous-timesinusoidalsignaloffrequency7Hzanditssampledversio
40、ngeneratedbyrunningamodifiedProgramP5_1areshownbelow:Continuous-timesignalx(t)日15051ad-aip2KUJ0Od0.80.91Tim已msecDiscrete-limesignalxno-OapE一-dulndinequivalentdisercle-limesignalsandlhenegenemlcdin(Jues-lionQ5.0?Ifnot.whynot?Answers:AcopyofProgramP52isgivenbelow:%ProgramP5_2%IllustrationofAliasingEff
41、ectintheTime-Domain%ProgramadaptedfromKra94withpermissionfrom%TheMathworks,Inc.,Natick,MA.clf;T=0.1;f=13;n=(0:T:1);xs=cos(2*pi*f*n);t=linspace(-0.5,1.5,500);ya=sinc(1/T)*t(:,ones(size(n)-(1/T)*n(:,ones(size(t)*xs;plot(n,xs,o,t,ya);grid;xlabel(Time,msec);ylabel(Amplitude);title(Reconstructedcontinuou
42、s-timesignaly_a(t);axis(01-1.21.2);Q5.6Theplotsofthediscrete-timesignalanditscontinuous-timeequivalentobtainedbyrunningProgramP5_2areshownbelow:epn莖dERecanstnjctpdcontinuQLi&tiiTiesign白Iy(t)clIE5oII00.050.507O.B0.91Tima,msecQ5.7TherangeoftintheProgramis-0.5,1.5u)=0.004050010,1Thevalueofthetimeincrem
43、entis-Therangeoftintheplotis-TheplotgeneratedbyrunningProgramP5_2againwiththerangeoftchangedsoastodisplaythefullrangeofya(t)isshownbelow:.51Reconstruct自dcontinuoij$tiirisiqn刮y(t)EL.5-5051o.o.-aprn-dr00511.5Time,msecBasedontheseresultswemakethefollowingobservations號可以復原,區(qū)間外的信號會發(fā)生時域混疊。采樣區(qū)間內的信Q5.8Thepl
44、otsofthediscrete-timesignalanditscontinuous-timeequivalentobtainedbyrunningProgramP5_2withtheoriginaldisplayrangerestoredandwiththefrequencyofthesinusoidalsignalchangedto3Hzareshownbelow:Reconstructedcontinuous-time合ign自Iy(t)呂01Time,msecTheplotsofthediscrete-timesignalanditscontinuous-timeequivalent
45、obtainedbyrunningProgramP5_2withtheoriginaldisplayrangerestoredandwiththefrequencyofthesinusoidalsignalchangedto7Hzareshownbelow:Reconstructedcontinuous-timesignaly(t)1505D-o-fl3PB=dlu0OJ0D.1Time,msecBasedontheseresultswemakethefollowingobservations即頻率之和等于采樣頻率的兩個正弦信號恢復后的連續(xù)信號相同。Theseresultscanbeexpla
46、inedasfollows-即頻率之和等于米樣頻率的兩個正弦信號采樣值是相同的,恢復后的連續(xù)信號當然也相同。而且由于混疊,其中頻率高于采樣頻率一半的那個信號是沒有正?;謴偷?。第七題Questions:Q5,9Wh;uislliecontinuous-limeIunctionxa(t)inProgramP5_3?HowistheCTFTolbeingcomputed?Q5,10RunProgramP5_3togenerateanddisplaybothIliediscrete-timesignalanditsconlinuous-liinecquivalcnl,andIheirrcspccliv
47、eFourierIrunsforms.Is(hereanyvisibleeffectofaliasing?Q5,l1RepeatProgramP5_3byincreasingthesamplingperiodto1.5.Isthereanyvisibleeffectofaliasing?Q5,12ModifyProgramP5_3lurlhecase山(t)=andrepealQuestionsQ.1()andQ5.11.”Answers:AcopyofProgramP53isgivenbelow:%ProgramP5_3%IllustrationoftheAliasingEffect%int
48、heFrequency-Domainclf;t=0:0.005:10;xa=2*t.*exp(-t);subplot(2,2,1)plot(t,xa);gridxlabel(Time,msec);ylabel(Amplitude);title(Continuous-timesignalx_a(t);subplot(2,2,2)wa=0:10/511:10;ha=freqs(2,121,wa);plot(wa/(2*pi),abs(ha);grid;xlabel(Frequency,kHz);ylabel(Amplitude);title(|X_a(jOmega)|);axis(05/pi02)
49、;subplot(2,2,3)T=1;n=0:T:10;xs=2*n.*exp(-n);k=0:length(n)-1;stem(k,xs);grid;xlabel(Timeindexn);ylabel(Amplitude);title(Discrete-timesignalxn);subplot(2,2,4)wd=0:pi/255:pi;hd=freqz(xs,1,wd);plot(wd/(T*pi),T*abs(hd);grid;xlabel(Frequency,kHz);ylabel(Amplitude);title(|X(eAjomega)|);axis(01/T02)Q5.9Thec
50、ontinuous-timefunctionxa(t)inProgramP5_3isx(t)=tetaTheCTFTofxa(t)isbeingcomputedbywa=0:10/511:10;ha=freqs(2,121,wa);Q5.10TheplotsgeneratedbyrunningProgramP5_3areshownbelow:|XaQQ)|XaQQ)|Continuous-time合ign自Ix(t)呂o6420D.o.0.豆-duly510Time,msec冊prqi-duuvDiscrete-timesignalxnTimeindexn86420.00D.CDpn七-aEV10observations-兩者頻譜有定Basedont
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯系上傳者。文件的所有權益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網頁內容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
- 4. 未經權益所有人同意不得將文件中的內容挪作商業(yè)或盈利用途。
- 5. 人人文庫網僅提供信息存儲空間,僅對用戶上傳內容的表現方式做保護處理,對用戶上傳分享的文檔內容本身不做任何修改或編輯,并不能對任何下載內容負責。
- 6. 下載文件中如有侵權或不適當內容,請與我們聯系,我們立即糾正。
- 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 2025年度廚房廚師長團隊聘用與績效管理合同4篇
- 2025年度城鄉(xiāng)水利工程勞務分包施工協議4篇
- 2025年中國控油面膜行業(yè)市場調查研究及投資前景預測報告
- 2025年雙組分環(huán)氧富鋅底漆行業(yè)深度研究分析報告
- 2025年中國文娛消費行業(yè)發(fā)展?jié)摿Ψ治黾巴顿Y方向研究報告
- 2025年中國瓷質蓄熱填料行業(yè)市場發(fā)展前景及發(fā)展趨勢與投資戰(zhàn)略研究報告
- 2025年度木飾面產品環(huán)保性能測試與評估合同4篇
- 二零二五版?zhèn)€人住宅分租管理合同范本2篇
- 2025年度金融商務區(qū)場地規(guī)則與條款詳細約定合同4篇
- 2025年電池檢測測試設備市場分析報告
- 人教版初中語文2022-2024年三年中考真題匯編-學生版-專題08 古詩詞名篇名句默寫
- 2024-2025學年人教版(2024)七年級(上)數學寒假作業(yè)(十二)
- 山西粵電能源有限公司招聘筆試沖刺題2025
- 醫(yī)療行業(yè)軟件系統應急預案
- 使用錯誤評估報告(可用性工程)模版
- 《精密板料矯平機 第2部分:技術規(guī)范》
- 2024光伏發(fā)電工程交流匯流箱技術規(guī)范
- 旅游活動碳排放管理評價指標體系構建及實證研究
- 2022年全國職業(yè)院校技能大賽-電氣安裝與維修賽項規(guī)程
- 2024年黑龍江省政工師理論知識考試參考題庫(含答案)
- 四年級上冊脫式計算300題及答案
評論
0/150
提交評論