版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進行舉報或認領(lǐng)
文檔簡介
微分方程的例題分析及解法yepxdxq(x)epxCy()yfxy令uuxx()yfx(,)fxyyp,y(,)yfyyypyp20pqf(x)eP(x)xm~(x)eP(x)cosxp(x)sinx和flnyf(x)g(y)f(x)g(y)0的微分方程稱為變量可分離的微分方程,或稱可分離變量的微分方程,若1122f(x)g(y)021g(y)f(x)21g(y)1f(x)2G(y)F(x)Cxc)y1yy()dyyyff()或xdxxyfu)ux()()ypxyqx(x)q(x)yy、,p(q(xep(x)C)yep(x)()0ypxyyC(x)epxdxCe()()ypxCC(x)C(x)yC(x)ep(x)dx。yxylnxdx(xlny)dy0x(y)xx1yyy()()ypxyqxy,n(0nyzn)p(x)zn)q(x)1zC(x)n,CC(x)C(x)于yp(x)y0yCep(x)dx(x)yx)ep(x)dxyp(x)yq(x)用CCC(x)C(x)()Cxep(x)dxqx()C(x)C(x)ep(x)dxC(x)C(x)解yC(x)。p(x)C(x)q(x)eDy21nx例求yxx12lnxyp(x)q(x)y0的解xxxy。yC(x)x2lnx()Cxxx2lnx12lnxd()C(x)x2x2222lnxdxlnxCxx2xx22(lnxC)x2xlnx2Cxyxx表yypf(x,p)ypyypdpypdyypf(y,p)()pyqyfx,pqy當f(x)0pq0,212f(x)0yyyy0ypyy(x)yfyy。表的形式q0(),()fx()同次的多項式f(x)n0yx(x)q0是特征方程的單根(即時pq0yx2(x)yQ(x)eammf(x)mm與多項式乘積yx2Q(x)emyA(x)cosxB(x)sinxllf(x)P(x)xlnQ(x)sinxyxA(x)cosxBxmllA(x、B(x)都是次多項式lllxBx()cos()sinxa不是特征根a是特征根f(x)e[p(x)xyaxnllQ(x)sinx]()cosxB(x)sinxeAxxyaxmll(x)ayfkkx2(x)Q(x)A(x),y或或mlB(x)ylxCe1)1是CmCxCxemx12mai(cosecxCxsin)12y(4)2y2y2y6y022210432((0_22i123,41()CCxeix123,4cosx_Csinx,所以通解中含加項C34yCeCxeCcosxCsinxxx1234例1)(y)yyx(y)2ycosx222yy53ln2xxy2yxyyxx,yx;,xyC2;yy22yyxCxxy,yy,xy1;22;yy)dxdxxesintxtt;;xtdtdtdxdxxttxt2;2;2dtdt2cosxy()yxx;yyexeCxCx);x12(CcosxCsinx)xe(CcosxCsinx);xex;2x12120yy)CeCey(CCx)e;yyxxx1212CxCxy(CCx)e;;x1212解(y)2和yy中(y)2D513lnxyx。yyxxBdx為t(xAdt(x)ecosxyyxe(CcosxCsinx),k由fxkx12aiaaie(CcosxCsinx),yB。x120yy的iyCxCxC正12例2。xye。x0yy(0)(0)1yy。y1y。x解xyx12121212yCy1Cyx2。x2yeyeCyeCxC,xxx1120yy20012為yCeCx12y(0)y(0)1C2ye2。Cx12y,xdu,,uln(4)設(shè)u則xxlny例3(ee)dx(ee)dy0;xyxyxyy2(x2y)dxxdy0;(yxy)dxxdyy0224x2y,y(0)1yxy2解e(edxe(edy0xyyxeexye1e1xyd(ed(eyxe1e1yxln(eln(eCyx1(eeCxydx、dy0x2當xyx2y)dxdy0xyy令uxdyudxxduuu)xdu)0u0du2dxu2x12lnxCu1yx2lnxCuxy1xy2lnCx(xy2dx、dy20當xxyy[1()20xxyxy令uu1u)dxudxxdu)02x1u2lnu1uln2u1u2y將uxyx10C,C1。yCx222y0yxyx222y(xy)x22221y(x22x(4y)2yx)2d(4y4y22)dx1x2)24y1x22ln(4y)x)lnC22(4yx)C22(Cy1C5x0(4yx)522例41xyxy(2xyxdx0y0,x2dy(23)1x3yx2yyy(xy)0yee0xyx解yyxxyep(x)[q(x)ep(x)C]p(x)x,q(x)x,ye[C]elncosx[secxelncosxdxC]cos[secxsecxdxC]xxC)sinxCcosx(Ctan0yyxy0將yy,xylnxC1CxCy11C(x)x,設(shè)y()cossec,()sec2CxxCxxx2C(x)secxdxtanxCy(tanxC)cosxsinxCcosx(Cdy211y2dxxxx211(x),q(x)pxxx21122ye[()]eCxxxx211e2lnx[()edxC]2lnxxx2111[()xdxC]2x2xx211[(xx)C]2x2211C2xxC21y0C2111y2x2x223x2y0yx3yCe23x2Ce1Cxe1dx3lnx3x3x2x21y1Ce11yx3exxyx(y)yy11x,(yy11p(y),q(y),yyyxe1[e11dydyC]dyylnyylnyy1elnlny[eC]lnlnyy1y[C]yy11(yC)2y21Cy(C2y(yee0xydy1eyedx,exx1eeyyln(eeCe1Cex,eyxyyx)(Ce()()yfxgyy()yfx()yfcuc[q(x)ep(x)C]yep(x)①()()ypxyqx②p(xq(x)yCep(x)dxC()CxyC(x)ep(x)dx③C(x)C(x)Cep(x)ep(x)q(x)ep(x)yC0例5yxe()0y2yyxx)y2xy,y(0)0,y(0)3y(y)y23,yyyy解yxedxxeeCxxx1y(xeeC)dxxx1xe2eCxCxx12pxyypp020pppyCyyCyp11yCxlnC12yCeCx120ypyCyCpyCecx1201yCeCx12,ypy設(shè)yp2xp1x2lnpx)lnC21pyC)x21y(0)3C31)yyx2x3xC32(0)1得C1y,1yx3x13yy與pyypxppp30當ppp12PyC,PyC)y將pyC)lnyC)xlnC即2sin(yC)Cex2yarcsin(Ce)C(CC)x211ypyppp3pp(p211)xC2p21即故p2Ce2x11edxxydxCe2x1Ce2x1arcsin(Ce)CCx121C()yfxypyxyyypxyypxy例640560yyyyyy解022iye2(Ccos3xCsin3x)x126026,111yCe6Cexx12例74y4yy0(0)y(0)0y解44102121,21y(CCx)ex21212y(0)y(0)0CC1211yx)ex22例82y5y5x2y6y9y(xe23xyyyyy2y5y020解y2為52125yCCex21205xea20xyx(Ax2BxC)e0Ax3Bx2Cxx(x)yQ(x)f2y3Ax2BxC2y6Ax2B15AxA10B)x(4BC)5x2215A512A10B04BC0128,B,CA3525128yxxx323525x(1285yCCexx2x)323512690yyy69023()yCCxe3特征根為兩個相符的實根x12a3yx2(Ax2BxC)e3x[3Ax(4a3B)x(3BC)xCxey4323xy[9Ax4(24A9B)x2A18B9c)x2(6B12C)xCe3x126Cx122112A,BC1211yx(x)e3x2212211yCCx)e3xx(x)e3x221221211(xxCxC)e423x12221例9816yxe4yyx22y,(0)(0)0yyyxeyx(x)xef(x)xf(x)e與4解f4xx12y8()yfxxyy①②1816()yfxx4yyx2yyy與yy1122020yAxB1y、y228A16Ax16Bx,11,BA163211y1x16324yCx2e42xy、y2212Cee,C4x4x1yx2e4x22111yy1y2xx24xe163221a2202y(AxB)exy(ABAx)exy(B2AAx)ex(AxB)exexxAB0yxexye(CcosxCsinx)x12yyye(CcosxCsinx)xexx12y(0)y(0)0CC012y(cosxx)ex例44ye2sin5xyyyx23(sinyxyx224cosxyyyex440解2212(x)esin5x,aai2if2xye2(Acos5xBsin5x)xsin5xf(x)Ae2xf(x)e2(sin5x0cos5x)xye2[(2A5B)cos5x(2B5A)sin5x]xye2[(20B21A)cos5x(20A21B)sin5x]x,yy將ye2(25Acos5x25Bsin5x)e2sin5xxx1B,A251ye2xsin5x25230,1f(x)(xsinx2屬12(x)e[p(x)cosxQ(x)sinx]ap(x)0于flny(axa)cosx(bxb)sinx1010,y,有yy(abbx)cosx(baax)sinx101101y(2abbx)sinx(2baax)cosx101101(4ab2ab4axbx)cosx001111(2a4b2a2b2axbx)sinx(xsinx0111114ab2ab000114ab0112ab2ab100112ab111115a,b1011111a,b25500011111y(x)cosx(x)sinx102555022021ifxex()4cosx(3)特征方程為~f(x)e型,這里ap(x)p(x)0,ai1nyxe(CcosxCsinx)x12(x)CxCx,為求導計算方便,設(shè)u12yxeuxye(uxuxu)xye(xu222)xuuxuux,uuxCxuC12y2y2ye(xuxu2)uxeux2e(CsinxCcosx)x124xxCC12y2xesinxxcos例yyy2x(x)sinx2解將f11f(x)cos2x22y0yyy①y121yyy②③cos2yyyx2yyyy和yy112213102i22331yeCx(xCx)222120yA11212yA1aiayBcos2xBsin2x212y、y221(3B2B)cos2x(3B2B)sin2xcos2x21221123B2B123B2B02131,B,B故26131231ycos2xsin2x26132yyyy1233131xeCxCx)2x2x222212例a2解設(shè)p(x,y)yf(x)Yyy(Xx)或Yy(Xx)y(X,Y)xX11Sx[y(Xx)ydX[y(Xx)yX]yxyx2x02220Sa2得1yxyxa2222y6a2y即xx22yCeCe2lnCx2xxyC(x)x26a26a2()CxxCx,()2x2x46a22a2C(x)Cx4x32a2y(C)x2x32a2y()2xx[x,xdx]dxydx例潛水艇下降過程中受到重力mgkdtkmd2x即2d2mkm①20km2k,mkxCCet②m12(x)mg,0fkAxAtmgmg,Akmgkxt③④kkxt)CCettm120x(0)x(0)0tx(0)CC012kkkx(0)(Cet)0mm2t0mg2m2gC,C2k21k2xtkmg2kxt)tet)mk2yx。
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負責。
- 6. 下載文件中如有侵權(quán)或不適當內(nèi)容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 2024上海市高壓供用電合同
- 2024安徽省集體合同條例
- 2024個人之間借款合同參考范本
- 2024【挖機轉(zhuǎn)讓協(xié)議合同范本】出租車轉(zhuǎn)讓協(xié)議合同范本
- 2024小區(qū)門衛(wèi)勞動合同范本
- 深圳大學《游戲發(fā)行的商業(yè)實戰(zhàn)》2021-2022學年第一學期期末試卷
- 寫字樓物業(yè)停電應急預案(9篇)
- 關(guān)于新學期學習計劃范文集合七篇
- 眼鏡店開荒保潔施工合同
- 體育學校租賃協(xié)議
- 舞臺照明燈項目申請報告(模板范文)
- 小學作文訓練中如何培養(yǎng)學生的觀察能力
- xx鎮(zhèn)發(fā)展鮮食玉米“一鎮(zhèn)一業(yè)”產(chǎn)業(yè)項目建設(shè)方案
- IEEE1588學習筆記
- 物業(yè)合資公司組建方案
- 風光攝影教程
- 《正確的寫字姿勢》PPT課件.ppt
- 鋼管落地卸料平臺
- 耐熱鋼的選用
- 民間借貸(欠款)糾紛人民調(diào)解協(xié)議書范本
- 日語授受關(guān)系PPT演示課件
評論
0/150
提交評論